Reasoning PYQs

Given:- 296758427849

If 1 is added to all even digits and 1 is subtracted from all odd digits of the number then -

The 4^th digit from the right end is 6 and the 7^th digit from the left end is 5.

Sum = 6 + 5 = 11.

Hence, the correct answer is 11.

Given series: Left side   T R G S O I W P A Q D V E U X Z B Y C H F   Right side

Such consonants that are immediately preceded by a vowel and followed by a consonant are:

T R G S O I W P A Q D V E U X Z B Y C H F

Thus, three consonants are immediately preceded by a vowel and followed by a consonant.

Hence, Three is the correct answer.

Let Sunday be represented by Su, Monday be Mo, Tuesday be Tu, Wednesday be We, Thursday be Th, Friday be Fr, Saturday be Sa in the following table.

Each letter starting from S is represented by the day of the week starting from Sunday:

Hence, the position of first occurring Sunday from right is fourth.

Given series: Left side   T R G S O I W P A Q D V E U X Z B Y C H F   Right side

Such vowels that are immediately preceded by a vowel and followed by a consonant are:

T R G S O I W P A Q D V E U X Z B Y C H F

Hence, two vowels are immediately preceded by a vowel and followed by a consonant.

Given series: Left side   T R G S O I W P A Q D V E U X Z B Y C H F   Right side

If all the vowels are dropped, the new series will be:

Left side   T R G S W P Q D V X Z B Y C H F  Right side

The ninth letter from the left side is V.   T R G S W P Q D V X Z B Y C H F

The fourth letter to the left of V is W. T R G S W P Q D V

Hence, W is the correct answer.

Given series: Left side   T R G S O I W P A Q D V E U X Z B Y C H F   Right side

1. First letters are forming different series:

P - 2 = I

I - 2 = S

S - 2 = R

R - 2 = F

2. Secondletters are forming different series:

Q + 2 = V

V + 2 = U

U + 2 = Z

Z + 2 = Y

3. Third letters are forming different series:

D - 1 = Q

Q - 1 = A

A - 1 = P

P - 1 = W

Hence, the word formed is RZP.

Eight friends - Komal, Ayesha, Aruba, Mary, Ritney, Tanmay, Rohit and Shubham.

Month - January, March, April, June, July, August, October and December.

1) Two people having exams between Ritney and Aruba.

2)  Ritney having an exam in one of the months which have less than 31 days.

3) Three people having exams between Aruba and Ayesha.

4) Rohit having an exam one of the month which have 30 days. (Rohit have an exam either in April or June. So, Case 2b is invalid.)

5) One person having an exam between Tanmay and Ritney.

6. One person having an exam between Mary and Shubham.

7. Shubham have an exam one of the month before Mary.

8) Mary having an exam before Komal.

(case 2b is invalid because in case 2b Mary having exam after Komal)

Final Solution

Komal - January → Komal's exam is in December. So, it is false.

Ritney - October → Ritney's exam is in April. So, it is false.

Shubham - March → Shubham's exam is in July. So, it is false.

Ayesha - July → Ayesha's exam is in March. So, it is false

Aruba - August → Aruba's exam is in August. So, it is true.

Hence, the answer is Aruba - August.

Eight friends - Komal, Ayesha, Aruba, Mary, Ritney, Tanmay, Rohit and Shubham.

Month - January, March, April, June, July, August, October and December.

1) Two people having exams between Ritney and Aruba.

2)  Ritney having an exam in one of the months which have less than 31 days.

3) Three people having exams between Aruba and Ayesha.

4) Rohit having an exam one of the month which have 30 days. (Rohit have an exam either in April or June. So, Case 2b is invalid.)

5) One person having an exam between Tanmay and Ritney.

6. One person having an exam between Mary and Shubham.

7. Shubham have an exam one of the month before Mary.

8) Mary having an exam before Komal.

(case 2b is invalid because in case 2b Mary having exam after Komal)

Final Solution

Shubham have exam in the month of July.

Hence, the answer is Shubham.

Eight friends - Komal, Ayesha, Aruba, Mary, Ritney, Tanmay, Rohit and Shubham.

Month - January, March, April, June, July, August, October and December.

1) Two people having exams between Ritney and Aruba.

2)  Ritney having an exam in one of the months which have less than 31 days.

3) Three people having exams between Aruba and Ayesha.

4) Rohit having an exam one of the month which have 30 days. (Rohit have an exam either in April or June. So, Case 2b is invalid.)

5) One person having an exam between Tanmay and Ritney.

6. One person having an exam between Mary and Shubham.

7. Shubham have an exam one of the month before Mary.

8) Mary having an exam before Komal.

(case 2b is invalid because in case 2b Mary having exam after Komal)

Final Solution

There is two people gap between Tanmay and Rohit or Komal and Shubham. Similary, there is two people gap between Aruba and Ritney.

Hence, the answer is Ritney.

Eight friends - Komal, Ayesha, Aruba, Mary, Ritney, Tanmay, Rohit and Shubham.

Month - January, March, April, June, July, August, October and December.

1) Two people having exams between Ritney and Aruba.

2)  Ritney having an exam in one of the months which have less than 31 days.

3) Three people having exams between Aruba and Ayesha.

4) Rohit having an exam one of the month which have 30 days. (Rohit have an exam either in April or June. So, Case 2b is invalid.)

5) One person having an exam between Tanmay and Ritney.

6. One person having an exam between Mary and Shubham.

7. Shubham have an exam one of the month before Mary.

8) Mary having an exam before Komal.

(case 2b is invalid because in case 2b Mary having exam after Komal)

Final Solution

As we can see that there are four people having exams between Mary and Ayesha.

Hence, the answer is Four.

Eight friends - Komal, Ayesha, Aruba, Mary, Ritney, Tanmay, Rohit and Shubham.

Month - January, March, April, June, July, August, October and December.

1) Two people having exams between Ritney and Aruba.

2)  Ritney having an exam in one of the months which have less than 31 days.

3) Three people having exams between Aruba and Ayesha.

4) Rohit having an exam one of the month which have 30 days. (Rohit have an exam either in April or June. So, Case 2b is invalid.)

5) One person having an exam between Tanmay and Ritney.

6. One person having an exam between Mary and Shubham.

7. Shubham have an exam one of the month before Mary.

8) Mary having an exam before Komal.

(case 2b is invalid because in case 2b Mary having exam after Komal)

Final Solution

Except Ritney, all are having exam in a month which have 31 days.

Hence, the answer is Ritney.

Only one such pair is there in the number ‘6358427’, each of which has as many digits between them in the number (both forward and backward direction) as they have between them in the Numeric Series.

‘su’ means ‘Aman’

‘qi’ means ‘is’

‘ki’ means ‘running’

‘te’ means ‘fast’

‘ga’ means ‘He’

‘ue’ means ‘late’

‘bo’ means ‘met’

‘pa’ means ‘clients’

‘ru’ means ‘are’

Hence, ‘He met Aman’ is the meaning of ‘ga bo su’.

‘su’ means ‘Aman’

‘qi’ means ‘is’

‘ki’ means ‘running’

‘te’ means ‘fast’

‘ga’ means ‘He’

‘ue’ means ‘late’

‘bo’ means ‘met’

‘pa’ means ‘clients’

‘ru’ means ‘are’

Hence, ‘Aman is with clients’ is coded as ‘su qi mo pa’.

‘su’ means ‘Aman’

‘qi’ means ‘is’

‘ki’ means ‘running’

‘te’ means ‘fast’

‘ga’ means ‘He’

‘ue’ means ‘late’

‘bo’ means ‘met’

‘pa’ means ‘clients’

‘ru’ means ‘are’

Hence, ‘fast’ is coded as ‘te’.

‘su’ means ‘Aman’

‘qi’ means ‘is’

‘ki’ means ‘running’

‘te’ means ‘fast’

‘ga’ means ‘He’

‘ue’ means ‘late’

‘bo’ means ‘met’

‘pa’ means ‘clients’

‘ru’ means ‘are’

Hence, ‘met running clients’ are coded as ‘bo ki pa’

‘su’ means ‘Aman’

‘qi’ means ‘is’

‘ki’ means ‘running’

‘te’ means ‘fast’

‘ga’ means ‘He’

‘ue’ means ‘late’

‘bo’ means ‘met’

‘pa’ means ‘clients’

‘ru’ means ‘are’

Hence, ‘are’ is coded as ‘ru’ in the given language

Answer: 5

Given

Statements:

Z = C < E > D; B ≥ C > F

**On combining:**B ≥ C = Z > F; E > C > D

I. B > D → False (as given B ≥ C < E > D Opposite signs are there so this Conclusion Holds false)

II. Z > E → False (as given E > C = Z here Z > E)

Hence, the correct answer is none follows.

Correct Answer:- (3)

**Given

Statement:

** L ≥ M ≥ N > Q < R; N ≥ J ≥ P 

i) L > J : False ( L ≥ M ≥ N ≥ J ; Two possibilities are there L can be greater than or equals to J.)

ii) L = J : False ( L ≥ M ≥ N ≥ J ; Two possibilities are there L can be greater than or equals to J.)

Hence, subject and predict are same and both are false. so, it is complementary pair. Either conclusion I or II follows.

Correct Answer:- (5)

**Given

Statement:

** A < B ≤ C > D; C > E ≥ F 

i) A < F → False ( A < B ≤ C > E ≥ F; No direct relation between A and F given so, we can not conclude anything.)

ii) D < B → False ( B ≤ C > D; No clear relation between B and D given, so we can not conclude anything.)

Hence**,** the correct answer is "None follows".