Reasoning PYQs

Solutions:

The least possible Venn diagram for the given statements is as follows

Conclusions:

1. Some daisy can be Rose ⇒ True ( As there is no relation between daisy and Rose, so it is possible)
2. Some Lily is not daisy ⇒ True ( As lily which is lotus can never be a daisy, so some lily is not daisy is true)

Hence, Both conclusions I and II follow.

Solution:

The least possible Venn diagram for the given statements is as follows,

Conclusions:

I. No bucky is captain. →  False (it is possible but not definite, because no direct relation between bucky and captain is given)

II. Some america is bucky. →  False (because only captain can be america)

Hence, Neither I nor II follows is the correct answer.

Additional Information:

Only captain is america means all america is captain and no other element can be america.

Only a few captain are hydra means some captains are hydra and some are not.

The least possible Venn diagram for the given statements is as follow

Conclusions:

I. Some mugs are table → False (It is possible but not definite)

II. No chair is cup → False (It is possible but not definite) 

Hence, neither conclusion I nor conclusion II follows.

Given series: H % 1 P ! F S ? * X 7 C T 4 $ 9 3 > @ / 6 N Q 5

1. Letters which are immediately preceded by consonants and immediately followed by a symbol

H % 1 P ! F S ? * X 7 C T 4 $ 9 3 > @ / 6 N Q 5

Hence, only one letter is there which is immediately preceded by consonants and immediately followed by a symbol i.e. FS?

Given Series: H % 1 P ! F S ? * X 7 C T 4 $ 9 3 > @ / 6 N Q 5

1. On dropping all the numbers, the arrangement is

Left Side H % P ! F S ? * X C T $ > @ / N Q Right Side

Right Side + Left Side = Left Side

5^th to the Right + 4^th to the Left = 9^th from the Left

Left Side H % P ! F S ? * X C T $ > @ / N Q Right Side

Hence, X is fifth to the right of fourth to the left end$.

Given Series: H % 1 P ! F S ? * X 7 C T 4 $ 9 3 > @ / 6 N Q 5

1. On dropping all the symbols, the arrangement is

Left Side H 1 P F S X 7 C T 49 3 6 N Q 5 Right Side

2. Element which is sixth from the right end

Left Side H 1 P F S X 7 C T 4 9 3 6 N Q 5 Right Side

Hence, 9 is sixth from the right end$.

Given Series: H % 1 P ! F S ? * X 7 C T 4 $ 9 3 > @ / 6 N Q 5

1. Numbers between ‘*’ and ‘>’

H % 1 P ! F S ? * X 7 C T 4 $ 9 3> @ / 6 N Q 5

Hence, the sum of the numbers between ‘*’ and ‘>’ = 7 + 4 + 9 + 3 = 23

Given Series: H % 1 P ! F S ? * X 7 C T 4 $ 9 3 > @ / 6 N Q 5

1. Numbers which are immediately followed by a symbol

H % 1 P ! F S ? * X 7 C T 4 $ 9 3 >@ / 6 N Q 5

Hence, two numbers are there which are immediately followed by a symbol- 4$ and 3>$

People: A, B, C, D, E, Q, R, and S.

1. Only two people sit between B and C.

2. S is an immediate neighbor of who faces C.

3. Only one person sits between S and R. R is not an immediate neighbor of E.

4. Q faces D.

5. D is an immediate left of A.

Hence, no one sits between Q and who faces A.

People: A, B, C, D, E, Q, R, and S.

1. Only two people sit between B and C.

2. S is an immediate neighbor of who faces C.

3. Only one person sits between S and R. R is not an immediate neighbor of E.

4. Q faces D.

5. D is an immediate left of A.

Hence, S and Q are immediate neighbors to each other is true.

People: A, B, C, D, E, Q, R, and S.

1. Only two people sit between B and C.

2. S is an immediate neighbor of who faces C.

3. Only one person sits between S and R. R is not an immediate neighbor of E.

4. Q faces D.

5. D is an immediate left of A.

Hence, the one who faces Q sits second to the left of C.

People: A, B, C, D, E, Q, R, and S.

1. Only two people sit between B and C.

2. S is an immediate neighbor of who faces C.

3. Only one person sits between S and R. R is not an immediate neighbor of E.

4. Q faces D.

5. D is an immediate left of A.

All except B does not sit at any end of the line.

Hence, B is the one that does not belong to the group.

People: A, B, C, D, E, Q, R, and S.

1. Only two people sit between B and C.

2. S is an immediate neighbor of who faces C.

3. Only one person sits between S and R. R is not an immediate neighbor of E.

4. Q faces D.

5. D is an immediate left of A.

Hence, C and R sit the extreme end of the row.

The logic followed here is:

The second letter has been obtained by adding 1 to the face value of the first letter and the third letter has been obtained by adding 2 to the face value of the second letter. 

Now, we check the given options one by one to find the odd one out as follows:

1. I,J,L → This pattern clearly follows the logic as mentioned above.
2. R,S,U → This pattern clearly follows the logic as mentioned above.
3. D,E,G → This pattern clearly follows the logic as mentioned above.
4. L,M,P → This pattern clearly doesn't follow the logic as mentioned above. We have to add 3 to the face value of M to get P.
5. W,X,Z → This pattern clearly follows the logic as mentioned above. 

Therefore, we see that L,M,P is the odd one out. 

Hence, L,M,P is the odd one out.

Given series: 309     312     319     324     327

On finding the difference between the first and third digit we get:

309 → 6

312 → 1

319 → 6

324 → 1

327 → 4

On multiplying the difference with 3:

309 → 6 × 3 → 18

312 → 1 × 3 → 3

319 → 6 × 3 → 18

324 → 1 × 3 → 3

327 → 4 × 3 → 12

Here only 18 is available in the result.

Hence answer is 18.

Given series: 309     312     319     324     327

When all the digits are clubbed then the series becomes:

309312319324327

On arranging the digits clubbed in ascending order from left side, we get:

011222333334799

12^th digit in the result is 4.

Hence answer is 4.

Given series: 309     312     319     324     327

Finding the highest number and lowest number, we get the maximum difference between two three-digit numbers:

Highest Number = 327

Lowest Number = 309

Difference = 327 - 309 = 18

Hence, the answer is 18.

Given series: 309     312     319     324     327

Considering the middle digits of all the given numbers:

0     1     1     2     2

Adding the middle digits, the sum becomes 0+1+1+2+2 =6 

Hence answer is 6.

Given series: 309     312     319     324     327

The numbers that are divisible by 3 are 309, 312, 324, and 327

On adding the number, we get:

309 + 312 + 324 + 327 = 1272

1272 is not divisible by 7 in the given options.

Hence answer is 7.

**Given

Statement:

** A > N = Q > T ≤ Y ≤ S < U

Conclusion: 

I. T < S → False (T ≤ Y ≤ S → T ≤ S)

II. T = S → False (T ≤ Y ≤ S → T ≤ S)

But they form complementary pair.

Hence, Either I or II follows.