Reasoning PYQs

Given series: 

LEFT END  L 4 B Δ W U S = 8 C N F 5 X T @ K O 1 Q V D β 6 A P E J R H + M Z  RIGHT END

Product of all the numbers:

LEFT END  L 4 B Δ W U S = 8 C N F 5 X T @ K O 1 Q V D β 6 A P E J R H + M Z  RIGHT END 

4×8×5×1×6 = 960

Total number of vowels in the series:

LEFT END  L 4 B Δ W U S = 8 C N F 5 X T @ K O 1 Q V D β 6 A P E J R H + M Z  RIGHT END 

There are 4 vowels: U, O, A, E

So, 960 ÷ 4 = 240

Hence, 240 is the correct answer.

Given series: 

LEFT END  L 4 B Δ W U S = 8 C N F 5 X T @ K O 1 Q V D β 6 A P E J R H + M Z  RIGHT END

By placing 7 elements from the right end between the 8^th and 9^th element from the left end.

LEFT END  L 4 B Δ W U S = E J R H + M Z 8 C N F 5 X T @ K O 1 Q V D β 6 A P  RIGHT END

7^th element in the new arrangement from the left end:

LEFT END  L 4 B Δ W U S = E J R H + M Z 8 C N F 5 X T @ K O 1 Q V D β 6 A P  RIGHT END

Clearly, S is the seventh element from the left end after the arrangement.

Hence, S is the correct answer.

Below table represents symbols used to draw a family tree,

1. S is mother of O, who is mother of Q.

2. N is mother of M.

3. S is married.

4. Q’s father is son-in-law of M. So, M must be husband of S.

5. The gender of P and Q is same. So, P must be father of Q, who must be male member.

We can draw the following Family Tree from the information given above:

Hence, N is Mother-in-law of S.

Below table represents symbols used to draw a family tree,

1. S is mother of O, who is mother of Q.

2. N is mother of M.

3. S is married.

4. Q’s father is son-in-law of M. So, M must be husband of S.

5. The gender of P and Q is same. So, P must be father of Q, who must be male member.

We can draw the following Family Tree from the information given above:

Hence, O is daughter of S.

Below table represents symbols used to draw a family tree,

1. S is mother of O, who is mother of Q.

2. N is mother of M.

3. S is married.

4. Q’s father is son-in-law of M. So, M must be husband of S.

5. The gender of P and Q is same. So, P must be father of Q, who must be male member.

We can draw the following Family Tree from the information given above:

  Hence, M is grandfather of Q.

Nine persons: J, K, L, M, N, O, P, Q, R

Faces both directions North and South.

1. J sits 4^th from one of the extreme ends.

2. K sits 5^th to the right of J.

3. Two persons sit between K and N and both K and N are facing towards the north.

4. One person sits between N and P, who sits to the immediate left of Q.

5. R sits third to the right of P, who faces south.

6. O sits to the immediate left of both L and J.

7. M and R face the same direction.

Clearly, R sits immediate right of J.

Nine persons: J, K, L, M, N, O, P, Q, R

Faces both directions North and South.

1. J sits 4^th from one of the extreme ends.

2. K sits 5^th to the right of J.

3. Two persons sit between K and N and both  K and N are facing towards the north.

4. One person sits between N and P, who sits to the immediate left of Q.

5. R sits third to the right of P, who faces south.

6. O sits to the immediate left of both L and J.

7. M and R face the same direction.

Clearly, all except K are facing south direction.

Nine persons: J, K, L, M, N, O, P, Q, R

Faces both directions North and South.

1. J sits 4^th from one of the extreme ends.

2. K sits 5^th to the right of J.

3. Two persons sit between K and N and both  K and N are facing towards the north.

4. One person sits between N and P, who sits to the immediate left of Q.

5. R sits third to the right of P, who faces south.

6. O sits to the immediate left of both L and J.

7. M and R face the same direction.

Hence, L sits fourth to the left of N.

Nine persons: J, K, L, M, N, O, P, Q, R

Faces both directions North and South.

1. J sits 4^th from one of the extreme ends.

2. K sits 5^th to the right of J.

3. Two persons sit between K and N and both  K and N are facing towards the north.

4. One person sits between N and P, who sits to the immediate left of Q.

5. R sits third to the right of P, who faces south.

6. O sits to the immediate left of both L and J.

7. M and R face the same direction.

Hence, R sits between J and N as well as O and Q.

Nine persons: J, K, L, M, N, O, P, Q, R

Faces both directions North and South.

1. J sits 4^th from one of the extreme ends.

2. K sits 5^th to the right of J.

3. Two persons sit between K and N and both  K and N are facing towards the north.

4. One person sits between N and P, who sits to the immediate left of Q.

5. R sits third to the right of P, who faces south.

6. O sits to the immediate left of both L and J.

7. M and R face the same direction.

Hence, Number of persons sitting to the right of N is equal to number of persons sitting to the left of J.

Persons: M1, M2, M3, M4, M5, M6 and M7.

1. At least three persons score better marks than M5.
2. The score of M7 is 37, which is the lowest marks that anyone has scored.
3. M2 scores better marks than M4 but notbetter than that of M5.
4. Person, who scored 2^nd highest marks, scored 88 marks.
5. Neither M1 nor M6 scored 88 marks.

 

Either M6 or M1 scored the highest marks.

Hence, ‘Cannot be determined’ is the correct answer.

Persons: M1, M2, M3, M4, M5, M6 and M7.

1. At least three persons score better marks than M5.
2. The score of M7 is 37, which is the lowest marks that anyone has scored.
3. M2 scores better marks than M4 but notbetter than that of M5.
4. Person, who scored 2^nd highest marks, scored 88 marks.
5. Neither M1 nor M6 scored 88 marks.

 

Either M6 or M1 scored the highest marks.

If M2 scores 67 then the arrangement is:

 

Hence, the possible score of M4 is 55.

Persons: M1, M2, M3, M4, M5, M6 and M7.

1. At least three persons score better marks than M5.
2. The score of M7 is 37, which is the lowest marks that anyone has scored.
3. M2 scores better marks than M4 but notbetter than that of M5.
4. Person, who scored 2^nd highest marks, scored 88 marks.
5. Neither M1 nor M6 scored 88 marks.

 

Either M6 or M1 scored the highest marks.

Hence, three persons score better marks than M5.

From the statement of Rahul: Exam can be on 13, 14, 15, 16, 17, and 18.

From the statement of Sahil: Exam can be on 14, 15, 16, 17, 18 and 19.

From the statement of Sonali: Exam can be on 16, 17, 18, 19, 20 and 21.

Here, combining all three statements the exam could be on 16, 17 or 18.

Hence, the exact date of their exam can not be determined.

Let us check the options

I. X > N = O ≥ S > P → N > P

II. X = N ≥ O ≥ S = P → S ≤ X

III. X > N ≥ O ≥ S = P → S < X, N ≥ P

IV. X > N > O ≥ S ≥ P → N > P

Hence, the correct sequence of symbols to satisfy the given condition is “>, ≥, =”.

Let us check each option:

A < B ≤ I = N < R < T → B < T

A < B < I ≤ N < R = T → B < T

A > B ≥ I = N ≥ R ≥ T → B ≥ T

A > B > I = N > R ≥ T → B > T

A > B = I ≥ N > R = T → B > T

Hence, the correct sequence of symbols to satisfy the given condition is “>, ≥, =, ≥, ≥”.

Let us check each option:

1. H > C < T < Y; C = L > J; J ≥ Z = A → Y > L; L > A

2. H > C = T < Y; C = L < J; J ≥ Z < A → Y > L; relation between L and A can’t be determined

3. H > C = T < Y; C = L = J; J ≥ Z < A → Y > L; relation between L and A can’t be determined.

4. H > C < T < Y; C = L ≥ J; J ≥ Z ≥ A → Y > L; L ≥ A as required.

5. H > C < T < Y; C = L = J; J ≥ Z > A → Y > L; L > A.

Hence, ‘<, ≥, >’ are to be placed so that both Y > L and L ≥ A hold definitely true.

Persons: A, B, C, D, E, F, G, H, I, J and K.

1**.** There are two people sitting between A and B. 2. G is the immediate neighbor of I and B. 3. I and A are not immediate members. 4. The number of persons between A and G is the same as the number of persons between K and A. 5. There is one person between H and F. H is not a immediate member of I and K.

6.There are three people between H and D. One of the neighbors of H is C. 7. E and J are immediate neighbors. 8. J sits to the immediate left of E.

So, Case 1, Case 2, Case 1B, Case 2B is invalid. 9. E and A are not immediate neighbors.

So. Case 2A is invalid.

The final arrangement is,

 

Hence, K is sitting third to the left of H.

Persons: A, B, C, D, E, F, G, H, I, J and K.

1. There are two people sitting between A and B.
2. G is the immediate neighbor of I and B.
3. I and A are not immediate members.
4. The number of persons between A and G is the same as the number of persons between K and A.
5. There is one person between H and F. H is not a immediate member of I and K.

6.There are three people between H and D. One of the neighbors of H is C. 7. E and J are immediate neighbors. 8. J sits to the immediate left of E.

So, Case 1, Case 2, Case 1B, Case 2B is invalid. 9. E and A are not immediate neighbors.

So. Case 2A is invalid.

The final arrangement is,

 

Hence, If I and J interchange their position, D sits to the immediate right of J.

Persons: A, B, C, D, E, F, G, H, I, J and K.

1. There are two people sitting between A and B.
2. G is the immediate neighbor of I and B.
3. I and A are not immediate members.
4. The number of persons between A and G is the same as the number of persons between K and A.
5. There is one person between H and F. H is not a immediate member of I and K.

6.There are three people between H and D. One of the neighbors of H is C. 7. E and J are immediate neighbors. 8. J sits to the immediate left of E.

So, Case 1, Case 2, Case 1B, Case 2B is invalid. 9. E and A are not immediate neighbors.

So. Case 2A is invalid.

The final arrangement is,

In DB, EH, JC and AF the first person is seated third to the right of the second person.

In GK the first person is seated third to the left of the second person

Hence, GK is the odd one out.