Reasoning PYQs

Eight people A, B, C, D, K, L, M, and N.

Four of them are sitting in Row-1 facing North.

Four are sitting in Row-2 facing South.

1- The one who likes Orange sits on one end of Row-1.

2- C likes black and sits immediately to M, who is facing the one who likes Orange.

3- One person is sitting between B and C.

 

Case-1

 

Case-2

 

4- Immediate neighbour of B faces D.

5- The one who likes Purple sits immediately to the right of D, who likes Blue colour.

6- Only one person is sitting between D and A.

 

Case-1

 Case-2

 

7- The one who likes Green sits immediately to the left of the one who likes Yellow.

8- K is an immediate neighbour of A.

 

Case-1

 

Case-2

 

9- Only one person sitting between K and L, who doesn't like either White or Purple.  So, case-2 gets eliminated.

So, the Final arrangement;

 

N likes Green colour.

Given: 67843624

digits less than 5 subtracted by one and digits greater than 5 added by one then,

 

So, Non repeated numbers are 8, 9, 2, 1.

Sum of 8+ 9+ 2+ 1= 20,

Hence,  20 is the sum of non repeated numbers.

1. Person A got last rank in class.

>>______> >> A

2) B got more marks than C. but he did not get Second rank in class. 

3) E got more marks than only A.

We have following cases.

Case l

B > C >______> _____> E > A

Case ll

B > __> C > __> E > A

Case III

>> B >  C > E > A

4) F was situated between D and B in class test ranking, and B score less than D.

Case l, II get eliminated.

D > F > B >  C > E > A

6. The Second highest person got 92 marks.so, F got 92 marks.

Hence, Two person got more marks than B.

1. Person A got last rank in class.

>>______> >> A

2) B got more marks than C. but he did not get Second rank in class. 

3) E got more marks than only A.

We have here two cases.

Case l

B > C >______> _____> E > A

Case ll

B > __> C > __> E > A

Case III

>> B >  C > E > A

4) F was situated between D and B in class test ranking, and B score less than D.

Case l, II get eliminated.

D > F > B >  C > E > A

6. The Second highest person got 92 marks.so, F got 92 marks.

Hence,  D got 93 marks possibly.

1. Person A got last rank in class.

>>______> >> A

2) B got more marks than C. but he did not get Second rank in class. 

3) E got more marks than only A.

We have here two cases.

Case l

B > C >______> _____> E > A

Case ll

B > __> C > __> E > A

Case III

>> B >  C > E > A

4) F was situated between D and B in class test ranking, and B score less than D.

Case l, II get eliminated.

D > F > B >  C > E > A

6. The Second highest person got 92 marks.so, F got 92 marks.

Hence, C's rank is four.

Given that:

There are seven persons, who were born in different years - 1961, 1968, 1972, 1988, 1993, 1999, and 2013. All the age calculations are done taking the base year as 2020.

So, their ages are:

 

1) D was born in a leap year but not in the year 1988.

So, here there are 3 leap years - 1968, 1972 and 1988 (all are divisible by 4)

So, 2 cases will generate D can born either in 1968 or 1972:

 

2) Only three persons were born between D and F.

3. C is the eldest person among them all.

So, C was born in 1961:

 

4) The difference between the ages of G and D is 4 years.

 

 

5) B was born in an odd-numbered year but not in 1993 nor he was the last one to be born.

Here, B was born in 1999, neither in 1993 nor in 2013 (at last).

6. The sum of the ages of A and F is a multiple of 13.

Here, age is 32 + 7 = 39 (39 is a multiple of 13).

So in there 2 statements Case I will be eliminate:

Here we have case II:

 

E was born in the year 1993.

Given that:

There are seven persons, who were born in different years - 1961, 1968, 1972, 1988, 1993, 1999, and 2013. All the age calculations are done taking the base year as 2020.

So, their ages are:

 

1) D was born in a leap year but not in the year 1988.

So, here there are 3 leap years - 1968, 1972 and 1988 (all are divisible by 4)

So, 2 cases will generate D can born either in 1968 or 1972:

 

2) Only three persons were born between D and F. 

3. C is the eldest person among them all.

So, C was born in 1961:

 

4) The difference between the ages of G and D is 4 years.

 

 

5) B was born in an odd-numbered year but not in 1993 nor he was the last one to be born.

Here, B was born in 1999, neither in 1993 nor in 2013 (at last).

6. The sum of the ages of A and F is a multiple of 13.

Here, age is 32 + 7 = 39 (39 is a multiple of 13).

So in there 2 statements Case I will be eliminate:

Here we have case II:

 

The sum of the ages of C and B is → 59 + 21 = 80 years.

Given that:

There are seven persons, who were born in different years - 1961, 1968, 1972, 1988, 1993, 1999, and 2013. All the age calculations are done taking the base year as 2020.

So, their ages are:

 

1) D was born in a leap year but not in the year 1988.

So, here there are 3 leap years - 1968, 1972 and 1988 (all are divisible by 4)

So, 2 cases will generate D can born either in 1968 or 1972:

 

2) Only three persons were born between D and F. 

3. C is the eldest person among them all.

So, C was born in 1961:

 

4) The difference between the ages of G and D is 4 years.

 

 

5) B was born in an odd-numbered year but not in 1993 nor he was the last one to be born.

Here, B was born in 1999, neither in 1993 nor in 2013 (at last).

6. The sum of the ages of A and F is a multiple of 13.

Here, age is 32 + 7 = 39 (39 is a multiple of 13).

So in there 2 statements Case I will be eliminate:

Here we have case II:

 

No one is born between G and D, so none.

Given that:

There are seven persons, who were born in different years - 1961, 1968, 1972, 1988, 1993, 1999, and 2013. All the age calculations are done taking the base year as 2020.

So, their ages are:

 

1) D was born in a leap year but not in the year 1988.

So, here there are 3 leap years - 1968, 1972 and 1988 (all are divisible by 4)

So, 2 cases will generate D can born either in 1968 or 1972:

 

2) Only three persons were born between D and F. 

3. C is the eldest person among them all.

So, C was born in 1961:

 

4) The difference between the ages of G and D is 4 years.

 

 

5) B was born in an odd-numbered year but not in 1993 nor he was the last one to be born.

Here, B was born in 1999, neither in 1993 nor in 2013 (at last).

6. The sum of the ages of A and F is a multiple of 13.

Here, age is 32 + 7 = 39 (39 is a multiple of 13).

So in there 2 statements Case I will be eliminate:

Here we have case II:

 

G does not belong to the group as G was born in the even - numbered years.

Given that:

There are seven persons, who were born in different years - 1961, 1968, 1972, 1988, 1993, 1999, and 2013. All the age calculations are done taking the base year as 2020.

So, their ages are:

 

1) D was born in a leap year but not in the year 1988.

So, here there are 3 leap years - 1968, 1972 and 1988 (all are divisible by 4)

So, 2 cases will generate D can born either in 1968 or 1972:

 

2) Only three persons were born between D and F. 

3. C is the eldest person among them all.

So, C was born in 1961:

 

4) The difference between the ages of G and D is 4 years.

 

 

5) B was born in an odd-numbered year but not in 1993 nor he was the last one to be born.

Here, B was born in 1999, neither in 1993 nor in 2013 (at last).

6. The sum of the ages of A and F is a multiple of 13.

Here, age is 32 + 7 = 39 (39 is a multiple of 13).

So in there 2 statements Case I will be eliminate:

Here we have case II:

 

B was born in 1999.

Given

Statements:

F = S ≥ G < V, Q > P ≥ X, F ≥ X, V ≤ M

On combining :  Q > P ≥  X ≤ F = S ≥ G < V ≤ M

I. M > G → True ( As M ≥ V > G is definitely true, Hence M > G is true )

II. S < Q → False ( As Q > P ≥  X ≤ F = S, So there is no direct relation between S and Q, Hence S < Q will be false.)

Hence, Only conclusion I follow.

Given statements : P > Q < R, R = S ≥ T, T ≤  U > V

On combining : P > Q < R = S ≥ T ≤ U > V

(I) S > P → False (as S = R > Q < P there is no direct relation given between the two, it might be a possibility but not definitely true, Hence false )

(II) U > R → False (as U ≥ T ≤ S = R there is no direct relation given between the two, it might be a possibility but not definitely true, Hence false ).

Hence, Neither I nor  II follows.

**Given

Statements:

**  T > N < V = L ≤ W < K, V = H > I > F

On combining:   T > N < V = L ≤ W < K,  T > N < V = H > I > F

I. V > F → True ( As V = H > I > F so V > F is true )

II. T > H → False ( As T > N < V = H > I > F no direct relation is given between the two, so it is possibility but not definitely true Hence T > H is false)

Only I follow.

Persons: A, B, C, E, F, G, H, K and M.

1. At least six persons buy books after H.
2. Two persons buy books between H and C. 

3. M buys book immediately after F and immediately before E. 4. Not more than two persons buy books between C and E.

5. A buys book before G and after H. 6. G is not the last one to buy book.

7. Less than three persons buy books between G and B. 8. B buy book before G but not at the first. 9. So Case 2, 3, 4 and 5  is eliminated.

The final arrangement is,

Hence**, M is the second last person to buy a book.**

Persons: A, B, C, E, F, G, H, K and M.

1. At least six persons buy books after H.
2. Two persons buy books between H and C. 

3. M buys book immediately after F and immediately before E. 4. Not more than two persons buy books between C and E.

5. A buys book before G and after H. 6. G is not the last one to buy book.

7. Less than three persons buy books between G and B. 8. B buy book before G but not at the first. 9. So Case 2, 3, 4 and 5  is eliminated.

The final arrangement is,

Hence, six persons buy books between B and E.

Persons: A, B, C, E, F, G, H, K and M.

1. At least six persons buy books after H.
2. Two persons buy books between H and C. 

3. M buys book immediately after F and immediately before E. 4. Not more than two persons buy books between C and E.

5. A buys book before G and after H. 6. G is not the last one to buy book.

7. Less than three persons buy books between G and B. 8. B buy book before G but not at the first. 9. So Case 2, 3, 4 and 5  is eliminated.

The final arrangement is,

Hence, K is the first person to buy a book.

Persons: A, B, C, E, F, G, H, K and M.

1. At least six persons buy books after H.
2. Two persons buy books between H and C. 

3. M buys book immediately after F and immediately before E. 4. Not more than two persons buy books between C and E.

5. A buys book before G and after H. 6. G is not the last one to buy book.

7. Less than three persons buy books between G and B. 8. B buy book before G but not at the first. 9. So Case 2, 3, 4 and 5  is eliminated.

The final arrangement is,

If F and K interchange their position

Hence, if F and K interchange their position, seven persons buy books between F and E.

Persons: A, B, C, E, F, G, H, K and M.

1. At least six persons buy books after H.
2. Two persons buy books between H and C. 

3. M buys book immediately after F and immediately before E. 4. Not more than two persons buy books between C and E.

5. A buys book before G and after H. 6. G is not the last one to buy book.

7. Less than three persons buy books between G and B. 8. B buy book before G but not at the first. 9. So Case 2, 3, 4 and 5  is eliminated.

The final arrangement is,

Every pair except AE has two persons between them. But AE has four persons in between them.

Hence, AE is the odd one out.

Given: 6953265

By adding 1 in the even digits and subtracting 1 from the odd digits, we will get,

 

Here can clearly says that 8, 2 and 3 are not repeated. Therefore, sum of the number = 8+2+3=13

Hence "13" is correct answer.

Given

Statement:

'for the victory sign' is coded as 'si vi th fo', 

‘empty the apartment now’ is coded as ‘no ap th em’

‘now for the finale’ is coded as ‘fi th fo no’

‘for empty sign victory’ is coded as ‘vi si em fo’

We get:

for - fo

the - th

empty - em

now – no

The codes for ‘apartment’ and ‘finale’ is determined by elimination, i.e. all the other codes in the sentence are determined:

apartment - ap

finale – fi

We can not clearly determine the codes for ‘victory’ and ‘sign’:

victory – vi/si

sign – si/vi

The code for 'Now' is no.