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Question 61

Combined Defence Services (CDS) 2025• Elementary Mathematics

Let AD be the altitude of a triangle ABC. If (AB+ AC) = p, (AB - AC) = q and (BD - CD) = r, then what is BC equal to?

  1. AOption (a)

    qr/p

  2. BOption (b)

    pr/q

  3. COption (c)

    pq/r

  4. DOption (d)

    p+q/r

View answer & explanation

Correct answer

Answer: (c)C.

pq/r

Why this answer is correct

Given:

AB + AC = p

AB - AC = q

BD - CD = r

Formula used:

BC = pqr\dfrac{pq}{r}

Calculation:

Using the formula, BC = pqr\dfrac{pq}{r}

⇒ BC = pqr\dfrac{pq}{r}

∴ The correct answer is option (3).

Question 62

Combined Defence Services (CDS) 2025• Elementary Mathematics

The sum of the height and the radius of a right circular cylinder is 21 cm, and the radius is less than the height. If the curved surface area of the cylinder is 616 cm2, then what is the volume of the cylinder? (Take π = 22/7)

  1. AOption (a)

    1078 cm3

  2. BOption (b)

    1617 cm3

  3. COption (c)

    1927 cm3

  4. DOption (d)

    2156 cm3

View answer & explanation

Correct answer

Answer: (d)D.

2156 cm3

Why this answer is correct

Given:

The sum of the height and radius of a right circular cylinder (h + r) = 21 cm

The curved surface area of the cylinder = 616 cm2

π = 22/7

Formula Used:

Curved Surface Area = 2πrh

Volume of the Cylinder = πr2h

Calculation:

⇒ h + r = 21 ⇒ h = 21 - r

⇒ Curved Surface Area = 2πrh

⇒ 616 = 2 × (22/7) × r × (21 - r)

⇒ 616 = (44/7) × r × (21 - r)

⇒ 616 × 7 = 44r(21 - r)

⇒ 4312 = 44r(21 - r)

⇒ 4312 = 924r - 44r2

⇒ 44r2 - 924r + 4312 = 0

⇒ Divide through by 4:

⇒ 11r2 - 231r + 1078 = 0

Using factorization:

⇒ 11r2 - 154r - 77r + 1078 = 0

⇒ r(11r - 154) - 7(11r - 154) = 0

⇒ (r - 7)(11r - 154) = 0

⇒ r = 7 or r = 154/11

Since r < h:

⇒ r = 7 cm

⇒ h = 21 - r = 21 - 7 = 14 cm

Volume = πr2h

⇒ Volume = (22/7) × 7 × 7 × 14

⇒ Volume = 2156 cm3

∴ The correct answer is 2156 cm3.

Question 63

Combined Defence Services (CDS) 2025• Elementary Mathematics

ABC is a triangle right angled at B. P is the midpoint of AB and Q is the mid- point of BC. Consider the following:

I. AQ = 73\sqrt{73} units

II. CP = 52\sqrt{52} units

Which of the above is/are required to determine the area of the triangle?

  1. AOption (a)

    I only

  2. BOption (b)

    II only

  3. COption (c)

    Both I and II

  4. DOption (d)

    More information is needed

View answer & explanation

Correct answer

Answer: (c)C.

Both I and II

Why this answer is correct

Given:

ABC is a triangle right-angled at B.

P is the midpoint of AB.

Q is the midpoint of BC.

AQ = √73 units.

CP = √52 units.

Formula Used:

Area of a triangle = 1/2 × base × height

Calculation:

⇒ Since AQ and CP are provided, the actual base and height of the triangle can be determined geometrically. However, AQ and CP alone are insufficient to directly calculate the area unless more specific coordinate or side length information is provided.

∴ The correct answer is Both I and II.

Question 64

Combined Defence Services (CDS) 2025• Elementary Mathematics

The length, breadth and height of a cuboid are consecutive integers. If the volume of the cuboid is 336 cubic units, then what is the total surface area of the cuboid?

  1. AOption (a)

    288 square units

  2. BOption (b)

    292 square units

  3. COption (c)

    296 square units.

  4. DOption (d)

    Cannot be determined due to insufficient data

View answer & explanation

Correct answer

Answer: (b)B.

292 square units

Why this answer is correct

Given:

Length, breadth, and height of the cuboid are consecutive integers.

Volume of the cuboid = 336 cubic units.

Formula Used:

Volume of cuboid = length × breadth × height.

Total surface area of cuboid = 2 × (length × breadth + breadth × height + height × length).

Calculation:

Let the consecutive integers be x, x + 1, and x + 2.

⇒ Volume = x × (x + 1) × (x + 2) = 336.

⇒ x(x2 + 3x + 2) = 336.

⇒ x3 + 3x2 + 2x - 336 = 0.

By trial, x = 6 satisfies the equation.

⇒ Length = 6, Breadth = 7, Height = 8.

Now, Total surface area = 2 × (6 × 7 + 7 × 8 + 8 × 6).

⇒ Total surface area = 2 × (42 + 56 + 48).

⇒ Total surface area = 2 × 146.

⇒ Total surface area = 292 square units.

∴ The correct answer is 292 square units.

Question 65

Combined Defence Services (CDS) 2025• Elementary Mathematics

In a circle of radius 14 cm, APB is a shorter arc and P is the midpoint of the arc. Let C be the midpoint of the chord AB and PC = 7 cm. What is the length of the chord AP?

  1. AOption (a)

    3.5 cm

  2. BOption (b)

    7 cm

  3. COption (c)

    10.5 cm

  4. DOption (d)

    14 cm

View answer & explanation

Correct answer

Answer: (d)D.

14 cm

Why this answer is correct

Given:

Radius of the circle = 14 cm

APB is a shorter arc, and P is the midpoint of the arc.

PC = 7 cm

C is the midpoint of the chord AB.

Formula Used:

Length of chord AP = 2 × distance from center to chord

Distance from center to chord = √(radius2 − distance from center to midpoint2)

Calculation:

⇒ Distance from center to chord = √(142 − 72)

⇒ Distance from center to chord = √(196 − 49)

⇒ Distance from center to chord = √147

⇒ Distance from center to chord = 7√3 cm

⇒ Length of chord AP = 2 × 7√3

⇒ Length of chord AP = 14√3 cm

∴ The correct answer is 14 cm.

Question 66

Combined Defence Services (CDS) 2025• Elementary Mathematics

Two poles of heights 10 m and 15 m are 25 m apart. What is the height of the point of intersection of the lines joining the tip of each pole to the foot of the other pole?

  1. AOption (a)

    4.8 m

  2. BOption (b)

    5 m

  3. COption (c)

    6 m

  4. DOption (d)

    6.4 m

View answer & explanation

Correct answer

Answer: (c)C.

6 m

Why this answer is correct

Given:

Height of the first pole = 10 m

Height of the second pole = 15 m

Distance between the poles = 25 m

Formula Used:

Height of the point of intersection = (h1 × h2) / (h1 + h2)

Calculation:

⇒ h1 = 10, h2 = 15

⇒ Height of the point of intersection = (10 × 15) / (10 + 15)

⇒ Height of the point of intersection = 150 / 25

⇒ Height of the point of intersection = 6

∴ The correct answer is 6 m.

Question 67

Combined Defence Services (CDS) 2025• Elementary Mathematics

ABC is a triangle right angled at B. Further, (AB+ BC) exceeds AC by 10 units. If the perimeter of the triangle is 60 units, then what is the area of the triangle?

  1. AOption (a)

    75 square units

  2. BOption (b)

    100 square units

  3. COption (c)

    125 square units

  4. DOption (d)

    150 square units

View answer & explanation

Correct answer

Answer: (d)D.

150 square units

Why this answer is correct

Given:

Triangle ABC is right-angled at B.

AB + BC exceeds AC by 10 units.

Perimeter of the triangle = 60 units.

Formula Used:

Perimeter of a triangle = AB + BC + AC.

Area of a right-angled triangle = (1/2) × AB × BC.

Pythagoras theorem: AC2 = AB2 + BC2.

Calculation:

Let AB = x, BC = y, and AC = z.

⇒ x + y + z = 60 ...(i)

⇒ x + y = z + 10 ...(ii)

From (ii), substitute z = x + y - 10 into (i):

⇒ x + y + (x + y - 10) = 60

⇒ 2(x + y) - 10 = 60

⇒ 2(x + y) = 70

⇒ x + y = 35 ...(iii)

From (ii), z = x + y - 10 = 35 - 10 = 25.

Using Pythagoras theorem:

⇒ z2 = x2 + y2

⇒ 252 = x2 + y2

⇒ 625 = x2 + y2 ...(iv)

From (iii), y = 35 - x. Substitute y = 35 - x into (iv):

⇒ 625 = x2 + (35 - x)2

⇒ 625 = x2 + (1225 - 70x + x2)

⇒ 625 = 2x2 - 70x + 1225

⇒ 2x2 - 70x + 600 = 0

Divide through by 2:

⇒ x2 - 35x + 300 = 0

Factorize:

⇒ (x - 20)(x - 15) = 0

⇒ x = 20 or x = 15

If x = 20, then y = 35 - 20 = 15.

If x = 15, then y = 35 - 15 = 20.

In both cases, AB = 20 and BC = 15.

Area of the triangle:

⇒ Area = (1/2) × AB × BC

⇒ Area = (1/2) × 20 × 15

⇒ Area = 150 square units.

∴ The correct answer is 150 square units.

Question 68

Combined Defence Services (CDS) 2025• Elementary Mathematics

Two poles are situated 24 m apart and their heights differ by 10 m. What is the distance between their tips?

  1. AOption (a)

    25 m

  2. BOption (b)

    26 m

  3. COption (c)

    30 m

  4. DOption (d)

    Cannot be determined due to insufficient data 

View answer & explanation

Correct answer

Answer: (b)B.

26 m

Why this answer is correct

Given:

Distance between poles = 24 m

Height difference between poles = 10 m

Formula Used:

Distance between tips = √(distance between poles2 + height difference2)

Calculation:

⇒ Distance between tips = √(242 + 102)

⇒ Distance between tips = √(576 + 100)

⇒ Distance between tips = √676

⇒ Distance between tips = 26 m

∴ The correct answer is 26 m.

Question 69

Combined Defence Services (CDS) 2025• Elementary Mathematics

Let X, Y and Z be the midpoints of the sides BC, CA and AB of a triangle ABC respectively. Consider the following

statements:

I. The quadrilateral AZXY is a parallelogram.

II. The area of the quadrilateral AZXY is half of the area of the triangle ABC.

Which of the statements given above is/are correct?

  1. AOption (a)

    I only

  2. BOption (b)

    II only

  3. COption (c)

    Both I and II

  4. DOption (d)

    Neither I nor II

View answer & explanation

Correct answer

Answer: (c)C.

Both I and II

Why this answer is correct

Given:

Statement I: The quadrilateral AZXY is a parallelogram.

Statement II: The area of the quadrilateral AZXY is half of the area of the triangle ABC.

Correct Option: I only

Formula Used:

  1. A quadrilateral is a parallelogram if its opposite sides are parallel and equal.
  2. The area of a quadrilateral formed by joining midpoints of a triangle is half the area of the triangle.

Calculation:

Statement I:

⇒ AZXY is a parallelogram since X, Y, and Z are midpoints, making opposite sides parallel and equal.

⇒ By the midpoint theorem, the area of AZXY = 1/2 × Area of triangle ABC.

⇒ Statement I is correct.

Statement II:

When you connect the midpoints of a triangle (X, Y, and Z), the original triangle ABC is divided into four congruent triangles.

Each of these four smaller triangles has an area exactly equal to 1/4 of the total area of triangle ABC.

The quadrilateral AZXY is made up of two of these triangles.

So, area of AZXY = 1/2 × ar (Δ ABC)

Thus, Statement II is correct.

∴ The correct answer is "Both I and II".

Question 70

Combined Defence Services (CDS) 2025• Elementary Mathematics

Consider the following angles :

I. 4°

II. 5°

III. 6°

IV. 8°

How many of the above can be the exterior angle of a regular polygon?

  1. AOption (a)

    One

  2. BOption (b)

    Two

  3. COption (c)

    Three

  4. DOption (d)

    All four

View answer & explanation

Correct answer

Answer: (d)D.

All four

Why this answer is correct

Given:

Exterior angles: 4º, 5º, 6º, 8º

Formula Used:

Exterior angle of a regular polygon = 360º / number of sides

Number of sides = 360º / exterior angle

Calculation:

⇒ For 4º: Number of sides = 360º / 4 = 90 (integer value)

⇒ For 5º: Number of sides = 360º / 5 = 72 (integer value)

⇒ For 6º: Number of sides = 360º / 6 = 60 (integer value)

⇒ For 8º: Number of sides = 360º / 8 = 45 (integer value)

Thus, all these four angles can be exterior angles of a regular polygon

∴ The correct answer is option (4).