Reasoning PYQs

1. Box A was kept two places below of box B.

2. Only one box was kept between B and C.

 

3) Box D kept below box E but above box A.

4. Box E neither kept at odd-numbered stack nor at the topmost position. So, case 1 and case 3 get eliminated.

5. At most one box was kept between box F and D.

 

6. Box F kept below of box G but above box H. So, case 4 gets eliminate here.

 

So, the final arrangement:

 

Hence, G is at the topmost position.

1. Box A was kept two places below of box B.

2. Only one box was kept between B and C.

 

3) Box D kept below box E but above box A.

4. Box E neither kept at odd-numbered stack nor at the topmost position. So, case 1 and case 3 get eliminated.

5. At most one box was kept between box F and D.

 

6. Box F kept below of box G but above box H. So, case 4 gets eliminate here.

 

So, the final arrangement:

 

Hence, Box A is kept 2^nd to the above of box H.

1. Box A was kept two places below of box B.

2. Only one box was kept between B and C.

 

3) Box D kept below box E but above box A.

4. Box E neither kept at odd-numbered stack nor at the topmost position. So, case 1 and case 3 get eliminated.

5. At most one box was kept between box F and D.

 

6. Box F kept below of box G but above box H. So, case 4 gets eliminate here.

 

So, the final arrangement:

 

Hence, box C is 5^th above with respect to box F.

1. Box A was kept two places below of box B.

2. Only one box was kept between B and C.

 

3) Box D kept below box E but above box A.

4. Box E neither kept at odd-numbered stack nor at the topmost position. So, case 1 and case 3 get eliminated.

5. At most one box was kept between box F and D.

 

6. Box F kept below of box G but above box H. So, case 4 gets eliminate here.

 

So, the final arrangement:

 

Hence, B is odd in the group because B is at odd box and remaining are kept at even box

If the digits are arranged in ascending order from left to right within the numbers, then we get:

992 → 299

986 → 689

867 → 678

756 → 567

886 → 688

Arranging the newly formed numbers: 299 < 567 < 678 < 688 < 689

Thus, 567 is the second-lowest among the newly formed numbers, and its original form was 756.

Hence, 756 will be the second-lowest number.

If 2 is subtracted from the odd digits within the numbers, then we get:

992 → 772

986 → 786

867 → 865

756 → 536

886 → 886

Arranging the newly formed numbers: 536 < 772 < 786 < 865 < 886

Hence, 986 will be the third-highest number.

If the digits are arranged in descending order from left to right within the numbers, then we get:

992 → 992

986 → 986

867 → 876

756 → 765

886 → 886

Thus, 992, 876, 986, and 886 are the numbers that are divisible by 2.

Hence, four numbers thus formed are divisible by 2.

Given Numbers   992  986  886  868  756

If the numbers are arranged in ascending order from right to left, then we get:

992 > 986 > 886 > 868 > 756

Third Number from the left 886

Second to the left of 886 is 992

Third digit of the number 992 is 2

Hence, 2 is the third digit of the number that is placed second to the left of the number which is third from the left end in the new arrangement.

If the first and the second digits are interchanged within the numbers, then we get:

992 → 992

986 → 896

867 → 687

756 → 576

886 → 886

Arranging the numbers thus formed: 576 < 687 < 886 < 896 < 992

Thus, among the newly formed numbers, 896 is the second-highest whose original form was 986.

Hence, 986 will be the second-highest number.

From the given instructions: 

1. Four people sit between F and G, but none of them sits at an extreme ends. So, here we hace two cases, 

 

2. E sits third to the left of F. E is an immediate neighbour of J, who sits third from the right end. 

 

Here, Case 2 gets cancelled because E is not an immediate neighbour of J in Case 2. 

3. I is sitting adjacent to F. Here, we have one more case in Case 1 as Case 1(a). 

 

4. More than three people (more than three means minimum four) sit between L and K, who does not sit at an extreme end.  

 

Here, Case 1(a) is invalid because K cannot be at an extreme end. So, Case 1(a) gets cancelled. 

5. No two people who are immediate neighbours of each other faces in the same direction. 

So, Final Arrangement: 

 

I sits at the left end of the row.

From the given instructions: 

1. Four people sit between F and G, but none of them sits at an extreme ends. So, here we hace two cases, 

 

2. E sits third to the left of F. E is an immediate neighbour of J, who sits third from the right end. 

 

Here, Case 2 gets cancelled because E is not an immediate neighbour of J in Case 2. 

3. I is sitting adjacent to F. Here, we have one more case in Case 1 as Case 1(a). 

 

4. More than three people (more than three means minimum four) sit between L and K, who does not sit at an extreme end.  

 

Here, Case 1(a) is invalid because K cannot be at an extreme end. So, Case 1(a) gets cancelled. 

5. No two people who are immediate neighbours of each other faces in the same direction. 

So, Final Arrangement: 

 

Three people are sitting between K and G.

From the given instructions: 

1. Four people sit between F and G, but none of them sits at an extreme ends. So, here we hace two cases, 

 

2. E sits third to the left of F. E is an immediate neighbour of J, who sits third from the right end. 

 

Here, Case 2 gets cancelled because E is not an immediate neighbour of J in Case 2. 

3. I is sitting adjacent to F. Here, we have one more case in Case 1 as Case 1(a). 

 

4. More than three people (more than three means minimum four) sit between L and K, who does not sit at an extreme end.  

 

Here, Case 1(a) is invalid because K cannot be at an extreme end. So, Case 1(a) gets cancelled. 

5. No two people who are immediate neighbours of each other faces in the same direction. 

So, Final Arrangement: 

 

E sits second to the left of the one (G) who sits third to the left of H.

From the given instructions: 

1. Four people sit between F and G, but none of them sits at an extreme ends. So, here we hace two cases, 

 

2. E sits third to the left of F. E is an immediate neighbour of J, who sits third from the right end. 

 

Here, Case 2 gets cancelled because E is not an immediate neighbour of J in Case 2. 

3. I is sitting adjacent to F. Here, we have one more case in Case 1 as Case 1(a). 

 

4. More than three people (more than three means minimum four) sit between L and K, who does not sit at an extreme end.  

 

Here, Case 1(a) is invalid because K cannot be at an extreme end. So, Case 1(a) gets cancelled. 

5. No two people who are immediate neighbours of each other faces in the same direction. 

So, Final Arrangement: 

 

So, L is the odd one out.

From the given instructions: 

1. Four people sit between F and G, but none of them sits at an extreme ends. So, here we hace two cases, 

 

2. E sits third to the left of F. E is an immediate neighbour of J, who sits third from the right end. 

 

Here, Case 2 gets cancelled because E is not an immediate neighbour of J in Case 2. 

3. I is sitting adjacent to F. Here, we have one more case in Case 1 as Case 1(a). 

 

4. More than three people (more than three means minimum four) sit between L and K, who does not sit at an extreme end.  

 

Here, Case 1(a) is invalid because K cannot be at an extreme end. So, Case 1(a) gets cancelled. 

5. No two people who are immediate neighbours of each other faces in the same direction. 

So, Final Arrangement: 

 

Only statement III is false.

The least possible Venn diagram;

Conclusion: 

I. All Beds are Tables → False (as in the statement itself it is mentioned that No Tables are Beds There will be no relation between Bed and Tables.)

II. All Beds being Camels is a possibility → True (Bed can be enclosed inside the camels and as it is a possibility case it is possible) 

The possibility diagram is as,

Hence, only conclusion II follows.

The least possible Venn diagram for the given statements is as follows:

Conclusions:

I. No adventure is sports → False (as there is no direct relation given between adventure and sports, so no definite conclusion could be drawn)

II. Some adventure are sports → False (as there is no direct relation given between adventure and sports, so no definite conclusion could be drawn)

Both are complementary conclusions.

Hence Either I or II follows.

Key Points

Conditions for Either - Or 

1. Subject and predicate should be the same
2. Both the individual conclusions should be false
3. One conclusion should be positive and one conclusion should be negative
4. There should either one of the following pairs present in the conclusions

• All + Some not
• Some + No

The least possible Venn diagram is:

 

Conclusion:

I. Some transparent are spectacles → True (Only a few spectacles are transparent. It means some Spectacles are transparent and some spectacles are not transparent Hence, Some transparent are spectacles is true)

II. Some sunglasses are definitely not transparent → False (It is possible but not definite As we can see in the diagram below that some sunglass can be transparent but noting can be sure about remaining part).

Hence only conclusion I follow.

1. N sits fourth from one of the extreme ends.

2. Five persons are sitting between N and R. 

3. X sits fourth to the right of R and third to the left of M. 

4.Number of persons sit between N and P is equal to the number of persons sit between P and X.

5. Total number of persons are sitting between N and X is more than four.

Case II eliminated because in this case number of persons are sitting between N and X is not more than 4. 6. Number of persons sits between N and A is one more than the persons sit between A and P. 7. Q sits seventh to the left of P.

8.  As many persons sit to the right of M is one less than the total number of persons sit to the left of Q. 

Hence,17 persons are sitting in a row.

1. N sits fourth from one of the extreme ends.

2. Five persons are sitting between N and R. 

3. X sits fourth to the right of R and third to the left of M. 

4.Number of persons sit between N and P is equal to the number of persons sit between P and X.

5. Total number of persons are sitting between N and X is more than four.

Case II eliminated because in this case number of persons are sitting between N and X is not more than 4. 6. Number of persons sits between N and A is one more than the persons sit between A and P. 7. Q sits seventh to the left of P.

8.  As many persons sit to the right of M is one less than the total number of persons sit to the left of Q. 

Hence, R sits fourth to the left of X.

1. N sits fourth from one of the extreme ends.

2. Five persons are sitting between N and R. 

3. X sits fourth to the right of R and third to the left of M. 

4.Number of persons sit between N and P is equal to the number of persons sit between P and X.

5. Total number of persons are sitting between N and X is more than four.

Case II eliminated because in this case number of persons are sitting between N and X is not more than 4. 6. Number of persons sits between N and A is one more than the persons sit between A and P. 7. Q sits seventh to the left of P.

8.  As many persons sit to the right of M is one less than the total number of persons sit to the left of Q. 

Hence, Nine persons are sitting between N and X.