Shortcut Trick
Efficiency ratio of A, B, and (A+B+C) = 1/20 : 1/30 : 1/8
Multiply by LCM(20, 30, 8) = 120 → A : B : (A+B+C) = 6 : 4 : 15
Efficiency of C = 15 − (6 + 4) = 5 units
C's wage share = (Efficiency of C / Total Efficiency) × Total Amount
C's share = (5/15) × 18,750 = 1/3 × 18,750 = ₹6,250
∴ The correct answer is ₹6,250.
Alternate Method
Given:
Time taken by A = 20 days
Time taken by B = 30 days
Time taken by A, B, and C together = 8 days
Total wage amount = ₹18,750
Formula Used:
Efficiency = Total Work ÷ Time
Wage Share = (Individual Efficiency ÷ Total Efficiency) × Total Wage
| Person | Days | Total Work (LCM) | Efficiency |
|---|
| A | 20 | 120 | 120 ÷ 20 = 6 |
| B | 30 | 120 ÷ 30 = 4 | |
| A + B + C | 8 | 120 ÷ 8 = 15 | |
Calculations:
⇒ Efficiency of A = 6 units/day
⇒ Efficiency of B = 4 units/day
⇒ Efficiency of A + B + C = 15 units/day
⇒ Efficiency of C = Efficiency of (A+B+C) − Efficiency of (A+B)
⇒ Efficiency of C = 15 − (6 + 4) = 5 units/day
⇒ Ratio of wages (A : B : C) = 6 : 4 : 5
⇒ Sum of ratio parts = 6 + 4 + 5 = 15
⇒ C's share = (5 ÷ 15) × 18,750
⇒ C's share = 1/3 × 18,750 = ₹6,250
∴ The correct answer is ₹6,250.
Additional Information
Work and Wages Principle
Wages are distributed in direct proportion to the work done by each individual. If they work for the same amount of time, the wage ratio is equal to their efficiency ratio.
Combined Efficiency
Total efficiency of a group working together is the sum of individual efficiencies: Etotal = E1 + E2 + ... + En.
Time-Efficiency Relation
Efficiency is inversely proportional to the time taken to complete a task (Efficiency ∝ 1/Time) when work is constant.