Arithmetic, number systems, percentages, ratios, profit and loss, time and work, algebra, geometry, mensuration, and trigonometry.
Directions (47-52): Find out the missing term of the number series given below.
Q51. 54, 67, 50, 63, 46, ?
63
29
33
51
59
Correct answer
59
Directions (47-52): Find out the missing term of the number series given below.
Q52. 60, ?, 63.6, 70.8, 99.6, 243.6
67.4
61.2
59.6
57.8
63.2
Correct answer
61.2
Q53. A, B and C together can complete a work in 16 4/11 days, while A and B together can complete the same work in 20 days. Find in how many days C alone can do 60% of the same work.
63 days
108 days
45 days
48 days
54 days
Correct answer
54 days
Q54. The length and breadth of a rectangle is 3 : 2 respectively. When length of the rectangle increased by 25% and the breadth remain same, then the area of the rectangle is increased by 24 m². Find original length (in meters) of the rectangle.
15
6
24
8
12
Correct answer
12
Q55. The average cost price of two articles P and Q is Rs 1350. Article P sold at 10% profit and article Q sold at 20% profit. The total selling price of article P and Q is Rs 3120. If article Q is sold at 40% profit, then find the selling price.
2000 Rs
2400 Rs
1900 Rs
2100 Rs
1680 Rs
Correct answer
2100 Rs
Q56. P and Q started a business by investing Rs 15000 & Rs (15000 + x) respectively. After four months, Q withdrew 40% of his initial investment. After a year, the total profit was Rs 47000 and the profit share of Q was Rs 22000. Find the value of ‘2x’.
1500
2400
3000
4500
6000
Correct answer
6000
Q57. A man invested Rs X and Rs x + 400 in two different schemes A & B respectively. The rate of interest offered by schemes A & B is 10% p.a. and 12% p.a. respectively. If the sum of interest received by man from scheme A after four years and from scheme B after two year is Rs 640, then find X.
850
1250
750
1150
1050
Correct answer
850
Q58. Vessel A contains 150 liters mixture of milk and water in which water is 40%. ‘x’ liters mixture is taken out (quantity of water in ‘x’ liters is 12 liters) and poured into vessel B which already contain ‘x’ liters water. Find the difference between quantity (in liters) of milk and water in resultant mixture of vessel B.
12
30
16
24
18
Correct answer
24
Q59. The total time taken by a boat to cover 400 km downstream and 320 upstream is 40 hours. If downstream speed of the boat is 4 km/hr more than upstream speed of the boat, then find the time taken (in hours) by the boat to cover 720 km downstream.
36
48
24
44
32
Correct answer
36
Q60. The average of 11 numbers is 71 and average of first five numbers is 67. If average of last four numbers is 91.5 and the ratio of sixth and seventh number is 9 : 7, then find the sixth number.
54
36
27
45
35
Correct answer
45
Directions (61-64): The information given about number of project handle by two companies (A and B) in three different years (2015, 2016 and 2017). Read the information carefully and answer the questions given below.
In 2015, Total projects handle by A are 1.5 times of B.
In 2016, Total project handle by B is 9 more than that of in 2015 and A handle 20 projects.
In 2017, total project handle by A is 25% more than that of by B in 2015 and B handle 30 projects.
Total projects handle by A in all three years is 42.
Q61. Find the projects handle by B in 2017 is how much more or less than the projects handle by A in 2016.
5
10
20
15
25
Correct answer
10
Directions (61-64): The information given about number of project handle by two companies (A and B) in three different years (2015, 2016 and 2017). Read the information carefully and answer the questions given below.
In 2015, Total projects handle by A are 1.5 times of B.
In 2016, Total project handle by B is 9 more than that of in 2015 and A handle 20 projects.
In 2017, total project handle by A is 25% more than that of by B in 2015 and B handle 30 projects.
Total projects handle by A in all three years is 42.
Q62. The projects handle by C in 2015 is 50% more than the project handle by A in 2017. Find the ratio between projects handle by B in 2015 to projects handle by C in 2015.
9:11
8:15
5:9
4:13
7:17
Correct answer
8:15
Directions (61-64): The information given about number of project handle by two companies (A and B) in three different years (2015, 2016 and 2017). Read the information carefully and answer the questions given below.
In 2015, Total projects handle by A are 1.5 times of B.
In 2016, Total project handle by B is 9 more than that of in 2015 and A handle 20 projects.
In 2017, total project handle by A is 25% more than that of by B in 2015 and B handle 30 projects.
Total projects handle by A in all three years is 42.
Q63. Projects handles by A in 2016 is how much percentage more or less than the projects handle by B in 2015?
75%
50%
200%
150%
25%
Correct answer
150%
Directions (61-64): The information given about number of project handle by two companies (A and B) in three different years (2015, 2016 and 2017). Read the information carefully and answer the questions given below.
In 2015, Total projects handle by A are 1.5 times of B.
In 2016, Total project handle by B is 9 more than that of in 2015 and A handle 20 projects.
In 2017, total project handle by A is 25% more than that of by B in 2015 and B handle 30 projects.
Total projects handle by A in all three years is 42.
Q64. Find the total projects handle by B in all three years.
5
15
25
55
35
Correct answer
55
Q65. The ratio of present ages of A to B is 3:4, X years ago the ratio was 5: 7 and sum of ages of A and B after X years is 48. Find the present age of B.
16 years
24 years
32 years
None of these.
Can’t be determined.
Correct answer
24 years
Directions: The given caselet shows the number of chairs and tables sold in the four different shops such as A, B, C and D.
Number of tables sold in shop A is x and the number of chairs sold in shop A is y. Number of tables sold in shop B is (x - 20). Number of chairs sold in shop A is 70% of the number of chairs sold in shop B. Number of tables sold in shop C is (x - 40). Number of tables sold in shop D is 60% of tables sold in shop A.Number of chairs sold in shop C is 80% of chairs sold in shop B. Number of chairs sold in shop D is 75% of the chairs sold in shop C. Total tables sold in all the shops is 170 more than total chairs sold in all the shops
Note:
x + y = 220
If the price of each table in shop A is Rs. a and the price of each chair is Rs. (a + 100) and the total revenue generated by selling all the chairs and tables in shop A is Rs. 73000. Find the value of a.
550
450
600
300
350
Correct answer
300
Why this answer is correct
General solution:
Number of tables sold in shop A = x
Number of chairs sold in shop A = y
Number of tables sold in shop B = (x - 20)
Number of chairs sold in shop A is 70% of number of chairs sold in shop B
Number of chairs sold in shop B = y/(70) × 100 = (10y/7)
Number of tables sold in shop C = (x - 40)
Number of tables sold in shop D = (60/100) × x = 0.6x
Number of chairs sold in shop C = 80/100 × (10y/7) = 8y/7
Number of chairs sold in shop D = (8y/7) × (75/100) = 6y/7
Total tables sold in all the shops is 170 more than total chairs sold in all the shops
[x + (x - 20) + (x - 40) + 0.6x] - [y + 10y/7 + (8y/7)y + (6y/7)] = 170
(3.6x - 60) - (y + 24y/7) = 170
(3.6x - 60) - (7y + 24y)/7 = 170
25.2x - 420 - (7y + 24y) = 1190
25.2x - 31y = 1610 —----> 1
2 × 31→ x + y = 220 —----->2
25.2x - 31y = 1610
31x + 31y = 6820
56.2x = 8430
x = 150
y = 70
Number of tables sold in shop A = x = 150
Number of chairs sold in shop A = y = 70
Number of tables sold in shop B = (x - 20) = (150 - 20) = 130
Number of chairs sold in shop A is 70% of number of chairs sold in shop B
Number of chairs sold in shop B = y/(70) × 100 = (10y/7) = 10 × 70/7 = 100
Number of tables sold in shop C = (x - 40) = (150 - 40) = 110
Number of tables sold in shop D = (60/100) × x = 0.6x = 150 × (0.6) = 90
Number of chairs sold in shop C = 80/100 × (10y/7) = 8y/7 = 8 × (70/7) = 80
Number of chairs sold in shop D = (8y/7) × (75/100) = 6y/7 = 6 × (70/7) = 60
Solution:
Price of each table in shop A = Rs. a
Price of each chair in shop A = Rs. (a + 100)
Total revenue generated = Rs. 73000
a× 150 + (a + 100) × 70 = 73000
150a + 70a + 7000 = 73000
220a = 66000
a = 300
Directions: The given caselet shows the number of chairs and tables sold in the four different shops such as A, B, C and D.
Number of tables sold in shop A is x and the number of chairs sold in shop A is y. Number of tables sold in shop B is (x - 20). Number of chairs sold in shop A is 70% of the number of chairs sold in shop B. Number of tables sold in shop C is (x - 40). Number of tables sold in shop D is 60% of tables sold in shop A.Number of chairs sold in shop C is 80% of chairs sold in shop B. Number of chairs sold in shop D is 75% of the chairs sold in shop C. Total tables sold in all the shops is 170 more than total chairs sold in all the shops
Note:
x + y = 220
If 3/5th and 4/11 th of the tables sold in shop A and C respectively are at discount and 3/7 th and 1/2 of the chairs sold in shop A and C respectively are sold at the discount. Find the total number of chairs and tables sold at discount in shop A and C.
350
300
270
200
250
Correct answer
200
Why this answer is correct
General solution:
Number of tables sold in shop A = x
Number of chairs sold in shop A = y
Number of tables sold in shop B = (x - 20)
Number of chairs sold in shop A is 70% of number of chairs sold in shop B
Number of chairs sold in shop B = y/(70) × 100 = (10y/7)
Number of tables sold in shop C = (x - 40)
Number of tables sold in shop D = (60/100) × x = 0.6x
Number of chairs sold in shop C = 80/100 × (10y/7) = 8y/7
Number of chairs sold in shop D = (8y/7) × (75/100) = 6y/7
Total tables sold in all the shops is 170 more than total chairs sold in all the shops
[x + (x - 20) + (x - 40) + 0.6x] - [y + 10y/7 + (8y/7)y + (6y/7)] = 170
(3.6x - 60) - (y + 24y/7) = 170
(3.6x - 60) - (7y + 24y)/7 = 170
25.2x - 420 - (7y + 24y) = 1190
25.2x - 31y = 1610 —----> 1
2 × 31→ x + y = 220 —----->2
25.2x - 31y = 1610
31x + 31y = 6820
56.2x = 8430
x = 150
y = 70
Number of tables sold in shop A = x = 150
Number of chairs sold in shop A = y = 70
Number of tables sold in shop B = (x - 20) = (150 - 20) = 130
Number of chairs sold in shop A is 70% of number of chairs sold in shop B
Number of chairs sold in shop B = y/(70) × 100 = (10y/7) = 10 × 70/7 = 100
Number of tables sold in shop C = (x - 40) = (150 - 40) = 110
Number of tables sold in shop D = (60/100) × x = 0.6x = 150 × (0.6) = 90
Number of chairs sold in shop C = 80/100 × (10y/7) = 8y/7 = 8 × (70/7) = 80
Number of chairs sold in shop D = (8y/7) × (75/100) = 6y/7 = 6 × (70/7) = 60
Solution:
Number of tables sold at discount in shop A = 150 × (3/5) = 90
Number of tables sold at discount in shop C = 110 × (4/11) = 40
Number of chairs sold at discount in shop A = 70 × (3/7) = 30
Number of chairs sold at discount in shop C = 80 × (1/2) = 40
Total number of chairs and tables in shop A and C sold at the discount = (90 + 40 +30 + 40) = 200
Directions: The given caselet shows the number of chairs and tables sold in the four different shops such as A, B, C and D.
Number of tables sold in shop A is x and the number of chairs sold in shop A is y. Number of tables sold in shop B is (x - 20). Number of chairs sold in shop A is 70% of the number of chairs sold in shop B. Number of tables sold in shop C is (x - 40). Number of tables sold in shop D is 60% of tables sold in shop A.Number of chairs sold in shop C is 80% of chairs sold in shop B. Number of chairs sold in shop D is 75% of the chairs sold in shop C. Total tables sold in all the shops is 170 more than total chairs sold in all the shops
Note:
x + y = 220
If the number of tables sold in shop D is increased by b% then the ratio between the number of tables and chairs sold in shop D is 2:
35%
20%
33.33%
25%
22%
Correct answer
33.33%
Why this answer is correct
General solution:
Number of tables sold in shop A = x
Number of chairs sold in shop A = y
Number of tables sold in shop B = (x - 20)
Number of chairs sold in shop A is 70% of number of chairs sold in shop B
Number of chairs sold in shop B = y/(70) × 100 = (10y/7)
Number of tables sold in shop C = (x - 40)
Number of tables sold in shop D = (60/100) × x = 0.6x
Number of chairs sold in shop C = 80/100 × (10y/7) = 8y/7
Number of chairs sold in shop D = (8y/7) × (75/100) = 6y/7
Total tables sold in all the shops is 170 more than total chairs sold in all the shops
[x + (x - 20) + (x - 40) + 0.6x] - [y + 10y/7 + (8y/7)y + (6y/7)] = 170
(3.6x - 60) - (y + 24y/7) = 170
(3.6x - 60) - (7y + 24y)/7 = 170
25.2x - 420 - (7y + 24y) = 1190
25.2x - 31y = 1610 —----> 1
2 × 31→ x + y = 220 —----->2
25.2x - 31y = 1610
31x + 31y = 6820
56.2x = 8430
x = 150
y = 70
Number of tables sold in shop A = x = 150
Number of chairs sold in shop A = y = 70
Number of tables sold in shop B = (x - 20) = (150 - 20) = 130
Number of chairs sold in shop A is 70% of number of chairs sold in shop B
Number of chairs sold in shop B = y/(70) × 100 = (10y/7) = 10 × 70/7 = 100
Number of tables sold in shop C = (x - 40) = (150 - 40) = 110
Number of tables sold in shop D = (60/100) × x = 0.6x = 150 × (0.6) = 90
Number of chairs sold in shop C = 80/100 × (10y/7) = 8y/7 = 8 × (70/7) = 80
Number of chairs sold in shop D = (8y/7) × (75/100) = 6y/7 = 6 × (70/7) = 60
Solution:
Number of tables sales in shop D is increased by p
(90 + p)/60 = 2/1
120 = 90 + p
p = 30
Value of b = (30/90) × 100 = 33.33%
Therefore the value of b = 33.33%
Directions: The given caselet shows the number of chairs and tables sold in the four different shops such as A, B, C and D.
Number of tables sold in shop A is x and the number of chairs sold in shop A is y. Number of tables sold in shop B is (x - 20). Number of chairs sold in shop A is 70% of the number of chairs sold in shop B. Number of tables sold in shop C is (x - 40). Number of tables sold in shop D is 60% of tables sold in shop A.Number of chairs sold in shop C is 80% of chairs sold in shop B. Number of chairs sold in shop D is 75% of the chairs sold in shop C. Total tables sold in all the shops is 170 more than total chairs sold in all the shops
Note:
x + y = 220
Number of tables sold in shop E is 25 more than the average number of tables sold in shop A and B. And the number of chairs sold in shop E is 35 more than the average number of chairs sold in shop A and D. Find the total number of tables and chairs sold in the shop E.
235
245
265
255
285
Correct answer
265
Why this answer is correct
General solution:
Number of tables sold in shop A = x
Number of chairs sold in shop A = y
Number of tables sold in shop B = (x - 20)
Number of chairs sold in shop A is 70% of number of chairs sold in shop B
Number of chairs sold in shop B = y/(70) × 100 = (10y/7)
Number of tables sold in shop C = (x - 40)
Number of tables sold in shop D = (60/100) × x = 0.6x
Number of chairs sold in shop C = 80/100 × (10y/7) = 8y/7
Number of chairs sold in shop D = (8y/7) × (75/100) = 6y/7
Total tables sold in all the shops is 170 more than total chairs sold in all the shops
[x + (x - 20) + (x - 40) + 0.6x] - [y + 10y/7 + (8y/7)y + (6y/7)] = 170
(3.6x - 60) - (y + 24y/7) = 170
(3.6x - 60) - (7y + 24y)/7 = 170
25.2x - 420 - (7y + 24y) = 1190
25.2x - 31y = 1610 —----> 1
2 × 31→ x + y = 220 —----->2
25.2x - 31y = 1610
31x + 31y = 6820
56.2x = 8430
x = 150
y = 70
Number of tables sold in shop A = x = 150
Number of chairs sold in shop A = y = 70
Number of tables sold in shop B = (x - 20) = (150 - 20) = 130
Number of chairs sold in shop A is 70% of number of chairs sold in shop B
Number of chairs sold in shop B = y/(70) × 100 = (10y/7) = 10 × 70/7 = 100
Number of tables sold in shop C = (x - 40) = (150 - 40) = 110
Number of tables sold in shop D = (60/100) × x = 0.6x = 150 × (0.6) = 90
Number of chairs sold in shop C = 80/100 × (10y/7) = 8y/7 = 8 × (70/7) = 80
Number of chairs sold in shop D = (8y/7) × (75/100) = 6y/7 = 6 × (70/7) = 60
Solution:
Number of tables sold in shop A = 150
Number of tables sold in shop B = 130
Number of tables sold in the shop E = (150 + 130)/2 = 280/2 = 140 + 25 = 165
Number of chairs sold in shop A = 70
Number of chairs sold in shop D = 60
Number of chairs sold in shop E = (60 + 70)/2 = 130/2 = 65 + 35 = 100
Required total = (165 + 100) = 265
In the following number series, a wrong number is given. Find out the wrong number.
4, 6, 18, 110, 1296, 31104
31104
110
4
6
18
Correct answer
110
Why this answer is correct
The pattern of the given series can be explained as:
4 × 1.5 = 6
6 × 3 = 18
18 × 6 = 108 ≠ 110
108 × 12 = 1296
1296 × 24 = 31104
∴ The wrong term is 110.
Solving previous year questions by topic helps identify recurring concepts, question patterns, and frequently asked sub-topics. Attempt each question, review the step-by-step explanation, and note down key formulas or facts for quick revision before the exam.