Question 1201
If 2 is added to each odd digit and 1 is subtracted from each even digit in the number 8354671, then how many digits will appear more than once in the new number thus formed?
- AOption (a)
One
- BOption (b)
Two
- COption (c)
None
- DOption (d)
Three
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Correct answer
Three
Why this answer is correct
Given number: 8354671
According to the question,
| Number given | 8 | 3 | 5 | 4 | 6 | 7 | 1 |
|---|---|---|---|---|---|---|---|
| Odd digit → (+2) Even digit → (-1) | (-1) | (+2) | (+2) | (-1) | (-1) | (+2) | (+2) |
| Resultant number | 7 | 5 | 7 | 3 | 5 | 9 | 3 |
So, number of digits that appeared more than once in the new number thus formed → 7, 5 and 3 = Three
Hence, "Option 4" is the correct answer.