Let water in container A = 7x
Let rum in container A = 4x
Total volume of container A = 11x
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Volume of vodka in container B = volume of rum in container A
volume of vodka in container B = 4x
Volume of rum in container B = 4x × (7/8) = 3.5x
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Volume of rum in container B = vodka in container C
vodka in container C = 3.5x
Volume of rum in container C = 2 × 3.5x = 7x
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Volume of container B = volume of container C
volume of water + (3.5x + 4x) = 3.5x + 7x
volume of water + 7.5x = 10.5x
volume of water in container B = 3x
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Volume of water in container D = 2 × water in container B
Volume of water container D = 2 × 3x = 6x
Volume of vodka in container D = 6x x (5/3) = 10x
total volume of container D = 10x + 6x = 16x
Difference of volume in container A and D = 16x - 11x = 5x
5x = 50
x = 10
value of x is solved and volume of every term is obtained in term of x , so on solving
| LIQUID | A | B | C | D |
|---|
| WATER | 70 | 30 | | 60 |
| RUM | 40 | 35 | 70 | |
| VODKA | - | 40 | 35 | 100 |
| TOTAL | 110 | 105 | 105 | 160 |
Volume of container B = 105 l (given)
Volume of containers C = 105 l (given)
Total volume of container B and C = 105 + 105 = 210 l
Volume of container D = 160 l (given)
Required ratio = 21 : 16