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Question 181

CSIR ASO 2024• Test

The cost price of article X is Rs. 'a + 1000' and it is marked 60% above its cost price. The profit earned on article X is Rs. 1000 when a discount of 12.5% is given. If the cost price of article B is Rs. 'a + 500' and selling price is 14.28% less than selling price of article X, then find the profit percentage earned on selling article B?

  1. AOption (a)

    25%

  2. BOption (b)

    40%

  3. COption (c)

    50%

  4. DOption (d)

    75%

View answer & explanation

Correct answer

Answer: (c)C.

50%

Why this answer is correct

Given:

Cost price of article = a + 1000

Profit = Rs. 1000

Discount = 12.5%

Solution:

Marked price = 160%  of (a + 1000) = 8/5(a + 1000)

Selling price = 7/8 of (8/5(a + 1000) = 7/5 of (a + 1000)   (12.5% = 1/8)

Now,

Profit = SP - CP

1000 = 7/5of (a + 1000) - (a +1000)

1000 = (2a + 2000)/5

2a + 2000 = 5000

2a = 3000

a = 1500

Selling price of X = 7/5(a + 1000) = 3500

Now,

Cost price = a + 500 = 2000

Selling price of B is 14.28% less than selling price of article X

Selling price = 6/7 x 3500  (14.28% = 1/7)

= 3000

Profit% = (SP - CP)/CP x100 = (3000 - 2000)/2000 x 100 = 50%

Hence option (3) is correct.

Question 182

CSIR ASO 2024• Test

What is the value of 17×18÷7251\frac{1}{7} \times \frac{1}{8} \div \frac{72}{51} of (19+18)+(6356×4872)\left(\frac{1}{9}+\frac{1}{8}\right)+\left(\frac{63}{56} \times \frac{48}{72}\right)

  1. AOption (a)

    41/56

  2. BOption (b)

    27/56

  3. COption (c)

    45/56

  4. DOption (d)

    19/56

View answer & explanation

Correct answer

Answer: (c)C.

45/56

Why this answer is correct

Given:

The expression 17×18÷7251\frac{1}{7} \times \frac{1}{8} \div \frac{72}{51} of (19+18)+(6356×4872)\left(\frac{1}{9}+\frac{1}{8}\right)+\left(\frac{63}{56} \times \frac{48}{72}\right)

Concept used:

⇒ BODMAS rule

Calculation:

⇒ 17×18÷7251\frac{1}{7} \times \frac{1}{8} \div \frac{72}{51} of (8+972)+(98×23)(\frac{8 + 9 }{72}) + (\frac{9}{8} \times \frac{2}{3})

⇒ 17×18÷7251\frac{1}{7} \times \frac{1}{8} \div \frac{72}{51} of 1772+34\frac{17 }{72} + \frac{3}{4}

⇒ 17×18÷(7251×1772)\frac{1}{7} \times \frac{1}{8} \div( \frac{72}{51} \times \frac{17}{72}) + 34+ \ \frac{3}{4}

⇒ 17×(18÷13)+34\frac{1}{7} \times( \frac{1}{8} \div \frac{1}{3}) + \frac{3}{4}

⇒ 17×38+34\frac{1}{7} \times \frac{3}{8} + \frac{3}{4}

⇒ 356+34\frac{3}{56} + \frac{3}{4}

⇒ 4556\frac{45}{56}

Hence, the value of expression is 45/56.

Question 183

CSIR ASO 2024• Test

A Sari shop owner announced 10% off season discount followed by 15% festival discount. Sunita selected a Sari which was slightly damaged and bargained for further discount of 10%. She paid ₹2754 for the Sari. What was its marked price?

  1. AOption (a)

    ₹4200

  2. BOption (b)

    ₹4000

  3. COption (c)

    ₹3850

  4. DOption (d)

    ₹3600

View answer & explanation

Correct answer

Answer: (b)B.

₹4000

Why this answer is correct

Given:

Discount = 10%, 15% and 10%

SP = 2754

Formula used:

Profit = SP – CP

Discount% = Discount/MP × 100

Calculation:

Let the marked price be MP 

⇒ MP × (9/10)(17/20)(9/10) = 2754

⇒ MP × 1377/2000 = 2754

MP = 4000

The answer is 4000.

Question 184

CSIR ASO 2024• Test

X can do a piece of work in 270 days. X worked at it for 55 days and then Y finished the remaining work in 215 days. In how many days can X and Y to finish the work?

  1. AOption (a)

    137

  2. BOption (b)

    135 

  3. COption (c)

    145

  4. DOption (d)

    139

View answer & explanation

Correct answer

Answer: (b)B.

135 

Why this answer is correct

Given:

X can do a work = 270 days

Concept used:

Total Work = Efficiency × Time

Calculation:

According to the question,

⇒ X × 270 = X × 55 + Y × 215

⇒ X × (270 - 55) = Y × 215

⇒ X × 215 = Y × 215

⇒ XY \dfrac{\text{X}}{\text{Y}}  =215215 \dfrac{215 }{215} = 11 \dfrac{1 }{1}

∴ Efficiency of X: Efficiency of Y = 1: 1

Now, Total work = X × 270 = 1 × 270 = 270 unit

Time is taken by X and Y together = 2701+1 \dfrac{270 }{1+1}  = 2702 \dfrac{270 }{2}  = 135 days

∴ The time is taken by X and Y together is 135 days.

Question 185

CSIR ASO 2024• Test

A room in a house measures 5 m in height and its length is 3 times its breadth. The cost of whitewashing its four walls at Rs. 2.50 per sq m is Rs. 200. What is the cost of carpeting the floor at Rs. 5 per sq m?

  1. AOption (a)

    Rs. 84

  2. BOption (b)

    Rs. 60

  3. COption (c)

    Rs. 72

  4. DOption (d)

    Rs. 50

View answer & explanation

Correct answer

Answer: (b)B.

Rs. 60

Why this answer is correct

Given:

Height = 5 m

Cost of whitewashing 4 walls at Rs. 2.50 per sq m = Rs. 200

Cost of carpeting the floor = Rs. 5/m2

Calculation:

Let breadth be x meter

⇒ Length = 3x meter

Area of 2 walls along length side = 2 × height × length = 2 × 5 × 3x = 30x

Area of 2 walls along breadth side = 2 × height × breadth = 2 × 5 × x = 10x

Total area of 4 walls = 30x + 10x = 40x

Now, 40x × Rs. 2.5 = Rs. 200

⇒ 40x = 80

⇒ x = 2

Breadth = 2 meter

Length = 2 × 3 = 6 meter

Now, area of floor = length × breadth = (6 × 2) m2 = 12 m2

Cost of carpeting the floor at Rs. 5/m2 = 12 × 5 = Rs. 60

∴ Cost of carpeting the floor is Rs. 60

Question 186

CSIR ASO 2024• Test

A worker works 4 hours per day for the first week, 5 hours per day for the second week, and 6 hours per day for the third and fourth week. If his salary is calculated on the basis of Rs. 100 for every 30 minutes, then the amount he would receive at the end of four weeks is(there is no holiday on any day of the week) - 

  1. AOption (a)

    Rs. 29400

  2. BOption (b)

    Rs. 29600

  3. COption (c)

    Rs 29450

  4. DOption (d)

    Rs. 30000

View answer & explanation

Correct answer

Answer: (a)A.

Rs. 29400

Why this answer is correct

Given:

Hours worked per day in first week = 4

Hours worked per day in second week = 5

Hours worked per day in third and fourth week = 6

Rate = Rs. 100 for every 30 minutes 

Concept:

In these type of questions we calculate total hours worked and multiply them by the rate.

Formula:

Amount = Total hours × Price per hour

Calculations:

Hours worked in first week = 4 × 7

⇒ 28 hours 

Hours worked in second week = 5 × 7

⇒ 35 hours

Hours worked in third week = 6 × 7

⇒ 42 hours 

Hours worked in fourth week = 6 × 7

⇒ 42 hours 

∴ Total hours worked = 28 + 35 + 42 + 42

⇒ 147 hours

Rate = Rs. 100 for every 30 minutes

⇒ Rs. 100 × 2 for every hour

⇒ Rs. 200 per hour

∴ Amount that the worker will receive = 147 × 200

⇒ Rs. 29400

Question 187

CSIR ASO 2024• Test

Directions

What approximate value will come in place of the question mark (?) in the following question?

5456×2120÷460=?\sqrt{5456}\times \sqrt{2120}\div \sqrt{460}=?

  1. AOption (a)

    110

  2. BOption (b)

    130

  3. COption (c)

    159

  4. DOption (d)

    190

View answer & explanation

Correct answer

Answer: (c)C.

159

Why this answer is correct

DIRECTIONS: What approximate value will come in place of the question mark (?) in the following question?

√5456 × √2120 ÷ √460 = ?

Calculation:

First, approximate the square roots of the given numbers:

√5456 ≈ 74 (since 74 × 74 = 5476, which is close to 5456)

√2120 ≈ 46 (since 46 × 46 = 2116, which is close to 2120)

√460 ≈ 21.5 (since 21.5 × 21.5 = 462.25, which is close to 460)

Now, substitute these approximations into the equation:

√5456 × √2120 ÷ √460 ≈ 74 × 46 ÷ 21.5

Calculate the numerator:

74 × 46 = 3404

Now, divide by the denominator:

3404 ÷ 21.5 ≈ 158.32 ≈ 159

Therefore, the approximate value that will come in place of the question mark is 159.

Question 188

CSIR ASO 2024• Test

What value should come in place of question mark (?) in the following question?

1100% of 44 + 115% of 240 = ? - 24

  1. AOption (a)

    729 

  2. BOption (b)

    841 

  3. COption (c)

    1444 

  4. DOption (d)

    784 

View answer & explanation

Correct answer

Answer: (d)D.

784 

Why this answer is correct

Calculation

⇒ 1100% of 44 + 115% of 240 = ? - 24

⇒ 484 + 23 × 12 = ? - 24

⇒ 484 + 276 + 24 = ?

⇒ 784 = ?

The answer is 784.

Question 189

CSIR ASO 2024• Test

Three friends visited a sweetshop, where the shopkeeper gave them 'Vadas' in three plates. Total number of 'Vadas' was 12. The number of vadas of these plates, if arranged properly, were consecutive three even numbers. What was the maximum number of Vadas kept in a plate ?

  1. AOption (a)

    2

  2. BOption (b)

    3

  3. COption (c)

    4

  4. DOption (d)

    6

View answer & explanation

Correct answer

Answer: (d)D.

6

Why this answer is correct

Given:

Total number of 'Vadas' was 12.

Calculation:

Let's assume that the consecutive 3-even numbers be 2x, (2x + 2), (2x + 4)

Now, according to the question

⇒ 2x +  (2x + 2) + (2x + 4) = 12

⇒ 6x + 6 = 12

⇒ x = 1

So, the numbers are 2, 4, 6

∴ The maximum number of Vadas kept in a plate is 6

Question 190

CSIR ASO 2024• Test

Aman started a business with a capital of Rs. 4000. Bunty and Chaman joined after 7 months and 4 months respectively. At the end of the year, the profit was divided in the ratio 1 ∶ 3 ∶ 7. What is the difference between the capitals invested by Bunty and Chaman?

  1. AOption (a)

    Rs. 24800

  2. BOption (b)

    Rs. 28800

  3. COption (c)

    Rs. 42000

  4. DOption (d)

    Rs. 13200

View answer & explanation

Correct answer

Answer: (d)D.

Rs. 13200

Why this answer is correct

Shortcut Trick

Profit share is directly proportional to Capital × Time.

Aman's 1 profit ratio part = 4000 × 12 = 48000.

Bunty's profit (3 parts) = 3 × 48000 = 144000 ⇒ Bunty's Capital = 144000 ÷ 5 = Rs. 28800.

Chaman's profit (7 parts) = 7 × 48000 = 336000 ⇒ Chaman's Capital = 336000 ÷ 8 = Rs. 42000.

Difference in their capitals = 42000 − 28800 = 13200.

∴ The correct answer is Rs. 13200.

Alternate Method

Given:

Aman's Capital (CA) = Rs. 4000

Time of investment for Aman (TA) = 12 months

Bunty joined after 7 months, so Time (TB) = 12 − 7 = 5 months

Chaman joined after 4 months, so Time (TC) = 12 − 4 = 8 months

Profit Ratio = 1 : 3 : 7

Formula Used:

Profit Ratio = (CA × TA) : (CB × TB) : (CC × TC)

Aman Cap: ₹4000 Time: 12 mo

Ratio: 1 = 48000 units

Bunty Cap: ? Time: 5 mo

Ratio: 3 = 144000 units

Chaman Cap: ? Time: 8 mo

Ratio: 7 = 336000 units

Calculations:

⇒ Aman's profit equivalent = 4000 × 12 = 48000

⇒ As per the ratio, 1 unit of profit is represented by 48000.

⇒ Bunty's profit equivalent = 3 units = 3 × 48000 = 144000

⇒ Bunty's Capital × 5 = 144000

⇒ Bunty's Capital = 144000 ÷ 5 = 28800

⇒ Chaman's profit equivalent = 7 units = 7 × 48000 = 336000

⇒ Chaman's Capital × 8 = 336000

⇒ Chaman's Capital = 336000 ÷ 8 = 42000

⇒ Difference = 42000 − 28800 = 13200

∴ The correct answer is Rs. 13200.

Additional Information

Basic Profit Division Rule

If partners invest different amounts for varying time periods, the total profit is distributed in the ratio of the product of their invested capital and the duration of investment: (C1 × T1 : C2 × T2 : C3 × T3).

Equivalent Capital

Equivalent capital represents the total amount that would need to be invested for a standard unit of time (like 1 month) to yield the exact same final profit share.

Working vs Sleeping Partners

A working partner actively manages the business and usually takes a fixed percentage of the profit or a fixed salary before the rest of the profit is divided among all partners based on their investments. A sleeping partner merely invests capital.