Reasoning PYQs

Given: 6 persons, namely, P, Q, R, S, T, and U, are going to an amusement park on six different days, Monday to Saturday, but not necessarily in the same order.

1. T went to the amusement park on Tuesday.

 

2. Only two people went between T and Q.

 

3. U went to the amusement park either immediately after or immediately before Q.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

 

4. S went to the amusement park three days before U.

 

5. R went to the amusement park before P.

 

6. P didn't go to the amusement park immediately after Q.

Now, we can eliminate Case 2.

This is our final arrangement,

 

Hence, the correct answer is U.

Given: 6 persons, namely, P, Q, R, S, T, and U, are going to an amusement park on six different days, Monday to Saturday, but not necessarily in the same order.

1. T went to the amusement park on Tuesday.

 

2. Only two people went between T and Q.

 

3. U went to the amusement park either immediately after or immediately before Q.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

 

4. S went to the amusement park three days before U.

 

5. R went to the amusement park before P.

 

6. P didn't go to the amusement park immediately after Q.

Now, we can eliminate Case 2.

This is our final arrangement,

 

Hence, the correct answer is Three.

Given: 6 persons, namely, P, Q, R, S, T, and U, are going to an amusement park on six different days, Monday to Saturday, but not necessarily in the same order.

1. T went to the amusement park on Tuesday.

 

2. Only two people went between T and Q.

 

3. U went to the amusement park either immediately after or immediately before Q.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

 

4. S went to the amusement park three days before U.

 

5. R went to the amusement park before P.

 

6. P didn't go to the amusement park immediately after Q.

Now, we can eliminate Case 2.

This is our final arrangement,

 

Hence, the correct answer is Three.

Given: 6 persons, namely, P, Q, R, S, T, and U, are going to an amusement park on six different days, Monday to Saturday, but not necessarily in the same order.

1. T went to the amusement park on Tuesday.

 

2. Only two people went between T and Q.

 

3. U went to the amusement park either immediately after or immediately before Q.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

 

4. S went to the amusement park three days before U.

 

5. R went to the amusement park before P.

 

6. P didn't go to the amusement park immediately after Q.

Now, we can eliminate Case 2.

This is our final arrangement,

 

Hence, the correct answer is Thursday - P.

Given: 6 persons, namely, P, Q, R, S, T, and U, are going to an amusement park on six different days, Monday to Saturday, but not necessarily in the same order.

1. T went to the amusement park on Tuesday.

 

2. Only two people went between T and Q.

 

3. U went to the amusement park either immediately after or immediately before Q.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

 

4. S went to the amusement park three days before U.

 

5. R went to the amusement park before P.

 

6. P didn't go to the amusement park immediately after Q.

Now, we can eliminate Case 2.

This is our final arrangement,

 

Hence, the correct answer is Q.

Given information can be represented as follows,

Thus ‘cricket’ is coded as ‘mo’.

Given information can be represented as follows,

Thus ‘se’ is code for ‘some' or ‘football’.

Given information can be represented as follows,

Code for ‘most’ is ‘pi’.

Code for ‘children’ is ‘ja’.

Code for ‘are’ is ‘da’.

Code for ‘cricket’ is ‘mo’.

Code for ‘good’ and ‘at’ will be some different code which is not present in present codes.

Hence, the possible coding will be “pi ja da su ta mo”.

Given information can be represented as follows,

Code ‘pi’ is for ‘most’.

Code ‘sun’ is for ‘love’.

Code ‘ko’ is for ‘some’ or ‘football’.

Code ‘ja’ is for ‘children’.

Code ‘za’ is a new code.

Hence, none of the above sentences can be coded as ‘za pi sun ko ja’.

Given information can be represented as follows,

Code for ‘Some’ is ‘se’ or ‘ko’.

Code for ‘are’ is ‘da’

Code for ‘playing’ is ‘sa’.

So, code for ‘kabbadi’ can be ‘jin’ or ‘te’.

The least possible diagram for the given statements is as follows

Conclusions:

I. Some candle being light is a possibility.→ False (Any part of wax can never be light)

II. Some wax is not light. → True (It is definitely true)          

Hence, only II follows.

The least possible diagram for the given statements is as follows

Conclusions:

I. Few fruits are green → True (It is definitely true)

II. No fruit is green → False (It is definitely false)

Hence, only I follows.

The least possible diagram for the given statements is as follows

Conclusions:

I. Some cooler is air conditioner. → False (It is possible but not definite)

II. No cooler is air conditioner. → False (It is possible but not definite)

Both are complementary conclusions.

Hence, either I or II follows.

Given: Six persons, namely, J, K, L, M, N, and P, have different weights.

1. J is heavier than exactly two persons. 

_ > _ > _ > J > _ > _

2. P is heavier than exactly one person. 

_ > _ > _ > J > P > _

3. N is neither the heaviest nor the lightest person. 

Case 1: _ > _ > N > J > P > _

Case 2: _ > N > _ > J > P > _

4. K is heavier than L but lighter than M.

Case 1: M > K > N > J > P > L

Case 2: M > N > K > J > P > L

5. N is not heavier than K.

Now, we can eliminate Case 2.

This is our final arrangement,

Case 1: M > K > N > J > P > L

Hence, the correct answer is M.

Given: Six persons, namely, J, K, L, M, N, and P, have different weights.

1. J is heavier than exactly two persons. 

_ > _ > _ > J > _ > _

2. P is heavier than exactly one person. 

_ > _ > _ > J > P > _

3. N is neither the heaviest nor the lightest person. 

Case 1: _ > _ > N > J > P > _

Case 2: _ > N > _ > J > P > _

4. K is heavier than L but lighter than M.

Case 1: M > K > N > J > P > L

Case 2: M > N > K > J > P > L

5. N is not heavier than K.

Now, we can eliminate Case 2.

This is our final arrangement,

Case 1: M > K > N > J > P > L

Hence, the correct answer is Two.

Given: Six persons, namely, J, K, L, M, N, and P, have different weights.

1. J is heavier than exactly two persons. 

_ > _ > _ > J > _ > _

2. P is heavier than exactly one person. 

_ > _ > _ > J > P > _

3. N is neither the heaviest nor the lightest person. 

Case 1: _ > _ > N > J > P > _

Case 2: _ > N > _ > J > P > _

4. K is heavier than L but lighter than M.

Case 1: M > K > N > J > P > L

Case 2: M > N > K > J > P > L

5. N is not heavier than K.

Now, we can eliminate Case 2.

This is our final arrangement,

Case 1: M > K > N > J > P > L

Hence, the correct answer is L.

Given word: ADVENTUREFUL

First, fourth, sixth, and tenth letters of the word = A, E, T, F

Meaningful word - FATE (your future; something that happens to you) and FEAT (something you do that shows great strength, skill or courage)

Hence, the correct answer is Y.

Given: 7 boxes, namely, J, K, L, M, N, O, and P, are placed one above the other in a stack, but not necessarily in the same order.

1. Box N is placed third from the bottom.

 

2. Only one box is placed between N and P.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

 

3. Three boxes are placed between P and L.

 

4. Box K is placed immediately below L.

Now, we can eliminate Case 2.

 

5. Box M is placed two boxes above Box K.

 

6. Box J is placed above Box O.

This is our final arrangement,

 

Hence, the correct answer is Box P.

Given: 7 boxes, namely, J, K, L, M, N, O, and P, are placed one above the other in a stack, but not necessarily in the same order.

1. Box N is placed third from the bottom.

 

2. Only one box is placed between N and P.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

 

3. Three boxes are placed between P and L.

 

4. Box K is placed immediately below L.

Now, we can eliminate Case 2.

 

5. Box M is placed two boxes above Box K.

 

6. Box J is placed above Box O.

This is our final arrangement,

 

Hence, the correct answer is Four.

Given: 7 boxes, namely, J, K, L, M, N, O, and P, are placed one above the other in a stack, but not necessarily in the same order.

1. Box N is placed third from the bottom.

 

2. Only one box is placed between N and P.

Here, we have 2 Cases, i.e., Case 1 and Case 2.

 

3. Three boxes are placed between P and L.

 

4. Box K is placed immediately below L.

Now, we can eliminate Case 2.

 

5. Box M is placed two boxes above Box K.

 

6. Box J is placed above Box O.

This is our final arrangement,

 

Hence, the correct answer is Box M.