A, B and C can do a job in 30, 40 and 48 days respectively. In how many days can A do the work if he is assisted by B and C every third day?
- AOption (a)
21
- BOption (b)
20.73
- COption (c)
21.14
- DOption (d)
20.14
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Correct answer
20.73
Why this answer is correct
Given
A can do a work = 30 days
B can do a work = 40 days
C can do a work = 48 days
Formula Used
Work = time × efficiency
Calculation
LCM of (30, 40 and 48) = 240
let total work be 240
Efficiency of A = 240/30 = 8/day
Efficiency of B = 240/40 = 6/ day
Efficiency of C = 240/48 = 5/day
1st 2 days work by A alone , so total work in 2 days = 16
on 3rd day, they work together , so total work on 3rd day = 19
3 days work = 16 + 19 = 35
⇒ 3 days × 6 = 35 × 6
⇒ 18 days work = 210
⇒ another 2 days work = 16
so, Remaining work by them after 20 days in time = 14/19 = .73
then total time to complete the work = 20 + .73 = 20.73 days
∴ The Required answer is 20.73 days.