Reasoning PYQs

Persons: Dev, Tom, Jak, Esha, Amu, and Hari

Metals: Brass, Gold, Tin, Silver, Copper, and Bronze 

Flat: Flat X and Flat Y 

Floors: 1,2, and 3.

1) Hari is living two floors above the floor of the person who likes Tin in the same type of flat. Esha lives to the southwest of Hari.

 

2) Dev lives northeast of Amu. In Case 2, Dev cannot be placed in the northeast of Amu.

 

3) The person who likes Copper lives to the northwest of the person who likes Bronze metal.

 

4) The person who likes gold lives immediately above the one who likes brass metal in the same type of flat.

Only Silver remains to be placed among the given metals. Place Silver at the remaining place.

 

5) Jak does not live on the same floor as the person who likes Silver. Tom will be placed on Floor 3 of Flat X as that is the only vacant place remaining.

The final arrangement is:

 

Hence, Amu(the person who likes Brass metal) lives in the Flat X on the first floor.

Persons: Dev, Tom, Jak, Esha, Amu, and Hari

Metals: Brass, Gold, Tin, Silver, Copper, and Bronze 

Flat: Flat X and Flat Y 

Floors: 1,2, and 3.

1) Hari is living two floors above the floor of the person who likes Tin in the same type of flat. Esha lives to the southwest of Hari.

 

2) Dev lives northeast of Amu. In Case 2, Dev cannot be placed in the northeast of Amu.

 

3) The person who likes Copper lives to the northwest of the person who likes Bronze metal.

 

4) The person who likes gold lives immediately above the one who likes brass metal in the same type of flat.

Only Silver remains to be placed among the given metals. Place Silver at the remaining place.

 

5) Jak does not live on the same floor as the person who likes Silver. Tom will be placed on Floor 3 of Flat X as that is the only vacant place remaining.

The final arrangement is:

 

The Combination indicates the metal a person likes. Esha likes Gold is only correct as per the logic. Hence, Esha-Gold is the correct combination.

Persons: Dev, Tom, Jak, Esha, Amu, and Hari

Metals: Brass, Gold, Tin, Silver, Copper, and Bronze 

Flat: Flat X and Flat Y 

Floors: 1,2, and 3.

1) Hari is living two floors above the floor of the person who likes Tin in the same type of flat. Esha lives to the southwest of Hari.

 

2) Dev lives northeast of Amu. In Case 2, Dev cannot be placed in the northeast of Amu.

 

3) The person who likes Copper lives to the northwest of the person who likes Bronze metal.

 

4) The person who likes gold lives immediately above the one who likes brass metal in the same type of flat.

Only Silver remains to be placed among the given metals. Place Silver at the remaining place.

 

5) Jak does not live on the same floor as the person who likes Silver. Tom will be placed on Floor 3 of Flat X as that is the only vacant place remaining.

The final arrangement is:

 

Hence, Dev lives immediately below Hari in the same type of flat.

Given word: GRATEFUL

All the consonants are arranged in English alphabetical order followed by all vowels in English alphabetical order then;

 

New Word: FGLRTAEU

So, the third letter from the left end is L.

Hence, the answer is L.

only Five pairs forming are EF, FI, CE, CF, CE 

Hence, there are more than four pairs of letters.

Person: Uma, Joe, Raj, Drake, Nick, Lin, Punit, and Hary

Four of them are sitting at the corners facing toward the center of the table while the other four are sitting at the middle facing away from the table.

1)  Raj sits at the immediate right of Nick, who does not sit in the middle of the table. Two persons are sitting between Hary and Raj.

2) Punit is sitting immediately left of Hary. Lin is sitting second to the right of Uma. 

3) Joe is not facing away from the center. Uma is not an immediate neighbor of Drake. In Case 2, Joe cannot be placed as the people at vacant places are facing away from the center. So, Case 2 is eliminated.

The final arrangement is:

 

Hence, Drake sits second to the left of the one who sits third to the right of Uma.

Person: Uma, Joe, Raj, Drake, Nick, Lin, Punit, and Hary

Four of them are sitting at the corners facing toward the center of the table while the other four are sitting at the middle facing away from the table.

1)  Raj sits at the immediate right of Nick, who does not sit in the middle of the table. Two persons are sitting between Hary and Raj.

2) Punit is sitting immediately left of Hary. Lin is sitting second to the right of Uma. 

3) Joe is not facing away from the center. Uma is not an immediate neighbor of Drake. In Case 2, Joe cannot be placed as the people at vacant places are facing away from the center. So, Case 2 is eliminated.

The final arrangement is:

 

Hence, Hary faces Nick.

Person: Uma, Joe, Raj, Drake, Nick, Lin, Punit, and Hary

Four of them are sitting at the corners facing toward the center of the table while the other four are sitting at the middle facing away from the table.

1)  Raj sits at the immediate right of Nick, who does not sit in the middle of the table. Two persons are sitting between Hary and Raj.

2) Punit is sitting immediately left of Hary. Lin is sitting second to the right of Uma. 

3) Joe is not facing away from the center. Uma is not an immediate neighbor of Drake. In Case 2, Joe cannot be placed as the people at vacant places are facing away from the center. So, Case 2 is eliminated.

The final arrangement is:

 

All the person except Lin are sitting at the corners of the table. Hence, Lin does not belongs to the group.

Person: Uma, Joe, Raj, Drake, Nick, Lin, Punit, and Hary

Four of them are sitting at the corners facing toward the center of the table while the other four are sitting at the middle facing away from the table.

1)  Raj sits at the immediate right of Nick, who does not sit in the middle of the table. Two persons are sitting between Hary and Raj.

2) Punit is sitting immediately left of Hary. Lin is sitting second to the right of Uma. 

3) Joe is not facing away from the center. Uma is not an immediate neighbor of Drake. In Case 2, Joe cannot be placed as the people at vacant places are facing away from the center. So, Case 2 is eliminated.

The final arrangement is:

 

Hence, Raj (the one who is sitting immediate right of Nick) sits third to the left of Hary.

Person: Uma, Joe, Raj, Drake, Nick, Lin, Punit, and Hary

Four of them are sitting at the corners facing toward the center of the table while the other four are sitting at the middle facing away from the table.

1)  Raj sits at the immediate right of Nick, who does not sit in the middle of the table. Two persons are sitting between Hary and Raj.

2) Punit is sitting immediately left of Hary. Lin is sitting second to the right of Uma. 

3) Joe is not facing away from the center. Uma is not an immediate neighbor of Drake. In Case 2, Joe cannot be placed as the people at vacant places are facing away from the center. So, Case 2 is eliminated.

The final arrangement is:

 

Hence, Five persons are sitting between Nick and Joe.​​

Six friends Praveen, Geetu, Nitin, Amit, Manisha, and Kiran have different weights. 

1) Kiran has more weight than Geetu and Manisha but not the highest.

At least two persons' weight is more than Geetu's. Nitin's weight is less than Geetu's but more than Manisha's. 

__ > Kiran > Geetu > Nitin > Manisha> __

2. The average weight of Praveen and Amit is equal to that of Nitin. Praveen has more weight than Nitin.

Weight of Nitin = (Weight of Praveen + Weight of Amit) / 2

This implies that Nitin's weight lies between the weight of Praveen and Amit.(Praveen > Nitin > Amit)

Praveen > Kiran > Geetu > Nitin > Manisha> Amit

3) The lowest weight is fifty-two and the highest weight is Seventy.

Praveen(70) > Kiran > Geetu > Nitin > Manisha> Amit(52)

4) Nitin's weight is the average of Praveen's weight and Amit's weight. So, weight of Nitin = (70 + 52) / 2 = 61.

The final arrangement is:

Praveen (70) > Kiran > Geetu > Nitin (61) > Manisha> Amit (52)

Hence, the difference in the age of Nitin and Praveen is nine years.

Six friends Praveen, Geetu, Nitin, Amit, Manisha, and Kiran have different weights. 

1) Kiran has more weight than Geetu and Manisha but not the highest.

At least two persons' weight is more than Geetu's. Nitin's weight is less than Geetu's but more than Manisha's. 

__ > Kiran > Geetu > Nitin > Manisha> __

2. The average weight of Praveen and Amit is equal to that of Nitin. Praveen has more weight than Nitin.

Weight of Nitin = (Weight of Praveen + Weight of Amit) / 2

This implies that Nitin's weight lies between the weight of Praveen and Amit.(Praveen > Nitin > Amit)

Praveen > Kiran > Geetu > Nitin > Manisha> Amit

3) The lowest weight is fifty-two and the highest weight is Seventy.

Praveen(70) > Kiran > Geetu > Nitin > Manisha> Amit(52)

4) Nitin's weight is the average of Praveen's weight and Amit's weight. So, weight of Nitin = (70 + 52) / 2 = 61.

The final arrangement is:

Praveen (70) > Kiran > Geetu > Nitin (61) > Manisha> Amit (52)

Nitin weight is not the highest. Also, Kiran weight is more than Amit's but less than Praveen's. So, statements I and III are not true. Hence, Only II (Geetu's weight is more than Manisha's.) is true.

Six friends Praveen, Geetu, Nitin, Amit, Manisha, and Kiran have different weights. 

1) Kiran has more weight than Geetu and Manisha but not the highest.

At least two persons' weight is more than Geetu's. Nitin's weight is less than Geetu's but more than Manisha's. 

__ > Kiran > Geetu > Nitin > Manisha> __

2. The average weight of Praveen and Amit is equal to that of Nitin. Praveen has more weight than Nitin.

Weight of Nitin = (Weight of Praveen + Weight of Amit) / 2

This implies that Nitin's weight lies between the weight of Praveen and Amit.(Praveen > Nitin > Amit)

Praveen > Kiran > Geetu > Nitin > Manisha> Amit

3) The lowest weight is fifty-two and the highest weight is Seventy.

Praveen(70) > Kiran > Geetu > Nitin > Manisha> Amit(52)

4) Nitin's weight is the average of Praveen's weight and Amit's weight. So, weight of Nitin = (70 + 52) / 2 = 61.

The final arrangement is:

Praveen (70) > Kiran > Geetu > Nitin (61) > Manisha> Amit (52)

The weight of Nitin is 61 and the weight of Amit is 52. So, the weight of Manisha would lie between 61 to 52. Hence, the weight of Manisha could be 55.

People: Pam, Andy, Farah, Manu, and Neha

Years:1940, 1953, 1966, 1976, and 1996.

Cities: Mumbai, Bhopal, Noida, Kolkata, and Chennai.

Base year: 2020

1) Andy was born ten years before Neha. Pam who was born in Bhopal was neither born in 1940 nor 1953.

 

2) The person who was born in Noida was born immediately before the one who was born in Kolkata. Andy was not born in Kolkata.

 

3) Manu's age is not divisible by two. The person born in Mumbai is born in a leap year.

Note:

To calculate leap year divide the year by 4. If the year is divisible by 4(zero remainder) then it is a leap year otherwise a normal year.

 

4) Farah is not born in Mumbai.

The final arrangement is:

 

Hence, Pam, Neha and Farah are born in leap year.

People: Pam, Andy, Farah, Manu, and Neha

Years:1940, 1953, 1966, 1976, and 1996.

Cities: Mumbai, Bhopal, Noida, Kolkata, and Chennai.

Base year: 2020

1) Andy was born ten years before Neha. Pam who was born in Bhopal was neither born in 1940 nor 1953.

 

2) The person who was born in Noida was born immediately before the one who was born in Kolkata. Andy was not born in Kolkata.

 

3) Manu's age is not divisible by two. The person born in Mumbai is born in a leap year.

Note:

To calculate leap year divide the year by 4. If the year is divisible by 4(zero remainder) then it is a leap year otherwise a normal year.

 

4) Farah is not born in Mumbai.

The final arrangement is:

 

Hence, the sum of the age of Farah( who is born in Noida) and the one who is born in 1976 is 124 years.

People: Pam, Andy, Farah, Manu, and Neha

Years:1940, 1953, 1966, 1976, and 1996.

Cities: Mumbai, Bhopal, Noida, Kolkata, and Chennai.

Base year: 2020

1) Andy was born ten years before Neha. Pam who was born in Bhopal was neither born in 1940 nor 1953.

 

2) The person who was born in Noida was born immediately before the one who was born in Kolkata. Andy was not born in Kolkata.

 

3) Manu's age is not divisible by two. The person born in Mumbai is born in a leap year.

Note:

To calculate leap year divide the year by 4. If the year is divisible by 4(zero remainder) then it is a leap year otherwise a normal year.

 

4) Farah is not born in Mumbai.

The final arrangement is:

 

Hence, Manu( the one who was born in Kolkata) age is a prime number( 67 years old).

People: Pam, Andy, Farah, Manu, and Neha

Years:1940, 1953, 1966, 1976, and 1996.

Cities: Mumbai, Bhopal, Noida, Kolkata, and Chennai.

Base year: 2020

1) Andy was born ten years before Neha. Pam who was born in Bhopal was neither born in 1940 nor 1953.

 

2) The person who was born in Noida was born immediately before the one who was born in Kolkata. Andy was not born in Kolkata.

 

3) Manu's age is not divisible by two. The person born in Mumbai is born in a leap year.

Note:

To calculate leap year divide the year by 4. If the year is divisible by 4(zero remainder) then it is a leap year otherwise a normal year.

 

4) Farah is not born in Mumbai.

The final arrangement is:

 

Hence, Two persons are born between the one who is born in Bhopal and Kolkata.

People: Pam, Andy, Farah, Manu, and Neha

**Years:**1940, 1953, 1966, 1976, and 1996.

Cities: Mumbai, Bhopal, Noida, Kolkata, and Chennai.

Base year: 2020

1) Andy was born ten years before Neha. Pam who was born in Bhopal was neither born in 1940 nor 1953.

 

2) The person who was born in Noida was born immediately before the one who was born in Kolkata. Andy was not born in Kolkata.

 

3) Manu's age is not divisible by two. The person born in Mumbai is born in a leap year.

Note: To calculate leap year divide the year by 4. If the year is divisible by 4(zero remainder) then it is a leap year otherwise a normal year.

 

4) Farah is not born in Mumbai.

The final arrangement is:

 

Hence, Andy was born in the year 1966.

Given word: BURKINAFASO

5^th, 8^th and 11^th letters of the word BURKINAFASO are: I, F and O

Combining and un-jumbling the letters we do not get any word

Hence, the answer is P.

Given

Statement:

A > P < N = Z > R ≤ O ≥ H = M < D > I ≥ K

Conclusions:

I. Z > H → False (Z > R ≤ O ≥ H, as relation between Z and H cannot be determined)

II. A < O → False ( A > P < N = Z > R ≤ O, as relation between A and O cannot be determined)

Hence, Neither conclusion I nor II follows.