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Quantitative Aptitude PYQs

Arithmetic, number systems, percentages, ratios, profit and loss, time and work, algebra, geometry, mensuration, and trigonometry.

1345 Total Questions41 Official PapersYears: 2018–2025Search in Quantitative Aptitude
Showing questions 401–420 of 1345Page 21 of 68
SBI PO Prelims Memory Based Paper (Held On: 5 August 2025 Shift 1) (Previous Year Paper)·Quantitative Aptitude
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Question 401

SBI Probationary Officer (PO) 2025• Quantitative Aptitude• Quantitative Aptitude

Read the data carefully and answer the following question.

Below given bar graph shows the quantity of fabric (silk and cotton) manufactured by different factories per day.

 

The following table shows the ratio between silk fabric and cotton fabric manufactured by each factory per day.

FactorySilk fabric: Cotton fabric
V5:7
W8:7
X3:4
Y2:7
Z11:13

Find the sum of total quantity of silk fabric manufactured by factory W and X together. 

  1. AOption (a)

    3200 m

  2. BOption (b)

    3400 m

  3. COption (c)

    3300 m

  4. DOption (d)

    3500 m

  5. EOption (e)

    3600 m

View answer & explanation

Correct answer

Answer: (c)C.

3300 m

Why this answer is correct

Common Solution:

Factory 'W',

Total quantity of fabric manufactured = 4500 m

Quantity of Silk fabric manufactured = (8/15) × 4500 = 2400 m

Quantity of Cotton fabric manufactured = (7/15) × 4500 = 2100 m

Factory 'X',

Total quantity of fabric manufactured = 2100 m

Quantity of Silk fabric manufactured = (3/7) × 2100 = 900 m

Quantity of Cotton fabric manufactured = (4/7) × 2100 = 1200 m

Similarly,  

FactoryQuantity of Silk fabric manufactured (in meters)Quantity of Cotton fabric manufactured (in meters)Total quantity of fabric manufactured (in meters)
V100014002400
W240021004500
X90012002100
Y80028003600
Z220026004800

 

Calculations:

Required sum = 2400 + 900 = 3300 m

SBI PO Prelims Memory Based Paper (Held On: 5 August 2025 Shift 1) (Previous Year Paper)·Quantitative Aptitude
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Question 402

SBI Probationary Officer (PO) 2025• Quantitative Aptitude• Quantitative Aptitude

Ravi received an amount of ₹11236 by depositing a sum of ₹10000 for 2 years in a bank which provides R% rate of interest compounded annually. What is the simple interest earned on ₹15000 at (R + 3)% rate of interest after (R + 5) years?

  1. AOption (a)

    ₹14500

  2. BOption (b)

    ₹14850

  3. COption (c)

    ₹15200

  4. DOption (d)

    ₹15600

  5. EOption (e)

    ₹14000

View answer & explanation

Correct answer

Answer: (b)B.

₹14850

Why this answer is correct

ATQ,

11236 = 10000(1 + R/100)²

Or, (1 + R/100)² = 11236/10000

Or, (1 + R/100)² = 1.1236

Or, 1 + (R/100) = 1.06

So, R = 6

Now,

P = 15000

R = (6 + 3)% = 9%

T = (6 + 5) = 11 years

SI = (15000 × 9 × 11)/100 = ₹14850

SBI PO Prelims Memory Based Paper (Held On: 5 August 2025 Shift 1) (Previous Year Paper)·Quantitative Aptitude
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Question 403

SBI Probationary Officer (PO) 2025• Quantitative Aptitude• Quantitative Aptitude

A box contains 7 white balls and 13 red balls. The average weight of the white balls is 9 grams, and the average weight of the red balls is 28 grams. Two white balls weighing X grams and Y grams are removed from the box, and three new red balls with an average weight of (Y - 2) grams are added. The new average weight of all the balls in the box becomes 20 grams. Here, X and Y are two distinct positive integers. Find the average weight of white balls that were removed from the box, if only Y is a prime number, and 20 > X > Y.

  1. AOption (a)

    9 gm

  2. BOption (b)

    10 gm

  3. COption (c)

    11 gm

  4. DOption (d)

    12 gm

  5. EOption (e)

    None of these

View answer & explanation

Correct answer

Answer: (c)C.

11 gm

Why this answer is correct

Total initial weight White balls = 7 × 9 = 63

Total initial weight Red balls = 13 × 28 = 364

Total initial weight Total balls = 427

Removed white balls = X and Y

Remaining white weight = 63 - X - Y

Remaining white count = 5

Added red balls = 3

Average weight of added red balls = (Y - 2)

Added red weight = 3(Y - 2) = 3Y - 6

Final total weight = (63 - X - Y) + (364 + 3Y - 6) = 421 - X + 2Y

Final number of balls = 5 + 13 + 3 = 21

Final average = 20

Total final weight = 21 × 20 = 420

ATQ,

421 - X + 2Y = 420

Or, −X + 2Y = -1

Or, X = 2Y + 1

Condition:

Y is prime, 20 > X > Y

Case (I): Y = 3

X = 2(3) + 1 = 7

X = 7 (prime)

Not valid

Case (II): Y = 5

X = 2(5) + 1 = 11

X = 11 (prime)

Not valid

Case (III): Y = 7

X = 2(7) + 1 = 15

20 > 15 > 7

Valid

Average weight of removed white balls = (X + Y) ÷ 2

= (15 + 7) ÷ 2 = 22 ÷ 2 = 11 gm

SBI PO Prelims Memory Based Paper (Held On: 5 August 2025 Shift 1) (Previous Year Paper)·Quantitative Aptitude
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Question 404

SBI Probationary Officer (PO) 2025• Quantitative Aptitude• Quantitative Aptitude

Read the following data carefully and answer the questions.

The data is about the total number of students who participate in dancing, singing, and drama from three classes, i.e. Class X, Class IX, and Class VIII.

The ratio of the total number of students who participate in dancing from Class X to the total number of students who participate in drama from Class IX is 7 : 6. The ratio of the total number of students who participate in drama from Class VIII to those who participate in drama from Class X is 5 : 6. The sum of the total number of students who participated in dancing, singing, and drama together from Class VIII is 865 and the total number of students who participated in drama from all three classes together is 1086.

The total number of students who participated in dancing and singing from Class VIII is 50 and 75 respectively less than those who participated in drama from Class VIII. The total number of students who participated in singing from Class X is 25% more than the students who participated in dancing from Class VIII. The average of the total number of students who participated in dancing and singing from Class IX is equal to the total number of students who participated in drama from Class X. Also, the total number of students who participated in singing from Class IX is 20% less than the total number of students who participated in dancing from Class IX.

Find the average of the total number of students who participate in dancing from Class VIII, dancing from Class IX, and drama from Class X.

  1. AOption (a)

    360

  2. BOption (b)

    372

  3. COption (c)

    384

  4. DOption (d)

    396

  5. EOption (e)

    400

View answer & explanation

Correct answer

Answer: (b)B.

372

Why this answer is correct

Common Solutions:

Let the total number of students who participate in drama from class VIII and class X be 5x and 6x respectively.

The total number of students who participate in dancing from class VIII = 5x - 50

The total number of students who participate in singing from class VIII = 5x - 75

ATQ,

(5x - 50) + (5x - 75) + 5x = 865

Or, 15x - 125 = 865

Or, 15x = 990

So, x = 66

The total number of students who participate in drama from class VIII = 5 × 66 = 330

The total number of students who participate in dancing from class VIII = 330 - 50 = 280

The total number of students who participate in singing from class VIII = 330 - 75 = 255

The total number of students who participate in drama from class X = 6 × 66 = 396

The total number of students who participate in drama from class IX = 1086 - (330 + 396) = 360

The total number of students who participate in dancing from class X = (7/6) × 360 = 420

The total number of students who participate in singing from class X = 125% of 280 = 350

The total number of students who participate in dancing and singing together from class IX = 360 × 2 = 720

The total number of students who participate in dancing from class IX = (100/120) × 528 = 440

The total number of students who participate in singing from class IX = 528 - 440 = 352

ClassNumber of students who participate in DancingNumber of students who participate in SingingNumber of students who participate in Drama
VIII200180240
IX400320300
X350250360

 

Calculation:

Required average = (280 + 440 + 396) ÷ 3

= 1116 ÷ 3 = 372

SBI PO Prelims Memory Based Paper (Held On: 5 August 2025 Shift 1) (Previous Year Paper)·Quantitative Aptitude
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Question 405

SBI Probationary Officer (PO) 2025• Quantitative Aptitude• Quantitative Aptitude

Read the following data carefully and answer the questions.

The data is about the total number of students who participate in dancing, singing, and drama from three classes, i.e. Class X, Class IX, and Class VIII.

The ratio of the total number of students who participate in dancing from Class X to the total number of students who participate in drama from Class IX is 7 : 6. The ratio of the total number of students who participate in drama from Class VIII to those who participate in drama from Class X is 5 : 6. The sum of the total number of students who participated in dancing, singing, and drama together from Class VIII is 865 and the total number of students who participated in drama from all three classes together is 1086.

The total number of students who participated in dancing and singing from Class VIII is 50 and 75 respectively less than those who participated in drama from Class VIII. The total number of students who participated in singing from Class X is 25% more than the students who participated in dancing from Class VIII. The average of the total number of students who participated in dancing and singing from Class IX is equal to the total number of students who participated in drama from Class X. Also, the total number of students who participated in singing from Class IX is 20% less than the total number of students who participated in dancing from Class IX.

The total number of students who participate in drama from class X is what percent more than the total number of students who participate in singing from class X. 

  1. AOption (a)

    10.5%

  2. BOption (b)

    11.75%

  3. COption (c)

    13.14%

  4. DOption (d)

    15.25%

  5. EOption (e)

    16.5%

View answer & explanation

Correct answer

Answer: (c)C.

13.14%

Why this answer is correct

Common Solutions:

Let the total number of students who participate in drama from class VIII and class X be 5x and 6x respectively.

The total number of students who participate in dancing from class VIII = 5x - 50

The total number of students who participate in singing from class VIII = 5x - 75

ATQ,

(5x - 50) + (5x - 75) + 5x = 865

Or, 15x - 125 = 865

Or, 15x = 990

So, x = 66

The total number of students who participate in drama from class VIII = 5 × 66 = 330

The total number of students who participate in dancing from class VIII = 330 - 50 = 280

The total number of students who participate in singing from class VIII = 330 - 75 = 255

The total number of students who participate in drama from class X = 6 × 66 = 396

The total number of students who participate in drama from class IX = 1086 - (330 + 396) = 360

The total number of students who participate in dancing from class X = (7/6) × 360 = 420

The total number of students who participate in singing from class X = 125% of 280 = 350

The total number of students who participate in dancing and singing together from class IX = 360 × 2 = 720

The total number of students who participate in dancing from class IX = (100/120) × 528 = 440

The total number of students who participate in singing from class IX = 528 - 440 = 352

ClassNumber of students who participate in DancingNumber of students who participate in SingingNumber of students who participate in Drama
VIII200180240
IX400320300
X350250360

 

Calculation:

Required percentage = (396 – 350)/350 x 100 = 13.14%

SBI PO Prelims Memory Based Paper (Held On: 5 August 2025 Shift 1) (Previous Year Paper)·Quantitative Aptitude
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Question 406

SBI Probationary Officer (PO) 2025• Quantitative Aptitude• Quantitative Aptitude

Read the following data carefully and answer the questions.

The data is about the total number of students who participate in dancing, singing, and drama from three classes, i.e. Class X, Class IX, and Class VIII.

The ratio of the total number of students who participate in dancing from Class X to the total number of students who participate in drama from Class IX is 7 : 6. The ratio of the total number of students who participate in drama from Class VIII to those who participate in drama from Class X is 5 : 6. The sum of the total number of students who participated in dancing, singing, and drama together from Class VIII is 865 and the total number of students who participated in drama from all three classes together is 1086.

The total number of students who participated in dancing and singing from Class VIII is 50 and 75 respectively less than those who participated in drama from Class VIII. The total number of students who participated in singing from Class X is 25% more than the students who participated in dancing from Class VIII. The average of the total number of students who participated in dancing and singing from Class IX is equal to the total number of students who participated in drama from Class X. Also, the total number of students who participated in singing from Class IX is 20% less than the total number of students who participated in dancing from Class IX.

Find the total number of students who participated in dancing, drama, and singing together from class IX.

  1. AOption (a)

    1086

  2. BOption (b)

    1120

  3. COption (c)

    1152

  4. DOption (d)

    1184

  5. EOption (e)

    1200

View answer & explanation

Correct answer

Answer: (c)C.

1152

Why this answer is correct

Common Solutions:

Let the total number of students who participate in drama from class VIII and class X be 5x and 6x respectively.

The total number of students who participate in dancing from class VIII = 5x - 50

The total number of students who participate in singing from class VIII = 5x - 75

ATQ,

(5x - 50) + (5x - 75) + 5x = 865

Or, 15x - 125 = 865

Or, 15x = 990

So, x = 66

The total number of students who participate in drama from class VIII = 5 × 66 = 330

The total number of students who participate in dancing from class VIII = 330 - 50 = 280

The total number of students who participate in singing from class VIII = 330 - 75 = 255

The total number of students who participate in drama from class X = 6 × 66 = 396

The total number of students who participate in drama from class IX = 1086 - (330 + 396) = 360

The total number of students who participate in dancing from class X = (7/6) × 360 = 420

The total number of students who participate in singing from class X = 125% of 280 = 350

The total number of students who participate in dancing and singing together from class IX = 360 × 2 = 720

The total number of students who participate in dancing from class IX = (100/120) × 528 = 440

The total number of students who participate in singing from class IX = 528 - 440 = 352

ClassNumber of students who participate in DancingNumber of students who participate in SingingNumber of students who participate in Drama
VIII200180240
IX400320300
X350250360

 

Calculation:

Required total number of students who participated in dancing, drama, and singing together from class IX = 440 + 352 + 360 = 1152

SBI PO Prelims Memory Based Paper (Held On: 5 August 2025 Shift 1) (Previous Year Paper)·Quantitative Aptitude
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Question 407

SBI Probationary Officer (PO) 2025• Quantitative Aptitude• Quantitative Aptitude

Read the following data carefully and answer the questions.

The data is about the total number of students who participate in dancing, singing, and drama from three classes, i.e. Class X, Class IX, and Class VIII.

The ratio of the total number of students who participate in dancing from Class X to the total number of students who participate in drama from Class IX is 7 : 6. The ratio of the total number of students who participate in drama from Class VIII to those who participate in drama from Class X is 5 : 6. The sum of the total number of students who participated in dancing, singing, and drama together from Class VIII is 865 and the total number of students who participated in drama from all three classes together is 1086.

The total number of students who participated in dancing and singing from Class VIII is 50 and 75 respectively less than those who participated in drama from Class VIII. The total number of students who participated in singing from Class X is 25% more than the students who participated in dancing from Class VIII. The average of the total number of students who participated in dancing and singing from Class IX is equal to the total number of students who participated in drama from Class X. Also, the total number of students who participated in singing from Class IX is 20% less than the total number of students who participated in dancing from Class IX.

Find the difference between the total number of students who participate in singing from classes VIII and IX together and the total number of students who participate in dancing from class X.

  1. AOption (a)

    167

  2. BOption (b)

    177

  3. COption (c)

    187

  4. DOption (d)

    197

  5. EOption (e)

    207

View answer & explanation

Correct answer

Answer: (c)C.

187

Why this answer is correct

Common Solutions:

Let the total number of students who participate in drama from class VIII and class X be 5x and 6x respectively.

The total number of students who participate in dancing from class VIII = 5x - 50

The total number of students who participate in singing from class VIII = 5x - 75

ATQ,

(5x - 50) + (5x - 75) + 5x = 865

Or, 15x - 125 = 865

Or, 15x = 990

So, x = 66

The total number of students who participate in drama from class VIII = 5 × 66 = 330

The total number of students who participate in dancing from class VIII = 330 - 50 = 280

The total number of students who participate in singing from class VIII = 330 - 75 = 255

The total number of students who participate in drama from class X = 6 × 66 = 396

The total number of students who participate in drama from class IX = 1086 - (330 + 396) = 360

The total number of students who participate in dancing from class X = (7/6) × 360 = 420

The total number of students who participate in singing from class X = 125% of 280 = 350

The total number of students who participate in dancing and singing together from class IX = 360 × 2 = 720

The total number of students who participate in dancing from class IX = (100/120) × 528 = 440

The total number of students who participate in singing from class IX = 528 - 440 = 352

ClassNumber of students who participate in DancingNumber of students who participate in SingingNumber of students who participate in Drama
VIII200180240
IX400320300
X350250360

 

Calculation:

The total number of students who participate in singing from classes VIII and IX together

= 255 + 352 = 607

The total number of students who participate in dancing from class X = 420

Required difference = 607 – 420 = 187

SBI PO Prelims Memory Based Paper (Held On: 5 August 2025 Shift 1) (Previous Year Paper)·Quantitative Aptitude
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Question 408

SBI Probationary Officer (PO) 2025• Quantitative Aptitude• Quantitative Aptitude

Read the following data carefully and answer the questions.

The data is about the total number of students who participate in dancing, singing, and drama from three classes, i.e. Class X, Class IX, and Class VIII.

The ratio of the total number of students who participate in dancing from Class X to the total number of students who participate in drama from Class IX is 7 : 6. The ratio of the total number of students who participate in drama from Class VIII to those who participate in drama from Class X is 5 : 6. The sum of the total number of students who participated in dancing, singing, and drama together from Class VIII is 865 and the total number of students who participated in drama from all three classes together is 1086.

The total number of students who participated in dancing and singing from Class VIII is 50 and 75 respectively less than those who participated in drama from Class VIII. The total number of students who participated in singing from Class X is 25% more than the students who participated in dancing from Class VIII. The average of the total number of students who participated in dancing and singing from Class IX is equal to the total number of students who participated in drama from Class X. Also, the total number of students who participated in singing from Class IX is 20% less than the total number of students who participated in dancing from Class IX.

The ratio of the total number of students who participate in dancing from classes VIII and X together to the total number of students who participate in singing from class X and drama from class IX together.

  1. AOption (a)

    67:71

  2. BOption (b)

    69:70

  3. COption (c)

    70:71

  4. DOption (d)

    71:72

  5. EOption (e)

    72:73

View answer & explanation

Correct answer

Answer: (c)C.

70:71

Why this answer is correct

Common Solutions:

Let the total number of students who participate in drama from class VIII and class X be 5x and 6x respectively.

The total number of students who participate in dancing from class VIII = 5x - 50

The total number of students who participate in singing from class VIII = 5x - 75

ATQ,

(5x - 50) + (5x - 75) + 5x = 865

Or, 15x - 125 = 865

Or, 15x = 990

So, x = 66

The total number of students who participate in drama from class VIII = 5 × 66 = 330

The total number of students who participate in dancing from class VIII = 330 - 50 = 280

The total number of students who participate in singing from class VIII = 330 - 75 = 255

The total number of students who participate in drama from class X = 6 × 66 = 396

The total number of students who participate in drama from class IX = 1086 - (330 + 396) = 360

The total number of students who participate in dancing from class X = (7/6) × 360 = 420

The total number of students who participate in singing from class X = 125% of 280 = 350

The total number of students who participate in dancing and singing together from class IX = 360 × 2 = 720

The total number of students who participate in dancing from class IX = (100/120) × 528 = 440

The total number of students who participate in singing from class IX = 528 - 440 = 352

ClassNumber of students who participate in DancingNumber of students who participate in SingingNumber of students who participate in Drama
VIII200180240
IX400320300
X350250360

 

Calculation:

The total number of students who participate in dancing from classes VIII and X together

= 280 + 420 = 700

The total number of students who participate in singing from class X and drama from class IX together = 350 + 360 = 710

Required ratio = 700: 710 = 70:71

SBI PO Prelims Memory Based Paper (Held On: 5 August 2025 Shift 1) (Previous Year Paper)·Quantitative Aptitude
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Question 409

SBI Probationary Officer (PO) 2025• Quantitative Aptitude• Quantitative Aptitude

A and B started a business investing ₹60,000 and ₹1,00,000 respectively. After 6 months, C joined the business by investing ₹80,000 as capital and ₹16,000 as goodwill (premium for joining). The goodwill amount was shared by A and B in the ratio of their capitals at that time. If the profit at the end of the year is ₹2,70,000, then find C's share.

  1. AOption (a)

    ₹45,000

  2. BOption (b)

    ₹50,000

  3. COption (c)

    ₹54,000

  4. DOption (d)

    ₹60,000

  5. EOption (e)

    ₹72,000

View answer & explanation

Correct answer

Answer: (c)C.

₹54,000

Why this answer is correct

Profit share of 'A', 'B' and 'C' = (60000 × 12) : (100000 × 12) : (80000 × 6)

= 6 :10 :4

C's share = (4/20) × 270000 = Rs. 54000

SBI PO Prelims Memory Based Paper (Held On: 5 August 2025 Shift 1) (Previous Year Paper)·Quantitative Aptitude
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Question 410

SBI Probationary Officer (PO) 2025• Quantitative Aptitude• Quantitative Aptitude

A container contains a mixture of milk and water in ratio 5 : 3 respectively. If 32 Liters of mixture are taken out from the container and after that mixed 12 Liters of water, then the ratio of milk to water becomes 3 : 2. Find the initial quantity of mixture.

  1. AOption (a)

    280 L

  2. BOption (b)

    320 L

  3. COption (c)

    360 L

  4. DOption (d)

    400 L

  5. EOption (e)

    240 L

View answer & explanation

Correct answer

Answer: (b)B.

320 L

Why this answer is correct

Let the initial quantity of Milk and Water be '5x' and '3x' respectively,

Quantity of Milk removed = 32 X (5/8) = 20 Liters

Quantity of Water removed = 32 X (3/8) = 12 Liters

Remaining quantity of milk = (5x - 20) Liters

Remaining quantity of water = (3x - 12) Liters

After adding 12 Liters of water,

Remaining quantity of water = (3x - 12 + 12) = 3x Liters

ATQ,

(5x – 20)/3x = 3/2

Or, 2(5x – 20) = 9x

Or, 10x – 40 = 9x

Or, x = 40

Initial mixture = 8 x 40 = 320 L

SBI PO Prelims Memory Based Paper (Held On: 5 August 2025 Shift 1) (Previous Year Paper)·Quantitative Aptitude
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Question 411

SBI Probationary Officer (PO) 2025• Quantitative Aptitude• Quantitative Aptitude

A sum of Rs. X is distributed among P, Q and R in the ratio of (a + 1) : 2a : a respectively. The total amount received by R is in the denomination of Rs. 5, Rs. 2 and Rs. 0.5 coins. The total number of coins received is 2200, where the number of Rs. 2 coins is 250 more than the number of Rs. 5 coins and the ratio between the number of Rs. 0.5 coins and Rs. 5 coins is 11:

  1. Find the value of X if the ratio of P's share to R's share is 6 : 5.
  1. AOption (a)

    Rs. 9975

  2. BOption (b)

    Rs. 10250

  3. COption (c)

    Rs. 9850

  4. DOption (d)

    Rs. 10750

  5. EOption (e)

    Rs. 11250 

View answer & explanation

Correct answer

Answer: (a)A.

Rs. 9975

Why this answer is correct

Let number of Rs. 5 coins be 'm'

So, the number of Rs. 2 coins = m + 250

Number of Rs. 0.5 coins = 11m

ATQ,

m + (m + 250) + 11m = 2200

Or, 13m + 250 = 2200

Or, 13m = 1950

So, m = 150

Number of Rs. 5 coins = 150

Number of Rs. 2 coins = 400

Number of Rs. 0.5 coins = 1650

Share of 'R' = 150 × 5 + 400 × 2 + 1650 × 0.5 = 750 + 800 + 825 = 2375

Share of 'P' = (6/5) × 2375 = 2850

Here, (a + 1)/a = 6/5

Or, 5a + 5 = 6a

So, a = 5

Share of 'Q' = (2a/a) × R's share = 2 × 2375 = 4750

ATQ,

Total amount (X) = P's share + Q's share + R's share = 2850 + 4750 + 2375 = 9975

SBI PO Prelims Memory Based Paper (Held On: 5 August 2025 Shift 1) (Previous Year Paper)·Quantitative Aptitude
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Question 412

SBI Probationary Officer (PO) 2025• Quantitative Aptitude• Quantitative Aptitude

Two equations I and II are given below in question. You have to solve these equations and give the answer.

I. x2 + 36x + 324 = 0

II. y2 – 4y – 221 = 0

  1. AOption (a)

    x < y

  2. BOption (b)

    x > y

  3. COption (c)

    x ≤ y

  4. DOption (d)

    x ≥ y

  5. EOption (e)

    x = y or the relation between x and y can't be established.

View answer & explanation

Correct answer

Answer: (a)A.

x < y

Why this answer is correct

Given:

I. x2 + 36x + 324 = 0

II. y2 – 4y – 221 = 0

Calculation:

I. x2 + 36x + 324 = 0

⇒ x2 + 18x + 18x + 324 = 0

⇒ x(x + 18) +  18(x + 18)= 0

⇒ (x + 18)(x + 18) = 0

⇒ x = (-18), (-18)

II. y2 – 4y – 221 = 0

⇒ y2 – 17y + 13y – 221 = 0

⇒ y(y – 17) + 13(y – 17) =0

⇒ (y – 17)(y + 13) = 0

⇒ y = 17, (-13)

Value of ‘x’RelationValue of ‘y’
-18<17
-18<-13

When we compared the values of ‘x’ and ‘y’ in the table above, we found that there is only ONE relation between X and Y i.e. <. So, a relation between x and y is “x < y”.

∴ After comparison, all the values of x and y the relation is "x < y".

SBI PO Prelims Memory Based Paper (Held On: 5 August 2025 Shift 1) (Previous Year Paper)·Quantitative Aptitude
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Question 413

SBI Probationary Officer (PO) 2025• Quantitative Aptitude• Quantitative Aptitude

In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.

I. x2 – 24x + 143 = 0

II. 6y2 – 25y + 26 = 0

  1. AOption (a)

    x > y

  2. BOption (b)

    x < y

  3. COption (c)

    x ≥ y

  4. DOption (d)

    x ≤ y

  5. EOption (e)

    x = y or relation between x and y can not be established.

View answer & explanation

Correct answer

Answer: (a)A.

x > y

Why this answer is correct

Given:

I. x2 – 24x + 143 = 0

II. 6y2 – 25y + 26 = 0

Calculation:

From I,

x2 – 24x + 143 = 0

⇒ x2 – 13x - 11x + 143 = 0

⇒ x(x - 13) - 11(x - 13) = 0

⇒ (x - 13)(x - 11) = 0

Taking,

⇒ (x - 13) = 0 or  (x - 11) = 0

⇒ x = 13 or 11

From II,

6y2 – 25y + 26 = 0

⇒ 6y2 – 13y - 12y + 26 = 0

⇒ y(6y - 13) - 2(6y - 13) = 0

⇒ (6y - 13)(y - 2) = 0

Taking,

⇒ (y - 2) = 0 or (6y - 13) = 0

⇒ y = 2 or (13/6)

Comparison between x and y (via Tabulation):

Value of xValue of yRelation
132x > y
1313/6x > y
112x > y
1113/6x > y

 

∴ x > y.

SBI PO Prelims Memory Based Paper (Held On: 5 August 2025 Shift 1) (Previous Year Paper)·Quantitative Aptitude
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Question 414

SBI Probationary Officer (PO) 2025• Quantitative Aptitude• Quantitative Aptitude

Two equations I and II are given below in question. You have to solve these equations and give the answer.

I. x2 + 11x + 18 = 0

II. y2 + 2y + 1 = 0

  1. AOption (a)

    x < y

  2. BOption (b)

    x > y

  3. COption (c)

    x ≤ y

  4. DOption (d)

    x ≥ y

  5. EOption (e)

    x = y or the relation between x and y can't be established.

View answer & explanation

Correct answer

Answer: (a)A.

x < y

Why this answer is correct

Given:

I. x2 + 11x + 18 = 0

II. y2 + 2y + 1 = 0

Calculation:

I. x2 + 11x + 18 = 0

⇒ x2 + 9x + 2x + 18 = 0

⇒ x(x + 9) + 2(x + 9)= 0

⇒ (x + 9)(x + 2) = 0

⇒ x = (-9), (-2)

II. y2 + 2y + 1 = 0

⇒ y2 + y + y + 1 = 0

⇒ y(y + 1) + 1(y + 1) =0

⇒ (y + 1)(y + 1) = 0

⇒ y = (-1), (-1)

Comparison between x and y (via Tabulation):

Value of ‘x’RelationValue of ‘y’
-9<-1
-2<-1

When we compared the values of ‘x’ and ‘y’ in the table above, we found that there is only ONE relation between X and Y i.e. <. So, a relation between x and y is “x < y”.

∴ After comparison, all the values of x and y the relation is “x < y”.

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How should I prepare for Quantitative Aptitude in SBI Probationary Officer (PO)?

Solving previous year questions by topic helps identify recurring concepts, question patterns, and frequently asked sub-topics. Attempt each question, review the step-by-step explanation, and note down key formulas or facts for quick revision before the exam.