Given:
10 men can finish a certain task in 10 days
12 women can finish the same task in 10 days
Formula used:
Work done by 1 man in 1 day = Total work / (Number of men × Number of days)
Work done by 1 woman in 1 day = Total work / (Number of women × Number of days)
Total work done by 15 men and 6 women in 1 day = (Work done by 1 man in 1 day × 15) + (Work done by 1 woman in 1 day × 6)
Number of days required to complete the task = Total work / Total work done by 15 men and 6 women in 1 day
Calculations:
Work done by 1 man in 1 day = 1 / (10 × 10)
⇒ Work done by 1 man in 1 day = 1 / 100
Work done by 1 woman in 1 day = 1 / (12 × 10)
⇒ Work done by 1 woman in 1 day = 1 / 120
Total work done by 15 men in 1 day = 15 × (1 / 100)
⇒ Total work done by 15 men in 1 day = 15 / 100
Total work done by 6 women in 1 day = 6 × (1 / 120)
⇒ Total work done by 6 women in 1 day = 6 / 120
⇒ Total work done by 6 women in 1 day = 1 / 20
Total work done by 15 men and 6 women in 1 day = (15 / 100) + (1 / 20)
⇒ Total work done by 15 men and 6 women in 1 day = (15 / 100) + (5 / 100)
⇒ Total work done by 15 men and 6 women in 1 day = 20 / 100
⇒ Total work done by 15 men and 6 women in 1 day = 1 / 5
Number of days required to complete the task = 1 / (1 / 5)
⇒ Number of days required to complete the task = 5 days
∴ The correct answer is option 1.