Reasoning PYQs

1. A is sitting second from one of the ends.

(Here, we will have two cases, Case 1: when A is second from the left end and Case 2: when A is second from the right end).

2. There are two persons sitting between A and B.

 

3. Four persons are sitting between B and D.

4. D is sitting just left of C.

 

5. F sits three places away to the right of B.

(Here, we can eliminate case 2 as A is already three places away to the right of B).

6. E sits at the extreme right end of the row.

7. G sits to the immediate right of B.

8. Two persons are sitting between C and E.

Hence, the final arrangement will be as follows:

Hence, G is sitting exactly between A and D.

1. A is sitting second from one of the ends.

(Here, we will have two cases, Case 1: when A is second from the left end and Case 2: when A is second from the right end).

2. There are two persons sitting between A and B.

3. Four persons are sitting between B and D.

4. D is sitting just left of C.

5. F sits three places away to the right of B.

(Here, we can eliminate case 2 as A is already three places away to the right of B).

6. E sits at the extreme right end of the row.

7. G sits to the immediate right of B.

8. Two persons are sitting between C and E.

Hence, the final arrangement will be as follows:

Hence, C is sitting third to the left of E.

Given word: JABBERING

The given word can be represented as follows,

Hence, we can see that 3 such pairs are there → Forward: AB, BG; Backward: GI

So, the answer is three pairs.

RENT - A tenant's regular payment to a landlord for the use of property or land.

TERN- A seabird related to the gulls, typically smaller and more slender, with long pointed wings and a forked tail.

Hence, M is the correct answer.

Students: A, B, C, P, Q, R.

1) The number of books that A has is the average of the number of books of B and C. It means A has books in between B and C because average always implies the mid value.

2) B has more books than P but not more than C. Hence we have the below order, 

C > A > B > P > __ > __

3) The number of books that R has is the average of the number of books of P and Q. It means R has books in between P and Q.

4) At least two members have less books than P. There are two places remaining in the order R will be in the middle of P and Q because R is the average of P and Q.

So the final arrangement will be ,

C > A > B > P > R > Q

Hence, C has the highest number of books.

Students: A, B, C, P, Q, R.

1) The number of books that A has is the average of the number of books of B and C. It means A has books in between B and C because average always implies the mid value.

2) B has more books than P but not more than C. Hence we have the below order, 

C > A > B > P > __ > __

3) The number of books that R has is the average of the number of books of P and Q. It means R has books in between P and Q.

4) At least two members have less books than P. There are two places remaining in the order R will be in the middle of P and Q because R is the average of P and Q.

So the final arrangement will be ,

C > A > B > P > R > Q

Hence**, B** has books in between A and P.

Students: A, B, C, P, Q, R.

1) The number of books that A has is the average of the number of books of B and C. It means A has books in between B and C because average always implies the mid value.

2) B has more books than P but not more than C. Hence we have the below order, 

C > A > B > P > __ > __

3) The number of books that R has is the average of the number of books of P and Q. It means R has books in between P and Q.

4) At least two members have less books than P. There are two places remaining in the order R will be in the middle of P and Q because R is the average of P and Q.

So the final arrangement will be ,

C > A > B > P > R > Q

Hence, Four students have more books than R.

From the given instructions:

1. B is to the northwest of E and one floor is between B and C. So, here we have three cases:

Case 1;

 

Case 2;

 

Case 3;

 

2) D lives just above A in the same flat.

Case 1;

 

Case 2;

 

Case 3;

 

So, here we can see that Case 1 is invalid as there is no space to place D and A. So, Case 1 gets eliminated.

3. D and E do not live on the same floor. 

Case 2;

 

Case 3;

 

So, here we can see that Case 2 is invalid because D and E lives on same floor. So, Case 2 gets eliminated.

So, Final Arrangement:

 

F lives just above C in the same flat.

From the given instructions:

1. B is to the northwest of E and one floor is between B and C. So, here we have three cases:

Case 1;

 

Case 2;

 

Case 3;

 

2) D lives just above A in the same flat.

Case 1;

 

Case 2;

 

Case 3;

 

So, here we can see that Case 1 is invalid as there is no space to place D and A. So, Case 1 gets eliminated.

3. D and E do not live on the same floor. 

Case 2;

 

Case 3;

 

So, here we can see that Case 2 is invalid because D and E lives on same floor. So, Case 2 gets eliminated.

So, Final Arrangement:

One person is living between D and E in the same flat.

From the given instructions:

1. B is to the northwest of E and one floor is between B and C. So, here we have three cases:

Case 1;

 

Case 2;

 

Case 3;

 

2) D lives just above A in the same flat.

Case 1;

 

Case 2;

 

Case 3;

 

So, here we can see that Case 1 is invalid as there is no space to place D and A. So, Case 1 gets eliminated.

3. D and E do not live on the same floor. 

Case 2;

 

Case 3;

 

So, here we can see that Case 2 is invalid because D and E lives on same floor. So, Case 2 gets eliminated.

So, Final Arrangement:

All options except A lives on odd floor.

So, A is the odd one out.

From the given instructions:

1. B is to the northwest of E and one floor is between B and C. So, here we have three cases:

Case 1;

 

Case 2;

 

Case 3;

 

2) D lives just above A in the same flat.

Case 1;

 

Case 2;

 

Case 3;

 

So, here we can see that Case 1 is invalid as there is no space to place D and A. So, Case 1 gets eliminated.

3. D and E do not live on the same floor. 

Case 2;

 

Case 3;

 

So, here we can see that Case 2 is invalid because D and E lives on same floor. So, Case 2 gets eliminated.

So, Final Arrangement:

Four people live below D.

From the given instructions:

1. B is to the northwest of E and one floor is between B and C. So, here we have three cases:

Case 1;

 

Case 2;

 

Case 3;

 

2) D lives just above A in the same flat.

Case 1;

 

Case 2;

 

Case 3;

 

So, here we can see that Case 1 is invalid as there is no space to place D and A. So, Case 1 gets eliminated.

3. D and E do not live on the same floor. 

Case 2;

 

Case 3;

 

So, here we can see that Case 2 is invalid because D and E lives on same floor. So, Case 2 gets eliminated.

So, Final Arrangement:

D lives to the northeast of F.

Seven friends - A, B, C, D, E, F, and G.

(1) C is facing in the north direction. (2) Only three persons are sitting between B and C and neither of them is sitting at any of the ends. (3) A sits third to the right of C. (4) D sits at the fourth position from the right end. (5) No two persons sitting together are facing in the same direction. (6) G sits second to the right of E.

Now, only F left, therefore the final seating arrangement is as follows:

Hence, A sits second to the right of F.

Seven friends - A, B, C, D, E, F, and G.

(1) C is facing in the north direction. (2) Only three persons are sitting between B and C and neither of them is sitting at any of the ends. (3) A sits third to the right of C. (4) D sits at the fourth position from the right end. (5) No two persons sitting together are facing in the same direction. (6) G sits second to the right of E.

Now, only F left, therefore the final seating arrangement is as follows:

We can see that all the persons in options are facing south, thus forming a group except C.

Hence, C does not belong to that group.

Seven friends - A, B, C, D, E, F, and G.

(1) C is facing in the north direction. (2) Only three persons are sitting between B and C and neither of them is sitting at any of the ends. (3) A sits third to the right of C. (4) D sits at the fourth position from the right end. (5) No two persons sitting together are facing in the same direction. (6) G sits second to the right of E.

Now, only F left, therefore the final seating arrangement is as follows:

Hence, one person sits between B and D

Seven friends - A, B, C, D, E, F, and G.

(1) C is facing in the north direction. (2) Only three persons are sitting between B and C and neither of them is sitting at any of the ends. (3) A sits third to the right of C. (4) D sits at the fourth position from the right end. (5) No two persons sitting together are facing in the same direction. (6) G sits second to the right of E.

Now, only F left, therefore the final seating arrangement is as follows:

We can see that A sits third to the right of C and D sits to the immediate right of A.

Hence, D sits to the immediate right of the person who sits third to the right of C.

Seven friends - A, B, C, D, E, F, and G.

(1) C is facing in the north direction. (2) Only three persons are sitting between B and C and neither of them is sitting at any of the ends. (3) A sits third to the right of C. (4) D sits at the fourth position from the right end. (5) No two persons sitting together are facing in the same direction. (6) G sits second to the right of E.

Now, only F left, therefore the final seating arrangement is as follows:

We can see that F sits second to the left of A and E does not sit to the immediate right of F.

Hence, E sits to the immediate right of the person who sits second to the left of A is false.

The least possible diagram for the given statements is as follows;

Conclusions:

I. Some Mobiles are Bags → False (As No Mobile is Bag, no part of Mobile will be Bag. So, it is false)

II. All Mobiles are Bags → False (As No Mobile is Bag, no part of Mobile will be Bag. So, it is false)

Hence, Neither conclusion I nor II follows.

The least possible diagram for the given statements is as follows;

Conclusions:

l.​ Some Copies are not Dictionary → True (As common part of Copies and Magazines is not a Dictionary. So, it is true) 

II. No Clips are Magzanie. → False (there is no direct relation between Clip and Magzanie whether it is true or not. So, it is false) 

Hence, Only I Follows.

Venn diagram for the given statements are follows

Conclusions

I. All Display can never be Tablet - True (Given Some Display is Screen and No Screen is Tablet Thus Some Display is also not Tablet so All Display can never be Tablet follows)

II. All Tablet can be Display - True (Given Some Display part which is Screen is not Tablet but the remaining part of the Display can be Tablet so All the Tablet can be Display follows)

Hence, Both I and II follows.

Additional Information

 ‘Only a few’ is equivalent to ‘Some’ + ‘Some not’.

If it is given that ‘Only a few A are B’ then conclusions ‘Some A are B’ and Some A are not B’ would always be considered as True.