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Given series:

% C & E @ % G # K R Z £ $ S @ C $ H V © Q €

The logic followed here is:

We need to find letters that are:

1. Immediately preceded by a letter, and

2. Immediately followed by a symbol.

Letter → Letter → Symbol

Checking each letter: % C & E @ % G # K R Z £ $ S @ C $ H V © Q €

Required letters:

Z in (R Z £)

V in (H V ©)

Number of such letters = 2

Hence, the correct answer is 'Option 3'.

Given:

E lives on the top floor. Therefore, E is on Floor 6.

C lives on an odd numbered floor but not 3. This leaves Floor 1 or Floor 5 for C.

The sum of floors on which C and F live is 7.

D lives immediately below B. The only two consecutive vacant floors are 4 and 3.

The remaining person A lives on the remaining Floor 1.

The final floor arrangement is:

From the table, C lives on Floor 5. Only E lives on Floor 6, which is above C.

Therefore, the number of people living above C is 1.

Hence, the correct answer is "Option 1".

The logic followed here is:

Step 1: Replace each letter with the letter immediately before it in the English alphabet.

ACADEMIC

A → Z

C → B

A → Z

D → C

E → D

M → L

I → H

C → B

Thus, the new letters formed are:

Z, B, Z, C, D, L, H, B

Step 2: Arrange these letters in alphabetical order.

B, B, C, D, H, L, Z, Z

Step 3: Find the fourth letter from the right.

From the right:

1^st → Z

2^nd → Z

3^rd → L

4^th → H

Therefore, the fourth letter from the right is H.

Hence, the correct answer is 'Option 4'.

Solution

⇒ D sits to the immediate right of E. (In a circular arrangement facing the centre, Right is Clockwise and Left is Anti-clockwise).

⇒ D sits second to the left of R. This means there is one person between R and D in the anti-clockwise direction. ∴ R is placed at the fourth position from E clockwise.

⇒ Q sits third to the left of E. Counting three places anti-clockwise from E, we place Q.

⇒ Only two people sit between R and F when counted from the left of F. Counting two seats anti-clockwise from R, we find the position for F.

⇒ T is not an immediate neighbour of Q. The only remaining seats are between D and R, and between Q and F. Since T cannot be next to Q, T sits between D and R. The last person P sits in the remaining seat between Q and F.

⇒ Therefore, there are 2 people (R and Q) sitting between P and T.

∴ Hence, the correct answer is "Option 1".

Solution

⇒ V sits third to the left of U. Since they are facing the centre, left direction is clockwise.

⇒ Only four people sit between V and S when counted from the right of V. Right direction is anticlockwise. Counting four seats anticlockwise from V, we place S.

⇒ Z is an immediate neighbor of both S and U. This means Z sits exactly between S and U.

⇒ T sits third to the left of Y. Placing Y at the seat between U and V, counting three places clockwise, T is placed between V and S.

⇒ X occupies the final remaining seat between Y and V.

⇒ There are 2 people (Y and U) between X and Z.

∴ Hence, the correct answer is "Option 1".

Solution

Given Statements:

Some walls are drums.

Some drums are lions.

The least possible Venn diagram for the given statement is:

Conclusions:

I. Some walls are lions - Does not follow (As there is no direct relation between walls and lions, it is a possibility but not a definite conclusion.)

II. All lions are drums - Does not follow (The statements only provide a partial relation that some drums are lions, so all lions being drums is not definite.)

So, neither conclusion I nor II follows.

Hence, the correct answer is "Option 2".

For the given series: (Left) P © £ I £ * & * @ S F % # H £ P @ R * & £ V (Right)

Logic: We need to identify letters that satisfy a specific condition: they must be immediately preceded by a letter and immediately followed by a symbol.

The required pattern is: Letter → Letter → Symbol

(Left) P © £ I £ * & * @ S F % # H £ P @ R * & £ V (Right)

Thus the pattern observed:

F in (S F %)

The pattern observed is: Only 1 such letter exists.

Hence, the correct answer is "Option 3".

Given: 

EXPO is coded as '5916'

OXES is coded as '1657'

Therefore, the code for 'S' is 7.

Hence, the correct answer is "Option 2".

Based on the information given, we can arrange the exam schedule from Monday to Sunday step by step:

1. No one has an exam after Z: This means Z has the exam on Sunday.

2. Only two people have an exam between Z and X: Counting back from Sunday, X must have the exam on Thursday (Friday and Saturday are the two days between them).

3. Only two people have an exam between A and X: Counting back from Thursday, A must have the exam on Monday (Tuesday and Wednesday are the two days between them).

4. I has an exam immediately after O: This means O and I must occupy consecutive available slots.

5. Only two people have an exam between E and I:

• If we place O and I on Friday and Saturday, then I is on Saturday. Two people between E and I (Friday and Thursday) would place E on Wednesday.
• This leaves Tuesday for U.

6. U has an exam on one of the days before O: In our current arrangement, U (Tuesday) is indeed before O (Friday). This satisfies all conditions.

Final Arrangement:

Therefore, U has an exam on Tuesday.

Hence, the correct answer is "Option 4".

The logic followed here is:

Step 1: Replace each letter with the letter immediately following it in the English alphabet.

TUGHRIK

T → U

U → V

G → H

H → I

R → S

I → J

K → L

Thus, the new letters formed are:

U, V, H, I, S, J, L

Step 2: Arrange these letters in alphabetical order.

H, I, J, L, S, U, V

Step 3: Find the fourth letter from the right.

From the right:

1^st → V

2^nd → U

3^rd → S

4^th → L

Therefore, the fourth letter from the right is L.

Hence, the correct answer is 'Option 2'.