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Given

In a certain store, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains constant.

Concept used

Profit and loss

Calculation

Let the CP be Rs.100

Profit = 320% of 100

Profit = Rs.320

SP = Rs.(320 + 100)

SP = Rs.420 

Cost price increases by 25% 

Cost price = Rs.125

Selling price = Rs.420

Profit = Rs.(420 - 125)

Profit = Rs.295

Required percentage = \(\frac{{295}}{{420}} \times 100\)

∴ 70% aprrox

Given

A child has three different kinds of chocolates costing Rs. 2, Rs. 5, Rs. 10. He spends total Rs. 120 on the chocolates. 

Concept used

Ratio and proportion

Calculation

Minimum number of chocolates are possible when he purchases maximum number of costliest chocolates.

He spents Rs.120 on the chocolates.

Rs.100 must be spent on 10 chocolates = 10 × 10

⇒ 2 × 5 + 5 × 2 = Rs.20

Minimum number of chocolates = 2 + 5 + 10 = 17

Given

given series 55, 60, 58, 63, 61, 66, 64 ___.

Concept 

Series

Calculation

The numbers at first, third, fifth have a common difference of 3

Similarly the numbers at second, fourth, sixth also has a difference of 3

⇒ 60 + 3 = 63

⇒ 63 + 3 = 66

⇒ 66 + 3 = 69

∴ Ans = 69

The logic follows here is :

First of all, Night occurs.

Then, Darkness comes.

After that, Lamp is switched on.

Then, it gives Light.

At last, we get Vision.

Thus, the final sequence will be :

Night → Darkness → Lamp → Light → Vision.

Hence, the correct answer is "1,2,3,4,5".

Given

The average of 4 terms is 20 and the 1^st term is 1/3 of the remaining terms.

Concept used

Average

Calculation

Let the four numbers be a, b, c, d

Average of 4 terms is 20

⇒ \(\frac{{a\ +\ b\ +\ c\ +\ d}}{4} = 20\)

⇒ a + b + c + d = 80

1^st term is 1/3 of the remaining terms

⇒ a = 1/3 (b + c + d)

⇒ a = 1 and b + c + d = 3 units

⇒ 4 units = 80

⇒ 1 unit = 20

∴ a = 20

Given

A train can travel 50% faster than a car. Both start from point A at the same time and reach point B, 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations.

Concept used

Time and Distance

Calculation

Let the speed of the car be x km/hr

Speed of train becomes 

⇒ \(x + \frac{x}{2} = \frac{{3x}}{2}km/hr\)

Time taken by car = 75/x

Time taken by Train = \(\frac{{75}}{{\frac{{3x}}{2}}} = \frac{{50}}{x}\)

As per the question,

⇒ \(\frac{{75}}{x} - \frac{{50}}{x} = \frac{{125}}{{600}}\)

⇒ \(\frac{{25}}{x} = \frac{{125}}{{600}}\)

⇒ x = 120 km/hr

Given

Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508

Concept used

Simple interest

Calculation

Let the investment in scheme A be Rs.x

Investment in scheme B be Rs.(13900 - x)

Si = (P × R × T) / 100

Si for Rs.x for 2 years at 14% p.a = \(\frac{{28x}}{{100}}\)

Si for Rs.(13900 - x) for 2 years at 11% p.a = \(\frac{{(13900 - x) \times\ 2\ \times\ 11}}{{100}}\)

As per the question,

⇒ \(\frac{{28x}}{{100}} + \frac{{(13900 - x) \times\ 2\ \times\ 11}}{{100}} = Rs.3508\)

⇒ 28x - 22x = 45000

⇒ 6x = 45000

⇒ x = 7500

Investment in scheme B = 13900 - 7500

∴ Rs.6400

Given

In the first 10 overs of a cricket game, the run rate was only 3.2. 

Concept used

Average

Calculation

For first 10 overs run rate was 3.2

Runs scored = 3.2 × 10 = 32

Total runs to be scored = 282

Remaining runs = 282 - 32

Remaining runs = 250

Runs to be scored in 40 overs = 250/40

Required run rate in remaining overs = 6.25

Given

Pooja is twice as efficient as Aarti and takes 90 days less than Aarti to complete the job. 

Concept used

Time and work

Calculation

Total work = Number of days × Efficiency

Efficiency of Pooja and Aarti = 2 : 1

Pooja takes 90 days less than Aarti

⇒ 2(90 - x) = 1x

⇒ 180 - 2x = x

⇒ x = 60

Total work = 60 × (2 + 1) = 180 units

Together they can do the work in 

⇒ 180 / 3 = 60 Days.

Given

Six years ago, the ratio of the ages of Kunal and Sagar was 6 : 5. Four years hence, the ratio of their ages will be 11 : 10. 

Concept used

Ratio and proportion

Calculation

Let the age of Kunal and Sagar 6 years ago be 6x and 5x

Their present age will be (6x + 6) and (5x + 6)

According to the question 

Age of Kunal 4 year hence (6x + 10)

Age of Sagar 4 year hence (5x + 10)

Now, According to the question

⇒ \(\frac{{6x\ +\ 10}}{{5x\ +\ 10}} = \frac{{11}}{{10}}\)

⇒ 5x = 10

⇒ x = 2

Sagar's present age 

⇒ 5 × 2 + 6

∴ 16 years.