Arithmetic, number systems, percentages, ratios, profit and loss, time and work, algebra, geometry, mensuration, and trigonometry.
What should come in place of question Mark ‘?’ in the following number series?
68, ?, 407, 470, 496, 503
283
229
217
253
None of these
Correct answer
283
Why this answer is correct
283 - 68 = 215 (63 - 1)
407 - 283 = 124 (53 - 1)
470 - 407 = 63 (43-1)
496 - 470 = 26 (33 - 1)
503 - 496 = 7 (23 - 1)
Hence 283 is the correct answer.
What should come in place of question Mark ‘?’ in the following number series?
54, 67, 50, 63, 46, ?
33
59
63
61
None of these
Correct answer
59
Why this answer is correct
54 + 13 = 67,
67 - 17 = 50,
50 + 13 = 63,
63 - 17 = 46
46 + 13 = 59
Next term in the series is 59
Hence next term in the series 59
What should come in place of question Mark ‘?’ in the following number series?
60, ?, 63.6, 70.8, 99.6, 243.6
60.8
61.2
60.5
62.2
None of these
Correct answer
61.2
Why this answer is correct
61.2 - 60 = 1.2,
63.6 - 61.2 = 2.4,
70.8 - 63.6 = 7.2,
99.6 - 70.8 = 28.8,
243.6 - 99.6 = 144
Missing term in the series is 61.2
Hence 61.2 is the missing the series.
What should come in place of question Mark ‘?’ in the following number series?
15, 34, 57, 86, ?, 170
117
123
125
121
None of these
Correct answer
123
Why this answer is correct
Given:
15, 34, 57, 86, ?, 170
Solution:
34 - 15 = 19
57 - 34 = 23
86 - 57 = 29
123 - 86 = 37
170 - 123 = 47
∴ Missing term in the series is 123.
Important Points
The difference in the numbers 19, 23, 29, 37 & 47 are multiple of 2.
⇒ 23 - 19 = 4
⇒ 29 - 23 = 6
⇒ 37 - 29 = 8
⇒ 47 - 37 = 10
Directions: - Read the following directions carefully and answer the following question.
The line graph represents the total number of population visited in Museums A, B, C and D on Sunday.
The table represents the number of males who visited in Museum out of total population.
| Museum | Number of Males out of the total People who visited in Museum |
|---|---|
| A | 2/9 |
| B | 11/13 |
| C | 13/16 |
| D | 19/40 |
If the number of male in Museum E are 7.69% more than the number of male who visited in Museum C and the number of female are 300 less than the number of Male visited in Museum B. Then find the difference between the number of male and female who visited Museum E?
456
560
352
678
876
Correct answer
352
Why this answer is correct
Number of Male who visited Museum A = 2/9 x 1701 = 378
Number of Male who visited Museum B = 11/13 x 1924 = 1628
Number of Male who visited Museum C = 13/16 x 1920 = 1560
Number of Male who visited Museum D = 19/40 x 2000 = 950
| Museum | Male | Female |
|---|---|---|
| A | 378 | 1323 |
| B | 1628 | 296 |
| C | 1560 | 360 |
| D | 950 | 1050 |
Number of Male who visited Museum E = 107.69% of 1560 = 1680
Number of Female who visited Museum E = 1628 - 300 = 1328
Required difference = 1680 - 1328 = 352
Directions: - Read the following directions carefully and answer the following question.
The line graph represents the total number of population visited in Museums A, B, C and D on Sunday.
The table represents the number of males who visited in Museum out of total population.
| Museum | Number of Males out of the total People who visited in Museum |
|---|---|
| A | 2/9 |
| B | 11/13 |
| C | 13/16 |
| D | 19/40 |
Museum A is in village Rampur where the number of population was 1,24,000 and the ratio of male and female 15:16 Then, find the percentage of total female on Sunday in Rampur village to the total number male in Museum B?
More than 4010%
Between 3508% to 4000%
Less than 3886%
Both option 1 and 3
None of these
Correct answer
More than 4010%
Why this answer is correct
Number of Male who visited Museum A = 2/9 x 1701 = 378
Number of Male who visited Museum B = 11/13 x 1924 = 1628
Number of Male who visited Museum C = 13/16 x 1920 = 1560
Number of Male who visited Museum D = 19/40 x 2000 = 950
| Museum | Male | Female |
|---|---|---|
| A | 378 | 1323 |
| B | 1628 | 296 |
| C | 1560 | 360 |
| D | 950 | 1050 |
The number of females in Rampur before Sunday = 16/31 x 1,24,000 = 64000
Total number of female population in village Rampur on Sunday = 64000 + 1323 = 65323
Required percentage = 65323/1628 x 100 = 4012.46%
Directions: - Read the following directions carefully and answer the following question.
The line graph represents the total number of population visited in Museums A, B, C and D on Sunday.
The table represents the number of males who visited in Museum out of total population.
| Museum | Number of Males out of the total People who visited in Museum |
|---|---|
| A | 2/9 |
| B | 11/13 |
| C | 13/16 |
| D | 19/40 |
What are the difference between male who visited museum B and C together to the average of female who visited museum A, B and C together?(approx value)
1962
2700
1882
2528
None of these
Correct answer
2528
Why this answer is correct
Number of Male who visited Museum A = 2/9 x 1701 = 378
Number of Male who visited Museum B = 11/13 x 1924 = 1628
Number of Male who visited Museum C = 13/16 x 1920 = 1560
Number of Male who visited Museum D = 19/40 x 2000 = 950
| Museum | Male | Female |
|---|---|---|
| A | 378 | 1323 |
| B | 1628 | 296 |
| C | 1560 | 360 |
| D | 950 | 1050 |
Average = (1323 + 296 + 360)/3 = 659.66 = 660 (Approx.)
Required difference = (1628 + 1560) - 660 = 3188 - 660 = 2528
Directions: - Read the following directions carefully and answer the following question.
The line graph represents the total number of population visited in Museums A, B, C and D on Sunday.
The table represents the number of males who visited in Museum out of total population.
| Museum | Number of Males out of the total People who visited in Museum |
|---|---|
| A | 2/9 |
| B | 11/13 |
| C | 13/16 |
| D | 19/40 |
If the cost price of male ticket and the female ticket Rs. X and Rs.(X-5). And the museum B get the revenue Rs. 94720. Find the total revenue getting from male ticket from museum A?(Consider approximate value of X)
18900
20800
20600
18700
None of these
Correct answer
18900
Why this answer is correct
Number of Male who visited Museum A = 2/9 x 1701 = 378
Number of Male who visited Museum B = 11/13 x 1924 = 1628
Number of Male who visited Museum C = 13/16 x 800 = 650
| Museum | Male | Female |
|---|---|---|
| A | 378 | 1323 |
| B | 1628 | 296 |
| C | 650 | 150 |
| D | 950 | 1050 |
Revenue generated by males in Museum B = 1628 × X
Revenue generated by females in Museum B = 296(X - 5)
Total revenue = 1628 × X + 296(X - 5) = 94720
1628X + 296X - 1480 = 94720
1925X = 94720 + 1480 = 96204
X = 96200/1925 = 50(Approx)
Total revenue getting from male tickets from museum A = 378 x 50 = 18900
Directions: - Read the following directions carefully and answer the following question.
The line graph represents the total number of population visited in Museums A, B, C and D on Sunday.
The table represents the number of males who visited in Museum out of total population.
| Museum | Number of Males out of the total People who visited in Museum |
|---|---|
| A | 2/9 |
| B | 11/13 |
| C | 13/16 |
| D | 19/40 |
Find the average number of vistiors in B, C and D ?
1176
2096
1556
1948
None of these
Correct answer
1948
Why this answer is correct
Number of Male who visited Museum A = 2/9 x 1701 = 378
Number of Male who visited Museum B = 11/13 x 1924 = 1628
Number of Male who visited Museum C = 13/16 x 1920 = 1560
Number of Male who visited Museum D = 19/40 x 2000 = 950
| Museum | Male | Female |
|---|---|---|
| A | 378 | 1323 |
| B | 1628 | 296 |
| C | 1560 | 360 |
| D | 950 | 1050 |
Average = (1924 + 1920 + 2000)/3 = 1948
Directions: - Read the following directions carefully and answer the following question.
The line graph represents the total number of population visited in Museums A, B, C and D on Sunday.
The table represents the number of males who visited in Museum out of total population.
| Museum | Number of Males out of the total People who visited in Museum |
|---|---|
| A | 2/9 |
| B | 11/13 |
| C | 13/16 |
| D | 19/40 |
The number of population of village Mowar was increased by p% on Sunday due to the number visitors visited at museum D. On sunday there were total female 30% of the population on that day and the number of male population on that day was 4200. Find the value of P?
200
150
300
100
None of these
Correct answer
200
Why this answer is correct
Number of Male who visited Museum A = 2/9 x 1701 = 378
Number of Male who visited Museum B = 11/13 x 1924 = 1628
Number of Male who visited Museum C = 13/16 x 1920 = 1560
| Museum | Male | Female |
|---|---|---|
| A | 378 | 1323 |
| B | 1628 | 296 |
| C | 1560 | 360 |
| D | 950 | 1050 |
70% of the population of Mowar village = 4200
So, on particular day, population of village = 4200 × 100/70 = 6000
then, (100 + p%) of 2000 = 6000
⇒ [(100 + p)/100] × 2000 = 6000
⇒ p = 200
The answer is option 1
Directions: Read the following instructions and answer the following question.
The tabular graph shows the number of articles sold by shop Pesto in three different months by three different entity
| Months | Average number of articles sold by (A, B & C) | % of articles sold by A out of the total | Number of articles sold by C |
|---|---|---|---|
| April | 100 | 20% | 160 |
| May | 120 | 25% | 70 |
| June | 72 | 50% | 65 |
Find the difference between the number of article sold by C in June and April months?
86
55
95
42
36
Correct answer
95
Why this answer is correct
Total number of articles sold by A, B and C together in April month = 100 x 3 = 300
Total number of articles sold by A, B and C together in May month = 120 x 3 = 360
Total number of articles sold by A, B and C together in June month = 72 x 3 = 216
Number of article sold by A in April = 20% of 300 = 60
Number of article sold by A in May = 25% of 360 = 90
Number of article sold by A in June = 50% of 216 = 108
Number of article sold by B in April = 300 - (60 + 160) = 80
Number of article sold by B in May = 360 - (90 + 70) = 200
Number of article sold by B in June = 216 - (108 + 65) = 43
| Months | Number of articles sold by A | Number of articles sold by B | Number of articles sold by C |
|---|---|---|---|
| April | 60 | 80 | 160 |
| May | 90 | 200 | 70 |
| June | 108 | 43 | 65 |
Number of articles sold by C in June and April months = 160 - 65 = 95
Directions: Read the following instructions and answer the following question.
The tabular graph shows the number of articles sold by shop Pesto in three different months by three different entity
| Months | Average number of articles sold by (A, B & C) | % of articles sold by A out of the total | Number of articles sold by C |
|---|---|---|---|
| April | 100 | 20% | 160 |
| May | 120 | 25% | 70 |
| June | 72 | 50% | 65 |
The price of article sold by B is Rs. 180 and in June they offer discount of p% and the company will get Rs. 4440. Find the p (approx)?
40
50
75
60
35
Correct answer
40
Why this answer is correct
Total number of articles sold by A, B and C together in April month = 100 x 3 = 300
Total number of articles sold by A, B and C together in May month = 120 x 3 = 360
Total number of articles sold by A, B and C together in June month = 72 x 3 = 216
Number of article sold by A in April = 20% of 300 = 60
Number of article sold by A in May = 25% of 360 = 90
Number of article sold by A in June = 50% of 216 = 108
Number of article sold by B in April = 300 - (60 + 160) = 80
Number of article sold by B in May = 360 - (90 + 70) = 200
Number of article sold by B in June = 216 - (108 + 65) = 43
| Months | Number of articles sold by A | Number of articles sold by B | Number of articles sold by C |
|---|---|---|---|
| April | 60 | 80 | 160 |
| May | 90 | 200 | 70 |
| June | 108 | 43 | 65 |
Income generated by article B in June = 180 x 43 = 7740
After a discount of p%, he will get Rs. 4440
Discount = 7740 - 4440 = 3300
Discount % = (3300/ 7740) x 100 = 42.63%
Directions: Read the following instructions and answer the following question.
The tabular graph shows the number of articles sold by shop Pesto in three different months by three different entity
| Months | Average number of articles sold by (A, B & C) | % of articles sold by A out of the total | Number of articles sold by C |
|---|---|---|---|
| April | 100 | 20% | 160 |
| May | 120 | 25% | 70 |
| June | 72 | 50% | 65 |
If out of the total number of products sold by A in june, 25% were returned due to defects, then find the ratio of non defective products sold by A in june and the number of products sold by C in April?
25:31
81 : 160
21:32
8:5
None of these
Correct answer
81 : 160
Why this answer is correct
Total number of articles sold by A, B and C together in April month = 100 x 3 = 300
Total number of articles sold by A, B and C together in May month = 120 x 3 = 360
Total number of articles sold by A, B and C together in June month = 72 x 3 = 216
Number of article sold by A in April = 20% of 300 = 60
Number of article sold by A in May = 25% of 360 = 90
Number of article sold by A in June = 50% of 216 = 108
Number of article sold by B in April = 300 - (60 + 160) = 80
Number of article sold by B in May = 360 - (90 + 70) = 200
Number of article sold by B in June = 216 - (108 + 65) = 43
| Months | Number of articles sold by A | Number of articles sold by B | Number of articles sold by C |
|---|---|---|---|
| April | 60 | 80 | 160 |
| May | 90 | 200 | 70 |
| June | 108 | 43 | 65 |
Total number of products sold by A in June = 108
Number of defective articles = 27
Number of non-defective articles = 108 - 27 = 81.
The ratio of non-defective products sold by A in June and the number of products sold by C in April
= 81 : 160
Hence 81: 160 is the correct answer
Directions: Read the following instructions and answer the following question.
The tabular graph shows the number of articles sold by shop Pesto in three different months by three different entity
| Months | Average number of articles sold by (A, B & C) | % of articles sold by A out of the total | Number of articles sold by C |
|---|---|---|---|
| April | 100 | 20% | 160 |
| May | 120 | 25% | 70 |
| June | 72 | 50% | 65 |
In April, if person B sold two types of products i.e. TV and Refrigerator in the ratio of 6:4, then find the difference between the total number of TVs sold by B in April and total number of products sold by B in June.
6
5
8
4
None of these
Correct answer
5
Why this answer is correct
Total number of articles sold by A, B and C together in April month = 100 x 3 = 300
Total number of articles sold by A, B and C together in May month = 120 x 3 = 360
Total number of articles sold by A, B and C together in June month = 72 x 3 = 216
Number of article sold by A in April = 20% of 300 = 60
Number of article sold by A in May = 25% of 360 = 90
Number of article sold by A in June = 50% of 216 = 108
Number of article sold by B in April = 300 - (60 + 160) = 80
Number of article sold by B in May = 360 - (90 + 70) = 200
Number of article sold by B in June = 216 - (108 + 65) = 43
| Months | Number of articles sold by A | Number of articles sold by B | Number of articles sold by C |
|---|---|---|---|
| April | 60 | 80 | 160 |
| May | 90 | 200 | 70 |
| June | 108 | 43 | 65 |
Number of TV sold by B in April = 80 x (6/10) = 48
Number of Refrigerator sold by B in April = 80 x (4/10) = 32
Difference between the total number of TVs sold by B in April and total number of products sold by B in June = 48 - 43 = 5
Directions: Read the following instructions and answer the following question.
The tabular graph shows the number of articles sold by shop Pesto in three different months by three different entity
| Months | Average number of articles sold by (A, B & C) | % of articles sold by A out of the total | Number of articles sold by C |
|---|---|---|---|
| April | 100 | 20% | 160 |
| May | 120 | 25% | 70 |
| June | 72 | 50% | 65 |
Find the average of number of products sold by B in May and that by C in June ?
132.5
120
118
124
None of these
Correct answer
132.5
Why this answer is correct
Total number of articles sold by A, B and C together in April month = 100 x 3 = 300
Total number of articles sold by A, B and C together in May month = 120 x 3 = 360
Total number of articles sold by A, B and C together in June month = 72 x 3 = 216
Number of article sold by A in April = 20% of 300 = 60
Number of article sold by A in May = 25% of 360 = 90
Number of article sold by A in June = 50% of 216 = 108
Number of article sold by B in April = 300 - (60 + 160) = 80
Number of article sold by B in May = 360 - (90 + 70) = 200
Number of article sold by B in June = 216 - (108 + 65) = 43
| Months | Number of articles sold by A | Number of articles sold by B | Number of articles sold by C |
|---|---|---|---|
| April | 60 | 80 | 160 |
| May | 90 | 200 | 70 |
| June | 108 | 43 | 65 |
The number of articles sold by B is May = 200
Number of articles sold by C in June = 65
Average = 265/2 = 132.5
Directions: Read the following instructions and answer the following question.
The tabular graph shows the number of articles sold by shop Pesto in three different months by three different entity
| Months | Average number of articles sold by (A, B & C) | % of articles sold by A out of the total | Number of articles sold by C |
|---|---|---|---|
| April | 100 | 20% | 160 |
| May | 120 | 25% | 70 |
| June | 72 | 50% | 65 |
If 1/3rd of the products sold by B in June were sold to females then find the Product of number of products sold by B to males in June and the number of products sold by A in May?
1120
1080
980
2580
None of these
Correct answer
2580
Why this answer is correct
Total number of articles sold by A, B and C together in April month = 100 x 3 = 300
Total number of articles sold by A, B and C together in May month = 120 x 3 = 360
Total number of articles sold by A, B and C together in June month = 72 x 3 = 216
Number of article sold by A in April = 20% of 300 = 60
Number of article sold by A in May = 25% of 360 = 90
Number of article sold by A in June = 50% of 216 = 108
Number of article sold by B in April = 300 - (60 + 160) = 80
Number of article sold by B in May = 360 - (90 + 70) = 200
Number of article sold by B in June = 216 - (108 + 65) = 43
| Months | Number of articles sold by A | Number of articles sold by B | Number of articles sold by C |
|---|---|---|---|
| April | 60 | 80 | 160 |
| May | 90 | 200 | 70 |
| June | 108 | 43 | 65 |
Number of products sold by B in June = 43
Number of products sold by B in June to Females = 43/3
Number of products sold by B to male = (43 × 2)/3
Number of products sold by A in May = 90
Product = [(43 × 2)/3] × 90 = 2580
In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.
I. x2 + 2x - 35 = 0
II. y2 - 2y - 48 = 0
x > y
x < y
x ≥ y
x ≤ y
x = y or relation between x and y can not be established.
Correct answer
x = y or relation between x and y can not be established.
Why this answer is correct
Given:
I. x2 + 2x - 35 = 0
II. y2 - 2y - 48 = 0
Calculation:
From I,
x2 + 2x - 35 = 0
⇒ x2 + 7x - 5x - 35 = 0
⇒ x(x + 7) - 5(x + 7) = 0
⇒ (x + 7)(x - 5) = 0
Taking,
⇒ (x + 7) = 0 or (x - 5) = 0
⇒ x = -7 or 5
From II,
y2 - 2y - 48 = 0
⇒ y2 - 8y + 6y - 48 = 0
⇒ y(y - 8) + 6(y - 8) = 0
⇒ (y - 8)(y + 6) = 0
Taking,
⇒ (y - 8) = 0 or (x + 6) = 0
⇒ x = 8 or -6
Comparison between x and y (via Tabulation):
| Value of x | Value of y | Relation |
|---|---|---|
| -7 | 8 | x < y |
| -7 | -6 | x < y |
| 5 | 8 | x < y |
| 5 | -6 | x > y |
∴ x = y or relation between x and y can not be established.
In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.
I. x2 - 10x + 16 = 0
II. y2 - 5y - 24 = 0
x > y
x < y
x ≥ y
x ≤ y
x = y or relation between x and y can not be established.
Correct answer
x = y or relation between x and y can not be established.
Why this answer is correct
Given:
I. x2 - 10x + 16 = 0
II. y2 - 5y - 24 = 0
Calculation:
From I,
x2 - 10x + 16 = 0
⇒ x2 - 8x - 2x + 16 = 0
⇒ x(x - 8) - 2(x - 8) = 0
⇒ (x - 2)(x - 8) = 0
⇒ x = 8, 2
From II,
y2 - 5y - 24 = 0
⇒ y2 - 8y + 3y - 24 = 0
⇒ y(y - 8) + 3(y - 8) = 0
⇒ (y - 8)(y + 3) = 0
Taking,
⇒ (y - 8) = 0 or (y + 3) = 0
⇒ y = 8 or (-3)
Comparison between x and y (via Tabulation):
| Value of x | Value of y | Relation |
|---|---|---|
| 8 | 8 | x = y |
| 8 | -3 | x > y |
| 2 | 8 | x < y |
| 2 | -3 | x > y |
∴ x = y or relation between x and y can not be established.
In the given question, two equations numbered I and II are given. Solve both the equations and mark the appropriate answer.
I. x2 – 52x + 51 = 0
II. y2 – 57y + 56 = 0
x > y
x < y
x ≥ y
x ≤ y
x = y or relationship between x and y cannot be established
Correct answer
x = y or relationship between x and y cannot be established
Why this answer is correct
Calculation:
From I,
x2 – 52x + 51 = 0
⇒ x2 – x – 51x + 51 = 0
⇒ x(x – 51) – 1(x – 51) = 0
⇒ (x – 1)(x – 51) = 0
⇒ x = 1, 51
From II,
y2 – 57y + 56 = 0
⇒ y2 – y – 56y + 56 = 0
⇒ y(y – 1) – 56(y – 1) = 0
⇒ (y – 56)(y – 1) = 0
⇒ y = 56, 1
Comparison between x and y (via Tabulation):
| Value of x | Value of y | Relation |
|---|---|---|
| 1 | 56 | x < y |
| 1 | 1 | x = y |
| 51 | 56 | x < y |
| 51 | 1 | x > y |
∴ x = y or relationship between x and y cannot be established
In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.
I. x2 – 3x + 2 = 0
II. y2 + 12y + 36 = 0
x > y
x < y
x ≥ y
x ≤ y
x = y or relationship between x and y cannot be established
Correct answer
x > y
Why this answer is correct
I. x2 – 3x + 2 = 0
⇒ x2 – x - 2x + 2 = 0
⇒ x(x – 1) - 2(x – 1) = 0
⇒ (x - 2)(x - 1) = 0
⇒ x = 2, 1
II. y2 + 12y + 36 = 0
⇒ y2 + 6y + 6y + 36 = 0
⇒ y(y + 6) + 6(y + 6) = 0
⇒ (y + 6)2 = 0
⇒ y = –6
Comparison between x and y (via Tabulation):
| Value of x | Value of y | Relation |
|---|---|---|
| 2 | -6 | x > y |
| 1 | -6 | x > y |
∴ Clearly x > y
Solving previous year questions by topic helps identify recurring concepts, question patterns, and frequently asked sub-topics. Attempt each question, review the step-by-step explanation, and note down key formulas or facts for quick revision before the exam.