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Question 51

CSIR ASO 2024• Test

What will be the least number which when doubled will be exactly divisible by 12, 18, 21 and 30?

  1. AOption (a)

    196

  2. BOption (b)

    630

  3. COption (c)

    1260

  4. DOption (d)

    2520

View answer & explanation

Correct answer

Answer: (b)B.

630

Why this answer is correct

Given:

Numbers = 12, 18, 21 and 30.

Calculation:

the least number which when doubled will be exactly divisible by 12, 18, 21 and 30.

LCM of (12, 18, 21, 30) = 1260.

∴ Required answer will be half of LCM = 1260/2 = 630.

Question 52

CSIR ASO 2024• Test

Successive discount of 15% and 35% is equivalent to a single discount of:

  1. AOption (a)

    42.28%

  2. BOption (b)

    12.5%

  3. COption (c)

    44.75%

  4. DOption (d)

    33.33%

View answer & explanation

Correct answer

Answer: (c)C.

44.75%

Why this answer is correct

Given:

Successive discounts of 15% and 35%

Calculation:

⇒ Equivalent discount = 1 - (1 - 15/100) × (1 - 35/100) = 0.4475 or 44.75%

Therefore, successive discounts of 15% and 35% is equivalent to a single discount of 0.4475 or 44.75%.

Question 53

CSIR ASO 2024• Test

The halves of the diagonals of a rhombus are 75 cm and 90 cm. Find its area.

  1. AOption (a)

    6750 cm2

  2. BOption (b)

    27000 cm2

  3. COption (c)

    3375 cm2

  4. DOption (d)

    13500 cm2

View answer & explanation

Correct answer

Answer: (d)D.

13500 cm2

Why this answer is correct

Shortcut Trick

Area of a rhombus = 2 × (Product of its half-diagonals).

Given half-diagonals are 75 cm and 90 cm.

Area = 2 × 75 × 90

Area = 150 × 90 = 13500 cm2.

∴ The correct answer is 13500 cm2.

Alternate Method

Given:

Half of first diagonal (d1/2) = 75 cm

Half of second diagonal (d2/2) = 90 cm

Formula Used:

Area of Rhombus = (1/2) × d1 × d2

⇒ First diagonal (d1) = 2 × 75 = 150 cm

⇒ Second diagonal (d2) = 2 × 90 = 180 cm

⇒ Area = (1/2) × 150 × 180

⇒ Area = 150 × 90

⇒ Area = 13500 cm2

∴ The correct answer is 13500 cm2.

Additional Information

Diagonal Property

The diagonals of a rhombus bisect each other at right angles (90°).

Side Length Formula

The side (a) of a rhombus can be calculated using half-diagonals: a = √((d1/2)2 + (d2/2)2).

Perimeter of Rhombus

The perimeter is 4 × side length, as all four sides of a rhombus are equal.

Question 54

CSIR ASO 2024• Test

Directions

What approximate value will come in place of the question mark (?) in the following question?

15.5% of 850 + 24.8% of 650 = ?

  1. AOption (a)

    293

  2. BOption (b)

    385

  3. COption (c)

    210

  4. DOption (d)

    375

View answer & explanation

Correct answer

Answer: (a)A.

293

Why this answer is correct

Given:

15.5% of 850 + 24.8% of 650 = ?

Calculation:

Let the unknown number be x.

15.5% of 850 + 24.8% of 650 = x

⇒ 15.5100\dfrac{15.5}{100} × 850 + 24.8100\dfrac{24.8}{100} × 650 = x

⇒ 131.75 + 161.2 = x

⇒ x = 292.95 ≈ 293

∴ 15.5% of 850 + 24.8% of 650 ≈ 293

Question 55

CSIR ASO 2024• Test

A certain number is subtracted from each of the numbers 20, 24, and 29. After the subtraction, the resulting numbers are in proportion. What is the number that was subtracted?

  1. AOption (a)

    6

  2. BOption (b)

    4

  3. COption (c)

    5

  4. DOption (d)

    3

View answer & explanation

Correct answer

Answer: (b)B.

4

Why this answer is correct

Shortcut Trick

The fastest way to solve this is by testing the options to find a common ratio.

Let's check Option 2, which gives the value 4.

Subtracting 4 from 20, 24, and 29 gives the numbers 16, 20, and 25.

Three numbers are in continued proportion if the ratio of the first to second equals the second to third.

Checking the ratios: 16 ÷ 20 = 4/5 and 20 ÷ 25 = 4/5. The condition is perfectly satisfied.

∴ The correct answer is 4.

Alternate Method

Given:

Three numbers: 20, 24, and 29

Formula Used:

If three numbers a, b, and c are in continued proportion, then a/b = b/c or b2 = a × c.

Calculations:

Let the number subtracted from each value be x.

⇒ The new numbers become (20 − x), (24 − x), and (29 − x).

⇒ According to the continued proportion rule: (20 − x) ÷ (24 − x) = (24 − x) ÷ (29 − x)

⇒ Cross-multiplying, we get:

⇒ (20 − x) × (29 − x) = (24 − x)2

⇒ 580 − 20x − 29x + x2 = 576 − 48x + x2

⇒ 580 − 49x = 576 − 48x

⇒ 580 − 576 = 49x − 48x

⇒ x = 4

∴ The correct answer is 4.

Additional Information

Proportion

Four numbers a, b, c, and d are said to be in proportion if a ÷ b = c ÷ d, denoted as a:b :: c:d.

Continued Proportion

Three numbers a, b, and c are in continued proportion if a:b = b:c, meaning b2 = a × c. Here, b is called the mean proportional between a and c.

Componendo and Dividendo Rule

For any valid proportion a/b = c/d, the rule states that (a + b) ÷ (a − b) = (c + d) ÷ (c − d). This property is highly useful for rapidly simplifying complex fractional equations without cross-multiplying.

Question 56

CSIR ASO 2024• Test

A dealer marks his goods at 44% above the cost price. Then he allows 50% discount on it. What would be his loss percentage?

  1. AOption (a)

    25%

  2. BOption (b)

    28%

  3. COption (c)

    26%

  4. DOption (d)

    32%

View answer & explanation

Correct answer

Answer: (b)B.

28%

Why this answer is correct

Given

Mark-up rate = 44%

Discount = 50%

Formula used:

M.P = (100 + m)/100 × C.P

where, m = mark-up rate, M.P = marked price and C.P = cost price

S.P = (100 - d)/100 × M.P

where, d = discount, M.P = marked price and S.P = selling price

Loss% = (C.P - S.P)/C.P × 100

Calculation

Let the C.P. be 100.

M.P = (100 + 44)/100 × 100

M.P = 144/100 × 100

M.P = 144

Now, the S.P will be:

S.P = (100 - 50)/100 × 144

S.P = 50/100 × 144

S.P = 72

Loss% = (100 - 72)/100 × 100

Loss% = 28

∴ The correct answer is option 2.

Question 57

CSIR ASO 2024• Test

The value of (1 + (1 - 2)-1 + 2 - (1 - 2)-2)2 is:

  1. AOption (a)

    1

  2. BOption (b)

    2

  3. COption (c)

    0

  4. DOption (d)

    -1

View answer & explanation

Correct answer

Answer: (a)A.

1

Why this answer is correct

Given:

(1 + (1 - 2)-1 + 2 - (1 - 2)-2)^2

Calculations:

(1 + (1 - 2)-1 + 2 - (1 - 2)-2)2

(1 - 2) is -1, so (1 - 2)-1 is -1 and (1 - 2)-2 is 1

⇒ (1 - 1 + 2 - 1)2

⇒ (1)2 = 1

∴ The value of the given expression is 1.

Question 58

CSIR ASO 2024• Test

If 2P = 3Q = 5R and P + Q + R = 6200, then the difference between P and R is:

  1. AOption (a)

    3000

  2. BOption (b)

    2000

  3. COption (c)

    1200

  4. DOption (d)

    1800

View answer & explanation

Correct answer

Answer: (d)D.

1800

Why this answer is correct

Given:

2P = 3Q = 5R

P + Q + R = 6200

Concept or Formula:

Use the given equations to express P, Q, and R in terms of a common variable.

Substitute these expressions into the second given equation to solve for the common variable.

Then calculate the values of P and R using the common variable.

The difference between P and R can be found by subtracting the smaller value from the larger one.

Solution:

Let 2P = 3Q = 5R = k (some constant)

⇒ P = k/2, Q = k/3, and R = k/5

Substitute P, Q, R in P + Q + R = 6200

⇒ k/2 + k/3 + k/5 = 6200

Solve the above equation for k,

⇒ k (1/2 + 1/3 + 1/5) = 6200

⇒ k (15/30 + 10/30 + 6/30) = 6200

⇒ k × 31/30 = 6200

⇒ k = 6200 × 30/31

⇒ k = 6000

Substitute k = 6000 in P = k/2 and R = k/5

⇒ P = 6000/2 = 3000 and R = 6000/5 = 1200

Find the difference between P and R

⇒ P - R = 3000 - 1200 = 1800

Therefore, the difference between P and R is 1800.

Question 59

CSIR ASO 2024• Test

A hemispherical dome of a tomb having diameter of 3.5 m is to be painted. If the cost of painting is 20 paise per cm2, then what is the cost (in Rs.) of painting the dome from inside? Take π = 227\frac{22}{7}

  1. AOption (a)

    Rs. 38,500

  2. BOption (b)

    Rs. 35,000

  3. COption (c)

    Rs. 28,500

  4. DOption (d)

    Rs. 25,000

View answer & explanation

Correct answer

Answer: (a)A.

Rs. 38,500

Why this answer is correct

Shortcut Trick

Radius (r) = 3.5 m / 2 = 1.75 m = 175 cm.

Inner Surface Area of dome = 2 × π × r2.

Area = 2 × (22/7) × 175 × 175 = 1,92,500 cm2.

Total Cost = Area × Rate = 1,92,500 × 0.20 = ₹38,500.

∴ The correct answer is ₹38,500.

Alternate Method

Given:

Diameter of the hemispherical dome (d) = 3.5 m

Cost of painting = 20 paise per cm2

Formula Used:

Inner surface area of a hemisphere = 2πr2

Total Cost = Surface Area × Rate

⇒ Radius (r) = d / 2 = 3.5 / 2 = 1.75 m

⇒ Radius in cm = 1.75 × 100 = 175 cm

⇒ Inner Surface Area = 2 × (22/7) × 175 × 175

⇒ Inner Surface Area = 2 × 22 × 25 × 175 = 1,92,500 cm2

⇒ Rate of painting = 20 paise = 20/100 = ₹0.20 per cm2

⇒ Total Cost = 1,92,500 × 0.20

⇒ Total Cost = ₹38,500

∴ The correct answer is ₹38,500.

Additional Information

Surface Area of a Sphere

The total surface area of a complete sphere is given by 4πr2, which is exactly double that of the curved surface area of a hemisphere.

Total Surface Area of a Hemisphere

If the base of the hemisphere is also included (closed hemisphere), the total surface area is 3πr2 (Curved area + Base area).

Volume of a Hemisphere

The volume of a hemisphere is half the volume of a sphere, calculated as V = (2/3)πr3.

Cost Calculation Rule

Always ensure that the units of dimensions (cm, m) and the rate (per cm2, per m2) are consistent before performing the final multiplication.

Question 60

CSIR ASO 2024• Test

The pie chart given below shows the production of wheat by six states. The total production of wheat by all these six states is 3600. The production of wheat of a particular state is shown in terms of degree with respect to the total production of wheat by all these six states.

What is the difference between average production of wheat by P and Q and the average production of wheat by R and T?

  1. AOption (a)

    300

  2. BOption (b)

    500

  3. COption (c)

    400

  4. DOption (d)

    200

View answer & explanation

Correct answer

Answer: (c)C.

400

Why this answer is correct

Calculation:

Total production of wheat by 6 states = 360° = 3600

⇒ 1° = 10

Production of state P = 110° = 110 × 10 = 1100

Production of state Q = 70° = 70 × 10 = 700

Average production by state P & Q = (1100 + 700)/2 = 900

Production of state R = 80° = 80 × 10 = 800

Production of state T = 20° = 20 × 10 = 200

Average production by state R & T = (800 + 200)/2 = 500

Difference between the average production of P and Q and R & T = 900 - 500 = 400

∴ The correct answer is 400.