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Question 91

Bihar Jeevika 2025• Test

Find the difference between the simple interest and the compound interest at an annual rate of 20% on the principal of Rs. 800 for 2 years.

  1. AOption (a)

    32

  2. BOption (b)

    20

  3. COption (c)

    42

  4. DOption (d)

    0

View answer & explanation

Correct answer

Answer: (a)A.

32

Why this answer is correct

Given: 

The principal is 800 rupee

Rate is 20%

Concept: 

SI = (P × R × T)/100

CI = P[(1 + r/100)n - 1]

Here, n is the number of terms in the year.

Calculation: 

The simple interest for 2 years

⇒ (800 × 20 × 2)/100

⇒ 8 × 20 × 2

⇒ 320 rupee

Now, Compound interest for 2 years is 

⇒ 800[(1 + 20/100)2 - 1]

⇒ 800[(120/100)2 - 1]

⇒ 800[(12/10)2 - 1]

⇒ 800 × [(144 - 100)/100]

⇒ 352 rupee 

Now, The difference between CI and SI is

⇒ 352 - 320

⇒ 32

∴ The difference between CI and SI is 32. 

Shortcut Trick

The difference between CI and SI for 2 years is P(r/100)2

The  difference is 

⇒ 800(20/100)2

⇒ 800 × (1/5)2

⇒ 32

∴ The difference between CI and SI is 32. 

Important Points

This short trick works only for 2 years.

Question 92

Bihar Jeevika 2025• Test

Rajesh saves 5% of his income after 4 years his income is increased by 25% but his savings remain the same. Then find the approximate percentage increase in his expenditure.

  1. AOption (a)

    50%

  2. BOption (b)

    22%

  3. COption (c)

    41%

  4. DOption (d)

    26%

View answer & explanation

Correct answer

Answer: (d)D.

26%

Why this answer is correct

Shortcut TrickLet the income of Rajesh be 100.

IncomeSavingsExpenditure
Initial100595
Final1255120

 

⇒ Percentage increase in expenditure = [(120 - 95)/95] × 100

⇒ Percentage increase in expenditure = (25/95) × 100 ≈ 26%

∴ The correct answer is Option 4).

Given:

Rajesh saving = 5%

Income increased = 25%

Formula used

Income = expenditure + saving

Calculation

Let income be 100

Given saving = 5% of 100 = 5

Expenditure = 100 – 5 = 95

The income increased by 25%

New income = 25% of 100 + 100 = 125

Saving is the same = 5

Then expenditure = 120

Change in expenditure = 120 – 95 = 25

Therefore, Percentage increase = (25 ÷ 95) × 100 = 26.31% ≈ 26%

∴ Percentage increase in his expenditure is 26%

Question 93

Bihar Jeevika 2025• Test

Rajeev and Abhay invest in a business. Profit was divided in 2:3. The profit is divided according to the investment. If Rajeev invested ₹40,000 then the amount invested by Abhay is:

  1. AOption (a)

    ₹40,000

  2. BOption (b)

    ₹50,000

  3. COption (c)

    ₹60,000

  4. DOption (d)

    ₹70,000

View answer & explanation

Correct answer

Answer: (c)C.

₹60,000

Why this answer is correct

Given:

The profit ratio of Rajeev : Abhay = 2 : 3.

Rajeev's invested amount = Rs. 40,000.

Concept used:

Amount invested Rajeev to Abhay = Ratio of their Profit

Calculation:

The amount of Rajeev invested Rs. 40000 and amount invested by Abhay is y.

Amount invested Rajeev to Abhay = Ratio of their profit

⇒ 40000/y = 2/3

⇒ y = 40000 × 3/2

⇒ y = Rs. 60000

∴ The amount invested by Q is Rs. 60000.

Question 94

Bihar Jeevika 2025• Test

A cycle listed at Rs.20,000 is sold to a retailer at Rs.14,000 after a discount. What is the percent discount given to retailer?

  1. AOption (a)

    20 percent

  2. BOption (b)

    10 percent

  3. COption (c)

    30 percent

  4. DOption (d)

    40 percent

View answer & explanation

Correct answer

Answer: (c)C.

30 percent

Why this answer is correct

Given:

The listed price of the cycle = Rs. 20,000

Selling price to the retailer = Rs. 14,000

Formula:

Percent discount = (Discount / Listed price) * 100

Calculation:

To calculate the percent discount, we need to find the discount first.

Discount = Listed price - Selling price

Substituting the given values:

Discount = Rs. 20,000 - Rs. 14,000

= Rs. 6,000

Now, we can calculate the percent discount:

Percent discount = (Discount / Listed price) * 100

= (6000 / 20000) * 100

= 30

Therefore, the percent discount given to the retailer is 30%.

Question 95

Bihar Jeevika 2025• Test

The ratio of the number of boys and girls in a school is 12 ∶ 13. If there are 372 boys, then the total number of students in the school is :

  1. AOption (a)

    775

  2. BOption (b)

    703

  3. COption (c)

    685

  4. DOption (d)

    603

View answer & explanation

Correct answer

Answer: (a)A.

775

Why this answer is correct

Calculation:

In the school ratio of boys : girls = 12 : 13

Now, 12 unit → 372, 

Then, (12 + 13) = 25 unit  → 372/12 × 25 = 775

∴ The correct answer is 775

Question 96

Bihar Jeevika 2025• Test

In an exam, a student got 40 marks and still failed by 20 percent marks. If the passing percentage is 40 percent, then what are the maximum marks of the exam?

  1. AOption (a)

    160

  2. BOption (b)

    250

  3. COption (c)

    200

  4. DOption (d)

    180

View answer & explanation

Correct answer

Answer: (c)C.

200

Why this answer is correct

Shortcut Trick

Student's scored percentage = Passing percentage − Failing gap percentage

Scored percentage = 40% − 20% = 20%

Since 20% of the maximum marks corresponds to the 40 marks obtained:

Maximum marks = (40 ÷ 20) × 100 = 200

∴ The correct answer is 200 marks.

Alternate Method

Given:

Marks obtained by the student = 40 marks

Failing gap = 20% of maximum marks

Passing percentage = 40% of maximum marks

Formula Used:

Passing Marks = Obtained Marks + Shortfall Marks

0% 20% 40% (Pass) 100%

Scored Failed by

40 Marks

20% Gap

Max Marks = 100% = 200 Marks

Calculations:

Let the maximum marks be x.

⇒ Passing marks = 40% of x = 0.4x

⇒ Shortfall (Failed by) marks = 20% of x = 0.2x

⇒ Obtained marks + Shortfall marks = Passing marks

⇒ 40 + 0.2x = 0.4x

⇒ 0.4x − 0.2x = 40

⇒ 0.2x = 40

⇒ x = 40 ÷ 0.2

⇒ x = 200

∴ The correct answer is 200 marks.

Additional Information

Concept of Passing Marks

If a student scores 'M' marks and fails by 'X' marks, then Passing Marks = M + X. If they score 'N' marks and get 'Y' marks above passing, then Passing Marks = N − Y.

Fraction Equivalent Strategy

Converting percentages to fractions speeds up calculations. 20% = 1/5 and 40% = 2/5. Here, (2/5)x − (1/5)x = 40 ⇒ (1/5)x = 40 ⇒ x = 200.

Percentage Base Rule

Whenever a percentage is mentioned (like 20% failed marks), it is always calculated on the Total/Maximum Marks of the exam unless specified otherwise.

Question 97

Bihar Jeevika 2025• Test

Reeta goes to office from home at a speed of 40 km/h. If she return to home from office at a speed of 60 km/h, then what is her average speed?

  1. AOption (a)

    44 km/h

  2. BOption (b)

    52 km/h

  3. COption (c)

    48 km/h

  4. DOption (d)

    50 km/h

View answer & explanation

Correct answer

Answer: (c)C.

48 km/h

Why this answer is correct

Given:

Speed of going = 40 km/h,

Speed of returning = 60 km/h

Concept:

Average speed = Total distance / Total time.

The total distance for the round trip is twice the one-way distance.

Solution:

One-way distance = d

⇒ Total time = d/40 + d/60 = (3d + 2d)/120 = d/24

⇒ Average speed = 2d/(d/24) = 48 km/h

Hence, her average speed is 48 km/h.

Question 98

Bihar Jeevika 2025• Test

The length of a train is 150 metres. In 3 seconds, it passes a man travelling at 2 km/h in the same direction as the train. Determine the train's speed.

  1. AOption (a)

    176 km/h

  2. BOption (b)

    191 km/h

  3. COption (c)

    168 km/h

  4. DOption (d)

    182 km/h

View answer & explanation

Correct answer

Answer: (d)D.

182 km/h

Why this answer is correct

Shortcut Trick

Relative Speed = Distance ÷ Time = 150 ÷ 3 = 50 m/s.

Convert relative speed to km/h: 50 × (18 ÷ 5) = 180 km/h.

Since both are moving in the same direction, Relative Speed = Speed of Train − Speed of Man.

180 = Speed of Train − 2 ⇒ Speed of Train = 182 km/h.

∴ The correct answer is 182 km/h.

Alternate Method

Given:

Length of the train = 150 m

Time taken to pass the man = 3 s

Speed of the man = 2 km/h

Formula Used:

Distance = Relative Speed × Time

Speed in m/s = Speed in km/h × (5 ÷ 18)

Calculations:

Let the speed of the train be v km/h.

⇒ Relative speed of train with respect to the man = (v − 2) km/h

⇒ Convert km/h to m/s = (v − 2) × (5 ÷ 18) m/s

⇒ Distance covered = Length of the train = 150 m

⇒ Time taken = 3 s

⇒ 150 = [(v − 2) × (5 ÷ 18)] × 3

⇒ 150 = (v − 2) × (15 ÷ 18)

⇒ 150 = (v − 2) × (5 ÷ 6)

⇒ v − 2 = 150 × (6 ÷ 5)

⇒ v − 2 = 30 × 6

⇒ v − 2 = 180

⇒ v = 180 + 2

⇒ v = 182 km/h

∴ The correct answer is 182 km/h.

Additional Information

Relative Speed (Same Direction)

When two objects move in the same direction, their relative speed is the difference of their individual speeds: Srel = S1 − S2.

Relative Speed (Opposite Direction)

When two objects move in opposite directions, their relative speed is the sum of their individual speeds: Srel = S1 + S2.

Speed Conversion Rules

To convert km/h to m/s, multiply the speed value by (5 ÷ 18). Conversely, to convert m/s to km/h, multiply by (18 ÷ 5).

Question 99

Bihar Jeevika 2025• Test

 In an election Santosh got 24000 more votes than Mantosh. If Mantosh and Santosh got 30% and 40% of the total votes respectively. Find the total number of votes cast. 

  1. AOption (a)

    250000

  2. BOption (b)

    254000

  3. COption (c)

    240000

  4. DOption (d)

    245000

View answer & explanation

Correct answer

Answer: (c)C.

240000

Why this answer is correct

Given:

Santosh got 24000 more votes than Mantosh

Mantosh and Santosh got 30% and 40% of the total votes respectively

Shortcut Trick

10% = 24000

1% = 2400

100% = 240000

Therefore, total number of votes are 240000.

Alternate Method Concept:

Calculation of total votes based on percentage shares of candidates.

Solution:

Let the total number of votes be X

As per the question,

Santosh's votes (40% of X) = Mantosh's votes (30% of X) + 24000

⇒ 40/100 × X = 30/100 × X + 24000

⇒ 10/100 × X = 24000

⇒ X = 240000

Therefore, total number of votes are 240000.

Question 100

Bihar Jeevika 2025• Test

Letters of a word have been jumbled up and numbered. Choose the option which gives the correct order of the letters as indicated by the numbers to form the word.

I, A, D, O, H, E, N, S

1 2 3 4 5 6 7 8

  1. AOption (a)

    3, 2, 5, 6, 8, 1, 4, 7

  2. BOption (b)

    2, 3, 5, 6, 4, 8, 1, 7

  3. COption (c)

    2, 3, 5, 6, 8, 1, 4, 7

  4. DOption (d)

    2, 3, 5, 6, 8, 4, 1, 7

View answer & explanation

Correct answer

Answer: (c)C.

2, 3, 5, 6, 8, 1, 4, 7

Why this answer is correct

We have checked the each option,

Option (1): 3, 2, 5, 6, 8, 1, 4, 7

32568147
DAHESION

The word formed from jumbled letters is "DAHESION" which is Not a Meaningful word.

Option (2): 2, 3, 5, 6, 4, 8, 1, 7

23564817
ADHEOSIN

The word formed from jumbled letters is "ADHEOSIN" which is Not a Meaningful word.

Option (3): 2, 3, 5, 6, 8, 1, 4, 7

23568147
ADHESION

The word formed from jumbled letters is "ADHESION" which is  a Meaningful word.

Option (4): 2, 3, 5, 6, 8, 4, 1, 7

23568417
ADHESOIN

The word formed from jumbled letters is "ADHESOIN" which is Not a Meaningful word.

Hence, the correct answer is "2, 3, 5, 6, 8, 1, 4, 7".