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Question 371

DSSSB Junior Assistant (LDC) 2025• Numerical Ability & Data Interpretation 1

The difference between the circumference and the diameter of a circle is 105 cm. Find the diameter.

  1. AOption (a)

    44 cm

  2. BOption (b)

    ​49 cm

  3. COption (c)

    42 cm

  4. DOption (d)

    35 cm

View answer & explanation

Correct answer

Answer: (b)B.

​49 cm

Why this answer is correct

Given:

The difference between the circumference and the diameter of a circle = 105 cm.

Formula used:

Circumference of a circle = 2πr

Diameter of a circle = 2r

Calculation:

Let the diameter of the circle be D cm and radius be r cm.

⇒ D = 2r

Circumference - Diameter = 105 cm

⇒ 2πr - 2r = 105

⇒ 2 × 227\dfrac{22}{7} ×  r - 2r = 105 

⇒ 44r7\dfrac{44\text{r}}{7} - 2r = 105

⇒ 44r−14r7\dfrac{44\text{r} - 14\text{r}}{7} = 105

⇒ 30r7\dfrac{30\text{r}}{7} = 105

⇒ 30r = 105 × 7 = 735

⇒ r = 73530\dfrac{735}{30} = 24.5 cm

Diameter (D) = 2r = 2 ×  24.5 = 49 cm

∴ The diameter of the circle is 4949 cm.

Question 372

DSSSB Junior Assistant (LDC) 2025• Numerical Ability & Data Interpretation 1

The radius of the base and height of a right circular cone are in the ratio 8 : 15. Find the slant height of the cone if its volume is 100557\frac{5}7 cm3

  1. AOption (a)

    12 cm

  2. BOption (b)

    17 cm

  3. COption (c)

    21 cm

  4. DOption (d)

    15 cm

View answer & explanation

Correct answer

Answer: (b)B.

17 cm

Why this answer is correct

Given:

Radius and height ratio = 8:15

Volume of the cone = 100557\frac{5}7 cm3

Formula Used:

Volume of a cone = (1/3) × π × r2 × h

Slant height (l) = √(r2 + h2)

Calculation:

Let radius be 8k and height be 15k.

Volume = 100557\frac{5}7 = 1005 + 5/7 = 7040/7 cm3

Volume of the cone = (1/3) × π × (8k)2 × (15k)

⇒ 7040/7 = (1/3) × π × 64k2 × 15k

⇒ 7040/7 = (1/3) × π × 960k3

⇒ 7040/7 = 320πk3

⇒ k3 = 1

⇒ k = 1

Therefore, radius r = 8k = 8 × 1 = 8 cm

Height h = 15k = 15 × 1 = 15 cm

Slant height (l) = √(r2 + h2)

⇒ l = √(82 + 152)

⇒ l = √(64 + 225)

⇒ l = √289

⇒ l = 17 cm

The slant height of the cone is 17 cm.

Question 373

DSSSB Junior Assistant (LDC) 2025• Numerical Ability & Data Interpretation 1

A cistern can be filled by a pipe in 10 hours. If there is a leak, it takes 2 hours more to fill it completely. If a cistern is full of water, in what time will it be empty?

  1. AOption (a)

    60 hours

  2. BOption (b)

    30 hours

  3. COption (c)

    20 hours

  4. DOption (d)

    45 hours

View answer & explanation

Correct answer

Answer: (a)A.

60 hours

Why this answer is correct

Given:

Time to fill a cistern = 10 hours

Time to fill a cistern when there is a leak in it = 10 + 2 = 12 hours

Calculation:

When there is a no-leak,

Pipe's 1-hour work = 1101\over10

When there is a leak,

Pipe's 1-hour work = 1121\over12

Now, a leak can empty a cistern in 'x' hour then,

⇒ 1101\over10 - 1121\over12 = 1x1\over x

⇒ 1601\over60 = 1x1\over x

⇒ x = 60 hours

Therefore, a cistern will empty in 60 hours.

Hence, the correct answer is 60 hours.

Question 374

DSSSB Junior Assistant (LDC) 2025• Numerical Ability & Data Interpretation 1

A shopkeeper marks the price of his goods at 20% higher than the cost price and allows a discount of 10%. What is his profit percentage?

  1. AOption (a)

    10%

  2. BOption (b)

    6%

  3. COption (c)

    8%

  4. DOption (d)

    4%

View answer & explanation

Correct answer

Answer: (c)C.

8%

Why this answer is correct

Shortcut Trick

Let the Cost Price (CP) be 100.

Marked Price (MP) = 100 + 20% of 100 = 120.

Selling Price (SP) = 120 − 10% of 120 = 120 − 12 = 108.

Profit Percentage = SP − CP = 108 − 100 = 8%.

Alternatively, use Successive Percentage formula: a + b + (a × b) ÷ 100.

Net change = 20 − 10 + (20 × −10) ÷ 100 = 10 − 2 = 8%.

∴ The correct answer is 8%.

Alternate Method

Given: Markup% = 20%, Discount% = 10%.

Formulas: SP = CP × (100 + Markup%) ÷ 100 × (100 − Discount%) ÷ 100 | Profit% = (SP − CP) ÷ CP × 100

⇒ Let Cost Price = 100 units.

⇒ Marked Price = 100 × (120 ÷ 100) = 120 units.

⇒ Selling Price = 120 × (90 ÷ 100) = 108 units.

⇒ Profit = SP − CP = 108 − 100 = 8 units.

⇒ Profit Percentage = (8 ÷ 100) × 100 = 8%.

∴ The correct answer is 8%.

Additional Information

Marked Price and Discount

The Marked Price (MP) is the price listed on the product. Discount is always calculated on the MP to arrive at the Selling Price (SP).

Successive Percentage Change

When a value is increased by x% and then decreased by y%, the net percentage change is given by: [x − y − (xy ÷ 100)]%.

Question 375

DSSSB Junior Assistant (LDC) 2025• Numerical Ability & Data Interpretation 1

Find the value of 53 × 24 × 25−2125 × 5−4{{5^3}\ ×\ {2^4}\ ×{\ 25^{-2}}}\over{{125} \ ×\ {5^{-4}}}

  1. AOption (a)

    16

  2. BOption (b)

    25

  3. COption (c)

    57

  4. DOption (d)

    125

View answer & explanation

Correct answer

Answer: (a)A.

16

Why this answer is correct

Calculation:

The given expression is:

53 × 24 × 25−2125 × 5−4{{5^3}\ ×\ {2^4}\ ×{\ 25^{-2}}}\over{{125} \ ×\ {5^{-4}}}

⇒ 53×24×54125×252{{5^3}×{2^4}×{5^{4}}}\over{{125}×{25^{2}}}

⇒ 57×2453×54{{5^7}×{2^4}}\over{{5^3}×{5^{4}}}

Since, 53 = 125 and 54 = 625

⇒ 57×2457{{5^7}×{2^4}}\over{{5^7}}

⇒ 24

⇒ 16

∴ the value of the expression is 16.

Question 376

DSSSB Junior Assistant (LDC) 2025• Numerical Ability & Data Interpretation 1

The population of a village is increased by 3%. Had there been 122 less, there would have been a decrease of 1%. Find the original population.

  1. AOption (a)

    3050

  2. BOption (b)

    3550

  3. COption (c)

    3555

  4. DOption (d)

    3000

View answer & explanation

Correct answer

Answer: (a)A.

3050

Why this answer is correct

Shortcut Trick

Difference in percentage = 3% − (−1%) = 4%

This 4% difference is equal to the numerical difference of 122.

⇒ 4% → 122

⇒ 1% → 122 ÷ 4 = 30.5

⇒ 100% → 30.5 × 100 = 3050

∴ The correct answer is 3050.

Alternate Method

Given:

Let the original population be P.

Increased population = P + 3% of P = 1.03P

Decreased population = P − 1% of P = 0.99P

Calculations:

According to the question, the difference between these two states is 122.

⇒ 1.03P − 0.99P = 122

⇒ 0.04P = 122

⇒ P = 122 ÷ 0.04

⇒ P = 12200 ÷ 4

⇒ P = 3050

∴ The correct answer is 3050.

Additional Information

Percentage Change

To find the net percentage change between an increase of x% and a decrease of y%, the total gap is (x + y)% if they are on opposite sides of the base value.

Base Value Concept

In population or price problems, the original value is always considered as 100% unless specified otherwise.

Successive Percentage

If a value changes by a% and then b%, the effective change is [a + b + (ab/100)]%.

Question 377

DSSSB Junior Assistant (LDC) 2025• Numerical Ability & Data Interpretation 1

The ratio of three numbers is 10: 15:13. If 10 percent of the first number is 66, what would be 50 percent of the difference of the third and second number?

  1. AOption (a)

    64

  2. BOption (b)

    65

  3. COption (c)

    68

  4. DOption (d)

    66

View answer & explanation

Correct answer

Answer: (d)D.

66

Why this answer is correct

Shortcut Trick

Let the numbers be 10x, 15x, and 13x.

Given: 10% of 10x = 66 ⇒ 1x = 66.

Required value: 50% of (15x − 13x) = 50% of 2x = 1x.

Since 1x = 66, the required value is 66.

∴ The correct answer is 66.

Alternate Method

Given: Ratio = 10 : 15 : 13 | 10% of 1st number = 66

Calculations:

⇒ Let the numbers be 10x, 15x, and 13x.

⇒ 10% of 10x = (10/100) × 10x = 1x

⇒ x = 66

⇒ Difference between 2nd and 3rd number = 15x − 13x = 2x

⇒ 50% of the difference = (50/100) × 2x = 1x

⇒ Since x = 66, the value is 66.

∴ The correct answer is 66.

Additional Information

Ratio and Proportion

If a : b : c is the ratio, then the numbers can be expressed as ax, bx, and cx where x is a common multiplier.

Percentage Calculation

To find p% of a number N, use the formula (p/100) × N. Note that 50% is equivalent to half (1/2) of the value.

Base Value Logic

When the percentage and the ratio part result in 1 unit of 'x', that value directly represents the scaling factor for all other calculations.

Question 378

DSSSB Junior Assistant (LDC) 2025• Numerical Ability & Data Interpretation 1

A man covers 30 km by car at a speed of 60 km/h and another 20 km by cycle. His whole journey is completed in 3 hours. What is the speed (in km/h) of the cycle?

  1. AOption (a)

    10

  2. BOption (b)

    12

  3. COption (c)

    8

  4. DOption (d)

    6

View answer & explanation

Correct answer

Answer: (c)C.

8

Why this answer is correct

Given:

Distance covered by car = 30 km

Speed of car = 60 km/h

Distance covered by cycle = 20 km

Total journey time = 3 hours

Formula used:

Time = Distance ÷ Speed

Total time = Time by car + Time by cycle

Calculation:

Time by car = Distance covered by car ÷ Speed of car

⇒ Time by car = 30 ÷ 60 = 0.5 hours

Total time = Time by car + Time by cycle

⇒ 3 = 0.5 + (Distance by cycle ÷ Speed of cycle)

⇒ 3 - 0.5 = (20 / Speed of cycle)

⇒ 2.5 = (20 / Speed of cycle)

⇒ Speed of cycle = 20 / 2.5 = 8 km/h

∴ The correct answer is option (3).

Question 379

DSSSB Junior Assistant (LDC) 2025• Numerical Ability & Data Interpretation 1

The curved surface area of a cylinder is three-fifth of its total surface area. Find the ratio between the height and radius of the cylinder.

  1. AOption (a)

    3 : 2

  2. BOption (b)

    2 : 5

  3. COption (c)

    3 : 5

  4. DOption (d)

    8 : 3

View answer & explanation

Correct answer

Answer: (a)A.

3 : 2

Why this answer is correct

Given:

The curved surface area of a cylinder is three-fifth of its total surface area.

Formula Used:

Curved Surface Area (CSA) of a cylinder = 2πrh

Total Surface Area (TSA) of a cylinder = 2πrh + 2πr2

CSA = (3/5) TSA

Calculation:

Let the radius of the cylinder be r and the height be h.

Given, CSA = (3/5) TSA

⇒ 2πrh = (3/5)(2πrh + 2πr2)

⇒ 2πrh = (6πrh + 6πr2)/5

⇒ 10πrh = 6πrh + 6πr2

⇒ 10rh = 6rh + 6r2

⇒ 4rh = 6r2

⇒ h/r = 6/4

⇒ h/r = 3/2

The ratio between the height and radius of the cylinder is 3:2.

Question 380

DSSSB Junior Assistant (LDC) 2025• Numerical Ability & Data Interpretation 1

The sum of five consecutive numbers is 260. The sum of the first and the last numbers is:

  1. AOption (a)

    96

  2. BOption (b)

    126

  3. COption (c)

    116

  4. DOption (d)

    104

View answer & explanation

Correct answer

Answer: (d)D.

104

Why this answer is correct

Shortcut Trick

In a set of consecutive numbers, the Average is always the middle term.

Average = Total Sum ÷ Number of terms = 260 ÷ 5 = 52

For any set of numbers in Arithmetic Progression, the sum of the 1st and last terms is equal to twice the average.

Sum of first and last = 2 × Average = 2 × 52 = 104

∴ The correct answer is 104.

Alternate Method

Given: Sum of 5 consecutive numbers = 260.

Formula Used: Let the five consecutive numbers be x, (x + 1), (x + 2), (x + 3), and (x + 4).

Calculations:

⇒ Sum = x + (x + 1) + (x + 2) + (x + 3) + (x + 4) = 260

⇒ 5x + 10 = 260

⇒ 5x = 260 − 10

⇒ 5x = 250

⇒ x = 50

⇒ First number = x = 50

⇒ Last number = x + 4 = 50 + 4 = 54

⇒ Sum of first and last numbers = 50 + 54 = 104

∴ The correct answer is 104.

Additional Information

Arithmetic Progression (AP)

Consecutive numbers form an Arithmetic Progression with a common difference of 1. The sum of such a series is given by S = n ÷ 2 × (a + l), where a is the first term and l is the last term.

Middle Term Property

For an odd number of terms (n), the Average is exactly equal to the middle term. For a set of 5 numbers, the 3rd number is the average.

Equidistant Sum Rule

In any AP, the sum of terms equidistant from the beginning and the end is constant. Thus, First + Last = Second + Second Last = 2 × Middle term.