Shortcut Trick
The given mathematical expression directly matches an algebraic identity.
x2 + y2 + z2 − 2xy − 2xz + 2yz = (x − y − z)2
Substitute the given variable values into the term (x − y − z):
⇒ (b + c) − (c − a) − (a − b) = b + c − c + a − a + b = 2b
⇒ (2b)2 = 4b2
∴ The correct answer is 4b2.
Alternate Method
Given:
⇒ x = b + c
⇒ y = c − a
⇒ z = a − b
Formula Used:
⇒ (p + q + r)2 = p2 + q2 + r2 + 2pq + 2qr + 2pr
Calculation:
⇒ Let us evaluate the given expression: x2 + y2 + z2 − 2xy − 2xz + 2yz
⇒ Comparing this with our standard formula, we take p = x, q = −y, and r = −z.
⇒ This simplifies our original expression cleanly to: (x − y − z)2
⇒ Next, we substitute the given expressions for x, y, and z into (x − y − z):
⇒ x − y − z = (b + c) − (c − a) − (a − b)
⇒ Distribute the negative signs and open the brackets:
⇒ x − y − z = b + c − c + a − a + b
⇒ Cancel out the opposite terms (+c − c) and (+a − a) and group together:
⇒ x − y − z = 2b
⇒ Finally, substitute this result back into the squared identity expression:
⇒ (x − y − z)2 = (2b)2 = 4b2
∴ The correct answer is 4b2.
Additional Information
Trinomial Expansion Identity
The fundamental identity for the square of a sum of three variables is represented as (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca.
Sign Variations in Expansion
By assigning negative signs to the variables, we derive adapted identities depending on the requirements. For instance, (a − b − c)2 = a2 + b2 + c2 − 2ab + 2bc − 2ca.
Important Cubic Identity
a3 + b3 + c3 − 3abc = (a + b + c)(a2 + b2 + c2 − ab − bc − ca). Notably, if a + b + c = 0, the equation cleanly reduces to a single relation: a3 + b3 + c3 = 3abc.