Reasoning PYQs

1. N is sitting at one end, and only two people are sitting between N and L.

 

 

2. Q is an immediate neighbor of one who is sitting at extreme end. No one is sitting between Q and M, who is sitting at extreme end

 

 

3. P is sitting to the immediate left of L and only two persons are sitting between P and O

 

 

4. R is an immediate neighbor of neither O nor Q

Hence, case 2 gets canceled.

So, the final arrangement will be

 

 

Hence, P is sitting second to the left of S.

1. N is sitting at one end, and only two people are sitting between N and L.

2. Q is an immediate neighbor of one who is sitting at extreme end. No one is sitting between Q and M, who is sitting at extreme end

3. P is sitting to the immediate left of L and only two persons are sitting between P and O

4. R is an immediate neighbor of neither O nor Q

Hence, case 2 gets canceled.

So, the final arrangement will be

Hence, Three people are sitting between R and O.

1. N is sitting at one end, and only two people are sitting between N and L.

2. Q is an immediate neighbor of one who is sitting at extreme end. No one is sitting between Q and M, who is sitting at extreme end

3. P is sitting to the immediate left of L and only two persons are sitting between P and O

4. R is an immediate neighbor of neither O nor Q

Hence, case 2 gets canceled.

So, the final arrangement will be

Hence, M is sitting fourth to the right of L.

1. N is sitting at one end, and only two people are sitting between N and L.

2. Q is an immediate neighbor of one who is sitting at extreme end. No one is sitting between Q and M, who is sitting at extreme end

3. P is sitting to the immediate left of L and only two persons are sitting between P and O

4. R is an immediate neighbor of neither O nor Q

Hence, case 2 gets canceled.

So, the final arrangement will be

Hence, O is sitting third to the right of P.

1. N is sitting at one end, and only two people are sitting between N and L.

2. Q is an immediate neighbor of one who is sitting at extreme end. No one is sitting between Q and M, who is sitting at extreme end

3. P is sitting to the immediate left of L and only two persons are sitting between P and O

4. R is an immediate neighbor of neither O nor Q

Hence, case 2 gets canceled.

So, the final arrangement will be

Immediate to the left of O → S

Second to the right of S → Q

Hence, Q is sitting second to the right of one, who is sitting immediate to the left of O.

The least possible diagram for the given statement is as follows,

Conclusions:

I. Some Cities is not Country → False (As there is no direct or negative relation between cities and country, it is possible that some cities can be country. So, some cities is not country is false. Hence, it does not follow) 

II. All Country being Cities is a possibility →True (As there is no direct or negative relation between cities and country, all country being cities is a possibility. Hence, it follows) 

Thus, Only Conclusion II follows.

The least possible Venn Diagram for the given statements will be as follows,

 

I. Some false can be wrong → False (as no false is correct and all wrong is correct. certainly, no false is wrong)

II. Some true can be correct → True (as we know only some true cannot be correct but there might be some true which is correct. So, the possibility holds true)

Hence, only II follow.

The least possible Venn diagram;

Conclusion :

I. Some ground are pond → True (As we can see from the diagram some part of pond is ground, Hence some ground are pond is true)

II. Some pond are land → True ( As we can see from diagram some part of pond is land, Hence some pond are land is true)

since both the conclusions are true Hence, both I and II follow.

Given- VOUCHERING

1^st, 2^nd, 6^th, and 9^th letters are - V, O, E, and N. 

Meaningful word is- OVEN.

(left end) O V E N (right end)

Hence, the second letter from the left end of the word is V.

Given: Eight friends deposit money on eight different days of four different months.

Based on the given conditions, we get the following possibilities-

1. L deposits on the second allotted date of the month that contains 30 days. N is the last person to deposit the money. From these, we get-

 

2. W deposits the money on the 8^th of May. W and F deposits in the same month. S deposits the money in the month of November. From these, we get-

 

3. B deposits the money in the month of January.  U deposit immediately before B.  X doesn’t deposit in the same month as N. From these, we get the final table as follows-

 

From the final table, we see that X deposits money on the 8^th of June.

Hence, X deposits in the month of June.

Given: Eight friends deposit money on eight different days of four different months.

Based on the given conditions, we get the following possibilities-

1. L deposits on the second allotted date of the month that contains 30 days. N is the last person to deposit the money. From these, we get-

 

2. W deposits the money on the 8^th of May. W and F deposits in the same month. S deposits the money in the month of November. From these, we get-

 

3. B deposits the money in the month of January.  U deposit immediately before B.  X doesn’t deposit in the same month as N. From these, we get the final table as follows-

 

From the final table, we see that U and B deposits in the same month.

Hence, U deposits in the same month as B.

Given: Eight friends deposit money on eight different days of four different months.

Based on the given conditions, we get the following possibilities-

1. L deposits on the second allotted date of the month that contains 30 days. N is the last person to deposit the money. From these, we get-

 

2. W deposits the money on the 8^th of May. W and F deposits in the same month. S deposits the money in the month of November. From these, we get-

 

3. B deposits the money in the month of January.  U deposit immediately before B.  X doesn’t deposit in the same month as N. From these, we get the final table as follows-

 

From the final table, we see that L deposits money on the 27^th of June.

Hence, L deposits on the 27^th of June.

Given: Eight friends deposit money on eight different days of four different months.

Based on the given conditions, we get the following possibilities-

1. L deposits on the second allotted date of the month that contains 30 days. N is the last person to deposit the money. From these, we get-

 

2. W deposits the money on the 8^th of May. W and F deposits in the same month. S deposits the money in the month of November. From these, we get-

 

3. B deposits the money in the month of January.  U deposit immediately before B.  X doesn’t deposit in the same month as N. From these, we get the final table as follows-

 

From the final table, we see that W and F deposit in the month of May.

Hence, the required pair is W and F.

Given: Eight friends deposit money on eight different days of four different months.

Based on the given conditions, we get the following possibilities-

1. L deposits on the second allotted date of the month that contains 30 days. N is the last person to deposit the money. From these, we get-

 

2. W deposits the money on the 8^th of May. W and F deposits in the same month. S deposits the money in the month of November. From these, we get-

 

3. B deposits the money in the month of January.  U deposit immediately before B.  X doesn’t deposit in the same month as N. From these, we get the final table as follows-

 

From the final table, we see that all of them deposit money on the 8^th of the month except B.

Hence, B is the odd one out.

Consider the series given:

6 6 5 9 9 6 9 9 6 2 1 6 7 9 9 9 8 5 2 6 9 5 9 5 9 5 6 9 9

Thus, there are 8 numbers that are prime.

Consider the series given:

6 6 5 9 9 6 9 9 6 2 1 6 7 9 9 9 8 5 2 6 9 5 9 5 9 5 6 9 9

Unique digits present in the sequence are 1 2 5 6 7 8 9 and the unique digits that are divisible by 2 are 2 6 8

Thus, there are 3 digits that are divisible by 2.

Consider the series given:

6 6 5 9 9 6 9 9 6 2 1 6 7 9 9 9 8 5 2 6 9 5 9 5 9 5 6 9 9

From the above sequence we can say that number 9 is repeated for 12 times in the series.

Thus, number 9 has the highest frequency in the sequence.

Consider the series given:

6 6 5 9 9 6 9 9 6 2 1 6 7 9 9 9 8 5 2 6 9 5 9 5 9 5 6 9 9

Arranging the numbers in ascending order, we get the following:

1 2 2 5 5 5 5 5 6 6 6 6 6 6 6 7 8 9 9 9 9 9 9 9 9 9 9 9 9

Thus, number 6 is at exactly middle of the sequence.

Consider the series given:

6 6 5 9 9 6 9 9 6 2 1 6 7 9 9 9 8 5 2 6 9 5 9 5 9 5 6 9 9

The highest three-digit number that can be formed from the given digits in the sequence (all three digits need to be unique) is = 987

6 6 5 9 9 6 9 9 6 2 1 6 7 9 9 9 8 5 2 6 9 5 9 5 9 5 6 9 9

The lowest three-digit number that can be formed from the given digits in the sequence is 125

Difference= Highest three-digit number – Lowest three-digit number

Highest number = 987

Lowest number =125

Difference = 987 – 125 = 862

Thus, the difference between highest three-digit number and lowest three-digit number is 862

Given word: HUNGRILY

Now, if the letter of this word are arranged in an alphabetical orders starting from the left to the right, then we get-

(left end) G H I L N R U Y (right end)

Therefore, we see that only one letter, that is Y remains in its original position. The rest of the letters change their positions. 

Hence, the position of only one letter remains unchanged.