RRB Clerk Prelims Memory Based Paper (Held On: 10 August 2024 Shift 3) (Previous Year Paper)

Given: Seven persons live on seven different floors numbered as 1, 2 and so on.

Based on the given conditions, we get the following possibilities-

1.K lives on the floor which is sixth from the top. Only two persons live above M. From these, we get-

 

2. U lives two floors below M. T lives on the floor that immediately above U. From these, we get-

 

3. V lives for floors above K. A doesn't live on the first floor. V doesn't live above A. From these, we get the final table as follows-

 

Therefore, from the final table, we see that G lives on the first floor.

Hence, G lives on the first floor.

Given: Seven persons live on seven different floors numbered as 1, 2 and so on.

Based on the given conditions, we get the following possibilities-

1.K lives on the floor which is sixth from the top. Only two persons live above M. From these, we get-

 

2. U lives two floors below M. T lives on the floor that immediately above U. From these, we get-

 

3. V lives for floors above K. A doesn't live on the first floor. V doesn't live above A. From these, we get the final table as follows-

 

Therefore, from the final table, we see that U lives three floors below V.

Hence, U lives three floors below V.

Given: Seven persons live on seven different floors numbered as 1, 2 and so on.

Based on the given conditions, we get the following possibilities-

1.K lives on the floor which is sixth from the top. Only two persons live above M. From these, we get-

 

2. U lives two floors below M. T lives on the floor that immediately above U. From these, we get-

 

3. V lives for floors above K. A doesn't live on the first floor. V doesn't live above A. From these, we get the final table as follows-

 

Therefore, from the final table, we see that five persons live below V. 

Hence, five persons live below V.

Given: Seven persons live on seven different floors numbered as 1, 2 and so on.

Based on the given conditions, we get the following possibilities-

1.K lives on the floor which is sixth from the top. Only two persons live above M. From these, we get-

 

2. U lives two floors below M. T lives on the floor that immediately above U. From these, we get-

 

3. V lives for floors above K. A doesn't live on the first floor. V doesn't live above A. From these, we get the final table as follows-

 

Therefore, from the final table, we see that U lives on the fifth floor when counted form the top.

Hence, U lives on the fifth floor when counted form the top.

Given: Seven persons live on seven different floors numbered as 1, 2 and so on.

Based on the given conditions, we get the following possibilities-

1.K lives on the floor which is sixth from the top. Only two persons live above M. From these, we get-

 

2. U lives two floors below M. T lives on the floor that immediately above U. From these, we get-

 

3. V lives for floors above K. A doesn't live on the first floor. V doesn't live above A. From these, we get the final table as follows-

 

Therefore, from the final table, we see that the number of persons living below M and G is the same as the number of persons living below T. 

Hence, the number of persons living below M and G is the same as the number of persons living below T.

Solutions:

The least possible Venn diagram for the given statements is as follows

Conclusions:

1. Some daisy can be Rose ⇒ True ( As there is no relation between daisy and Rose, so it is possible)
2. Some Lily is not daisy ⇒ True ( As lily which is lotus can never be a daisy, so some lily is not daisy is true)

Hence, Both conclusions I and II follow.

Solution:

The least possible Venn diagram for the given statements is as follows,

Conclusions:

I. No bucky is captain. →  False (it is possible but not definite, because no direct relation between bucky and captain is given)

II. Some america is bucky. →  False (because only captain can be america)

Hence, Neither I nor II follows is the correct answer.

Additional Information:

Only captain is america means all america is captain and no other element can be america.

Only a few captain are hydra means some captains are hydra and some are not.

The least possible Venn diagram for the given statements is as follow

Conclusions:

I. Some mugs are table → False (It is possible but not definite)

II. No chair is cup → False (It is possible but not definite) 

Hence, neither conclusion I nor conclusion II follows.

Given series: H % 1 P ! F S ? * X 7 C T 4 $ 9 3 > @ / 6 N Q 5

1. Letters which are immediately preceded by consonants and immediately followed by a symbol

H % 1 P ! F S ? * X 7 C T 4 $ 9 3 > @ / 6 N Q 5

Hence, only one letter is there which is immediately preceded by consonants and immediately followed by a symbol i.e. FS?

Given Series: H % 1 P ! F S ? * X 7 C T 4 $ 9 3 > @ / 6 N Q 5

1. On dropping all the numbers, the arrangement is

Left Side H % P ! F S ? * X C T $ > @ / N Q Right Side

Right Side + Left Side = Left Side

5^th to the Right + 4^th to the Left = 9^th from the Left

Left Side H % P ! F S ? * X C T $ > @ / N Q Right Side

Hence, X is fifth to the right of fourth to the left end.

Given Series: H % 1 P ! F S ? * X 7 C T 4 $ 9 3 > @ / 6 N Q 5

1. On dropping all the symbols, the arrangement is

Left Side H 1 P F S X 7 C T 49 3 6 N Q 5 Right Side

2. Element which is sixth from the right end

Left Side H 1 P F S X 7 C T 4 9 3 6 N Q 5 Right Side

Hence, 9 is sixth from the right end.

Given Series: H % 1 P ! F S ? * X 7 C T 4 $ 9 3 > @ / 6 N Q 5

1. Numbers between ‘*’ and ‘>’

H % 1 P ! F S ? * X 7 C T 4 $ 9 3> @ / 6 N Q 5

Hence, the sum of the numbers between ‘*’ and ‘>’ = 7 + 4 + 9 + 3 = 23

Given Series: H % 1 P ! F S ? * X 7 C T 4 $ 9 3 > @ / 6 N Q 5

1. Numbers which are immediately followed by a symbol

H % 1 P ! F S ? * X 7 C T 4 $ 9 3 >@ / 6 N Q 5

Hence, two numbers are there which are immediately followed by a symbol- 4$ and 3>

People: A, B, C, D, E, Q, R, and S.

1. Only two people sit between B and C.

2. S is an immediate neighbor of who faces C.

3. Only one person sits between S and R. R is not an immediate neighbor of E.

4. Q faces D.

5. D is an immediate left of A.

Hence, no one sits between Q and who faces A.

People: A, B, C, D, E, Q, R, and S.

1. Only two people sit between B and C.

2. S is an immediate neighbor of who faces C.

3. Only one person sits between S and R. R is not an immediate neighbor of E.

4. Q faces D.

5. D is an immediate left of A.

Hence, S and Q are immediate neighbors to each other is true.

People: A, B, C, D, E, Q, R, and S.

1. Only two people sit between B and C.

2. S is an immediate neighbor of who faces C.

3. Only one person sits between S and R. R is not an immediate neighbor of E.

4. Q faces D.

5. D is an immediate left of A.

Hence, the one who faces Q sits second to the left of C.

People: A, B, C, D, E, Q, R, and S.

1. Only two people sit between B and C.

2. S is an immediate neighbor of who faces C.

3. Only one person sits between S and R. R is not an immediate neighbor of E.

4. Q faces D.

5. D is an immediate left of A.

All except B does not sit at any end of the line.

Hence, B is the one that does not belong to the group.

People: A, B, C, D, E, Q, R, and S.

1. Only two people sit between B and C.

2. S is an immediate neighbor of who faces C.

3. Only one person sits between S and R. R is not an immediate neighbor of E.

4. Q faces D.

5. D is an immediate left of A.

Hence, C and R sit the extreme end of the row.

The logic followed here is:

The second letter has been obtained by adding 1 to the face value of the first letter and the third letter has been obtained by adding 2 to the face value of the second letter. 

Now, we check the given options one by one to find the odd one out as follows:

1. I,J,L → This pattern clearly follows the logic as mentioned above.  2. R,S,U → This pattern clearly follows the logic as mentioned above.  3. D,E,G → This pattern clearly follows the logic as mentioned above.  4. L,M,P → This pattern clearly doesn't follow the logic as mentioned above. We have to add 3 to the face value of M to get P.  5. W,X,Z → This pattern clearly follows the logic as mentioned above. 

Therefore, we see that L,M,P is the odd one out. 

Hence, L,M,P is the odd one out.

Given series: 309     312     319     324     327

On finding the difference between the first and third digit we get:

309 → 6

312 → 1

319 → 6

324 → 1

327 → 4

On multiplying the difference with 3:

309 → 6 × 3 → 18

312 → 1 × 3 → 3

319 → 6 × 3 → 18

324 → 1 × 3 → 3

327 → 4 × 3 → 12

Here only 18 is available in the result.

Hence answer is 18.

Given series: 309     312     319     324     327

When all the digits are clubbed then the series becomes:

309312319324327

On arranging the digits clubbed in ascending order from left side, we get:

011222333334799

12^th digit in the result is 4.

Hence answer is 4.

Given series: 309     312     319     324     327

Finding the highest number and lowest number, we get the maximum difference between two three-digit numbers:

Highest Number = 327

Lowest Number = 309

Difference = 327 - 309 = 18

Hence, the answer is 18.

Given series: 309     312     319     324     327

Considering the middle digits of all the given numbers:

0     1     1     2     2

Adding the middle digits, the sum becomes 0+1+1+2+2 =6 

Hence answer is 6.

Given series: 309     312     319     324     327

The numbers that are divisible by 3 are 309, 312, 324, and 327

On adding the number, we get:

309 + 312 + 324 + 327 = 1272

1272 is not divisible by 7 in the given options.

Hence answer is 7.

Given Statement: A > N = Q > T ≤ Y ≤ S < U

Conclusion: 

I. T < S → False (T ≤ Y ≤ S → T ≤ S)

II. T = S → False (T ≤ Y ≤ S → T ≤ S)

But they form complementary pair.

Hence, Either I or II follows.

Given Statement: H > K ≤ L = M < N < Q = S

Conclusions:

I. M < S → True (M < N ≤ Q = S → M < S)

II. Q < K → False (K ≤ L = M < N < Q → K < Q)

Hence, Only conclusion I follows.

Given Statement: A > B = C < D < P > Q

Conclusions:

I. A < D → False ( A > B = C < D no definite relationship between A and D can be determined).

II. P > C → True (C < D < P → P > C)

Hence, Only II is true

Given word: ACKNOWLEDGEMENTS

The fourth, seventh, eighth, and sixteenth letters are N, L, E, and S respectively.

There is only one word that can be formed using these letters i.e. LENS.

Therefore, the second letter from the right end of the word 'LENS' is N. 

Hence, the required letter is N.

Given: A person went to the supermarket to buy six products. The products he buys are Clips, Cheese, Chocolates, Pens, Milk, and Scissors but not necessarily in the same order. 

Based on the given conditions, we get the following possibilities-

1. Cheese was the last item to be bought. Scissors were bought two products before Cheese. From these, we get-

 

2.  Pens were the second product to be bought. Two products were bought between Pens and Chocolates. From these, we get-

 

3. Clips weren't the first product to be bought. From this, we get the final table as follows-

 

Therefore, from the final table, we see that chocolates is the second last product to have been bought. 

Hence, chocolates is the second last product to have been bought.

Given: A person went to the supermarket to buy six products. The products he buys are Clips, Cheese, Chocolates, Pens, Milk, and Scissors but not necessarily in the same order. 

Based on the given conditions, we get the following possibilities-

1. Cheese was the last item to be bought. Scissors were bought two products before Cheese. From these, we get-

 

2.  Pens were the second product to be bought. Two products were bought between Pens and Chocolates. From these, we get-

 

3. Clips weren't the first product to be bought. From this, we get the final table as follows-

 

Therefore, from the final table, we see that no products were bought between Pens and Clips.  

Hence, zero products were bought between Pens and Clips.

Given: A person went to the supermarket to buy six products. The products he buys are Clips, Cheese, Chocolates, Pens, Milk, and Scissors but not necessarily in the same order. 

Based on the given conditions, we get the following possibilities-

1. Cheese was the last item to be bought. Scissors were bought two products before Cheese. From these, we get-

 

2.  Pens were the second product to be bought. Two products were bought between Pens and Chocolates. From these, we get-

 

3. Clips weren't the first product to be bought. From this, we get the final table as follows-

 

Therefore, from the final table, we see that Milk was bought immediately before Pens.  

Hence, Milk was bought immediately before Pens.

Given: A person went to the supermarket to buy six products. The products he buys are Clips, Cheese, Chocolates, Pens, Milk, and Scissors but not necessarily in the same order. 

Based on the given conditions, we get the following possibilities-

1. Cheese was the last item to be bought. Scissors were bought two products before Cheese. From these, we get-

 

2.  Pens were the second product to be bought. Two products were bought between Pens and Chocolates. From these, we get-

 

3. Clips weren't the first product to be bought. From this, we get the final table as follows-

 

Therefore, from the final table, we see that four products were bought before chocolates.  

Hence, four products were bought before chocolates.

Given: A person went to the supermarket to buy six products. The products he buys are Clips, Cheese, Chocolates, Pens, Milk, and Scissors but not necessarily in the same order. 

Based on the given conditions, we get the following possibilities-

1. Cheese was the last item to be bought. Scissors were bought two products before Cheese. From these, we get-

 

2.  Pens were the second product to be bought. Two products were bought between Pens and Chocolates. From these, we get-

 

3. Clips weren't the first product to be bought. From this, we get the final table as follows-

 

Therefore, from the final table, we see that the number of products bought after Clips is the same as the number of products that were bought before Scissors and that is three products. 

Hence, the number of products bought after Clips is the same as the number of products that were bought before Scissors.

Given: An uncertain number of persons are sitting in a linear row, facing the north.

Based on the given conditions, we get the following arrangements:

1. M sits fourth from the right end of the row. M sits second to the right of L. G sits seventh to the left of M. From these, we get-

2. The number of persons sitting between R and G is two. Only three persons sit between S and L. L sits to the right of S. From these, we get-

3. K sits third to the left of R. Only four persons sit to the left of N. Only one person sits between K and N. From these, we get-

4. N sits second to the right of V. From this, we get the final arrangement as follows:

From the final arrangement, we see that G sits to the immediate left of S.

Hence, G sits to the immediate left of S.

Given: An uncertain number of persons are sitting in a linear row, facing the north.

Based on the given conditions, we get the following arrangements:

1. M sits fourth from the right end of the row. M sits second to the right of L. G sits seventh to the left of M. From these, we get-

2. The number of persons sitting between R and G is two. Only three persons sit between S and L. L sits to the right of S. From these, we get-

3. K sits third to the left of R. Only four persons sit to the left of N. Only one person sits between K and N. From these, we get-

4. N sits second to the right of V. From this, we get the final arrangement as follows:

From the final arrangement, we see that 10 persons sit between K and L.

Hence, 10 persons sit between K and L.

Given: An uncertain number of persons are sitting in a linear row, facing the north.

Based on the given conditions, we get the following arrangements:

1. M sits fourth from the right end of the row. M sits second to the right of L. G sits seventh to the left of M. From these, we get-

2. The number of persons sitting between R and G is two. Only three persons sit between S and L. L sits to the right of S. From these, we get-

3. K sits third to the left of R. Only four persons sit to the left of N. Only one person sits between K and N. From these, we get-

4. N sits second to the right of V. From this, we get the final arrangement as follows:

From the final arrangement, we see that a total of 23 persons are sitting in the row.

Now, 23 ÷ 6 gives us 3 as the quotient and 5 as the remainder.

Hence, the required remainder is 5.

The alphabets are positioned in the following order:

The word can be represented as follows:

In forward direction: “CF”

Thus, there is one pair of letters in the word “TACKIFIES” as according to the English alphabetical series.

Hence, one is the correct answer.

According to the given information, we get the following figure,

Hence, Point B is in the North-East direction with respect to F.

According to the given information, we get the following figure,

The first point is in North West from the second point.

Hence, Option D is different.

According to the given information, we get the following figure,

Hence, Point C is in the South West direction with respect to F.

Given:

Initial ratio of milk to water = 11 : 3

26 liters of milk is added, then another 13 liters of milk is added.

Final ratio of milk to water = 12 : 3

Let:

Initial quantity of milk = 11x liters

Initial quantity of water = 3x liters

26 liters + 13 liters = 39 liters

Final milk = 11x + 39

(11x + 39) : 3x = 12 : 3

(11x + 39) / 3x = 4

11x + 39 = 12x

39 = 12x - 11x

x = 39

Initial milk = 11x = 11 x 39 = 429 liters

The initial quantity of milk in the mixture was 429 liters.

Bull's work rate = 1 field / 5 days = 1 / 5 field/day

Buffalo's work rate =1 field / 10 days = 1 / 10 field/day

3 Bulls = 3 × 1 / 5 = 3 / 5 field/day

2 Buffaloes = 2 × 1 / 10 = 2 / 10 = 1 / 5 field/day

Total work rate = (3 / 5) + (1 / 5) = 4 / 5 field/day

Time = Total Work / Work Rate =  1field / (4/5 field/day) = 5 / 4 days = 1.25 days

Thus, the correct answer is 1.25 days.

Let the greater number be x.

Then, the smaller number = (x/2) + 13 

Given:

Difference = x - [(x/2) + 13] = 30

x - (x/2) - 13 = 30

x/2 = 30 + 13

x/2 = 43

x = 86

Thus, the correct answer is 86.

Given:

Perimeter (P) = 40 cm

Difference between length and breadth = l - b = 6 cm

Perimeter formula for a rectangle:

P = 2(l + b)

Substituting the given perimeter:

2l + b = 40

l + b = 20.......................(Equation 1)

Given difference:

l - b = 6............................(Equation 2)

Add Equation 1 and Equation 2:

(l + b) + (l  - b) = 20 + 6

2l = 26

l = 13cm

Substitute l = 13 into Equation 1:

13 + b = 20

b = 7cm

A = l × b = 13 × 7 = 91cm²

Thus, the correct answer is 91 cm²

Books sold by P = 32

Books sold by S = 50

Difference = 50 (S) - 32 (P) = 18

Percentage increase = 18 / 32 × 100% = 56.25%

Thus, the correct answer is 56.25%.

Books sold by Q on Saturday = 36

If Shop Q sold 25% more books on Sunday than on Saturday , then

Sunday sales = 36 (Saturday) + 25% of 36 = 36 + 9 = 45

Thus, the correct answer is 45.

Given Data:

Shop P sold 32 books

Shop Q sold 36 books

Total books P + Q = 32 + 36 = 68

Online sales = 25% × 68 = 0.25 × 68 = 17

Offline sales = Total books - Online sales = 68 - 17 = 51

Thus, 51 books were sold to offline customers by Shop P and Q combined.

Sum of books sold by P and R:

P + R = 32 + 30 = 62

Sum of books sold by Q and S:

Q + S = 36 + 50 = 86

Ratio = 62:86=31:4362:86 = 31:43

Thus, the correct answer is 31:43.

Person A (July): 5 × 23 = 115

Person D (July): 4 × 35 = 140

Ratio = 115:140 = 23:28.

Total Tasks = 43 (March) + 53 (April) + 39 (June) = 135

Average = Total Tasks / Number of Months = 135 / 3 = 45

Thus, the average number of tasks completed by Shop D in March, April, and June is 45.

From the table:

Tasks completed by B in April = 45

Tasks completed by D in April = 53

Total tasks completed by B and D together in April:

45 + 53 = 98

From the table:

Tasks completed by A in March = 53

Tasks completed by C in March = 41

Total tasks completed by A and C together in March:

53 + 41 = 94

The ratio of tasks completed by B and D together in April to tasks completed by A and C together in March is:

98 / 94 = 49 / 47

Thus, the ratio is 49:47.

From the table:

March: 41

April: 69

May: 28

June: 42

Total tasks by C:

41 + 69 + 28 + 42 = 180

From the table:

March: 33

April: 45

May: 37

June: 35

Total tasks by B:

33 + 45 + 37 + 35 = 150

Difference = Total tasks by C - Total tasks by B = 180 - 150 = 30

The percentage difference is calculated relative to the total tasks completed by B:

Percentage Difference =Difference / Total tasks by B × 100 = 30 / 150 × 100 = 20%

Thus, the number of tasks completed by Person C in all months is 20% more than the number of tasks completed by Person B in all months.

From the table, the number of tasks completed by each person in April is:

A: 23

B: 45

C: 69

D: 53

Total tasks in April:

23 + 45 + 69 + 53 = 190

From the table, the number of tasks completed by each person in May is:

A: 40

B: 37

C: 28

D: 35

Total tasks in May:

40 + 37 + 28 + 35 = 140

Difference = Total Tasks in April Total Tasks in May = 190 - 140 = 50

Thus, the difference between the number of tasks completed by all in April and May is 50.

From the table:

Tasks completed by A in March = 53

Tasks completed by A in April = 23

Tasks completed by A in May = 40

Tasks completed by A in June = 54

Total tasks completed by A:

53 + 23 + 40 + 54 = 170

From the table:

Tasks completed by A in June = 54

Tasks completed by B in June = 35

Tasks completed by C in June = 42

Tasks completed by D in June = 39

Total tasks completed by all persons in June:

54 + 35 + 42 + 39 = 170

Percentage = Tasks by A / Tasks by All in June × 100 = 170 / 170 × 100 = 100%

Thus, the number of tasks completed by Person A in all months is 100% of the tasks completed by all persons in June.

GIVEN:

11.11% of 819 + 55% of 800 = ?

FORMULA USED:

These types of questions, the knowledge of conversion from percentage to fraction should be known.

 

Concept :

Follow BODMAS rule to solve this question, as per the order given below.

Step - 1: Parts of an equation enclosed in 'Brackets' must be solved first, and following BODMAS rule in the bracket -

Step - 2: Any mathematical 'Of' or 'Exponent' must be solved next.

Step - 3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated.

Step - 4: Last but not the least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

CALCULATION:

11.11% of 819 = (1/9) × 819 = 91

55% of 400 = (11/20) × 400 = 220

Given expression is

11.11% of 819 + 55% of 400 = ?

⇒ 91 + 220 = ?

⇒ 311 = ?

∴ ? = 311

Follow BODMAS rule to solve this question, as per the order given below.

Step-1: Parts of an equation enclosed in 'Brackets' must be solved first, and following BODMAS rule in the bracket -

Step-2: Any mathematical 'Of' or 'Exponent' must be solved next.

Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated.

Step-4: Last but not the least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Since, we need to find out the approximate value, we can write these values to their nearest integers.

Given expression is

8 × 6 + 3 - 6/2 = ?

⇒ 48 + 3 - 3 = ?

⇒ ? = 48

Follow BODMAS rule to solve this question, as per the order given below.

Step-1: Parts of an equation enclosed in 'Brackets' must be solved first, and following BODMAS rule in the bracket -

Step-2: Any mathematical 'Of' or 'Exponent' must be solved next.

Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated.

Step-4: Last but not the least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Since, we need to find out the approximate value, we can write these values to their nearest integers.

Given expression is

4000 + 500 ÷ 50 - 820 = 10 ×?

⇒ 4000 + 10 - 820 = 10 × ?

⇒ ? = 319

Concept used:

Calculation:

1/16 of 48 + 97% of ? = ?

⇒ 1/16 × 48 + 97/100 × ? = ?

⇒ 3 + 0.97 × ? = ?

⇒ 3 = ?(1 - 0.97)

⇒ 3 = 0.03 × ?

⇒ ? = 3/0.03

⇒ ? = 100

∴ The value of ? is 100.

The double "?" indicates that there is one unknown at 2 places in the question

Follow BODMAS rule to solve this question, as per the order given below.

Step-1: Parts of an equation enclosed in 'Brackets' must be solved first, and following BODMAS rule in the bracket -

Step-2: Any mathematical 'Of' or 'Exponent' must be solved next.

Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated.

Step-4: Last but not the least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Since, we need to find out the approximate value, we can write these values to their nearest integers.

CALCULATION:

512^(1/9) × 729^(1/6) = ?^(1/2)

⇒ 512^{(1/3 × 1/3)} × 729 ^{(1/3 × 1/ 2)} = ?^1/2

⇒ 8^1/3 × 9^1/2 = ?^{1 / 2}

⇒ 2 × 3 = ?^1/2

⇒ 6 = ?^1/2

∴ ? = 36.

Concept used:

Follow BODMAS rule to solve this question, as per the order given below.

Calculation:

65% of 800 – 56 ÷ ? = 29

⇒ 520 – 56 ÷ ? = 512

⇒ 520 – 512 = 56 ÷ ?

⇒ 8 = 56 ÷ ?

⇒ ? = 7

∴ The value of ? is 7

Concept used:

Follow BODMAS rule to solve this question, as per the order given below.

Calculation:

720 – (1/3) of 450 = 6 × ?

⇒ 720 – 150 = 6 × ?

⇒ 570/6 = ?

⇒ ? = 95

∴ The value of ? is 95

Follow BODMAS rule to solve this question, as per the order given below, 

Step-1: Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket, 

Step-2: Any mathematical 'Of' or 'Exponent' must be solved next, 

Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated, 

Step-4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated 

[992 ÷ 32 × 5 + (360 ÷ 45)] =? 

⇒[31 × 5 + (8)] = ?

⇒ [155 + 8] = ?

∴ ? = 163

Follow BODMAS rule to solve this question, as per the order given below,  

Step-1: Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket, 

Step-2: Any mathematical 'Of' or 'Exponent' must be solved next, 

Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated, 

Step-4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated 

56 ÷ √? × 30 = 6720

⇒ (56 × 30)/√? = 6720

⇒ 1/√? = 6720/(56 × 30)

⇒ 1/√? = 4

∴ ? = 1/16

Follow BODMAS rule to solve this question, as per the order given below.

Step - 1: Parts of an equation enclosed in 'Brackets' must be solved first, and following BODMAS rule in the bracket -

Step - 2: Any mathematical 'Of' or 'Exponent' must be solved next.

Step - 3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated.

Step - 4: Last but not the least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Given expression is

1/4 of 42 – 12 of 1500% + 32 = ?

⇒  4 – 12 × 15 + 9 = ?

⇒ 4 – 180 + 9 = ?

∴ ? = - 167

Follow BODMAS rule to solve this question, as per the order given below.

Step - 1: Parts of an equation enclosed in 'Brackets' must be solved first, and following BODMAS rule in the bracket -

Step - 2: Any mathematical 'Of' or 'Exponent' must be solved next.

Step - 3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated.

Step - 4: Last but not the least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Given expression is

15% of 500 + 12% of 250 – 102 = ?

⇒ 75 + 30 – 102 = ?

⇒ 3 = ?

∴ ? = 3

Follow BODMAS rule to solve this question, as per the order given below, 

Step-1: Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket, 

Step-2: Any mathematical 'Of' or 'Exponent' must be solved next, 

Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated, 

Step-4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated 

105 + 35 – 23 × 5 = √?

⇒ 140 – 115 = √?

⇒ 25 = √?

∴ ? = 625

Given:

∛512 × √36 – ? × 16 = 16

Concept:

Calculation:

∛512 × √36 – ? × 16 = 16

⇒ 8 × 6 – ? × 16 = 16

⇒ 48 – ? × 16 = 16

⇒ 48 – 16 = ? × 16

⇒ 32 = ? × 16

∴ ? = 2

Concept:

Follow BODMAS rule to solve this question, as per the order given below.

Step - 1: Parts of an equation enclosed in 'Brackets' must be solved first, and following BODMAS rule in the bracket -

Step - 2: Any mathematical 'Of' or 'Exponent' must be solved next.

Step - 3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated.

Step - 4: Last but not the least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Calculation:

Given expression is 

(84 × 16 ÷ 4 of 3 - 2) =? - 45 

⇒ (84 × 16 ÷ 12 - 2) =? - 45 

⇒ (84 × (4/3) - 2) =? - 45 

⇒ (112 - 2) = ? - 45

⇒ 110 + 45 =?

∴ ? = 155

Follow BODMAS rule to solve this question, as per the order given below, 

Step-1: Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket, 

Step-2: Any mathematical 'Of' or 'Exponent' must be solved next, 

Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated, 

Step-4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated 

14% of 300 + 18% of 500 = ?

⇒ 42 + 90 = ?

∴ ? = 132

Given:

Age of Leo : Age of David = 4 : 3

Age of Leo after 5 years : Age of David after 5 years = 9 : 7

Calculation:

Let us assume,

Present age of Leo = 4x

Present age of David = 3x

Difference in their ages = 4x – 3x = x

ATQ,

(4x + 5)/(3x + 5) = 9/7

⇒ 28x + 35 = 27x + 45

⇒ x = 10

∴ Difference in their ages is 10 years.

Given: 

Mean of 5 number = 30

When one of the numbers is excluded, the mean gets reduced by 4.

Calculation:

Sum of these 5 number = (30 × 5) = 150

Mean of the remaining 4 numbers = (30 - 4) = 26

Sum of these remaining 4 number = (26 × 4) = 104

Excluded number = (Sum of the given 5 numbers) - (sum of the remaining 4 numbers) = 150 - 104  =  46

∴ The excluded number is 46

Given:

Interest = 4005

Rate = 9%

Time = 5 years

Formula:

Simple interest = Principal × rate × time/100

Calculations:

Principal = (100 × 4005)/5 × 9

⇒ (100 × 4005)/45

⇒ Rs 8900

∴ The sum is Rs. 8900

GIVEN :

Ratio of income of A and B = 3 : 2

Ratio of expenditure of A and B = 8 : 5

 

CONCEPT :

Ratio method

 

ASSUMPTION :

Let the income of A and B be 3x and 2x respectively

And, let the expenditure of A and B be 8y and 5y respectively

 

CALCULATION :

According to question

3x – 8y = 6000     ----(1)

2x – 5y = 5000     ----(2)

By equating equation 1 and 2

We get x = 10,000 and y = 3000

So, income of A = 3 × 10000 = Rs. 30,000

The series follows the following pattern:

10 + 2² = 14

14 + 3³ = 41

41 + 5² = 66

66 + 7³ = 409

409 + 11² = 530

The series follows the following pattern:

9 × 2 = 18

18 × 3 = 54

54 × 4 = 216

216 × 5 = 1080

1080 × 6 = 6480

The series follows the following pattern:

100 – 11 = 89

89  – 10 = 79

79  – 11 = 68

68 – 10 = 58

58 – 11 = 47

∴ The missing term in the series is  47.

The series follows the following pattern:

2 + 5 = 7

7 + 7 = 14

14 + 9 = 23

23 + 11 = 34

34 + 13 = 47

∴ The missing term in the series is 23.

The series follows the following pattern:

24 + 4 = 28

28 + 8 = 36

36 + 16 = 52

52 + 32 = 84

84 + 64 = 148

Given:

Manisha scores 35% and fail by 15 marks

Deepti scores 45% marks and get 35 more than the passing marks

Calculations:

Let total number in examination be x.

Manisha’s passing marks = x × 35/100 + 15

Deepti’s passing marks = x × 45/100 – 35

⇒ x × 35/100 + 15 = x × 45/100 – 35

⇒ 10x/100 = 50

⇒ x = 500

Manisha’s score = 500 × 35/100 = 175

Deepti’s score = 500 × 45/100 = 225

Passing marks = 225 – 35 = 190

∴ Passing marks = 190.

Given:

Ratio of X and Y capital = 5 : 2.

Formula used:

Share of profit = amount invested × time period

Calculation:

Ratio of share of profit = X : Y

(5 × 10) : (2 × t) = 5 : 1; t = 5 months