By adding water to 80 litres of a 20% acid solution, the acid concentration is reduced to 10%. What volume of water was added?
- AOption (a)
50 L
- BOption (b)
75 L
- COption (c)
60 L
- DOption (d)
80 L
View answer & explanationHide answer & explanation
Correct answer
80 L
Why this answer is correct
Shortcut Trick
Since only water is added, the amount of acid remains constant.
Initial Concentration × Initial Volume = Final Concentration × Final Volume
20% × 80 L = 10% × (80 + Added Water)
16 = 0.1 × (80 + Added Water) ⇒ 160 = 80 + Added Water ⇒ Added Water = 80 L.
∴ The correct answer is 80 L.
Alternate Method
Given: Initial volume = 80 L, Initial acid = 20%, Final acid = 10%, Water acid concentration = 0%.
We use the Alligation Method to find the ratio of Initial Solution to Added Water.
⇒ Ratio of Acid Solution to Water = 10 : 10 = 1 : 1.
⇒ Since 1 unit represents the Initial Volume = 80 L.
⇒ Therefore, 1 unit of Added Water = 80 L.
∴ The correct answer is 80 L.
Additional Information
Rule of Constant Component
In dilution problems, identify the substance whose quantity does not change. Use the formula: Initial % × Initial Total = Final % × Final Total.
Alligation Cross Method
Ratio of ingredients = (Higher Value − Mean Value) : (Mean Value − Lower Value). It is the fastest way to solve mixture problems involving two components.
Water Concentration in Mixtures
When pure water is added to an acid/milk solution, the concentration of acid/milk in the added water is always taken as 0%.