Find the least number that on being divided by 5, 6, 8, 9 and 12 leaves 4 as the remainder in each case.
- AOption (a)
364
- BOption (b)
366
- COption (c)
368
- DOption (d)
360
View answer & explanationHide answer & explanation
Correct answer
364
Why this answer is correct
Given:
Divisors: 5, 6, 8, 9, and 12
Remainder = 4
Formula used:
Let the least number be N. According to the problem:
N = LCM(5, 6, 8, 9, 12) + 4
Calculations:
First, we need to find the LCM of 5, 6, 8, 9, and 12:
Factors:
5 = 5
6 = 2 × 3
8 = 23
9 = 3212 = 2<sup>2 × 3</sup>
LCM = 23 × 32 × 5
⇒ LCM = 8 × 9 × 5 = 360
⇒ N = 360 + 4 = 364
∴ The least number is 364.














