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Question 11

CRPF Constable 2023• Elementary Mathematics

The ratio of the salaries of Ravi and Sarita is 3 ∶ 5. If the salary of each is increased by ₹ 5,000, the new ratio becomes 29 ∶ 45. What is the present salary of Sarita?

  1. AOption (a)

    Rs. 24,000

  2. BOption (b)

    Rs. 30,000

  3. COption (c)

    Rs. 45,000

  4. DOption (d)

    Rs. 40,000

View answer & explanation

Correct answer

Answer: (d)D.

Rs. 40,000

Why this answer is correct

Given:

The ratio of the salaries of Ravi and Sarita is 3 ∶ 5.

If the salary of each is increased by ₹ 5,000, the new ratio becomes 29 ∶ 45.

Formula Used:

Initial salaries: R = 3x and S = 5x.

New salaries: R + 5000 and S + 5000.

New ratio: (R + 5000) / (S + 5000) = 29/45.

Calculation:

Substituting the values of R and S in the new ratio equation:

(3x + 5000) / (5x + 5000) = 29 / 45

Cross multiplying to solve for x:

⇒ 45 × (3x + 5000) = 29 × (5x + 5000)

⇒ 135x + 225000 = 145x + 145000

⇒ 145x - 135x = 225000 - 145000

⇒ 10x = 80000

⇒ x = 8000

Now, finding the current salary of Sarita:

S = 5x = 5 × 8000

S = 40000

The present salary of Sarita is ₹ 40,000.

Shortcut Trick

Question 12

CRPF Constable 2023• Elementary Mathematics

Two stations X and Y are 390 KM apart from each other. A train starts from station 'X' at 11 a.m. and moves towards station Y at a speed of 65 km/h. Another train starts from station Y at 12 noon and moves towards station X at a speed of 35 km/h. At what time do those two trains meet?

  1. AOption (a)

    3:25 p.m.

  2. BOption (b)

    2:15 p.m.

  3. COption (c)

    3:15 p.m.

  4. DOption (d)

    4:15 p.m.

View answer & explanation

Correct answer

Answer: (c)C.

3:15 p.m.

Why this answer is correct

Shortcut Trick

Distance covered by Train X in 1 hour (11 a.m. to 12 noon) = 65 km.

Remaining distance at 12 noon = 390 − 65 = 325 km.

Relative speed (opposite direction) = 65 + 35 = 100 km/h.

Time taken to meet after 12 noon = 325 ÷ 100 = 3.25 hours.

0.25 hours = 0.25 × 60 = 15 minutes. So, 3 hours 15 minutes after 12 noon.

∴ The correct answer is 3:15 p.m.

Alternate Method

Given:

Total Distance = 390 km

Speed of Train X (S1) = 65 km/h (Starts at 11 a.m.)

Speed of Train Y (S2) = 35 km/h (Starts at 12 noon)

Formula Used:

Distance = Speed × Time

Relative Speed (Opposite Direction) = S1 + S2

Calculations:

⇒ Distance covered by Train X before Train Y starts (1 hour) = 65 × 1 = 65 km

⇒ Remaining distance to be covered relatively = 390 − 65 = 325 km

⇒ Relative speed = 65 + 35 = 100 km/h

⇒ Time taken to meet = 325 ÷ 100 = 3.25 hours

⇒ 3.25 hours = 3 hours + (0.25 × 60) minutes = 3 hours 15 minutes

⇒ Meeting time = 12:00 noon + 3 hours 15 minutes = 3:15 p.m.

∴ The correct answer is 3:15 p.m.

Additional Information

Relative Speed Concept

When two objects move in opposite directions, their relative speed is the sum of their individual speeds (S1 + S2). When moving in the same direction, it is the difference (S1 − S2).

Meeting Time Calculation

Always calculate the distance covered by the first object until the second object starts moving to find the effective distance for relative speed application.

Average Speed

For a journey with two equal distances at speeds a and b, Average Speed = 2ab ÷ (a + b).

Question 13

CRPF Constable 2023• Elementary Mathematics

Pipe A can fill an empty tank in 6 h and pipe B in 8 h. If both the pipes are opened at the same time and pipe A is closed after 2 hours, then how long will pipe B alone take to fill the remaining tank?

  1. AOption (a)

    3 h

  2. BOption (b)

    4 h

  3. COption (c)

    \(3\frac{1}{3}\) h

  4. DOption (d)

    \(\frac{12}{5}\) h

View answer & explanation

Correct answer

Answer: (c)C.

\(3\frac{1}{3}\) h

Why this answer is correct

Given : 

Pipe A can fill an empty tank in 6 h and pipe B in 8 h.

Both the pipes are opened at the same time and pipe A is closed after 2 hours.

Calculation:

Total work = LCM of (6, 8) = 24 unit

Efficiency of pipe A = 24/6 = 4 unit and efficiency of pipe B = 24/8 = 3 unit

In the 1st two hours both pipes are opened, the work done = (4 + 3) × 2 = 14 unit

Remaining = (24 - 14) = 10 unit

Now, pipe B can do it in = 10/3 = \(3\frac{1}{3}\) hour

∴ The correct answer is \(3\frac{1}{3}\) hour

Question 14

CRPF Constable 2023• Elementary Mathematics

Three candidates P, Q and R participated in an election. P got 35% more votes than Q. R got 25% more votes than Q. Also P beats R by 1250 votes. If 80% of the voters voted and no invalid votes were cast, then what was the number of voters in the voting list?

  1. AOption (a)

    58,280

  2. BOption (b)

    60,000

  3. COption (c)

    51,520

  4. DOption (d)

    56,250

View answer & explanation

Correct answer

Answer: (d)D.

56,250

Why this answer is correct

Given : 

P got 35% more votes then Q.

R got 25% more votes than Q.

Also P beats R by 1250 votes​.

Calculation:

Let's assume that  Q's vote count = x,

P's vote count =  1.35x and R's votes = 1.25x

We also know that P beats R by 1250 votes, then

⇒ 1.35x - 1.25x = 1250

⇒ 0.1x = 1250

⇒ x = 1250/0.1

⇒ x = 12500

So, Q got 12500 votes,

P got 1.35 × 12500 = 16875 votes

And R got 1.25 × 12500 = 15625 votes.

The total votes cast = 16875 + 12500 + 15625 = 45000 votes

Now, 80% of the voters voted, then

Total number of voters = 45000 / 0.80 = 56250

∴ The correct answer is 56250

Question 15

CRPF Constable 2023• Elementary Mathematics

What will be the value of the given equation? 

23 - 50 = ?

  1. AOption (a)

    3

  2. BOption (b)

    8

  3. COption (c)

    7

  4. DOption (d)

    1

View answer & explanation

Correct answer

Answer: (c)C.

7

Why this answer is correct

Calculation : 

⇒ 23 - 50 = 8 - 1 - 7

∴ The correct answer is 7.

Question 16

CRPF Constable 2023• Elementary Mathematics

Amrita took a loan of ₹ 21,300 at SI for the same number of years as the rate of interest. If he paid ₹5,325 as interest at the end of the loan period, what was the annual rate of interest per cent?

  1. AOption (a)

    4

  2. BOption (b)

    2

  3. COption (c)

    5

  4. DOption (d)

    3

View answer & explanation

Correct answer

Answer: (c)C.

5

Why this answer is correct

Given : 

P = Rs. 21300

Time = Rate 

SI = Rs.5325

Formula used : 

SI = (P × R × T)/100

Calculation : 

According to question,

Let the rate and time be x.

⇒ 5325 = (21300 × x2)/100

⇒ x2 = 5325/213

⇒ x2 = 25

⇒ x = + 5, - 5

∴ The correct answer is 5.

Question 17

CRPF Constable 2023• Elementary Mathematics

A number when divided by a divisor leaves a remainder of 25. When twice the original number is divided by the same divisor, the remainder is 13. What is the value of the divisor?

  1. AOption (a)

    36

  2. BOption (b)

    37

  3. COption (c)

    39

  4. DOption (d)

    38

View answer & explanation

Correct answer

Answer: (b)B.

37

Why this answer is correct

Shortcut Trick

Let the remainder in the first case be R1 = 25.

When the number is doubled, the new remainder should be 2 × R1 = 2 × 25 = 50.

However, the actual remainder is R2 = 13.

The divisor (D) is the difference between the expected remainder and the actual remainder.

⇒ Divisor = (2 × R1) − R2 = 50 − 13 = 37.

∴ The correct answer is 37.

Alternate Method

Given:

Let the number be N and the divisor be D.

⇒ N = D × q + 25 (where q is the quotient)

Calculations:

⇒ 2N = 2(D × q + 25)

⇒ 2N = 2Dq + 50

Since 2N divided by D leaves a remainder of 13:

⇒ 50 = D × k + 13 (where k is some integer)

⇒ D × k = 50 − 13

⇒ D × k = 37

Since 37 is a prime number and the remainder (25) must be less than the divisor (D > 25):

⇒ D = 37

∴ The correct answer is 37.

Additional Information

Division Algorithm

Dividend = (Divisor × Quotient) + Remainder. The remainder must always be 0 ≤ Remainder < Divisor.

Remainder Theorem Property

If a number N leaves remainder R when divided by D, then kN leaves the same remainder as kR divided by D.

Finding Divisor from Two Remainders

If N1 leaves R1 and N2 leaves R2, and (N1+N2) leaves R3 when divided by D, then D = R1 + R2 − R3.

Question 18

CRPF Constable 2023• Elementary Mathematics

Kiran buys an article at 12% below its cost and sells it at 12% above its cost. Find his profit percentage.

  1. AOption (a)

    23.76%

  2. BOption (b)

    28.83%

  3. COption (c)

    25.55%

  4. DOption (d)

    27.27%

View answer & explanation

Correct answer

Answer: (d)D.

27.27%

Why this answer is correct

Given : 

CP = 12% below its cost

SP = 12% above its cost

Calculation :

Let the CP be 100.

So, Real CP = 88

Real SP = 112

Profit = 112 - 88 = 24

⇒ 24/88 × 100 = 2400/88

⇒ 27.27%

∴ The correct answer is 27.27%.

Question 19

CRPF Constable 2023• Elementary Mathematics

The bases of a hemisphere and a cone are equal. If their height is also the same, then what is the ratio between their curved surface areas?

  1. AOption (a)

    √3 ∶ 1

  2. BOption (b)

    √2 ∶ √3

  3. COption (c)

    1 ∶ √3

  4. DOption (d)

    √2 ∶ 1

View answer & explanation

Correct answer

Answer: (d)D.

√2 ∶ 1

Why this answer is correct

Given:

The radius of the cone is equal to the radius of the hemisphere

The height of the cone is equal to the height of the hemisphere

Formula used:

The curved surface area of the hemisphere = 2πr2

The curved surface area of the Cone = πrl

l = √ (h2 + r2)

Where 'l' is a slant height

Calculations:

Let the radius of the cone is equal to the radius of the hemisphere be r.

So the height of the cone, h = r.

According to the question,

The ratio of the areas of curved surfaces of hemispheres and cone

⇒ 2π × r2 :  π × r × l

⇒  2π × r2 :  π × r × √ (r2 + r2)

⇒  2π × r2  :  π × r × √ (2r2)

⇒  2 : \(\sqrt{2}\)

⇒  \(\sqrt{2}\) : 1

∴ The ratio of the areas of curved surfaces of hemisphere and cone is \(\sqrt{2}\) : 1.

Question 20

CRPF Constable 2023• Elementary Mathematics

The average of six consecutive numbers A, B, C, D, E and F is 62. What is the product of B and F?

  1. AOption (a)

    3002.25

  2. BOption (b)

    2002.25

  3. COption (c)

    3902.25

  4. DOption (d)

    2902.25

View answer & explanation

Correct answer

Answer: (c)C.

3902.25

Why this answer is correct

Given :

Average of six consecutive numbers A, B, C, D, E and F is 62.

Formula used : 

Average = Sum of all observations/Number of observations

Calculation : 

Let the Numbers A, B, C, D, E, F be x, x + 1, x + 2, x + 3, x + 4, x + 5.

According to question,

⇒ x + x + 1 + x + 2 + x + 3 + x + 4 + x + 5 = 62 × 6

⇒ 6x + 15 = 372

⇒ 6x = 372 - 15 = 357

⇒ 6x = 357

⇒ x = 59.5

⇒ B = x  + 1 = 60.5

⇒ F = x + 5 = 64.5

Product of B and F = 60.5 × 64.5 = 3902.25

∴ The correct answer is 3902.25.