Reasoning PYQs

Given: Nine persons — R, S, T, U, V, W, X, Y and Z — sit around a circular table facing the centre, but not necessarily in the same order.

1. U sits fourth to the left of S.
2. Two persons sit between S and R. 

Here, there are two cases, i.e. Case 1 and case 2. 3. V sits fourth to the right of R. 4. Two persons sit between V and Y. 5. Y is not immediate neighbour of R. 6. Two persons sit between Y and W. 7. X sits third to the left of T. 8. Z is not immediate neighbour of T.

Case 1 gets eliminated because there is no place for A. Hence, the final arragement:

Y is seventh to the left of X.

Hence, the correct answer is ‘Seventh to the left’.

Given: Nine persons — R, S, T, U, V, W, X, Y and Z — sit around a circular table facing the centre, but not necessarily in the same order.

1. U sits fourth to the left of S.
2. Two persons sit between S and R. 

Here, there are two cases, i.e. Case 1 and case 2. 3. V sits fourth to the right of R. 4. Two persons sit between V and Y. 5. Y is not immediate neighbour of R. 6. Two persons sit between Y and W. 7. X sits third to the left of T. 8. Z is not immediate neighbour of T.

Case 1 gets eliminated because there is no place for A. Hence, the final arragement:

In R and U, only one person sits between them (when counted from either side).

Hence, the correct answer is ‘R and U’.

Given: Nine persons — R, S, T, U, V, W, X, Y and Z — sit around a circular table facing the centre, but not necessarily in the same order.

1. U sits fourth to the left of S.
2. Two persons sit between S and R. 

Here, there are two cases, i.e. Case 1 and case 2. 3. V sits fourth to the right of R. 4. Two persons sit between V and Y. 5. Y is not immediate neighbour of R. 6. Two persons sit between Y and W. 7. X sits third to the left of T. 8. Z is not immediate neighbour of T.

Case 1 gets eliminated because there is no place for A. Hence, the final arragement:

In VXS, first person sits immediate left of the second person and second person sits immediate left of third person.

Hence, the correct answer is ‘VXS’.

Given: Nine persons — R, S, T, U, V, W, X, Y and Z — sit around a circular table facing the centre, but not necessarily in the same order.

1. U sits fourth to the left of S.
2. Two persons sit between S and R. 

Here, there are two cases, i.e. Case 1 and case 2. 3. V sits fourth to the right of R. 4. Two persons sit between V and Y. 5. Y is not immediate neighbour of R. 6. Two persons sit between Y and W. 7. X sits third to the left of T. 8. Z is not immediate neighbour of T.

Case 1 gets eliminated because there is no place for A. Hence, the final arragement:

The first person sits immediate right of the second person. So, X is related to V.

Hence, the correct answer is ‘V’.

Given: Nine persons — R, S, T, U, V, W, X, Y and Z — sit around a circular table facing the centre, but not necessarily in the same order.

1. U sits fourth to the left of S.
2. Two persons sit between S and R. 

Here, there are two cases, i.e. Case 1 and case 2. 3. V sits fourth to the right of R. 4. Two persons sit between V and Y. 5. Y is not immediate neighbour of R. 6. Two persons sit between Y and W. 7. X sits third to the left of T. 8. Z is not immediate neighbour of T.

Case 1 gets eliminated because there is no place for A. Hence, the final arragement:

Four persons sit between Z and T, when counted anti-clockwise from Z.

Hence, the correct answer is ‘Four’.

Given: Seven boxes—T, U, V, W, X, Y and Z —are stacked one above the other but not necessarily in the same order.

Each box is painted in a different colour, namely Red, Blue, Green, Yellow, Black, White and Pink.

1. Box T is kept five boxes below box W.
2. Box Z is kept immediately below green colour box.
3. Green colour box is kept two boxes below box W.
4. More than one box is kept between box Z and red box. 

Here, there are two cases, i.e. Case 1 and case 2.

 

5. Three boxes are kept between red box and box V.
6. Box V is not of green colour.
7. Box V is kept above pink box.
8. As many boxes are kept below pink box as above white box.
9. Box U is kept above black box but below white box. 
10. Neither box Z nor box V is of black colour. 

Case 2 gets eliminated because there is no place for black colour. 

 

11. Yellow box is kept two boxes below box Y. So, the final arrangement:

 

If Box W is related to green colour and in the same way box V is related to black colour then Box Z is related to Pink colour.

Hence, the correct answer is ‘Pink’.

Given: Seven boxes—T, U, V, W, X, Y and Z —are stacked one above the other but not necessarily in the same order.

Each box is painted in a different colour, namely Red, Blue, Green, Yellow, Black, White and Pink.

1. Box T is kept five boxes below box W.
2. Box Z is kept immediately below green colour box.
3. Green colour box is kept two boxes below box W.
4. More than one box is kept between box Z and red box. 

Here, there are two cases, i.e. Case 1 and case 2.

 

5. Three boxes are kept between red box and box V.
6. Box V is not of green colour.
7. Box V is kept above pink box.
8. As many boxes are kept below pink box as above white box.
9. Box U is kept above black box but below white box. 
10. Neither box Z nor box V is of black colour. 

Case 2 gets eliminated because there is no place for black colour. 

 

11. Yellow box is kept two boxes below box Y. So, the final arrangement:

 

Four boxes are kept between the red box and Box T.

Hence, the correct answer is ‘Four’.

Given: Seven boxes—T, U, V, W, X, Y and Z —are stacked one above the other but not necessarily in the same order.

Each box is painted in a different colour, namely Red, Blue, Green, Yellow, Black, White and Pink.

1. Box T is kept five boxes below box W.
2. Box Z is kept immediately below green colour box.
3. Green colour box is kept two boxes below box W.
4. More than one box is kept between box Z and red box. 

Here, there are two cases, i.e. Case 1 and case 2.

 

5. Three boxes are kept between red box and box V.
6. Box V is not of green colour.
7. Box V is kept above pink box.
8. As many boxes are kept below pink box as above white box.
9. Box U is kept above black box but below white box. 
10. Neither box Z nor box V is of black colour. 

Case 2 gets eliminated because there is no place for black colour. 

 

11. Yellow box is kept two boxes below box Y. So, the final arrangement:

 

Box Y is of White colour.

Hence, the correct answer is ‘White’.

Given: Seven boxes—T, U, V, W, X, Y and Z —are stacked one above the other but not necessarily in the same order.

Each box is painted in a different colour, namely Red, Blue, Green, Yellow, Black, White and Pink.

1. Box T is kept five boxes below box W.
2. Box Z is kept immediately below green colour box.
3. Green colour box is kept two boxes below box W.
4. More than one box is kept between box Z and red box. 

Here, there are two cases, i.e. Case 1 and case 2.

 

5. Three boxes are kept between red box and box V.
6. Box V is not of green colour.
7. Box V is kept above pink box.
8. As many boxes are kept below pink box as above white box.
9. Box U is kept above black box but below white box. 
10. Neither box Z nor box V is of black colour. 

Case 2 gets eliminated because there is no place for black colour. 

 

11. Yellow box is kept two boxes below box Y. So, the final arrangement:

 

Box V is coloured blue.

Hence, the correct answer is ‘Box V’.

Given: Seven boxes—T, U, V, W, X, Y and Z —are stacked one above the other but not necessarily in the same order.

Each box is painted in a different colour, namely Red, Blue, Green, Yellow, Black, White and Pink.

1. Box T is kept five boxes below box W.
2. Box Z is kept immediately below green colour box.
3. Green colour box is kept two boxes below box W.
4. More than one box is kept between box Z and red box. 

Here, there are two cases, i.e. Case 1 and case 2.

 

5. Three boxes are kept between red box and box V.
6. Box V is not of green colour.
7. Box V is kept above pink box.
8. As many boxes are kept below pink box as above white box.
9. Box U is kept above black box but below white box. 
10. Neither box Z nor box V is of black colour. 

Case 2 gets eliminated because there is no place for black colour. 

 

11. Yellow box is kept two boxes below box Y. So, the final arrangement:

 

Yellow box is kept three boxes above box X.

Hence, the correct answer is ‘Yellow box’.

The pattern for the code is as follows,

Here, the letters are codded alphabetically opposite.

Similarly,

Hence, the code for ‘EYEBALL’ is ‘VVBYOZO’.

Given: Nine persons – R, S, T, U, V, W, X, Y and Z– hold nine different designations in an organization, namely – Chairman, Managing Director (MD), Chief Executive Officer (CEO), Chief Operating Officer (COO), General Manager (GM), Senior Manager (SM), Manager, Assistant Manager (AM) and Executive. The given designations are in descending order of hierarchy where Chairman is the senior-most designation while Executive is the junior-most.

1. W is designated senior to COO.
2. More than four persons are designated between W and S.
3. S is designated senior to R.
4. Two persons are designated between R and U. 

Here, there are four cases, i.e. Case 1, case 2, case 3 and case 4.

 

5. The number of persons designated senior to U is one less than the number of persons designated junior to T.
6. One person is designated between T and Y.
7. Z is designated two persons senior to T but is not the senior-most person. 

Case 4 gets eliminated because there is no space left for Z.

 

8. More than three persons are designated Z and X.

Cases 1 and 3 get eliminated because there is no place for A. So, the final arrangement:

 

I. Less than three persons are designated between Y and W (False)

II. Z is designated senior to CEO (True)

III. V is designated three persons junior to W (False)

Hence, the correct answer is ‘Both I and III’.

Given: Nine persons – R, S, T, U, V, W, X, Y and Z– hold nine different designations in an organization, namely – Chairman, Managing Director (MD), Chief Executive Officer (CEO), Chief Operating Officer (COO), General Manager (GM), Senior Manager (SM), Manager, Assistant Manager (AM) and Executive. The given designations are in descending order of hierarchy where Chairman is the senior-most designation while Executive is the junior-most.

1. W is designated senior to COO.
2. More than four persons are designated between W and S.
3. S is designated senior to R.
4. Two persons are designated between R and U. 

Here, there are four cases, i.e. Case 1, case 2, case 3 and case 4.

 

5. The number of persons designated senior to U is one less than the number of persons designated junior to T.
6. One person is designated between T and Y.
7. Z is designated two persons senior to T but is not the senior-most person. 

Case 4 gets eliminated because there is no space left for Z.

 

8. More than three persons are designated Z and X.

Cases 1 and 3 get eliminated because there is no place for A. So, the final arrangement:

 

The position of no person remains unchanged.

Hence, the correct answer is ‘None’.

Given: Nine persons – R, S, T, U, V, W, X, Y and Z– hold nine different designations in an organization, namely – Chairman, Managing Director (MD), Chief Executive Officer (CEO), Chief Operating Officer (COO), General Manager (GM), Senior Manager (SM), Manager, Assistant Manager (AM) and Executive. The given designations are in descending order of hierarchy where Chairman is the senior-most designation while Executive is the junior-most.

1. W is designated senior to COO.
2. More than four persons are designated between W and S.
3. S is designated senior to R.
4. Two persons are designated between R and U. 

Here, there are four cases, i.e. Case 1, case 2, case 3 and case 4.

 

5. The number of persons designated senior to U is one less than the number of persons designated junior to T.
6. One person is designated between T and Y.
7. Z is designated two persons senior to T but is not the senior-most person. 

Case 4 gets eliminated because there is no space left for Z.

 

8. More than three persons are designated Z and X.

Cases 1 and 3 get eliminated because there is no place for A. So, the final arrangement:

 

Six persons are junior to the one who is designated two persons senior to U.

Hence, the correct answer is ‘Six’.

Given: Nine persons – R, S, T, U, V, W, X, Y and Z– hold nine different designations in an organization, namely – Chairman, Managing Director (MD), Chief Executive Officer (CEO), Chief Operating Officer (COO), General Manager (GM), Senior Manager (SM), Manager, Assistant Manager (AM) and Executive. The given designations are in descending order of hierarchy where Chairman is the senior-most designation while Executive is the junior-most.

1. W is designated senior to COO.
2. More than four persons are designated between W and S.
3. S is designated senior to R.
4. Two persons are designated between R and U. 

Here, there are four cases, i.e. Case 1, case 2, case 3 and case 4.

 

5. The number of persons designated senior to U is one less than the number of persons designated junior to T.
6. One person is designated between T and Y.
7. Z is designated two persons senior to T but is not the senior-most person. 

Case 4 gets eliminated because there is no space left for Z.

 

8. More than three persons are designated Z and X.

Cases 1 and 3 get eliminated because there is no place for A. So, the final arrangement:

 

U is designated as General Manager

Hence, the correct answer is ‘U’.

Given: Nine persons – R, S, T, U, V, W, X, Y and Z– hold nine different designations in an organization, namely – Chairman, Managing Director (MD), Chief Executive Officer (CEO), Chief Operating Officer (COO), General Manager (GM), Senior Manager (SM), Manager, Assistant Manager (AM) and Executive. The given designations are in descending order of hierarchy where Chairman is the senior-most designation while Executive is the junior-most.

1. W is designated senior to COO.
2. More than four persons are designated between W and S.
3. S is designated senior to R.
4. Two persons are designated between R and U. 

Here, there are four cases, i.e. Case 1, case 2, case 3 and case 4.

 

5. The number of persons designated senior to U is one less than the number of persons designated junior to T.
6. One person is designated between T and Y.
7. Z is designated two persons senior to T but is not the senior-most person. 

Case 4 gets eliminated because there is no space left for Z.

 

8. More than three persons are designated Z and X.

Cases 1 and 3 get eliminated because there is no place for A. So, the final arrangement:

 

Y – SM – is the correct combination.

Hence, the correct answer is ‘Y – SM’.

**Given

Statements:

** K > S > A ≤ P, Y < T > P, U = Z > K

On combining: U = Z > K > S > A ≤ P < T > Y

Conclusions:

I. A < P → False (As A ≤ P, so it is false)

II. A = P → False (As A ≤ P, so it is false)

III. A < T → True (As A ≤ P < T → A < T, so it is true)

Here, A ≤ P → A < P or A = P, so Either I or II is true.

Hence, Either I or II and III is correct.

Key Points

Conditions for Either - or

I. Subject and predicate should be the same

II. Both the individual conclusions must be false

**Given

Statements:

** P < I, B = A, K ≥ B, I < N < T ≥  K

On combining: P < I < N < T ≥ K ≥ B = A

Conclusions:

I. T > P → True (As P < I < N < T → T > P).

II. T > A → False (As T ≥ K ≥ B = A → T ≥ A, which means either T > A or T = A. Here, no clear relation between T and A can be determined)

III. A = T → False (As T ≥ K ≥ B = A → T ≥ A, which means either T > A or T = A. Here, no clear relation between T and A can be determined)

Here, Conclusion II and Conclusion III both are complementary to each other, So it is "Either or" case.

Hence, Either Conclusion II or III and Conclusion I is correct.

**Given

Statement:

** G > X = Z ≤ T < Q = E > S = P ≤ J

Conclusions:

I. G > Z → False (as G > X = Z)

II. J > X → False (as X = Z ≤ T < Q = E > S = P ≤ J → no clear relation between J and X can be determined)

III. S < Q → False (as Q = E > S)

Hence, Both conclusion I and III is true.

Given: Seven persons—A, B, C, D, E, F and G—live on different floors of a seven-floor building, numbered one to seven from bottom to top.

Each person likes a different fruit—Apple, Guava, Litchi, Watermelon, Mango, Kiwi and Grapes, but not necessarily in the same order.

1. Four floors are there between the floor on which E and the one who likes Mango lives.
2. E lives immediately below the one who likes Litchi.
3. The one who likes Litchi lives two floors above D. 

Here, there are two cases, i.e. Case 1 and case 2.

 

4. The number of floors below the floor of D is one less than the number of floors above the floor of the one who likes Grapes.
5. One floor is there between the floor of C and the one who likes Grapes.
6. C lives above the one who likes Apple.
7. D doesn’t like Apple. 

 

8. B lives two floors above G but doesn’t like Mango.
9. A lives three floors above the floor of the one who likes Kiwi. 
10. The one who likes Guava lives below the floor of the one who likes Kiwi.

Case 1 gets eliminated because there is no place for Guava. So, the final arrangement:

 

G likes Litchi.

Hence, the correct answer is ‘G’.