Arithmetic, number systems, percentages, ratios, profit and loss, time and work, algebra, geometry, mensuration, and trigonometry.
What should come in place of the question mark '?' in the following number series?
332, 331, 323, 296, 232, ?
103
101
105
107
108
Correct answer
107
Why this answer is correct
The series follows the following pattern:
332 – 13 = 331
331 – 23 = 323
323 – 33 = 296
296 – 43 = 232
232 – 53 = 107
∴ The missing term in the series is 107.
What should come in place of the question mark '?' in the following number series?
728, 716, 692, ?, 608, 548
635
642
656
649
663
Correct answer
656
Why this answer is correct
The series follows the following pattern:
728 – (12 × 1) = 716
716 – (12 × 2) = 692
692 – (12 × 3) = 656
656 – (12 × 4) = 608
608 – (12 × 5) = 548
∴ The missing term in the series is 656.
What should come in place of the question mark '?' in the following number series?
1, 5, 13, 29, ?, 125
60
61
62
63
64
Correct answer
61
Why this answer is correct
The given series follows the pattern shown below:
1
1 × 2 + 3 = 5
5 × 2 + 3 = 13
13 × 2 + 3 = 29
29 × 2 + 3 = 61
61 × 2 + 3 = 125
What should come in place of the question mark '?' in the following number series?
3, 7, ?, 27, -37, 63
12
-18
15
-9
-12
Correct answer
-9
Why this answer is correct
The given series follows the pattern shown below:
3 + 22 = 7
7 – 42 = –9
–9 + 62 = 27
27 – 82 = –37
–37 + 102 = 63
What should come in place of the question mark '?' in the following number series?
25, 30, 40, 55, 75, ?
90
100
110
120
105
Correct answer
100
Why this answer is correct
The series follows the following pattern:
25 + 5 = 30
30 + 10 = 40
40 + 15 = 55
55 + 20 = 75
75 + 25 = 100
A man marks an article 25% above the cost price of an article. if he gives 20% discount on markup price what will be his loss or gain percentage?
5% gain.
5% loss.
10% loss.
no gain no loss.
10% gain.
Correct answer
no gain no loss.
Why this answer is correct
Given:
Discount percentage = 20%
And markup price = 25% above the cost price
Formula used:
Mark up price = cost price × [(100 + markup percentage)/100]
Selling price = markup price × [(100 - discount percentage)/100]
Calculation:
Let the cost price of an article be Rs. x
Markup price = x × [(100 + 25)/100]
⇒ 125x/100
⇒ 1.25x
Selling price = 1.25x × [(100 - 20)/100]
⇒ 1.25x × (80/100)
⇒ 100x/100
⇒ x
We can see the cost price and the selling price of an article are the same ie. equal to Rs.
x. ∴ There will be no loss or gain percentage on an article.
Train A of length 100 m crosses a platform of length 20 m in 5 sec. It crosses another train B of length 80 m running in opposite direction in 4 sec. Find the speed of train B.
26 m/s
25 m/s
21 m/s
30 m/s
None of these
Correct answer
21 m/s
Why this answer is correct
GIVEN :
Train A of length 100 m crosses a platform of length 20 m in 5 sec.
It crosses another train B of length 80 m running in opposite direction in 4 sec.
CALCULATION :
1st case
Total distance = 100 + 20 = 120 m
Speed of train A = 120/5 = 24 m/s
2nd case
Total distance = 100 + 80 = 180 m
Let speed of train B = x m/s
Relative speed = (24 + x)m/s
According to question,
24 + x = 180/4
⇒ 24 + x = 45
⇒ x = 21 m/s
∴ Speed of train B = 21 m/s
Study the following information carefully and answer the questions given below:
The table given below shows the percentage of marks in a Mock-test obtained by five friends in three different subjects.
| Subjects (Maximum marks) | English (100) | Quantitative Aptitude (125) | Reasoning Ability (175) |
|---|---|---|---|
| Aman | 63% | 88% | 76% |
| Bharat | 78% | 64% | 68% |
| Chetan | 52% | 72% | 92% |
| Dheeraj | 84% | 56% | 52% |
| Elvish | 92% | 48% | 84% |
What is the difference between highest and lowest Reasoning scores?
60
90
70
55
65
Correct answer
70
Why this answer is correct
Calculations:
⇒ Chetan = 92 × 175 ÷ 100 = 161
⇒ Dheeraj = 52 × 175 ÷ 100 = 91
Highest = 161
Lowest = 91
⇒ Difference = 161 − 91 = 70
∴ Difference between highest and lowest Reasoning marks = 70.
Study the following information carefully and answer the questions given below:
The table given below shows the percentage of marks in a Mock-test obtained by five friends in three different subjects.
| Subjects (Maximum marks) | English (100) | Quantitative Aptitude (125) | Reasoning Ability (175) |
|---|---|---|---|
| Aman | 63% | 88% | 76% |
| Bharat | 78% | 64% | 68% |
| Chetan | 52% | 72% | 92% |
| Dheeraj | 84% | 56% | 52% |
| Elvish | 92% | 48% | 84% |
If Chetan improves their English score by 25% of their previous English score, what will be the approximate percentage change in their total marks across all three subjects?
4%
8%
10%
12%
6%
Correct answer
4%
Why this answer is correct
Calculations:
⇒ Increase in English = 25% × 52
⇒ = 0.25 × 52 = 13
⇒ New English = 52 + 13 = 65
Original total = 52 + 90 + 161 = 303
New total = 65 + 90 + 161 = 316
⇒ Increase = 316 − 303 = 13
⇒ % change = 13 ÷ 303 × 100
⇒ 4.29% ≈ 4%
∴ Approximate percentage change in total marks = 4%.
Study the following information carefully and answer the questions given below:
The table given below shows the percentage of marks in a Mock-test obtained by five friends in three different subjects.
| Subjects (Maximum marks) | English (100) | Quantitative Aptitude (125) | Reasoning Ability (175) |
|---|---|---|---|
| Aman | 63% | 88% | 76% |
| Bharat | 78% | 64% | 68% |
| Chetan | 52% | 72% | 92% |
| Dheeraj | 84% | 56% | 52% |
| Elvish | 92% | 48% | 84% |
If a person qualifies only if they score at least 60% in each subject, how many friends qualify?
1
0
3
2
4
Correct answer
2
Why this answer is correct
Calculations:
⇒ Aman: 63, 88, 76 → Qualifies
⇒ Bharat: 78, 64, 68 → Qualifies
⇒ Chetan: 52 (fails), 72, 92 → Not qualify
⇒ Dheeraj: 84, 56 (fails), 52 (fails) → Not qualify
⇒ Elvish: 92, 48 (fails), 84 → Not qualify
⇒ Total qualifiers = 2
∴ Number of friends who qualify = 2.
Study the following information carefully and answer the questions given below:
The table given below shows the percentage of marks in a Mock-test obtained by five friends in three different subjects.
| Subjects (Maximum marks) | English (100) | Quantitative Aptitude (125) | Reasoning Ability (175) |
|---|---|---|---|
| Aman | 63% | 88% | 76% |
| Bharat | 78% | 64% | 68% |
| Chetan | 52% | 72% | 92% |
| Dheeraj | 84% | 56% | 52% |
| Elvish | 92% | 48% | 84% |
What is the average marks scored by person Chetan across all three subjects?
104
101
108
112
124
None of these
Correct answer
101
Why this answer is correct
Calculations:
⇒ Total = 52 + 90 + 161 = 303
⇒ Average = 303 ÷ 3
⇒ Average = 101
∴ Average marks of Chetan = 101.
Study the following information carefully and answer the questions given below:
The table given below shows the percentage of marks in a Mock-test obtained by five friends in three different subjects.
| Subjects (Maximum marks) | English (100) | Quantitative Aptitude (125) | Reasoning Ability (175) |
|---|---|---|---|
| Aman | 63% | 88% | 76% |
| Bharat | 78% | 64% | 68% |
| Chetan | 52% | 72% | 92% |
| Dheeraj | 84% | 56% | 52% |
| Elvish | 92% | 48% | 84% |
Who scored the highest total marks across all three subjects?
Aman
Bharat
Elvish
Dheeraj
Chetan
Correct answer
Aman
Why this answer is correct
Calculations:
Aman:
⇒ English = 63 × 100 ÷ 100 = 63
⇒ Quant = 88 × 125 ÷ 100 = 110
⇒ Reasoning = 76 × 175 ÷ 100 = 133
Total = 63 + 110 + 133 = 306
Bharat:
⇒ English = 78
⇒ Quant = 64 × 125 ÷ 100 = 80
⇒ Reasoning = 68 × 175 ÷ 100 = 119
Total = 78 + 80 + 119 = 277
Chetan:
⇒ English = 52
⇒ Quant = 72 × 125 ÷ 100 = 90
⇒ Reasoning = 92 × 175 ÷ 100 = 161
Total = 52 + 90 + 161 = 303
Dheeraj:
⇒ English = 84
⇒ Quant = 56 × 125 ÷ 100 = 70
⇒ Reasoning = 52 × 175 ÷ 100 = 91
Total = 84 + 70 + 91 = 245
Elvish:
⇒ English = 92
⇒ Quant = 48 × 125 ÷ 100 = 60
⇒ Reasoning = 84 × 175 ÷ 100 = 147
Total = 92 + 60 + 147 = 299
∴ Aman scored the highest total marks = 306.
In a company, three persons A, B, and C share their profit in the ratio 4 : 7 : 3 respectively. B retired from the company and, A & C decided to share the profit in the ratio 4 : 3. Calculate the ratio of their gain.
3 : 4
4 : 3
3 : 5
5 : 3
4 : 5
Correct answer
4 : 3
Why this answer is correct
Given:
A, B, and C share their profit in the ratio 4 : 7 : 3 respectively
B retired from the company and, A & C decided to share the profit in the ratio 4 : 3
Calculation:
The initial profit share of A = 4/(4 + 7 + 3) = 4/14 unit
The initial profit share of C = 3/(4 + 7 + 3) = 3/14 unit
After B retired,
The profit share of A = 4/(4 + 3) = 4/7
The profit share of C = 3/(4 + 3) = 3/7
Gain of A = (4/7) - (4/14) = 28/98
Gain of C = (3/7) - (3/14) = 21/98
The respective ratio of gain of A and C = (28/98) : (21/98) = 4 : 3
∴ The correct answer is option 2
A batsman scored 90 runs in his 12th match. Due to this, his average run is increased by 2. Find the initial average runs scored by him.
65
63
68
66
70
Correct answer
66
Why this answer is correct
Given:
Runs in 12th match = 90
Calculation:
Let the average till 11th match or initial average = x
According to the question
⇒ 11x + 90 = (x + 2) × 12
∴ x = 66
What will come in place of the question mark ‘?’ in the following question?
(8536 – √2209) × 0.3 = ?
2556.7
2456.7
2546.7
2645.7
2654.7
Correct answer
2546.7
Why this answer is correct
Follow BODMAS rule to solve this question, as per the order given below,
Step -1- Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket,
Step -2- Any mathematical 'Of' or 'Exponent' must be solved next,
Step -3- Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,
Step -4- Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.
Given expression is,
(8536 – √2209) × 0.3 = ?
⇒ ? = (8536 – 47) × 0.3
⇒ ? = (8489) × 0.3
∴ ? = 2546.7
What will come in place of question Mark ‘?’ in the following question?
81% of 2300 – 34% of 596 = ?
1060.63
1060.36
1660.36
1006.63
1600.36
Correct answer
1660.36
Why this answer is correct
Follow BODMAS rule to solve this question, as per the order given below,
Step-1- Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket,
Step-2- Any mathematical 'Of' or 'Exponent' must be solved next,
Step-3- Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,
Step-4- Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.
Given expression is,
81% of 2300 – 34% of 596 = ?
⇒ ? = (81/100 × 2300) – (34/100 × 596)
⇒ ? = (81 × 2300) – (34 × 5.96)
⇒ ? = 1863 – 202.64
∴ ? = 1660.36
What will come in place of question mark (?) in the following question?
13.6 – 1.6 – 1 + 1.3 × 2 = ?
13.6
12.6
14.6
11.6
15.6
Correct answer
13.6
Why this answer is correct
Concept used:
Follow BODMAS rule to solve this question, as per the order given below:
13.6 – 1.6 – 1 + 1.3 × 2 = ?
⇒ 13.6 – 1.6 – 1 + 2.6 = ?
⇒ 13.6 – 1.6 + 1.6 = ?
⇒ 13.6 + 0 = ?
∴ ? = 13.6
What will come in place of question mark ‘?’ in the following question?
350% of ? ÷ 50 + 278 = 1825
22200
22150
44100
22100
None of these
Correct answer
22100
Why this answer is correct
Follow BODMAS rules to solve the equation
Step -1: The part of the equation containing 'Brackets' must be solved first, and in the bracket,
Step -2: Any mathematical 'Of' or 'Exponent' must be solved next,
Step -3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are solved
Step -4: At last, the part of the equation that contains 'Addition' and 'Subtraction' should be solved.
⇒ 350% of ? ÷ 50 + 278 = 1825
⇒ [350 × (?)] / (100 × 50) + 278 = 1825
⇒ 7/100 × ? = 1547
⇒ ? = (1547 × 100) /7
⇒ ? = 221 × 100 = 22100
∴ ? = 22100
What will come in place of ? in the following equation?
[(140)2 ÷ 35 × 32] ÷ 8 = 7 × ?
32
320
160
80
None of these
Correct answer
320
Why this answer is correct
Follow these BODMAS rules to solve the question
⇒ (140 × 140 × 32) / (35 × 8) = 7 × ?
⇒ 16 × 140 = 7 × ?
⇒ ? = (16 × 140)/7
⇒ ? = 320
What will come in place of question mark ‘?’ in the following question?
46 × 1536 ÷ (2√2304) = (?)3 + √49
7
8
9
6
10
Correct answer
9
Why this answer is correct
Concept used:
Follow BODMAS rule to solve this question, as per the order given below:
Calculation:
46 × 1536 ÷ (2√2304) = (?)3 + √49
⇒ 46 × 1536 ÷ (2 × 48) = (?)3 + 7
⇒ 46 × 1536 ÷ 96 = (?)3 + 7
⇒ 46 × 16 – 7 = ?3
⇒ ?3 = 729
⇒ ? = 9
∴ The value of ? is 9
Solving previous year questions by topic helps identify recurring concepts, question patterns, and frequently asked sub-topics. Attempt each question, review the step-by-step explanation, and note down key formulas or facts for quick revision before the exam.