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Question 31

Bihar Police ASI Operations 2026• Test

Phase velocity and group velocity are associated with:

  1. AOption (a)

    Wave propagation

  2. BOption (b)

    Newton's laws of motion

  3. COption (c)

    Electrostatic force

  4. DOption (d)

    Thermal expansion

View answer & explanation

Correct answer

Answer: (a)A.

Wave propagation

Why this answer is correct

Concept:

Phase velocity and group velocity are fundamental concepts in wave mechanics that describe how waves and wave packets propagate through a medium.

Explanation:

Phase velocity is the speed at which a wave's phase travels, while group velocity is the speed at which the wave packet or energy propagates. These concepts are used to analyze wave propagation in quantum mechanics, optics, and electromagnetism.

Correct Answer:

Option (1): Wave propagation.

Question 32

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The I – V characteristics of a p - n junction diode in forward bias is shown in the figure. The ratio of dynamic resistance, corresponding to forward bias voltage of 2 V and 4 V respectively, is :

  1. AOption (a)

    1 ∶ 2

  2. BOption (b)

    5 ∶ 1

  3. COption (c)

    1 ∶ 40

  4. DOption (d)

    20 ∶ 1

View answer & explanation

Correct answer

Answer: (b)B.

5 ∶ 1

Why this answer is correct

Concept:

  • The p-n junction diode is a semiconductor device that allows current to flow in one direction under forward bias conditions.
  • In forward bias, the p-side of the diode is connected to the positive terminal and the n-side to the negative terminal of the supply.
  • The I-V characteristics of a diode show how the current through the diode changes with the applied voltage.
  • Dynamic Resistance:
  • It is defined as the ratio of a small change in voltage to the corresponding change in current.
  • SI Unit: Ohm (Ω)
  • Dimensional Formula: [ML2T-3A-2]
  • Formula: \(r_d = \frac{\Delta V}{\Delta I}\)
  • Forward Bias Voltage:
  • It is the external potential applied to a p-n junction diode to reduce the depletion layer.
  • SI Unit: Volt (V)
  • Dimensional Formula: [ML2T-3A-1]

 

Calculation:

From the given graph,

Case 1: At V = 2 V

ΔV1 = 2.1 - 2.0 = 0.1 V

ΔI1 = 15 - 10 = 5 mA = 5 × 10-3 A

Dynamic resistance r1 is,

\(r_1 = \frac{\Delta V_1}{\Delta I_1}\)

⇒ r1 = 0.1 / (5 × 10-3)

⇒ r1 = 20 Ω

Case 2: At V = 4 V

ΔV2 = 4.2 - 4.0 = 0.2 V

ΔI2 = 250 - 200 = 50 mA = 50 × 10-3 A

Dynamic resistance r2 is,

\(r_2 = \frac{\Delta V_2}{\Delta I_2}\)

⇒ r2 = 0.2 / (50 × 10-3)

⇒ r2 = 4 Ω

Calculating the ratio:

⇒ Ratio = r1 : r2

⇒ Ratio = 20 : 4

⇒ Ratio = 5 : 1

∴ The ratio of dynamic resistance is 5 : 1.

Question 33

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In Dirac notation, Bra (⟨ψ|) is associated with:

  1. AOption (a)

    Conjugate transpose

  2. BOption (b)

    Wave function normalization

  3. COption (c)

    Momentum operator

  4. DOption (d)

    Probability density

View answer & explanation

Correct answer

Answer: (a)A.

Conjugate transpose

Why this answer is correct

Concept:

In Dirac notation, a quantum state is represented by a ket, |ψ⟩. The corresponding bra, ⟨ψ|, is obtained by taking the Hermitian conjugate (conjugate transpose) of the ket.

Explanation:

A ket |ψ⟩ is a column vector representing a quantum state, while the bra ⟨ψ| is the corresponding row vector formed by taking its complex conjugate and transpose. This conjugate transpose operation is essential for calculating inner products, probabilities, and expectation values in quantum mechanics.

Correct Answer:

Option (1): Conjugate transpose.

Question 34

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The Schrödinger equation describes

  1. AOption (a)

    Evolution of the wave function with time

  2. BOption (b)

    Motion of planets around the Sun

  3. COption (c)

    Propagation of electromagnetic waves

  4. DOption (d)

     Thermal motion of molecules

View answer & explanation

Correct answer

Answer: (a)A.

Evolution of the wave function with time

Why this answer is correct

Concept:

The Schrödinger equation is the fundamental equation of quantum mechanics. It describes how the wave function (ψ) of a quantum system changes with time.

Explanation:

The wave function contains all the information about the quantum state of a particle. Solving the Schrödinger equation predicts how this wave function evolves with time, allowing the probability of finding the particle at different positions to be determined. Hence, it describes the evolution of the wave function, not the motion of planets, electromagnetic waves, or thermal motion of molecules.

Correct Answer:

Option (1): Evolution of the wave function with time.

Question 35

Bihar Police ASI Operations 2026• Test

The Norton equivalent of a circuit has IN = 4 A and RN = 6 Ω. The corresponding Thevenin voltage is:

  1. AOption (a)

    10 V

  2. BOption (b)

     20 V

  3. COption (c)

    24 V

  4. DOption (d)

    30 V

View answer & explanation

Correct answer

Answer: (c)C.

24 V

Why this answer is correct

Concept:

The Thevenin and Norton equivalent circuits are related by the equation: VTh = IN × RN.

Calculation:

Given:

IN = 4 A

RN = 6 Ω

VTh = IN × RN

= 4 × 6

= 24 V

Correct Answer:

Option (3): 24 V.

Question 36

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For the logic circuit shown, the output waveform at Y is:

  1. AOption (a)

  2. BOption (b)

  3. COption (c)

  4. DOption (d)

View answer & explanation

Correct answer

Answer: (b)B.

Why this answer is correct

Calculation:

For the given circuit the truth table would be :

ABY
000
011
101
111

The truth table shows that the output graph is given by :

∴ Option (2) is correct.

Question 37

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Radioactive decay cannot be predicted exactly for a single nucleus because the process is __________.

  1. AOption (a)

    Controlled by temperature only

  2. BOption (b)

    Random in nature

  3. COption (c)

    Completely deterministic

  4. DOption (d)

    Dependent on chemical state always

View answer & explanation

Correct answer

Answer: (b)B.

Random in nature

Why this answer is correct

The correct answer is Random in nature.

Key Points

  • Radioactive decay is a spontaneous and stochastic (random) process occurring at the level of individual atoms.
  • For any specific unstable nucleus, it is fundamentally impossible to predict the exact moment it will undergo disintegration because it does not follow a classical deterministic path.
  • The process is governed by the laws of quantum mechanics and probability; a nucleus has no 'memory' of how long it has existed, and its chance of decaying remains constant over time.
  • While the behavior of a single nucleus is unpredictable, the statistical behavior of a large collection of nuclei is highly predictable and follows the exponential decay law.
  • The decay constant (λ) represents the probability of decay per unit time for a particular type of radioisotope.
  • The transformation involves the emission of alpha particles, beta particles, or gamma rays as the nucleus seeks a more stable energy state.

 Additional Information

  • Temperature and External Factors
  • Unlike chemical reactions, radioactive decay is an intranuclear process. This means it is not affected by external physical conditions such as temperature, pressure, or magnetic fields.
  • The nuclear binding energy is significantly higher than the thermal energy available in ordinary environments, making the decay rate constant regardless of heat.
  • Deterministic vs. Stochastic
  • A deterministic process would allow us to calculate the exact time of an event if we knew all initial conditions. However, nuclear physics is non-deterministic; identical nuclei in identical environments will decay at different, random times.
  • Chemical State Independence
  • The chemical state (whether an atom is in a pure form or part of a compound) does not influence the nuclear instability because the nucleus is isolated from the valence electrons by vast distances on a subatomic scale.
  • Half-life (T1/2)
  • The half-life is a statistical measure representing the time required for half of the radioactive atoms in a sample to decay. It highlights how randomness at the micro-level leads to mathematical precision at the macro-level.

Question 38

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The stability of the nucleus is mainly due to the balance between ________.

  1. AOption (a)

    Electron attraction and neutron decay

  2. BOption (b)

    Nuclear attraction and proton repulsion

  3. COption (c)

    Gravitational force and magnetic flux

  4. DOption (d)

    Atomic volume and electric current

View answer & explanation

Correct answer

Answer: (b)B.

Nuclear attraction and proton repulsion

Why this answer is correct

Concept:

Nuclear Stability:

  • The stability of a nucleus depends on the interaction between two fundamental forces within the atomic nucleus.
  • Strong Nuclear Force: This is a short-range attractive force that acts between all nucleons (protons and neutrons).
  • Electrostatic Force: This is a long-range repulsive force that acts between positively charged protons.
  • A nucleus remains stable when the Nuclear attraction is sufficient to overcome the Proton repulsion.

Strong Nuclear Force:

  • Definition: The powerful attractive force that binds protons and neutrons together in the nucleus.
  • SI Unit: Newton (N)
  • Dimensional Formula: [MLT−2]
  • Important Property: It is charge-independent and has a very short range (approx 10−15 m).

Electrostatic Force:

  • Definition: The repulsive force between two like-charged particles (protons).
  • SI Unit: Newton (N)
  • Formula: \(F = \frac{k q_1 q_2}{r^2}\)
  • Dimensional Formula: [MLT−2]

Proton:

  • Definition: A subatomic particle with a positive charge found in the nucleus.
  • SI Unit of Charge: Coulomb (C)
  • Dimensional Formula of Charge: [AT]
  • Charge Magnitude: 1.6 × 10−19 C

 

Calculation:

Given,

Attractive Force = Fn (Nuclear Force)

Repulsive Force = Fe (Coulombic Force)

⇒ Stability requires a balance of forces.

⇒ Fn acts between all nucleons.

⇒ Fe acts only between protons.

⇒ Fn provides Nuclear attraction.

⇒ Fe provides Proton repulsion.

⇒ Stability exists when Fn balances Fe.

∴ The stability of the nucleus is mainly due to the balance between Nuclear attraction and proton repulsion.

Question 39

Bihar Police ASI Operations 2026• Test

Beta decay helps unstable nuclei achieve stability mainly by adjusting the __________.

  1. AOption (a)

    Electron orbital speed only

  2. BOption (b)

    Nuclear volume to infinity

  3. COption (c)

    Neutron-proton ratio

  4. DOption (d)

    Atomic radius only

View answer & explanation

Correct answer

Answer: (c)C.

Neutron-proton ratio

Why this answer is correct

Concept:

Beta Decay:

  • Beta decay is a type of radioactive decay in which a beta particle (fast energetic electron or positron) is emitted from an atomic nucleus.
  • It transforms the unstable nucleus into a more stable one by changing the number of protons and neutrons.
  • SI Unit: The unit for radioactivity is Becquerel (Bq).
  • Dimensional Formula: [M0L0T−1]

Nuclear Stability:

  • The stability of a nucleus is primarily determined by its Neutron-Proton ratio (n/p ratio).
  • Nuclei with an excess of neutrons or protons lie outside the stability belt and undergo radioactive decay.
  • For lighter nuclei, stability occurs when the n/p ratio is approximately 1.
  • For heavier nuclei, the ratio increases to about 1.5 due to electrostatic repulsion between protons.

Neutron-Proton Ratio:

  • It is the ratio of the number of neutrons (N) to the number of protons (Z) in an atomic nucleus.
  • Formula: Ratio = N / Z
  • It is a dimensionless quantity.

 

Calculation:

Given,

Process = Beta decay

Goal = Achieve nuclear stability

In Beta-minus (β−) decay:

⇒ A neutron converts into a proton.

⇒ n → p + e− + antineutrino

⇒ Number of neutrons decreases.

⇒ Number of protons increases.

⇒ This decreases the n/p ratio.

In Beta-plus (β+) decay:

⇒ A proton converts into a neutron.

⇒ p → n + e+ + neutrino

⇒ Number of neutrons increases.

⇒ Number of protons decreases.

⇒ This increases the n/p ratio.

Both processes adjust the n/p ratio.

This adjustment brings the nucleus toward the

stability belt.

∴ Beta decay helps unstable nuclei achieve stability mainly by adjusting the Neutron-proton ratio.

Question 40

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During a nuclear fusion reaction -

  1. AOption (a)

    A light nucleus breaks up due to bombardment of thermal neutrons.

  2. BOption (b)

    A heavy nucleus breaks up due to bombardment of thermal neutrons.

  3. COption (c)

    Two light nuclei combine to give a heavier nucleus and possibly other products.

  4. DOption (d)

    A heavy nucleus breaks into two fragments by itself.

View answer & explanation

Correct answer

Answer: (c)C.

Two light nuclei combine to give a heavier nucleus and possibly other products.

Why this answer is correct

Concept

  • Nuclear fusion is the process in which two or more light atomic nuclei combine to form one or more different, heavier atomic nuclei and subatomic particles (like neutrons or protons).
  • This process releases a tremendous amount of energy because the mass of the resulting single nucleus is less than the combined mass of the original nuclei. The "missing" mass is converted into energy according to Einstein's equation \(E = mc^2\).

Key Points

  • Fusion: Combining light nuclei (e.g., Hydrogen isotopes fusing to form Helium).
  • Fission: The splitting of a heavy nucleus into lighter fragments (e.g., Uranium-235 splitting after neutron bombardment).
  • Coulomb Barrier: High temperature and pressure are required for fusion to overcome the electrostatic repulsion between positively charged nuclei.

Explanation

To identify the correct description of nuclear fusion, let's look at the nature of the reaction:

  • Statement A & B: These describe the "breaking up" of a nucleus. If a nucleus breaks up after being hit by a neutron, it is called induced nuclear fission. This is characteristic of heavy elements like Uranium or Plutonium, not fusion.
  • Statement D: A heavy nucleus breaking into fragments by itself is known as spontaneous fission or radioactive decay.
  • Statement C: This accurately describes nuclear fusion. In this process, light nuclei (such as isotopes of hydrogen) are forced together under extreme conditions to form a heavier, more stable nucleus (such as helium), releasing energy in the process. This is the reaction that powers the Sun and other stars.

Hence, during a nuclear fusion reaction, two light nuclei combine to give a heavier nucleus and possibly other products.