Reasoning PYQs

Given

Statement:

'for the victory sign' is coded as 'si vi th fo', 

‘empty the apartment now’ is coded as ‘no ap th em’

‘now for the finale’ is coded as ‘fi th fo no’

‘for empty sign victory’ is coded as ‘vi si em fo’

We get:

for - fo

the - th

empty - em

now – no

The codes for ‘apartment’ and ‘finale’ is determined by elimination, i.e. all the other codes in the sentence are determined:

apartment - ap

finale – fi

We can not clearly determine the codes for ‘victory’ and ‘sign’:

victory – vi/si

sign – si/vi

The code for 'Victory' is either vi or si.

Given

Statement:

'for the victory sign' is coded as 'si vi th fo', 

‘empty the apartment now’ is coded as ‘no ap th em’

‘now for the finale’ is coded as ‘fi th fo no’

‘for empty sign victory’ is coded as ‘vi si em fo’

We get:

for - fo

the - th

empty - em

now – no

The codes for ‘apartment’ and ‘finale’ is determined by elimination, i.e. all the other codes in the sentence are determined:

apartment - ap

finale – fi

We can not clearly determine the codes for ‘victory’ and ‘sign’:

victory – vi/si

sign – si/vi

The code for 'Finale' is fi.

Given

Statement:

'for the victory sign' is coded as 'si vi th fo', 

‘empty the apartment now’ is coded as ‘no ap th em’

‘now for the finale’ is coded as ‘fi th fo no’

‘for empty sign victory’ is coded as ‘vi si em fo’

We get:

for - fo

the - th

empty - em

now – no

The codes for ‘apartment’ and ‘finale’ is determined by elimination, i.e. all the other codes in the sentence are determined:

apartment - ap

finale – fi

We can not clearly determine the codes for ‘victory’ and ‘sign’:

victory – vi/si

sign – si/vi

The code for 'the empty sign' is 'si em th'.

Given

Statement:

'for the victory sign' is coded as 'si vi th fo', 

‘empty the apartment now’ is coded as ‘no ap th em’

‘now for the finale’ is coded as ‘fi th fo no’

‘for empty sign victory’ is coded as ‘vi si em fo’

We get:

for - fo

the - th

empty - em

now – no

The codes for ‘apartment’ and ‘finale’ is determined by elimination, i.e. all the other codes in the sentence are determined:

apartment - ap

finale – fi

We can not clearly determine the codes for ‘victory’ and ‘sign’:

victory – vi/si

sign – si/vi

The code for 'apartment' is 'ap'.

Given words: PROPELLER

1^st, 3^rd, 6^th, and 8^th letter of the word PROPELLER is: P, O, L, and E

Combining and un-jumbling the letters we get: POLE and LOPE

Since 2 words are possible from the letters.

The answer is Y.

The pattern for the code is as follows,

As per the English Alphabetical Series,

Z - 2 = X; X - 2 = V

D - 2 = B; B - 2 = Z

G + 2 = I; I + 2 = K

F - 2 = D; D - 2 = B

K - 2 = I; I - 2 = G

'GIK' is the odd one out.

Given:

5 designations - CEO, CFO, Manager, Clerk, and Peon

CEO is the senior most and Peon is the juniormost person. 

They have a different number of pens such that no two persons have the same number of pens.

Now,

1. Two persons are junior to Z. It means Z is a Manager.

2. The one who is just senior to the one who is Manager has 33 pens. It means CFO has 33 pens.

3. One designation lies between the one who has 33 pens and A. It means A is Clerk.

 

4. A is just senior to the one who has 45 pens. It means Peon has 45 pens.

5. There is one designation between the Manager and R. It means R can be either CEO or Peon.

Case I

 

Case II

 

6. A has 11 pens more and 9 pens more than W and Q respectively. It means A = W+11 and A = Q+9. W+11 = Q+9. Q-W = 2. Q has more pens than W. In case I, Q has 45 pens and W has 33 pens. But 45-33 is not equal to 2. So, the case I get eliminated. In case II, again there are two possibilities:

Possibility I - W have 33 pens. So Q will have 35 pens and A will have 44 pens.

Possibility II - Q has 33 pens so W will have 31 pens and A will have 42 pens.

Case II (a)

 

Case II (b)

 

7. The difference in the number of pens between R and Z is 14 and Z has the least number of pens. So, R – 14 = Z. Z has 45-14 =31 pens. But no two persons can have the same number of pens. So, case II (b) gets eliminated as W also has 31 pens in it. 

The final arrangement is -

 

The total number of pens by the persons who are on the post of CEO and CFO is 35 + 33 = 68.

Hence, The correct answer is 68.

Given:

5 designations - CEO, CFO, Manager, Clerk, and Peon

CEO is the senior most and Peon is the juniormost person. 

They have a different number of pens such that no two persons have the same number of pens.

Now,

1. Two persons are junior to Z. It means Z is a Manager.

2. The one who is just senior to the one who is Manager has 33 pens. It means CFO has 33 pens.

3. One designation lies between the one who has 33 pens and A. It means A is Clerk.

 

4. A is just senior to the one who has 45 pens. It means Peon has 45 pens.

5. There is one designation between the Manager and R. It means R can be either CEO or Peon.

Case I

 

Case II

 

6. A has 11 pens more and 9 pens more than W and Q respectively. It means A = W+11 and A = Q+9. W+11 = Q+9. Q-W = 2. Q has more pens than W. In case I, Q has 45 pens and W has 33 pens. But 45-33 is not equal to 2. So, the case I get eliminated. In case II, again there are two possibilities:

Possibility I - W have 33 pens. So Q will have 35 pens and A will have 44 pens.

Possibility II - Q has 33 pens so W will have 31 pens and A will have 42 pens.

Case II (a)

 

Case II (b)

 

7. The difference in the number of pens between R and Z is 14 and Z has the least number of pens. So, R – 14 = Z. Z has 45-14 =31 pens. But no two persons can have the same number of pens. So, case II (b) gets eliminated as W also has 31 pens in it. 

The final arrangement is -

 

Hence, The correct answer is CEO-Q-35.

Given:

5 designations - CEO, CFO, Manager, Clerk, and Peon

CEO is the senior most and Peon is the juniormost person. 

They have a different number of pens such that no two persons have the same number of pens.

Now,

1. Two persons are junior to Z. It means Z is a Manager.

2. The one who is just senior to the one who is Manager has 33 pens. It means CFO has 33 pens.

3. One designation lies between the one who has 33 pens and A. It means A is Clerk.

 

4. A is just senior to the one who has 45 pens. It means Peon has 45 pens.

5. There is one designation between the Manager and R. It means R can be either CEO or Peon.

Case I

 

Case II

 

6. A has 11 pens more and 9 pens more than W and Q respectively. It means A = W+11 and A = Q+9. W+11 = Q+9. Q-W = 2. Q has more pens than W. In case I, Q has 45 pens and W has 33 pens. But 45-33 is not equal to 2. So, the case I get eliminated. In case II, again there are two possibilities:

Possibility I - W have 33 pens. So Q will have 35 pens and A will have 44 pens.

Possibility II - Q has 33 pens so W will have 31 pens and A will have 42 pens.

Case II (a)

 

Case II (b)

 

7. The difference in the number of pens between R and Z is 14 and Z has the least number of pens. So, R – 14 = Z. Z has 45-14 =31 pens. But no two persons can have the same number of pens. So, case II (b) gets eliminated as W also has 31 pens in it. 

The final arrangement is -

 

Hence, The correct answer is Three.

Given:

5 designations - CEO, CFO, Manager, Clerk, and Peon

CEO is the senior most and Peon is the juniormost person. 

They have a different number of pens such that no two persons have the same number of pens.

Now,

1. Two persons are junior to Z. It means Z is a Manager.

2. The one who is just senior to the one who is Manager has 33 pens. It means CFO has 33 pens.

3. One designation lies between the one who has 33 pens and A. It means A is Clerk.

 

4. A is just senior to the one who has 45 pens. It means Peon has 45 pens.

5. There is one designation between the Manager and R. It means R can be either CEO or Peon.

Case I

 

Case II

 

6. A has 11 pens more and 9 pens more than W and Q respectively. It means A = W+11 and A = Q+9. W+11 = Q+9. Q-W = 2. Q has more pens than W. In case I, Q has 45 pens and W has 33 pens. But 45-33 is not equal to 2. So, the case I get eliminated. In case II, again there are two possibilities:

Possibility I - W have 33 pens. So Q will have 35 pens and A will have 44 pens.

Possibility II - Q has 33 pens so W will have 31 pens and A will have 42 pens.

Case II (a)

 

Case II (b)

 

7. The difference in the number of pens between R and Z is 14 and Z has the least number of pens. So, R – 14 = Z. Z has 45-14 =31 pens. But no two persons can have the same number of pens. So, case II (b) gets eliminated as W also has 31 pens in it. 

The final arrangement is -

 

Hence, The correct answer is W.

Given:

5 designations - CEO, CFO, Manager, Clerk, and Peon

CEO is the senior most and Peon is the juniormost person. 

They have a different number of pens such that no two persons have the same number of pens.

Now,

1. Two persons are junior to Z. It means Z is a Manager.

2. The one who is just senior to the one who is Manager has 33 pens. It means CFO has 33 pens.

3. One designation lies between the one who has 33 pens and A. It means A is Clerk.

 

4. A is just senior to the one who has 45 pens. It means Peon has 45 pens.

5. There is one designation between the Manager and R. It means R can be either CEO or Peon.

Case I

 

Case II

 

6. A has 11 pens more and 9 pens more than W and Q respectively. It means A = W+11 and A = Q+9. W+11 = Q+9. Q-W = 2. Q has more pens than W. In case I, Q has 45 pens and W has 33 pens. But 45-33 is not equal to 2. So, the case I get eliminated. In case II, again there are two possibilities:

Possibility I - W have 33 pens. So Q will have 35 pens and A will have 44 pens.

Possibility II - Q has 33 pens so W will have 31 pens and A will have 42 pens.

Case II (a)

 

Case II (b)

 

7. The difference in the number of pens between R and Z is 14 and Z has the least number of pens. So, R – 14 = Z. Z has 45-14 =31 pens. But no two persons can have the same number of pens. So, case II (b) gets eliminated as W also has 31 pens in it. 

The final arrangement is -

 

Hence, The correct answer is 44.

Detailed solution will be provided soon.

Given word : REVOLUTION

Forward pair - None

Backward pair -4 - NO, IL, TU and OR.

Detailed solution will be provided soon.

Given 9 member in a family- F, G, H, I, J, K, L, M and N.

Three generations, two married couples. There is no single parent in the family. 

1. N is the daughter of F who has two children. F is the sister-in-law of I. N has a son.

So, F and N both are married. Because there is no single parent in the family.

2. J is the son of K and J doesn’t have a sister.

3. M is the only brother-in-law of J’s grandfather. G belongs to the first generation of the family. Also, L is G’s child. So, G is married. G is the grandfather of J and M is the only brother of F.

 

4. H is the only brother-in-law of N.

Gender of L is not known.

Relation between L and maternal uncle of N cannot be determined.

Detailed solution will be provided soon.

Given 9 member in a family- F, G, H, I, J, K, L, M and N.

Three generations, two married couples. There is no single parent in the family. 

1. N is the daughter of F who has two children. F is the sister-in-law of I. N has a son.

So, F and N both are married. Because there is no single parent in the family.

2. J is the son of K and J doesn’t have a sister.

3. M is the only brother-in-law of J’s grandfather. G belongs to the first generation of the family. Also, L is G’s child. So, G is married. G is the grandfather of J and M is the only brother of F.

4. H is the only brother-in-law of N.

If G does not have a brother, then I is the sister of G.

 I is the paternal aunt of H's sister-in-law N.

Detailed solution will be provided soon.

Given 9 member in a family- F, G, H, I, J, K, L, M and N.

Three generations, two married couples. There is no single parent in the family. 

1. N is the daughter of F who has two children. F is the sister-in-law of I. N has a son.

So, F and N both are married. Because there is no single parent in the family.

2. J is the son of K and J doesn’t have a sister.

3. M is the only brother-in-law of J’s grandfather. G belongs to the first generation of the family. Also, L is G’s child. So, G is married. G is the grandfather of J and M is the only brother of F.

 

4. H is the only brother-in-law of N.

If L is the daughter of G, we still can't find the gender of I.

Number of male members cannot be determined.

Given:- 

Row 1 – A, B, C, and D facing north but not necessarily in the same order.

Row 2 – P, Q, R, and S facing South but not necessarily in the same order.

8 cities - Delhi, Damascus, Tokyo, New York, London, Beijing, Dhaka, and Madrid, 

Now,

1. D sits second to the left of B and faces the person who is from New York. Here two possibilities exist:

2. More than one person sits between B and A. It means Case II gets eliminated as B sits at the extreme right end and A sits at the extreme left end of row 1. So, the remaining C sits between B and D.

3. S is sitting second to the right of Q and faces D who is from Damascus.

Case I -

4. Persons coming from London and Beijing sit adjacent to each other. They can be Q and his adjacent person or C and B.

5. The person who is from London sits second to the left of the person who is from Delhi. This is possible in Case I (a) only. So, Case I (b) gets eliminated.

6. P sits at one of the extreme ends of the row but does not face the person who is from Madrid. The remaining R sits between S and Q.

7. The person who is from Dhaka sits adjacent to the person who is from Madrid but not at the end of the row.  It means C is from Dhaka and B form Madrid. The remaining A is from Tokyo.

The final arrangement is as follows:

P faces the person who is from Tokyo.

The correct answer is P.

Given:- 

Row 1 – A, B, C, and D facing north but not necessarily in the same order.

Row 2 – P, Q, R, and S facing South but not necessarily in the same order.

8 cities - Delhi, Damascus, Tokyo, New York, London, Beijing, Dhaka, and Madrid, 

Now,

1. D sits second to the left of B and faces the person who is from New York. Here two possibilities exist:

2. More than one person sits between B and A. It means Case II gets eliminated as B sits at the extreme right end and A sits at the extreme left end of row 1. So, the remaining C sits between B and D.

3. S is sitting second to the right of Q and faces D who is from Damascus.

Case I -

4. Persons coming from London and Beijing sit adjacent to each other. They can be Q and his adjacent person or C and B.

5. The person who is from London sits second to the left of the person who is from Delhi. This is possible in Case I (a) only. So, Case I (b) gets eliminated.

Case I (a) -

6. P sits at one of the extreme ends of the row but does not face the person who is from Madrid. The remaining R sits between S and Q.

7. The person who is from Dhaka sits adjacent to the person who is from Madrid but not at the end of the row.  It means C is from Dhaka and B form Madrid. The remaining A is from Tokyo.

The final arrangement is as follows:

All the pairs have the second letter being the immediate neighbor of the person sitting opposite to the first letter of the pair except SB.

The correct answer is SB.

Given:- 

Row 1 – A, B, C, and D facing north but not necessarily in the same order.

Row 2 – P, Q, R, and S facing South but not necessarily in the same order.

8 cities - Delhi, Damascus, Tokyo, New York, London, Beijing, Dhaka, and Madrid, 

Now,

1. D sits second to the left of B and faces the person who is from New York. Here two possibilities exist:

2. More than one person sits between B and A. It means Case II gets eliminated as B sits at the extreme right end and A sits at the extreme left end of row 1. So, the remaining C sits between B and D.

3. S is sitting second to the right of Q and faces D who is from Damascus.

Case I -

4. Persons coming from London and Beijing sit adjacent to each other. They can be Q and his adjacent person or C and B.

5. The person who is from London sits second to the left of the person who is from Delhi. This is possible in Case I (a) only. So, Case I (b) gets eliminated.

Case I (a) -

6. P sits at one of the extreme ends of the row but does not face the person who is from Madrid. The remaining R sits between S and Q.

7. The person who is from Dhaka sits adjacent to the person who is from Madrid but not at the end of the row.  It means C is from Dhaka and B form Madrid. The remaining A is from Tokyo.

The final arrangement is as follows:

One person sit between the person from Damascus and Madrid.

The correct answer is 1.

Given:- 

Row 1 – A, B, C, and D facing north but not necessarily in the same order.

Row 2 – P, Q, R, and S facing South but not necessarily in the same order.

8 cities - Delhi, Damascus, Tokyo, New York, London, Beijing, Dhaka, and Madrid, 

Now,

1. D sits second to the left of B and faces the person who is from New York. Here two possibilities exist:

2. More than one person sits between B and A. It means Case II gets eliminated as B sits at the extreme right end and A sits at the extreme left end of row 1. So, the remaining C sits between B and D.

3. S is sitting second to the right of Q and faces D who is from Damascus.

Case I -

4. Persons coming from London and Beijing sit adjacent to each other. They can be Q and his adjacent person or C and B.

5. The person who is from London sits second to the left of the person who is from Delhi. This is possible in Case I (a) only. So, Case I (b) gets eliminated.

Case I (a) -

6. P sits at one of the extreme ends of the row but does not face the person who is from Madrid. The remaining R sits between S and Q.

7. The person who is from Dhaka sits adjacent to the person who is from Madrid but not at the end of the row.  It means C is from Dhaka and B form Madrid. The remaining A is from Tokyo.

The final arrangement is as follows:

D is sitting opposite to the person from New York

The correct answer is D.

Given:- 

Row 1 – A, B, C, and D facing north but not necessarily in the same order.

Row 2 – P, Q, R, and S facing South but not necessarily in the same order.

8 cities - Delhi, Damascus, Tokyo, New York, London, Beijing, Dhaka, and Madrid, 

Now,

1. D sits second to the left of B and faces the person who is from New York. Here two possibilities exist:

2. More than one person sits between B and A. It means Case II gets eliminated as B sits at the extreme right end and A sits at the extreme left end of row 1. So, the remaining C sits between B and D.

3. S is sitting second to the right of Q and faces D who is from Damascus.

Case I -

4. Persons coming from London and Beijing sit adjacent to each other. They can be Q and his adjacent person or C and B.

5. The person who is from London sits second to the left of the person who is from Delhi. This is possible in Case I (a) only. So, Case I (b) gets eliminated.

Case I (a) -

6. P sits at one of the extreme ends of the row but does not face the person who is from Madrid. The remaining R sits between S and Q.

7. The person who is from Dhaka sits adjacent to the person who is from Madrid but not at the end of the row.  It means C is from Dhaka and B form Madrid. The remaining A is from Tokyo.

The final arrangement is as follows:

D is from Damascus.

The correct answer is D is from Dhaka.