An ultrasound of a twin pregnancy shows one shared placenta and a thin membrane separating the two babies. This pattern indicates which type of placentation?

- AOption (a)
Monochorionic–diamniotic
- BOption (b)
Dichorionic–diamniotic
- COption (c)
Monochorionic–monoamniotic
- DOption (d)
Conjoined twins
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Correct answer
Monochorionic–diamniotic
Why this answer is correct
Correct Answer: Monochorionic–diamniotic
Rationale:
- In twin pregnancies, placentation is determined by the number of chorions (placentas) and amnions (sacs). An ultrasound showing one shared placenta indicates that the pregnancy is monochorionic.
- The presence of a thin membrane separating the two fetuses means each baby has its own amniotic sac. When twins share one placenta but are separated by a membrane, the pregnancy is diamniotic.
- Thus, one chorion + two amnions = Monochorionic–diamniotic (MCDA) twins.
- MCDA is the most common form of identical twinning and carries risks such as twin-to-twin transfusion syndrome (TTTS), making accurate identification clinically important.
- Therefore, the ultrasound findings of a single placenta with a thin dividing membrane match the pattern of monochorionic–diamniotic placentation.
Explanation of Other Options:
Dichorionic–diamniotic
- Rationale: Di–Di twins have two placentas (or one thick fused placenta) and a thicker separating membrane. The question states one shared placenta, ruling this out.
Monochorionic–monoamniotic
- Rationale: Mo–Mo twins share both the placenta and the amniotic sac, so there is no membrane between them. The presence of a membrane excludes this option.
Conjoined twins
- Rationale: Conjoined twins are always monoamniotic with no separating membrane. The image shows a membrane, making this incorrect.
Conclusion:
- A single placenta plus a thin membrane separating the fetuses is diagnostic of monochorionic–diamniotic twins.