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Question 961

DSSSB Junior Assistant (LDC) 2025• Mental Ability & Reasoning 2

Six persons like different colours and they were seated in a row facing north. Two persons were seated between the one who likes Black colour and the one who likes Pink colour and neither of them was seated at the end. The one who likes Black colour was seated second to the left of the one who likes Red colour. The one who likes Green colour was seated at the right end. The one who likes Yellow colour was seated to the left of the one who likes Blue colour. Who was seated second to the left of the one who likes Blue colour?

  1. AOption (a)

    Yellow

  2. BOption (b)

    Cannot be determined

  3. COption (c)

    Green

  4. DOption (d)

    None of these

View answer & explanation

Correct answer

Answer: (a)A.

Yellow

Why this answer is correct

Correct option - 1

  1. Two persons were seated between the one who likes Black colour and the one who likes Pink colour and neither of them was seated at the end. The one who likes Black colour was seated second to the left of the one who likes Red colour.

  2. The one who likes Green colour was seated at the right end. The one who likes Yellow colour was seated to the left of the one who likes Blue colour. 

The one who likes Yellow colour was seated second to the left of the one who likes Blue colour

Hence, option 1 is the correct answer

Question 962

DSSSB Junior Assistant (LDC) 2025• Mental Ability & Reasoning 2

Select the figure that will come next in the following series.

  1. AOption (a)

  2. BOption (b)

  3. COption (c)

  4. DOption (d)

View answer & explanation

Correct answer

Answer: (d)D.

Why this answer is correct

The pattern followed is,

In each step, elements shift from left to right column-wise. For example, all the elements of column 1 shift to column 2, those of column 2 shift to column 3.

Then, the symbols in the first column rotate in a cyclic manner from top to bottom.

The figure which will come next is,

Hence, option 4 is the correct answer.

Question 963

DSSSB Junior Assistant (LDC) 2025• Mental Ability & Reasoning 2

In the following mixed series, one term is missing. Find out the missing term.

32H5, 16K10, 8O20, 4T40, ?

  1. AOption (a)

    2Y80

  2. BOption (b)

    2Z80

  3. COption (c)

    1Z80

  4. DOption (d)

    1Y80

View answer & explanation

Correct answer

Answer: (b)B.

2Z80

Why this answer is correct

Given Series: 32H5, 16K10, 8O20, 4T40, ?

The logic followed for first number is:

32 ÷ 2 = 16

16 ÷ 2 =   8

8 ÷ 2 =   4

4 ÷ 2 =   2

So, First digit will be 2.

The logic followed for the letters is:

Letters are: H, K, O, T

So, letter will be Z.

The logic followed for the number is:

Second numbers: 5, 10, 20, 40

5 × 2 = 10

10 × 2 = 20

20 × 2 = 40

40 × 2 = 80

Hence, the next term is 2Z80.

Question 964

DSSSB Junior Assistant (LDC) 2025• Mental Ability & Reasoning 2

Find the wrong term in the following series:

11, 20, 57, 226, 1115

  1. AOption (a)

    20

  2. BOption (b)

    57

  3. COption (c)

    226

  4. DOption (d)

    1115

View answer & explanation

Correct answer

Answer: (c)C.

226

Why this answer is correct

The series is:

11

11 × 2 - 2 = 20

20 × 3 - 3 = 57

57 × 4 - 4 = 224

224 × 5 - 5 = 1115

Hence, wrong term is 226, Option (3) is correct.

Question 965

DSSSB Junior Assistant (LDC) 2025• Mental Ability & Reasoning 2

Select the number that can replace the question mark ? In the following series.

30, 38, 52, ?, 98, 130

  1. AOption (a)

    70

  2. BOption (b)

    71

  3. COption (c)

    72

  4. DOption (d)

    75

View answer & explanation

Correct answer

Answer: (c)C.

72

Why this answer is correct

Given series: 30, 38, 52, ?, 98, 130

The logic is:

Hence, 72 is the correct answer.

Question 966

DSSSB Junior Assistant (LDC) 2025• Numerical Ability & Data Interpretation 1

A shopkeeper marks up the price of an article 60% above the C.P. and gives 10% discount, Find the profit %.

  1. AOption (a)

    48

  2. BOption (b)

    24

  3. COption (c)

    54

  4. DOption (d)

    44

View answer & explanation

Correct answer

Answer: (d)D.

44

Why this answer is correct

Given: 

Mark up% = 60%

Discount = 10%

Concept used:

Marked price = C.P. + Markup % of C.P.

Selling Price = Marked price - Discount

Profit % = \({S.P. - C.P. \over C.P.}\) ×  100%

Calculations:

 

Marked price = C.P. + Markup % of C.P.

Selling Price = Marked price - Discount

Profit % = \({S.P. - C.P. \over C.P.}\) × 100%

Let the C.P. of the article = 100x

Marked price = 100x + 60% of 100x = 160x

Selling price = 160x - 10% of 160x = 144x

Profit % = \({144x - 100x\over 100x}\) × 100 % = 44%

Let the C.P. of the article = 100x

Marked price = 100x + 60% of 100x 

 ⇒ Marked price = 160x

Selling price = 160x - 10% of 160x

 ⇒ Selling price = 160x - 16x

 ⇒ Selling price = 144x

Profit = \({144x - 100x\over 100x}\) × 100 %

 ⇒ Profit = 44%

Hence option D is the correct answer.

Shortcut Trick⇒ M.P. = 160% of C.P

⇒ S.P. = 90% of M.P

⇒ (S.P.)/(C.P.) = (160/100) × (90/100) = 144/100

if, C.P. = 100, then S.P. = 144.

∴ Profit of Rs. 44 and P% of 44%, as we're calculating everything on 100.

Question 967

DSSSB Junior Assistant (LDC) 2025• Numerical Ability & Data Interpretation 1

P and Q starts a business with investment of Rs. 28000 and Rs. 42000 respectively. P invests for 8 months and Q invests for one year. If the total profit at the end of the year is Rs. 21125, then what is the share of P?

  1. AOption (a)

    Rs. 12625

  2. BOption (b)

    Rs. 14625

  3. COption (c)

    Rs. 6500

  4. DOption (d)

    Rs. 8750

View answer & explanation

Correct answer

Answer: (c)C.

Rs. 6500

Why this answer is correct

GIVEN:

Money invested by P is Rs. 28000 per month and he has invested for 8 months.

Money invested by Q is Rs. 42000 per month and he has invested for 12 months.

CONCEPT:

In this type of questions, the profit ratio among the persons is the same as that of the ratio of their capital investment. So we will find the ratio of capital investment, which will be the same as the profit ratio and since we know the total profit and profit ratio, we can find the individual profit.

FORMULA USED:

Profit made by A = (Amount of money invested by A × Total profit) / Total money invested by A and B together)

CALCULATION:

Total money invested by A = 28000 × 8 = 224000

Total money invested by A and B together = 28000 × 8 + 42000 × 12 = 728000

Profit made by A = (224000 × 21125) / 728000 = 6500

∴ The profit made by A is Rs. 6500.

Question 968

DSSSB Junior Assistant (LDC) 2025• Numerical Ability & Data Interpretation 1

Sunil purchased a fan at a 10% discount on the labelled price. If he had purchased it at a 15% discount, he would have saved ₹400. Find the labelled price of the fan.

  1. AOption (a)

    ₹8,400

  2. BOption (b)

    ₹7,500

  3. COption (c)

    ₹800

  4. DOption (d)

    ₹8,000

View answer & explanation

Correct answer

Answer: (d)D.

₹8,000

Why this answer is correct

Given:

Sunil purchased a fan at a 10% discount on the labeled price.

If he had purchased it at a 15% discount, he would have saved ₹400.

Concept used:

Cost price = Labelled price × (100 - discount)%

Calculation:

Let the labeled price of the fan be Rs. 100x

Now,

After the actual discount cost price of the fan for Sunil was = 100x × 90%

⇒ 90x

Now,

If he gets a 15% discount then,

Cost price = 100x × 85%

⇒ 85x

According to the question,

90x - 85x = 400

⇒ 5x = 400

⇒ x = 80

So, 100x = 8000

∴ The labeled price of the fan is ₹8,000.

Shortcut Trick

​A difference of 5% discount saved Rs.400

Then 100% → 400/5 × 100 = 8000 (Marked Price)

Question 969

DSSSB Junior Assistant (LDC) 2025• Numerical Ability & Data Interpretation 1

A sum of ₹3,596 is divided between A, B, and C in the ratio \(\frac{1}{6},:,\frac{1}{8}:,\frac{1}{9}\). What is the difference (in ₹) between the shares of A and C?

  1. AOption (a)

    434

  2. BOption (b)

    620

  3. COption (c)

    496

  4. DOption (d)

    372

View answer & explanation

Correct answer

Answer: (c)C.

496

Why this answer is correct

Shortcut Trick

LCM of the denominators 6, 8, and 9 is 72. Multiplying fractions by 72 gives integer ratio.

A : B : C = (1/6 × 72) : (1/8 × 72) : (1/9 × 72) = 12 : 9 : 8

Total units = 12 + 9 + 8 = 29 units → ₹3,596

1 unit = ₹3,596 ÷ 29 = ₹124

Difference between A and C = 12 − 8 = 4 units → 4 × 124 = 496

∴ The correct answer is ₹496.

Alternate Method

Given:

Total amount to be divided = ₹3,596

Initial ratio of shares of A, B, and C = 1/6 : 1/8 : 1/9

Calculations:

⇒ LCM of the denominators 6, 8, and 9 is 72.

⇒ Multiplying each fraction by 72 to get simple integer ratios:

⇒ Share of A = 1/6 × 72 = 12 units

⇒ Share of B = 1/8 × 72 = 9 units

⇒ Share of C = 1/9 × 72 = 8 units

⇒ Simplified ratio of shares A : B : C = 12 : 9 : 8

⇒ Total sum of ratio units = 12 + 9 + 8 = 29 units

⇒ We know, 29 units = ₹3,596

⇒ 1 unit = 3596 ÷ 29 = 124

⇒ Difference in ratio between A and C = 12 units − 8 units = 4 units

⇒ Total difference in amount = 4 × 124 = 496

∴ The correct answer is ₹496.

Additional Information

Ratio Simplification

To convert fractional ratios into simplest integer ratios, multiply each fraction by the Least Common Multiple (LCM) of all the denominators.

Proportion

When two ratios are equal, they are said to be in proportion (a/b = c/d). The core rule of proportion is that the product of the extremes equals the product of the means (a × d = b × c).

Distribution of Amount

If a total quantity T is to be divided among participants in the ratio a : b : c, the individual share can be calculated as Share = (Individual Ratio Unit ÷ Total Ratio Units) × T.

Question 970

DSSSB Junior Assistant (LDC) 2025• Numerical Ability & Data Interpretation 1

The boy-girl ratio of a class is 4 ∶ 3. The number of girls scoring above 60% and below 60% is in the ratio 5 ∶ 3. If the total strength of class is 56, how many girls score below 60%?

  1. AOption (a)

    6

  2. BOption (b)

    7

  3. COption (c)

    8

  4. DOption (d)

    9

View answer & explanation

Correct answer

Answer: (d)D.

9

Why this answer is correct

Total no. of students = 56

Boy-girl ratio = 4 ∶ 3

⇒ Total no. of girls = 3/7 × 56 = 24

Ratio of girls scoring above 60% and below 60% = 5 ∶ 3

∴ No of girls scoring below 60% = 3/8 × 24 = 9