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Question 221

DSSSB Jail Warder 2025• Arithmetical and Numerical Ability 2

A right circular metal cone (solid) is 8 cm high and the radius is 2 cm. It is melted and recast into a sphere. What is the radius of the sphere?

  1. AOption (a)

    2 cm

  2. BOption (b)

    3 cm

  3. COption (c)

    4 cm

  4. DOption (d)

    5 cm

View answer & explanation

Correct answer

Answer: (a)A.

2 cm

Why this answer is correct

Given:

Height of cone = 8 cm

Radius of cone = 2 cm

Formula used:

Volume of sphere = 43\frac{4}{{3}}πR3

Volume of cone = 13\frac{1}{{3}}πr2h

Calculation:

According to the question

The volume of a sphere = Volume of a cone

⇒  43\frac{4}{{3}}πR3 = 13\frac{1}{{3}}πr2h

⇒ 43\frac{4}{{3}} × π × R3 = 13\frac{1}{{3}} × π × 2 × 2 × 8

⇒ R3 = 8

⇒ R = 2 cm

∴ The radius of the sphere is 2 cm.

Question 222

DSSSB Jail Warder 2025• Arithmetical and Numerical Ability 2

(81)-1 × 3-5 × 39 × (64)5/6 × (33)6=?(\sqrt[3]{3})^6=?

  1. AOption (a)

    299

  2. BOption (b)

    288

  3. COption (c)

    388

  4. DOption (d)

    188

View answer & explanation

Correct answer

Answer: (b)B.

288

Why this answer is correct

Given:

(81)-1 × 3-5 × 39 × (64)5/6 ×(33)6=?(\sqrt[3]{3})^6=?

Calculation:

Let the unknown number be x.

(81)-1 × 3-5 × 39 × (64)5/6 × (33)6(\sqrt[3]{3})^6 = x

⇒ (34)-1 × 3-5 × 39 × (26)5/6 × (31/3)6 = x

⇒ 3-4× 3-5 ×  39 × 2(6 × 5/6) × 3 6/3 = x

⇒ 3-4× 3-5 ×  39 × 2(6 × 5/6) × 32 = x

⇒ 3(- 4 - 5 + 9 + 2) × 25 = x

⇒ 32 × 32 = x 

⇒ x = 288

∴ The correct answer is option 2 i.e. 288

Question 223

DSSSB Jail Warder 2025• Arithmetical and Numerical Ability 2

If the inner radius of a hemispherical bowl is 5 cm and its thickness is 0.25 cm, then find the volume of the material required in making the bowl. (use π = 227\frac{22}{7}) (Rounded up to two places of decimals).

  1. AOption (a)

    34 cm3

  2. BOption (b)

    44 cm3

  3. COption (c)

    45.34 cm3

  4. DOption (d)

    41.28 cm3

View answer & explanation

Correct answer

Answer: (d)D.

41.28 cm3

Why this answer is correct

Shortcut Trick

Volume of material in a hemispherical bowl = 2/3 × π × (R3 − r3)

Inner radius (r) = 5 cm, Outer radius (R) = 5 + 0.25 = 5.25 cm

Volume = 2/3 × 22/7 × (5.253 − 53) ≈ 2.095 × (144.703 − 125) ≈ 2.095 × 19.703

Volume ≈ 41.28 cm3

∴ The correct answer is 41.28 cm3.

Alternate Method

Given:

Inner radius (r) = 5 cm

Thickness (t) = 0.25 cm

Outer radius (R) = Inner radius + Thickness = 5 + 0.25 = 5.25 cm

Formula Used:

Volume of material = 23\frac{2}{3} × π × (R3 − r3)

Calculations:

⇒ Volume = 2/3 × 22/7 × (5.253 − 53)

⇒ Volume = 44/21 × (144.703125 − 125)

⇒ Volume = 44/21 × 19.703125

⇒ Volume = 866.9375 / 21

⇒ Volume ≈ 41.2827... cm3

∴ The correct answer is 41.28 cm3.

Additional Information

Volume of Hemisphere

The volume of a solid hemisphere is given by V = 2/3 × π × r3.

Surface Area of Hemispherical Bowl

Inner Curved Surface Area = 2πr2; Outer Curved Surface Area = 2πR2.

Total Surface Area of Bowl

TSA = Outer CSA + Inner CSA + Area of Ring = 2πR2 + 2πr2 + π(R2 − r2).

Question 224

DSSSB Jail Warder 2025• Arithmetical and Numerical Ability 2

The radius of a hemisphere is 42 cm. Find half of its curved surface area (π=227)\left(\pi=\frac{22}{7}\right).

  1. AOption (a)

    4554 cm2

  2. BOption (b)

    5544 cm2

  3. COption (c)

    3663 cm2

  4. DOption (d)

    2772 cm2

View answer & explanation

Correct answer

Answer: (b)B.

5544 cm2

Why this answer is correct

Shortcut Trick

Radius (r) = 42 cm.

Curved Surface Area (CSA) of a hemisphere = 2πr2.

Half of CSA = (1/2) × 2πr2 = πr2.

Calculation: (22/7) × 42 × 42 = 22 × 6 × 42 = 132 × 42 = 5544 cm2.

∴ The correct answer is 5544 cm2.

Alternate Method

Given:

Radius (r) of the hemisphere = 42 cm.

Value of π = 22/7.

Formula Used:

Curved Surface Area (CSA) of a hemisphere = 2πr2

Required Value = (1/2) × CSA = πr2

Calculations:

⇒ Required Area = π × r × r

⇒ Required Area = (22/7) × 42 × 42

⇒ Required Area = 22 × (42 ÷ 7) × 42

⇒ Required Area = 22 × 6 × 42

⇒ Required Area = 132 × 42

⇒ Required Area = 5544 cm2

∴ The correct answer is 5544 cm2.

Additional Information

Total Surface Area of Hemisphere

The Total Surface Area (TSA) includes the curved part and the flat circular base: TSA = 3πr2.

Volume of Hemisphere

The Volume of a hemisphere is exactly half the volume of a sphere: V = (2/3)πr3.

Sphere Properties

For a complete Sphere, the Surface Area is 4πr2 and the Volume is (4/3)πr3.

Question 225

DSSSB Jail Warder 2025• Arithmetical and Numerical Ability 2

What is the compound interest on a sum of Rs. 12,000 for 258\frac{5}{8} years at 8% p.a. when the interest is compounded annually (nearest to a rupee)?

  1. AOption (a)

    Rs. 2,654

  2. BOption (b)

    Rs. 2,642

  3. COption (c)

    Rs. 2,712

  4. DOption (d)

    Rs. 2,697

View answer & explanation

Correct answer

Answer: (d)D.

Rs. 2,697

Why this answer is correct

Interest rate for first 2 years = 8%

Interest rate for 5/8 year = 5/8 × 8 = 5%

P = 12,000

As we know,

A = P (1 + r/100)3

⇒ A = 12,000 × (108/100) × (108/100) × (105/100)

⇒ A = 12,000 × (27/25) × (27/25) × (21/20)

⇒ A = 14697

∴ CI = 14697 – 12000 = 2697

Short Trick:

12500 unit = 12000

15309 – 12500 = 2809 unit

∴ 2809 unit = 12000/12500 × 2809 = 2697

Question 226

DSSSB Jail Warder 2025• Arithmetical and Numerical Ability 2

P and Q have invested in a business of 4 : 7. P has invested for 21 months. If P and Q receive profit in the ratio of 3 : 5, then for how many month did Q invested?

  1. AOption (a)

    20

  2. BOption (b)

    18

  3. COption (c)

    17

  4. DOption (d)

    15

View answer & explanation

Correct answer

Answer: (a)A.

20

Why this answer is correct

Shortcut Trick

We know that, Profit Ratio = Ratio of Equivalent Capital (Investment × Time).

Profit of P / Profit of Q = (P's Capital × P's Time) / (Q's Capital × Q's Time)

3 / 5 = (4 × 21) / (7 × Q's Time)

3 / 5 = 12 / Q's Time ⇒ Q's Time = (12 × 5) / 3 = 20

∴ The correct answer is 20 months.

Alternate Method

Given:

Investment ratio of P : Q = 4 : 7

P's investment period = 21 months

Profit ratio of P : Q = 3 : 5

Formula Used:

Profit Ratio = (Capital of A × Time of A) : (Capital of B × Time of B)

Calculation:

Let the investments of P and Q be 4x and 7x respectively.

Let Q's investment period be t months.

⇒ Profit of P / Profit of Q = (4x × 21) / (7x × t)

⇒ 3 / 5 = 84x / 7xt

⇒ 3 / 5 = 12 / t

⇒ 3 × t = 12 × 5

⇒ 3t = 60

⇒ t = 20

∴ The correct answer is 20 months.

Additional Information

Basic Principle of Partnership

In a partnership, the profit is distributed in proportion to the product of capital invested and the time period of investment. Hence, Profit = Capital × Time.

Active and Sleeping Partners

An active partner actively manages the business and usually receives a fixed salary or a specific percentage of profit for their effort, while the remaining profit is distributed according to capital investments.

Joining Mid-Way

If a business runs for a specific period (e.g., 12 months) and a partner joins after 'x' months, their capital is considered invested only for the remaining time, i.e., (12 − x) months.

Question 227

DSSSB Jail Warder 2025• Arithmetical and Numerical Ability 2

An amount of money is to be distributed between P, Q and R in the ratio of 3 : 7 : 12. If the difference between the shares of P and Q is Rs. X, and the difference between Q and R's share is Rs. 30000. find the total amount of money?

  1. AOption (a)

    11000

  2. BOption (b)

    12400

  3. COption (c)

    132000

  4. DOption (d)

    14300

View answer & explanation

Correct answer

Answer: (c)C.

132000

Why this answer is correct

Given:

P : Q : R = 3 : 7 : 12

Q - P = Rs. X

R - Q = Rs. 30000

Solution:

Let, k = constant

R - Q = 12k - 7k = 30000

⇒k = 30000/5 = 6000

Q - P = 7k - 3k = 4k = X

X = 4 x 6000 = 24000

Total money = 3k + 7k + 12k = 22k = 22 x 6000 = Rs. 132000

Hence, the correct option is 3.

Question 228

DSSSB Jail Warder 2025• Arithmetical and Numerical Ability 2

Today, the age of a father is thrice the age of his son. After 5 years, the age of father will be 2.5 times the age of his son. The age of son today is :

  1. AOption (a)

    20 years

  2. BOption (b)

    15 years

  3. COption (c)

    18 years

  4. DOption (d)

    22 years

View answer & explanation

Correct answer

Answer: (b)B.

15 years

Why this answer is correct

Shortcut Trick

Ratio of Father to Son Today = 3 : 1 (Difference = 2 units)

Ratio after 5 years = 2.5 : 1 = 5 : 2 (Difference = 3 units)

To equate difference, multiply Today by 3 and Future by 2:

Today = 9 : 3 | After 5 years = 10 : 4

Growth of 1 unit = 5 years. Son age today = 3 units = 3 × 5 = 15 years.

∴ The correct option is B.

Alternate Method

Given:

Let Son age today = S years

Father age today = 3S years

After 5 years: Son = S + 5 | Father = 3S + 5

Present F = 3S S = S After 5 Yrs F + 5 = 2.5(S+5)

  • 5 years

Ratio change: 3:1 → 2.5:1

Calculation:

⇒ Fatherfuture = 2.5 × Sonfuture

⇒ 3S + 5 = 2.5(S + 5)

⇒ 3S + 5 = 2.5S + 12.5

⇒ 3S − 2.5S = 12.5 − 5

⇒ 0.5S = 7.5

⇒ S = 7.5 ÷ 0.5

⇒ S = 15 years

∴ The correct option is B.

Additional Information

Constant Age Difference

The difference between the ages of two persons always remains constant regardless of the number of years passed.

Ratio Balancing Method

If A:B is the current ratio and C:D is the ratio after n years, equate (B−A) and (D−C) by multiplying with suitable constants to find the value of 1 unit.

Ages n years ago

If current age is X, then age n years ago was (X − n) and age n years hence will be (X + n).

Question 229

DSSSB Jail Warder 2025• Arithmetical and Numerical Ability 2

A number when increased by 50%, gives 2430. The number is:

  1. AOption (a)

    1620

  2. BOption (b)

    4860

  3. COption (c)

    810

  4. DOption (d)

    3240

View answer & explanation

Correct answer

Answer: (a)A.

1620

Why this answer is correct

Given:

A number when increased by 50% gives 2430.

Formula used:

If a number is increased by x%, the new value = original number × (1 + x/100).

Calculation:

Let the number be N.

According to the problem:

⇒ N × (1 + 50/100) = 2430

⇒ N × 1.5 = 2430

⇒ N = 2430 ÷ 1.5

⇒ N = 1620

∴ The correct answer is option (1).

Question 230

DSSSB Jail Warder 2025• Arithmetical and Numerical Ability 2

The simple interest per annum on a sum of Rs. x at the rate of 723%7\frac{2}{3}\% for 2122\frac{1}{2} years is Rs. 862.50. Find x.

  1. AOption (a)

    Rs. 3,200

  2. BOption (b)

    Rs. 4,500

  3. COption (c)

    Rs. 2,850

  4. DOption (d)

    Rs. 3,875

View answer & explanation

Correct answer

Answer: (b)B.

Rs. 4,500

Why this answer is correct

Given:

SI = Rs. 862.50

Rate = 7(2/3)%

Time = 2(1/2) years

Formula Used:

SI = PRT/100

Where, P = Principal, R = Rate, T = Time(in years)

Calculation:

According to the question,

862.50 = x×723×212100\frac{x\times7\frac{2}{3}\times2\frac{1}{2}}{100}

⇒ 862.50 = x×23×53×2×100\frac{x\times23\times5}{3\times2\times100}

⇒ x = 862.5×3×223×5\frac{862.5\times3\times2}{23\times5} = 4500

∴ The value of x is Rs. 4500.