If \(x=\frac{1}{\sqrt{13}-3}\), \(y=\frac{1}{\sqrt{7}-\sqrt{3}}\), \(z=\frac{1}{\sqrt{2}(\sqrt{3}-1)}\), then
- AOption (a)
x < y < z
- BOption (b)
y < z < x
- COption (c)
z < y < x
- DOption (d)
x < z < y
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Correct answer
x < y < z