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Question 761

DSSSB Junior Assistant (LDC) 2025• Mental Ability & Reasoning 2

In a certain code language, 'MODERN' is coded as ‘KOBALJ'. What is the code for ‘PEOPLE’ in that code language?

  1. AOption (a)

    BIMLCM

  2. BOption (b)

    BINLBN

  3. COption (c)

    BIMLBM

  4. DOption (d)

    BIMLBN

View answer & explanation

Correct answer

Answer: (c)C.

BIMLBM

Why this answer is correct

The logic followed here is:

'MODERN' is coded as ‘KOBALJ',

Similarly, for 'PEOPLE'

So, 'PEOPLE' will be coded as 'BIMLBM'.

Hence, the correct answer is "Option 3".

Question 762

DSSSB Junior Assistant (LDC) 2025• Mental Ability & Reasoning 2

In a certain coded language, ‘distant face’ is coded as ‘human sad’, ‘face stairs’ is coded as ‘sad overpower’, ‘distant cup’ is coded as ‘human tea’, and ‘stairs cup’ is coded as ‘overpower tea’. What is the code word for ‘face’?

  1. AOption (a)

    overpower

  2. BOption (b)

    tea

  3. COption (c)

    human

  4. DOption (d)

    sad

View answer & explanation

Correct answer

Answer: (d)D.

sad

Why this answer is correct

On following the given pattern we get that :

Hence, code word of face is "sad".

Question 763

DSSSB Junior Assistant (LDC) 2025• Mental Ability & Reasoning 2

If A means ×, B means ÷, C means +, D means -, then what will be the value of the given expression?

51 A 22 D (D 206 C 190) D (22 A 15) B 30 A 72

  1. AOption (a)

    22

  2. BOption (b)

    122

  3. COption (c)

    216

  4. DOption (d)

    40

View answer & explanation

Correct answer

Answer: (b)B.

122

Why this answer is correct

Decoding the information, 

SignABCD
Means×÷+-

Given:

51 A 22 D (D 206 C 190) D (22 A 15) B 30 A 72

After replacing the signs from left to right and using the BODMAS rule,

= 51 × 22 - (- 206 + 190) - (22 × 15) ÷ 30 × 72

= 51 × 4 - (- 206 + 190) - (4 × 15) ÷ 30 × 49

= 51 × 4 - (- 16) – 60 ÷ 30 × 49

= 51 × 4 + 16 – 60 ÷ 30 × 49

= 51 × 4 + 16 – 2 × 49

= 204 + 16 – 98

= 220 – 98

= 122

Hence, “122” is the correct answer.

Question 764

DSSSB Junior Assistant (LDC) 2025• Mental Ability & Reasoning 2

Directions

Find the missing term from the given alternatives:

17, 43, 81, 131, ?

  1. AOption (a)

    300

  2. BOption (b)

    193

  3. COption (c)

    375

  4. DOption (d)

    468

View answer & explanation

Correct answer

Answer: (b)B.

193

Why this answer is correct

17, 43, 81, 131, ?

43 – 17 = 26

81 – 43 = 38 (26 + 12)

131 – 81 = 50 (38 + 12)

⇒ next difference = 50 + 12 = 62

⇒ ? = 131 + 62 = 193

Hence, 193 is the answer.

Question 765

DSSSB Junior Assistant (LDC) 2025• Mental Ability & Reasoning 2

Four letter clusters have been given, out of which three are alike in some manner, while one is different. Select the odd letter cluster.

  1. AOption (a)

    DGFI

  2. BOption (b)

    GJHK

  3. COption (c)

    NQOR

  4. DOption (d)

    PSQT

View answer & explanation

Correct answer

Answer: (a)A.

DGFI

Why this answer is correct

The pattern followed here is:

Therefore, “DGFI” is odd among them.

Hence, “DGFI” is the correct answer.

Question 766

DSSSB Junior Assistant (LDC) 2025• Numerical Ability & Data Interpretation 1

A loss of \(10\frac{1}{2}%\) gets converted into a profit of \(11\frac{3}{5}%\) when the selling price is increased by Rs. 132.60. The cost price (in Rs.) the article is:

  1. AOption (a)

    750

  2. BOption (b)

    800

  3. COption (c)

    600

  4. DOption (d)

    500

View answer & explanation

Correct answer

Answer: (c)C.

600

Why this answer is correct

Given:

A loss of \(10\frac{1}{2}%\) gets converted into a profit of \(11\frac{3}{5}%\) when the selling price is increased by Rs. 132.60

Concept used:

SP = CP + CP × Profit%

SP = CP - CP × Loss%

Calculation:

Let CP of the article be 100a

Now,

SP for 1st case = 100a - 100a × \(10\frac{1}{2}%\)

⇒ 89.5a

SP for 2nd case = 100a + 100a × \(11\frac{3}{5}%\)

⇒ 111.6a

According to the question,

111.6a - 89.5a = 132.6

⇒ 22.1a = 132.6

⇒ a = 132.6/22.1

⇒ a = 6

So, cost price = 100 × 6

⇒ Rs. 600

∴ The cost price (in Rs.) the article is 600.

Shortcut TrickLoss = 10.5%, Profit = 11.6%

Overall profit increased = 11.6% - (- 10.5%) = 22.1%

22.1% = 132.6

1% = 6

100% = Rs. 600

Question 767

DSSSB Junior Assistant (LDC) 2025• Numerical Ability & Data Interpretation 1

The average age of a family of 11 members is 22 years. Surya is the youngest and his age is 2 years, then what was the average age of the family just before Surya was born?

  1. AOption (a)

    24

  2. BOption (b)

    22

  3. COption (c)

    18

  4. DOption (d)

    20

View answer & explanation

Correct answer

Answer: (b)B.

22

Why this answer is correct

Sum of age of 11 members of a family = 22 × 11 = 242

Before 2 year the sum of ages of all family members = 242 – 22 = 220 (before 2 years, ages of all family members will be less than 2 years. Hence, overall reduction in age = 11 × 2 = 22)

Now, there are only 10 members in the family, hence average age = 220/10 = 22

Question 768

DSSSB Junior Assistant (LDC) 2025• Numerical Ability & Data Interpretation 1

During the first year, the population of a town increased by 12%. The next year, due to some contagious disease, it decreased by 8%. At the end of the second year, the population was 64,400. Find the population of the town at beginning of the first year.

  1. AOption (a)

    50,000

  2. BOption (b)

    54,750

  3. COption (c)

    62,500

  4. DOption (d)

    50,500

View answer & explanation

Correct answer

Answer: (c)C.

62,500

Why this answer is correct

Given:

First year increase rate = 12%

Second year decrease rate = 8%

Calculations:

Let the initial population be x.

Then, According to question,

92% of 112% of x = 64,400

⇒ 0.92 × 1.12x = 64,400

⇒ x = 64,400/(0.92×1.12)

⇒ x = 64,400/1.0304

⇒ x = 62,500

Hence, The Required value is 62,500.

Question 769

DSSSB Junior Assistant (LDC) 2025• Numerical Ability & Data Interpretation 1

What is the value of \(2.\overline 3+4.\overline 3\)?

  1. AOption (a)

    \(\frac{21}{4}\)

  2. BOption (b)

    \(\frac{22}{7}\)

  3. COption (c)

    \(\frac{20}{3}\)

  4. DOption (d)

    \(\frac{18}{7}\)

View answer & explanation

Correct answer

Answer: (c)C.

\(\frac{20}{3}\)

Why this answer is correct

Given:

\(2.\overline 3+4.\overline 3\)

Formula Used:

\(a.\overline b\) = (ab - a)/9

Solution:

\(2.\overline 3+4.\overline 3\)

According to the formula 

⇒ (23 - 2)/9 + (43 - 4)/9

⇒ 21/9 + 39/9

⇒ 60/9

⇒ 20/3

∴ The value of \(2.\overline 3+4.\overline 3\) is 20/3.

Question 770

DSSSB Junior Assistant (LDC) 2025• Numerical Ability & Data Interpretation 1

In an election between 2 candidates, one got 55% of the valid votes, 10% of the votes were declared invalid. If the total numbers of votes were 18000, the numbers of valid votes the other candidate got?

  1. AOption (a)

    7290

  2. BOption (b)

    8450

  3. COption (c)

    11230

  4. DOption (d)

    5685

View answer & explanation

Correct answer

Answer: (a)A.

7290

Why this answer is correct

Total numbers of votes = 18000

Total numbers of invalid votes = 18000 × (10/100) = 1800

⇒ Total numbers of valid votes = (18000 − 1800) = 16200

One candidate got 55% of valid votes = 16200 × (55/100) = 8910

∴ The numbers of valid votes other candidate got = (16200 − 8910) = 7290

Shortcut TrickLet total number of votes = 1000 units

⇒ 1000 units = 18000

⇒ 1 units = 18

⇒ 405 units = 18 × 405 = 7290 votes