Reasoning PYQs

1) Sia sits third to the right of Tulsi. Tulsi faces North. One person is sitting between Ana and Sia. Ana is not an immediate neighbor of Tulsi. 

2) One person sits between Tulsi and Diru. Diru and Jasu are immediately left of each other. 

3) Resham sits immediately left of Sia. Chanda sits second to the left of Resham. Sia and Resham face opposite directions.

Case 1, Case 2, and Case 3 do not satisfy the given conditions. So, Case 1, Case 2, Case 3 is eliminated.

4) Jasu and Chanda face in the same direction. The person who sits at extreme end faces opposite directions to each other.

5. Immediate neighbors of Golu face the same direction. This condition is not satisfied by Case 4(a). So, Case 4(a) is eliminated. Jasu sits to the right of Golu.

Hence, the one who sits second to the left of Ana(Sia) sits on the immediate right of Chanda.

1) Sia sits third to the right of Tulsi. Tulsi faces North. One person is sitting between Ana and Sia. Ana is not an immediate neighbor of Tulsi. 

2) One person sits between Tulsi and Diru. Diru and Jasu are immediately left of each other. 

3) Resham sits immediately left of Sia. Chanda sits second to the left of Resham. Sia and Resham face opposite directions.

Case 1, Case 2, and Case 3 do not satisfy the given conditions. So, Case 1, Case 2, Case 3 is eliminated.

4) Jasu and Chanda face in the same direction. The person who sits at extreme end faces opposite directions to each other.

5. Immediate neighbors of Golu face the same direction. This condition is not satisfied by Case 4(a). So, Case 4(a) is eliminated. Jasu sits to the right of Golu.

 

Hence, One person sits between Jasu and Golu.

1) Sia sits third to the right of Tulsi. Tulsi faces North. One person is sitting between Ana and Sia. Ana is not an immediate neighbor of Tulsi. 

2) One person sits between Tulsi and Diru. Diru and Jasu are immediately left of each other. 

3) Resham sits immediately left of Sia. Chanda sits second to the left of Resham. Sia and Resham face opposite directions.

Case 1, Case 2, and Case 3 do not satisfy the given conditions. So, Case 1, Case 2, Case 3 is eliminated.

4) Jasu and Chanda face in the same direction. The person who sits at extreme end faces opposite directions to each other.

5. Immediate neighbors of Golu face the same direction. This condition is not satisfied by Case 4(a). So, Case 4(a) is eliminated. Jasu sits to the right of Golu.

 

Hence, Diru and Ana sit at the extreme end of the row.

1) Only Param is taller than Tanu. Kiku is not the shortest. 

Case 1

Param > Tanu > ___ > ___ > Kiku > ____

Case 2

Param > Tanu > ___ > Kiku  > ___ > ____

Case 3

Param > Tanu > Kiku > ___ > ___ > ____

2) Raju's height is the average height of Lina and Param. Raju's height is 165 cm which is 2cm shorter than Sana's. 

Case 1

Param > Tanu > Sana (167) > Raju(165cm) > Kiku > Lina

Case 2

Param > Tanu > Sana(167cm) > Kiku  > Raju (165cm) > Lina

Case 3

Param > Tanu > Kiku > Sana(167 cm)> Raju (165 cm) > Lina 

3) Lina's height is 153 cm. Raju's height is not shorter than Kiku. This condition is not satisfied in Case 2 and Case 3. So, Case 2, and Case 3 are eliminated. 

The final arrangement is:

Param > Tanu > Sana (167) > Raju (165cm) > Kiku > Lina (153 cm)

Hence, Tanu is the second tallest person.

1) Only Param is taller than Tanu. Kiku is not the shortest. 

Case 1

Param > Tanu > ___ > ___ > Kiku > ____

Case 2

Param > Tanu > ___ > Kiku  > ___ > ____

Case 3

Param > Tanu > Kiku > ___ > ___ > ____

2) Raju's height is the average height of Lina and Param. Raju's height is 165 cm which is 2cm shorter than Sana's. 

Case 1

Param > Tanu > Sana (167) > Raju(165cm) > Kiku > Lina

Case 2

Param > Tanu > Sana(167cm) > Kiku  > Raju (165cm) > Lina

Case 3

Param > Tanu > Kiku > Sana(167 cm)> Raju (165 cm) > Lina 

3) Lina's height is 153 cm. Raju's height is not shorter than Kiku. This condition is not satisfied in Case 2 and Case 3. So, Case 2, and Case 3 are eliminated. 

The final arrangement is:

Param > Tanu > Sana (167) > Raju (165cm) > Kiku > Lina (153 cm)

Hence, Lina is the shortest among all.

1) Only Param is taller than Tanu. Kiku is not the shortest. 

Case 1

Param > Tanu > ___ > ___ > Kiku > ____

Case 2

Param > Tanu > ___ > Kiku  > ___ > ____

Case 3

Param > Tanu > Kiku > ___ > ___ > ____

2) Raju's height is the average height of Lina and Param. Raju's height is 165 cm which is 2cm shorter than Sana's. 

Case 1

Param > Tanu > Sana (167) > Raju(165cm) > Kiku > Lina

Case 2

Param > Tanu > Sana(167cm) > Kiku  > Raju (165cm) > Lina

Case 3

Param > Tanu > Kiku > Sana(167 cm)> Raju (165 cm) > Lina 

3) Lina's height is 153 cm. Raju's height is not shorter than Kiku. This condition is not satisfied in Case 2 and Case 3. So, Case 2, and Case 3 are eliminated. 

The final arrangement is:

Param > Tanu > Sana (167) > Raju (165cm) > Kiku > Lina (153 cm)

The height of Kiku is between 165 cm and 153 cm.

Hence, 157cm could be the possible height of Kiku.

Logic: First the vowels are arranged in alphabetical arrangement from the left side then the consonants are placed in alphabetical order after the vowels.

Vowels: A, E, I, O, U

DOCTOR → OOCDRT

BETTER → EEBRTT

RABBIT → AIBBRT

Hence,  “RABBIT” will be written in the same language as "AIBBRT".

Given Word: RELATIVE

Forward Pairs: EI, AE, TV

Backward Pair: IL

Hence, Four is the correct option.

Statement:

A > B = C = D ≤ E > F > G ≥ H

Conclusion:

I. B ≤ E → True (B = C = D ≤ E)

II. F > H → True ( F > G ≥ H)

Hence, Both I and II are true.

Statement:

Q > E < N < J ≤ O = R; I > N ≥ U > B

Conclusion:

I. J > I → False (N < J,  I > N. No relation between J and I )

II. U < O → True (N ≥ U,  N < J ≤ O, So, U < O)

Hence, Only II is true.

Statement:

P < Q ≤ R < S < T = Y > I ≥ O ≥ M

Conclusion:

I. I > M → False ( I ≥ O ≥ M, So, I ≥ M)

II. I = M → False ( I ≥ O ≥ M. So, I ≥ M)

As  I ≥ M, So, Either I > M or I = M.

Hence, Either I or II is true.

1) The one who has a performance in Bhuj has a performance immediately after the person who has a performance in Jaipur but not after Thursday. Jeet has a performance on Friday in Delhi. 

 

2) Only one person has a performance between Jeet and Azad. Two people have performances between Chirag and Ojas but Chirag does have performances in Jaipur or Bhuj.

 

3) Nimit has performance immediately after the one who has performance in Indore. One person has a performance in between Nimit and the person who has a performance in Gaya.

Case 1 and Case 3 do not satisfy the given conditions. So, Case 1 and Case 3 are eliminated.

 

4) Chirag does not have a performance in Gaya.

The final arrangement is: 

 

Hence, Dhruv's performance is on Saturday.

1) The one who has a performance in Bhuj has a performance immediately after the person who has a performance in Jaipur but not after Thursday. Jeet has a performance on Friday in Delhi. 

 

2) Only one person has a performance between Jeet and Azad. Two people have performances between Chirag and Ojas but Chirag does have performances in Jaipur or Bhuj.

 

3) Nimit has performance immediately after the one who has performance in Indore. One person has a performance in between Nimit and the person who has a performance in Gaya.

Case 1 and Case 3 do not satisfy the given conditions. So, Case 1 and Case 3 are eliminated.

 

4) Chirag does not have a performance in Gaya.

The final arrangement is: 

 

Hence, the one who has performed in Gaya performed two days after the day on which Nimit performed.

1) The one who has a performance in Bhuj has a performance immediately after the person who has a performance in Jaipur but not after Thursday. Jeet has a performance on Friday in Delhi. 

 

2) Only one person has a performance between Jeet and Azad. Two people have performances between Chirag and Ojas but Chirag does have performances in Jaipur or Bhuj.

 

3) Nimit has performance immediately after the one who has performance in Indore. One person has a performance in between Nimit and the person who has a performance in Gaya.

Case 1 and Case 3 do not satisfy the given conditions. So, Case 1 and Case 3 are eliminated.

 

4) Chirag does not have a performance in Gaya.

The final arrangement is: 

 

Hence, The number of days after the day Ojas performed is the same as the number of days before on which Azad performed.

1) The one who has a performance in Bhuj has a performance immediately after the person who has a performance in Jaipur but not after Thursday. Jeet has a performance on Friday in Delhi. 

 

2) Only one person has a performance between Jeet and Azad. Two people have performances between Chirag and Ojas but Chirag does have performances in Jaipur or Bhuj.

 

3) Nimit has performance immediately after the one who has performance in Indore. One person has a performance in between Nimit and the person who has a performance in Gaya.

Case 1 and Case 3 do not satisfy the given conditions. So, Case 1 and Case 3 are eliminated.

 

4) Chirag does not have a performance in Gaya.

The final arrangement is: 

 

Hence, One performance is between the days on which cities Indore and Bhuj are visited for the performance.

1) The one who has a performance in Bhuj has a performance immediately after the person who has a performance in Jaipur but not after Thursday. Jeet has a performance on Friday in Delhi. 

 

2) Only one person has a performance between Jeet and Azad. Two people have performances between Chirag and Ojas but Chirag does have performances in Jaipur or Bhuj.

 

3) Nimit has performance immediately after the one who has performance in Indore. One person has a performance in between Nimit and the person who has a performance in Gaya.

Case 1 and Case 3 do not satisfy the given conditions. So, Case 1 and Case 3 are eliminated.

 

4) Chirag does not have a performance in Gaya.

The final arrangement is: 

 

Hence, Gaya is visited on Thursday for a performance.

According to the information given in the question we can draw the figure given below: 

 

AD = BC = 8m

Hence, the shortest distance between A and D is 8m.

1) Z is on the Mechanical Engineering team. U is neither with Z nor in the Aeronautical engineering team. U and R are in the same team but not in the team of W. 

 

2) T and Y belong to the same team but not to the team of Z and W. T does not belong to the Aeronautical team. 

 

3)  S is in the group in which either W or U. The group to which U belongs already has four members. So, S belongs to the group of W.

 

4) V and Y are not in the same team. V belongs to the same team as S. In Case 1, V will belong to the Mechanical Team but then the condition that there are not less than two people in a team will be violated. The Aeronautical team would have one member. So, Case 1 is eliminated.

The final arrangement is:

 

Hence, Only I and III statements are true.

1) Z is on the Mechanical Engineering team. U is neither with Z nor in the Aeronautical engineering team. U and R are in the same team but not in the team of W. 

 

2) T and Y belong to the same team but not to the team of Z and W. T does not belong to the Aeronautical team. 

 

3)  S is in the group in which either W or U. The group to which U belongs already has four members. So, S belongs to the group of W.

 

4) V and Y are not in the same team. V belongs to the same team as S. In Case 1, V will belong to the Mechanical Team but then the condition that there are not less than two people in a team will be violated. The Aeronautical team would have one member. So, Case 1 is eliminated.

The final arrangement is:

 

Hence, V-Aeronautical is the correct combination.

1) Z is on the Mechanical Engineering team. U is neither with Z nor in the Aeronautical engineering team. U and R are in the same team but not in the team of W. 

 

2) T and Y belong to the same team but not to the team of Z and W. T does not belong to the Aeronautical team. 

 

3)  S is in the group in which either W or U. The group to which U belongs already has four members. So, S belongs to the group of W.

 

4) V and Y are not in the same team. V belongs to the same team as S. In Case 1, V will belong to the Mechanical Team but then the condition that there are not less than two people in a team will be violated. The Aeronautical team would have one member. So, Case 1 is eliminated.

The final arrangement is:

 

Hence, T belongs to Electrical Engineering.