Reasoning PYQs

Persons: A, B, C, D, E, F, G, H and I

Five persons are facing outside while four are facing inside.

1) F is sitting third to the right of A who is facing inside.

2. Three persons are sitting between F and E.

Since it is not clear E is sitting in which direction with respect to F, two cases will be formed.

Case 1:

Case 2:

3) C is sitting third to the right of H who is one of the neighbours of A.

4. H is not facing outside.

In case 2, H can either sit to the right of A or to the left of A. So, two cases can be formed.

Case 1: 

Case 2(a):

Case 2(b):

5) Two persons are sitting between D and I who is adjacent to C.

6) E, who is not sitting adjacent to B, is one of the immediate neighbours of H.

E is the neighbour of H only in case 2(b). So other cases will be cancelled.

7) B and G are sitting immediate left of each other.

From point 6, E cannot sit adjacent to B, so the diagram will be as follows:

8) F is sitting to the immediate left of C while to the immediate right of D.

9) Not more than two persons facing the same direction are sitting together.

H sits third to the left of C.

Hence, If C and B exchange their positions, H will sit third to the left of C.

Persons: A, B, C, D, E, F, G, H and I

Five persons are facing outside while four are facing inside.

1) F is sitting third to the right of A who is facing inside.

2. Three persons are sitting between F and E.

Since it is not clear E is sitting in which direction with respect to F, two cases will be formed.

Case 1:

Case 2:

3) C is sitting third to the right of H who is one of the neighbours of A.

4. H is not facing outside.

In case 2, H can either sit to the right of A or to the left of A. So, two cases can be formed.

Case 1: 

Case 2(a):

Case 2(b):

5) Two persons are sitting between D and I who is adjacent to C.

6) E, who is not sitting adjacent to B, is one of the immediate neighbours of H.

E is the neighbour of H only in case 2(b). So other cases will be cancelled.

7) B and G are sitting immediate left of each other.

From point 6, E cannot sit adjacent to B, so the diagram will be as follows:

8) F is sitting to the immediate left of C while to the immediate right of D.

9) Not more than two persons facing the same direction are sitting together.

Third to the right of I - E; Second to the right of the one who is third to the right of I (E) - B.

Hence, B is sitting second to the right of the person who is third to the right of I.

Persons: A, B, C, D, E, F, G, H and I

Five persons are facing outside while four are facing inside.

1) F is sitting third to the right of A who is facing inside.

2. Three persons are sitting between F and E.

Since it is not clear E is sitting in which direction with respect to F, two cases will be formed.

Case 1:

Case 2:

3) C is sitting third to the right of H who is one of the neighbours of A.

4. H is not facing outside.

In case 2, H can either sit to the right of A or to the left of A. So, two cases can be formed.

Case 1: 

Case 2(a):

Case 2(b):

5) Two persons are sitting between D and I who is adjacent to C.

6) E, who is not sitting adjacent to B, is one of the immediate neighbours of H.

E is the neighbour of H only in case 2(b). So other cases will be cancelled.

7) B and G are sitting immediate left of each other.

From point 6, E cannot sit adjacent to B, so the diagram will be as follows:

8) F is sitting to the immediate left of C while to the immediate right of D.

9) Not more than two persons facing the same direction are sitting together.

Hence, I is sitting second to the left of F.

Persons: A, B, C, D, E, F, G, H and I

Five persons are facing outside while four are facing inside.

1) F is sitting third to the right of A who is facing inside.

2. Three persons are sitting between F and E.

Since it is not clear E is sitting in which direction with respect to F, two cases will be formed.

Case 1:

Case 2:

3) C is sitting third to the right of H who is one of the neighbours of A.

4. H is not facing outside.

In case 2, H can either sit to the right of A or to the left of A. So, two cases can be formed.

Case 1: 

Case 2(a):

Case 2(b):

5) Two persons are sitting between D and I who is adjacent to C.

6) E, who is not sitting adjacent to B, is one of the immediate neighbours of H.

E is the neighbour of H only in case 2(b). So other cases will be cancelled.

7) B and G are sitting immediate left of each other.

From point 6, E cannot sit adjacent to B, so the diagram will be as follows:

8) F is sitting to the immediate left of C while to the immediate right of D.

9) Not more than two persons facing the same direction are sitting together.

Hence, I is sitting to the immediate right of A.

Six person A, B, C, D, E and F

1. A belongs to Delhi and was born in the month having 30 days.

2) Two people were born between the one who belongs to Delhi and either B or D.

3) E was born after B but not immediately.

4) C was neither born in the month having 31 days nor belongs to Kolkata.

5) A and E were born in the adjacent month but on different dates. 

6) F was born immediately after B.

7) The one who belongs to  Bengaluru was born in the month having 30 days.

8) Two people were born between E and the one who belongs to Kolkata.

9) The one who belongs to Mumbai was born immediately after the one who was born in Chennai.

10. One person was born in Hyderabad.

Hence, the correct combination is 17 March - B - Hyderabad.

Six person A, B, C, D, E and F

1. A belongs to Delhi and was born in the month having 30 days.

2) Two people were born between the one who belongs to Delhi and either B or D.

3) E was born after B but not immediately.

4) C was neither born in the month having 31 days nor belongs to Kolkata.

5) A and E were born in the adjacent month but on different dates. 

6) F was born immediately after B.

7) The one who belongs to  Bengaluru was born in the month having 30 days.

8) Two people were born between E and the one who belongs to Kolkata.

9) The one who belongs to Mumbai was born immediately after the one who was born in Chennai.

10. One person was born in Hyderabad.

Hence, C was born on 17^th April.

Six person A, B, C, D, E and F

1) A belongs to Delhi and was born in the month having 30 days.

2) Two people were born between the one who belongs to Delhi and either B or D.

3) E was born after B but not immediately.

4) C was neither born in the month having 31 days nor belongs to Kolkata.

5) A and E were born in the adjacent month but on different dates. 

6) F was born immediately after B.

7) The one who belongs to  Bengaluru was born in the month having 30 days.

8) Two people were born between E and the one who belongs to Kolkata.

9) The one who belongs to Mumbai was born immediately after the one who was born in Chennai.

10. One person was born in Hyderabad.

Hence, B belongs to Hyderabad.

Six person A, B, C, D, E and F

1. A belongs to Delhi and was born in the month having 30 days.

2) Two people were born between the one who belongs to Delhi and either B or D.

3) E was born after B but not immediately.

4) C was neither born in the month having 31 days nor belongs to Kolkata.

5) A and E were born in the adjacent month but on different dates. 

6) F was born immediately after B.

 

7) The one who belongs to  Bengaluru was born in the month having 30 days.

8) Two people were born between E and the one who belongs to Kolkata.

9) The one who belongs to Mumbai was born immediately after the one who was born in Chennai.

10. One person was born in Hyderabad.

 

Hence, 2 people were born between F and the one who belongs to Chennai.

Six person A, B, C, D, E and F

1. A belongs to Delhi and was born in the month having 30 days.

2) Two people were born between the one who belongs to Delhi and either B or D.

3) E was born after B but not immediately.

4) C was neither born in the month having 31 days nor belongs to Kolkata.

5) A and E were born in the adjacent month but on different dates. 

6) F was born immediately after B.

 

7) The one who belongs to  Bengaluru was born in the month having 30 days.

8) Two people were born between E and the one who belongs to Kolkata.

9) The one who belongs to Mumbai was born immediately after the one who was born in Chennai.

10. One person was born in Hyderabad.

 

Hence, F belongs to Kolkata.

The diagram given below shows the position of all points and path followed by A.

Since with respect to Z,

Point P is to the Northwest

Point R is to the Northwest

Point X is to the Northwest

Point Y is to the North

Point Q is to the Northwest

Hence, Y is alike from the remaining.

The diagram given below shows the position of all points and path followed by A.

Therefore, distance between A's initial position and point P = ( 5 + 5 + 10 + 8 ) = 28 metre

Hence, the correct answer is 28 metre.

The diagram given below shows the position of all points and path followed by A.

Hence, A is to the northeast of its initial position.

From the given information,

Here Twelve pair are there of numbers.

Hence, More than six pairs will be there in the arrangement.

From the given information,

I) Box S is in fourth stack. V is place immediate above J and number of boxes below J are one more than the box above V. so here is  one condition will satisfy this will be as,

 

II) More than three boxes are between S and D and D is not on the top. Here two possibility will be there two place the Box D.

 

III) More than six boxes between D and K. Here we can place Box K at two place in case II, So in case II here two possibility will be there (a), (b).

 

IV) Box below G are one more than the box above D. G is also below the S. Here in case I we cannot place G according to the given condition. In other cases we can place box.

 

Here Case I gets cancelled because if we place box G below S then Box below G are not one more than box above D, so it will be wrong according to the given condition.

V) Three boxes are between R and T, which is near to D. so here only just below D we can place T and then three boxes are between T and R.

 

VI) N is just below T. M is not on the top and not near to G. Here in case II (b) only two place are left one is near to G another one is on the top, so we cannot place G is here.

 

Case II(b) gets cancelled because we cannot place box G according to the given condition.

VII) P is one of the box, here only one place remaining which is on top of stack.

 

This will be the final arrangement of the boxes in the stack.

Hence, there are Four boxes between J and P.

From the given information,

I) Box S is in fourth stack. V is place immediate above J and number of boxes below J are one more than the box above V. so here is  one condition will satisfy this will be as,

 

II) More than three boxes are between S and D and D is not on the top. Here two possibility will be there two place the Box D.

 

III) More than six boxes between D and K. Here we can place Box K at two place in case II, So in case II here two possibility will be there (a), (b).

 

IV) Box below G are one more than the box above D. G is also below the S. Here in case I we cannot place G according to the given condition. In other cases we can place box.

 

Here Case I gets cancelled because if we place box G below S then Box below G are not one more than box above D, so it will be wrong according to the given condition.

V) Three boxes are between R and T, which is near to D. so here only just below D we can place T and then three boxes are between T and R.

 

VI) N is just below T. M is not on the top and not near to G. Here in case II (b) only two place are left one is near to G another one is on the top, so we cannot place G is here.

 

Case II(b) gets cancelled because we cannot place box G according to the given condition.

VII) P is one of the box, here only one place remaining which is on top of stack.

 

This will be the final arrangement of the boxes in the stack.

Here eight boxes are below T same as eight boxes will be above G.

Hence, below box T is same as the above box G.

From the given information,

I) Box S is in fourth stack. V is place immediate above J and number of boxes below J are one more than the box above V. so here is  one condition will satisfy this will be as,

 

II) More than three boxes are between S and D and D is not on the top. Here two possibility will be there two place the Box D.

 

III) More than six boxes between D and K. Here we can place Box K at two place in case II, So in case II here two possibility will be there (a), (b).

 

IV) Box below G are one more than the box above D. G is also below the S. Here in case I we cannot place G according to the given condition. In other cases we can place box.

 

Here Case I gets cancelled because if we place box G below S then Box below G are not one more than box above D, so it will be wrong according to the given condition.

V) Three boxes are between R and T, which is near to D. so here only just below D we can place T and then three boxes are between T and R.

 

VI) N is just below T. M is not on the top and not near to G. Here in case II (b) only two place are left one is near to G another one is on the top, so we cannot place G is here.

 

Case II(b) gets cancelled because we cannot place box G according to the given condition.

VII) P is one of the box, here only one place remaining which is on top of stack.

 

This will be the final arrangement of the boxes in the stack.

Hence, box M is placed on the bottom of the stack

From the given information,

I) Box S is in fourth stack. V is place immediate above J and number of boxes below J are one more than the box above V. so here is  one condition will satisfy this will be as,

 

II) More than three boxes are between S and D and D is not on the top. Here two possibility will be there two place the Box D.

 

III) More than six boxes between D and K. Here we can place Box K at two place in case II, So in case II here two possibility will be there (a), (b).

 

IV) Box below G are one more than the box above D. G is also below the S. Here in case I we cannot place G according to the given condition. In other cases we can place box.

 

Here Case I gets cancelled because if we place box G below S then Box below G are not one more than box above D, so it will be wrong according to the given condition.

V) Three boxes are between R and T, which is near to D. so here only just below D we can place T and then three boxes are between T and R.

 

VI) N is just below T. M is not on the top and not near to G. Here in case II (b) only two place are left one is near to G another one is on the top, so we cannot place G is here.

 

Case II(b) gets cancelled because we cannot place box G according to the given condition.

VII) P is one of the box, here only one place remaining which is on top of stack.

 

This will be the final arrangement of the boxes in the stack.

Hence, there are Three boxes between R and M.

From the given information,

I) Box S is in fourth stack. V is place immediate above J and number of boxes below J are one more than the box above V. so here is  one condition will satisfy this will be as,

 

II) More than three boxes are between S and D and D is not on the top. Here two possibility will be there two place the Box D.

 

III) More than six boxes between D and K. Here we can place Box K at two place in case II, So in case II here two possibility will be there (a), (b).

 

IV) Box below G are one more than the box above D. G is also below the S. Here in case I we cannot place G according to the given condition. In other cases we can place box.

 

Here Case I gets cancelled because if we place box G below S then Box below G are not one more than box above D, so it will be wrong according to the given condition.

V) Three boxes are between R and T, which is near to D. so here only just below D we can place T and then three boxes are between T and R.

 

VI) N is just below T. M is not on the top and not near to G. Here in case II (b) only two place are left one is near to G another one is on the top, so we cannot place G is here.

 

Case II(b) gets cancelled because we cannot place box G according to the given condition.

VII) P is one of the box, here only one place remaining which is on top of stack.

 

This will be the final arrangement of the boxes in the stack.

Hence, box N is placed in eighth stack..

Given logic is; If the third letter from the left in each word taken it forms a meaningful word,

Given words are,

1. ROKI, KENL, ROET, MNER.

The third letters from each word are: ROKI → K, KENL → N,  ROET → E, MNER → E. From these letters, the meaningful word formed is 'KNEE' 

2) SPDN, RION, PROT, SARU.

The third letters from each word are: SPDN → D, RION → O,  PROT → O,  SARU → R. From these letters, the meaningful word formed is 'DOOR'.

3) SORT, NGOK, CRSU, QREP

The third letters from each word are: SORT → R, NGOK → O,  →  CRSU → S, QREP → E. From these letters, the meaningful word formed is 'ROSE' 

4) ROMI, KEOL, ROST, MNTR

The third letters from each word are: ROMI → M, KEOL → O, ROST → S,  MNTR → T. From these letters, the meaningful word formed is 'MOST'

5) NAOT, STON, NITY, SITT

The third letters from each word are:  NAOT → O, STON → O, NITY → T, SITT → T. After arranging these letters we find 'OOTT' here we can see that no meaningful word is formed by these letters so it is the odd one.

Hence, Option 'five' is the odd one.

Given word, 'GRAYHOUND',

When each vowel of this word is changed to the previous letter as in the English alphabetical series and each consonant is changed to the next letter as in the English alphabetical series then new arrangement is;

Here we can see the the one letter 'Z' is repeated.

Hence, in new arrangement one letter is repeated.