Reasoning PYQs

Box = A, B, C, D, E, F, and G

Fruits = Grapes, Apple, Mango, Banana, Orange, Strawberry, and Guava

1. There are four boxes above box A but below box F.

2. Either box C or box E is at the bottom.

(Implies, box A is not at the bottom. Thus, there is only one possibility now i.e. box F is at the top and box A is at the second position from bottom.)

 

3. The box at the top contains either Apple or Guava.

4. At least five boxes are kept below the box that contains Banana.

(Implies, the box that contains Banana is either at the 6^th position or at the 7^th position from the bottom. Also, according to statement 3, the box that contains Banana is not at the top which means it is at the 6^th position from the bottom.)

 

5. There are three boxes between box C and box B.

(It is only possible if we place box C or box B at the bottom and the other box at the 5^th position from the bottom. Also, according to statement 2, we know that either box C or box E is at the bottom which means that box C is at the bottom and box B is at the 5^th position.)

 

6. The box that contains Apple is just below the box that contains Banana but two boxes above the box that contains Mango.

(Implies, box B contains Apple and the box that contains Mango is at the 3^rd position from bottom.)

 

7. Box G contains either Strawberry or Apple.

(It is clear from the current setup in the table that box G is at the 4^th position. Also, according to statement 3, it is clear that the box at the top does not contain Apple. Implies, the box at the top contains Guava.)

 

8. The box that contains Grapes is two boxes below box E.

(It is only possible if we place box E at the 3^rd position from bottom and the box that contains Grapes at the bottom. Now, only one box i.e. D is left to be placed that we can place at the 6^th position from the bottom as it is the only position left. Also, only one fruit is left to be mapped with its box i.e. Orange, thus, box A contains Orange.)

 

Clearly, box E contains Mango.

Box = A, B, C, D, E, F, and G

Fruits = Grapes, Apple, Mango, Banana, Orange, Strawberry, and Guava

1. There are four boxes above box A but below box F.

2. Either box C or box E is at the bottom.

(Implies, box A is not at the bottom. Thus, there is only one possibility now i.e. box F is at the top and box A is at the second position from bottom.)

 

3. The box at the top contains either Apple or Guava.

4. At least five boxes are kept below the box that contains Banana.

(Implies, the box that contains Banana is either at the 6^th position or at the 7^th position from the bottom. Also, according to statement 3, the box that contains Banana is not at the top which means it is at the 6^th position from the bottom.)

 

5. There are three boxes between box C and box B.

(It is only possible if we place box C or box B at the bottom and the other box at the 5^th position from the bottom. Also, according to statement 2, we know that either box C or box E is at the bottom which means that box C is at the bottom and box B is at the 5^th position.)

 

6. The box that contains Apple is just below the box that contains Banana but two boxes above the box that contains Mango.

(Implies, box B contains Apple and the box that contains Mango is at the 3^rd position from bottom.)

 

7. Box G contains either Strawberry or Apple.

(It is clear from the current setup in the table that box G is at the 4^th position. Also, according to statement 3, it is clear that the box at the top does not contain Apple. Implies, the box at the top contains Guava.)

 

8. The box that contains Grapes is two boxes below box E.

(It is only possible if we place box E at the 3^rd position from bottom and the box that contains Grapes at the bottom. Now, only one box i.e. D is left to be placed that we can place at the 6^th position from the bottom as it is the only position left. Also, only one fruit is left to be mapped with its box i.e. Orange, thus, box A contains Orange.)

 

स्पष्टतः, बॉक्स D सबसे ऊपर से दूसरे स्थान पर स्थित है।

Box = A, B, C, D, E, F, and G

Fruits = Grapes, Apple, Mango, Banana, Orange, Strawberry, and Guava

1. There are four boxes above box A but below box F.

2. Either box C or box E is at the bottom.

(Implies, box A is not at the bottom. Thus, there is only one possibility now i.e. box F is at the top and box A is at the second position from bottom.)

 

3. The box at the top contains either Apple or Guava.

4. At least five boxes are kept below the box that contains Banana.

(Implies, the box that contains Banana is either at the 6^th position or at the 7^th position from the bottom. Also, according to statement 3, the box that contains Banana is not at the top which means it is at the 6^th position from the bottom.)

 

5. There are three boxes between box C and box B.

(It is only possible if we place box C or box B at the bottom and the other box at the 5^th position from the bottom. Also, according to statement 2, we know that either box C or box E is at the bottom which means that box C is at the bottom and box B is at the 5^th position.)

 

6. The box that contains Apple is just below the box that contains Banana but two boxes above the box that contains Mango.

(Implies, box B contains Apple and the box that contains Mango is at the 3^rd position from bottom.)

 

7. Box G contains either Strawberry or Apple.

(It is clear from the current setup in the table that box G is at the 4^th position. Also, according to statement 3, it is clear that the box at the top does not contain Apple. Implies, the box at the top contains Guava.)

 

8. The box that contains Grapes is two boxes below box E.

(It is only possible if we place box E at the 3^rd position from bottom and the box that contains Grapes at the bottom. Now, only one box i.e. D is left to be placed that we can place at the 6^th position from the bottom as it is the only position left. Also, only one fruit is left to be mapped with its box i.e. Orange, thus, box A contains Orange.)

 

Clearly, box F contains Guava.

Box = A, B, C, D, E, F, and G

Fruits = Grapes, Apple, Mango, Banana, Orange, Strawberry, and Guava

1. There are four boxes above box A but below box F.

2. Either box C or box E is at the bottom.

(Implies, box A is not at the bottom. Thus, there is only one possibility now i.e. box F is at the top and box A is at the second position from bottom.)

 

3. The box at the top contains either Apple or Guava.

4. At least five boxes are kept below the box that contains Banana.

(Implies, the box that contains Banana is either at the 6^th position or at the 7^th position from the bottom. Also, according to statement 3, the box that contains Banana is not at the top which means it is at the 6^th position from the bottom.)

 

5. There are three boxes between box C and box B.

(It is only possible if we place box C or box B at the bottom and the other box at the 5^th position from the bottom. Also, according to statement 2, we know that either box C or box E is at the bottom which means that box C is at the bottom and box B is at the 5^th position.)

 

6. The box that contains Apple is just below the box that contains Banana but two boxes above the box that contains Mango.

(Implies, box B contains Apple and the box that contains Mango is at the 3^rd position from bottom.)

 

7. Box G contains either Strawberry or Apple.

(It is clear from the current setup in the table that box G is at the 4^th position. Also, according to statement 3, it is clear that the box at the top does not contain Apple. Implies, the box at the top contains Guava.)

 

8. The box that contains Grapes is two boxes below box E.

(It is only possible if we place box E at the 3^rd position from bottom and the box that contains Grapes at the bottom. Now, only one box i.e. D is left to be placed that we can place at the 6^th position from the bottom as it is the only position left. Also, only one fruit is left to be mapped with its box i.e. Orange, thus, box A contains Orange.)

 

Box E is at the third position from the bottom and it contains Mango.

Box = A, B, C, D, E, F, and G

Fruits = Grapes, Apple, Mango, Banana, Orange, Strawberry, and Guava

1. There are four boxes above box A but below box F.

2. Either box C or box E is at the bottom.

(Implies, box A is not at the bottom. Thus, there is only one possibility now i.e. box F is at the top and box A is at the second position from bottom.)

 

3. The box at the top contains either Apple or Guava.

4. At least five boxes are kept below the box that contains Banana.

(Implies, the box that contains Banana is either at the 6^th position or at the 7^th position from the bottom. Also, according to statement 3, the box that contains Banana is not at the top which means it is at the 6^th position from the bottom.)

 

5. There are three boxes between box C and box B.

(It is only possible if we place box C or box B at the bottom and the other box at the 5^th position from the bottom. Also, according to statement 2, we know that either box C or box E is at the bottom which means that box C is at the bottom and box B is at the 5^th position.)

 

6. The box that contains Apple is just below the box that contains Banana but two boxes above the box that contains Mango.

(Implies, box B contains Apple and the box that contains Mango is at the 3^rd position from bottom.)

 

7. Box G contains either Strawberry or Apple.

(It is clear from the current setup in the table that box G is at the 4^th position. Also, according to statement 3, it is clear that the box at the top does not contain Apple. Implies, the box at the top contains Guava.)

 

8. The box that contains Grapes is two boxes below box E.

(It is only possible if we place box E at the 3^rd position from bottom and the box that contains Grapes at the bottom. Now, only one box i.e. D is left to be placed that we can place at the 6^th position from the bottom as it is the only position left. Also, only one fruit is left to be mapped with its box i.e. Orange, thus, box A contains Orange.)

 

Clearly, box G is at the 4^th position from the bottom.

Persons: P, Q, R, S, T, U, V and W.

Lucky numbers: 10, 13, 17, 18, 25, 30, 33 and 40.

1. T sits third to the right of U and both face in same direction.

2. The lucky number of T is three more than that of P.

3. The one, whose lucky number is 40, sits second to the right of T.

4. The neighbors of U face in same direction.

Case 1:

Case 2:

5. The lucky number of Q is 18 and Q faces towards the center.

6. Neither U nor T is adjacent to Q.

Case 1:

Case 2:

7. The persons adjacent to Q face in same direction. So, case 2 is rejected.

8. S faces towards the center and is not opposite to Q.

9. P sits immediate right of W, whose lucky number is 13.

10. The lucky number of V is greater than that of R. So, the lucky number of V must be 40.

11. The person opposite to R has lucky number 33. So, the lucky number of T and P must be 33 and 30 respectively.

12. The lucky number of S is a prime number. So, the lucky number of S is 17.

Final Case:

Hence, the lucky number of T is 33.

Persons: P, Q, R, S, T, U, V and W.

Lucky numbers: 10, 13, 17, 18, 25, 30, 33 and 40.

1. T sits third to the right of U and both face in same direction.

2. The lucky number of T is three more than that of P.

3. The one, whose lucky number is 40, sits second to the right of T.

4. The neighbors of U face in same direction.

Case 1:

Case 2:

5. The lucky number of Q is 18 and Q faces towards the center.

6. Neither U nor T is adjacent to Q.

Case 1:

Case 2:

7. The persons adjacent to Q face in same direction. So, case 2 is rejected.

8. S faces towards the center and is not opposite to Q.

9. P sits immediate right of W, whose lucky number is 13.

10. The lucky number of V is greater than that of R. So, the lucky number of V must be 40.

11. The person opposite to R has lucky number 33. So, the lucky number of T and P must be 33 and 30 respectively.

12. The lucky number of S is a prime number. So, the lucky number of S is 17.

Final Case:

Hence, T sits immediate left of W.

Persons: P, Q, R, S, T, U, V and W.

Lucky numbers: 10, 13, 17, 18, 25, 30, 33 and 40.

1. T sits third to the right of U and both face in same direction.

2. The lucky number of T is three more than that of P.

3. The one, whose lucky number is 40, sits second to the right of T.

4. The neighbors of U face in same direction.

Case 1:

Case 2:

5. The lucky number of Q is 18 and Q faces towards the center.

6. Neither U nor T is adjacent to Q.

Case 1:

Case 2:

7. The persons adjacent to Q face in same direction. So, case 2 is rejected.

8. S faces towards the center and is not opposite to Q.

9. P sits immediate right of W, whose lucky number is 13.

10. The lucky number of V is greater than that of R. So, the lucky number of V must be 40.

11. The person opposite to R has lucky number 33. So, the lucky number of T and P must be 33 and 30 respectively.

12. The lucky number of S is a prime number. So, the lucky number of S is 17.

Final Case:

The difference in the lucky number of U and R = 25 – 10 = 15.

Hence, the difference in the lucky number of U and R is 15.

Persons: P, Q, R, S, T, U, V and W.

Lucky numbers: 10, 13, 17, 18, 25, 30, 33 and 40.

1. T sits third to the right of U and both face in same direction.

2. The lucky number of T is three more than that of P.

3. The one, whose lucky number is 40, sits second to the right of T.

4. The neighbors of U face in same direction.

Case 1:

Case 2:

5. The lucky number of Q is 18 and Q faces towards the center.

6. Neither U nor T is adjacent to Q.

Case 1:

Case 2:

7. The persons adjacent to Q face in same direction. So, case 2 is rejected.

8. S faces towards the center and is not opposite to Q.

9. P sits immediate right of W, whose lucky number is 13.

10. The lucky number of V is greater than that of R. So, the lucky number of V must be 40.

11. The person opposite to R has lucky number 33. So, the lucky number of T and P must be 33 and 30 respectively.

12. The lucky number of S is a prime number. So, the lucky number of S is 17.

Final Case:

Hence, the lucky number of V is 40.

Persons: P, Q, R, S, T, U, V and W.

Lucky numbers: 10, 13, 17, 18, 25, 30, 33 and 40.

1. T sits third to the right of U and both face in same direction.

2. The lucky number of T is three more than that of P.

3. The one, whose lucky number is 40, sits second to the right of T.

4. The neighbors of U face in same direction.

Case 1:

Case 2:

5. The lucky number of Q is 18 and Q faces towards the center.

6. Neither U nor T is adjacent to Q.

Case 1:

Case 2:

7. The persons adjacent to Q face in same direction. So, case 2 is rejected.

8. S faces towards the center and is not opposite to Q.

9. P sits immediate right of W, whose lucky number is 13.

10. The lucky number of V is greater than that of R. So, the lucky number of V must be 40.

11. The person opposite to R has lucky number 33. So, the lucky number of T and P must be 33 and 30 respectively.

12. The lucky number of S is a prime number. So, the lucky number of S is 17.

Final Case:

Hence, S sits second to the left of W.

:The pattern for the code is as follows,

Similarly,

Therefore, INTEREST is written as SMHSFUTF.

Given:  Eleven persons – A, B, C, D, E, F, G, H, I, J and K are participating in three different sports viz. Cricket, Football and Badminton. At-least two persons but not more than four persons are participating in the same sport.

Note: If it is given that ‘X’ is participating in the sport along with ‘Y’, then both are participating in the same sport.

1. B is participating in the sport along with H but doesn’t participate in Cricket. 
2. D is participating in neither Badminton nor participating in the sport along with H. 

So, there are three cases here case 1, case 2 and case 2a;

 

3. A is neither participating in the sport with D nor participating in Badminton. 
4. I is not participating in Football and Cricket. 
5. Both F and C are participating in the same sport.  6. C is participating in the sport with A.

Case 2 gets eliminated because there is no space left for C.

 

7. Neither C nor A are participating in the sport along with G. 
8. Both G and E are participating in different sports. 
9. E doesn’t participate in the sport along with B and C. 10. J and K participate in Football.

Case 1 gets eliminated because there is no place left for E. So, the final arrangement:

 

If D is related to Football and I is related to Badminton in a certain way, then in the same way, A is related to Cricket.

Hence, the correct answer is ‘Cricket ’.

Given:  Eleven persons – A, B, C, D, E, F, G, H, I, J and K are participating in three different sports viz. Cricket, Football and Badminton. At-least two persons but not more than four persons are participating in the same sport.

Note: If it is given that ‘X’ is participating in the sport along with ‘Y’, then both are participating in the same sport.

1. B is participating in the sport along with H but doesn’t participate in Cricket. 
2. D is participating in neither Badminton nor participating in the sport along with H. 

So, there are three cases here case 1, case 2 and case 2a;

 

3. A is neither participating in the sport with D nor participating in Badminton. 
4. I is not participating in Football and Cricket. 
5. Both F and C are participating in the same sport.  6. C is participating in the sport with A.

Case 2 gets eliminated because there is no space left for C.

 

7. Neither C nor A are participating in the sport along with G. 
8. Both G and E are participating in different sports. 
9. E doesn’t participate in the sport along with B and C. 10. J and K participate in Football.

Case 1 gets eliminated because there is no place left for E. So, the final arrangement:

 

Four persons are participating in the Football.

Hence, the correct answer is ‘Four’.

Given:  Eleven persons – A, B, C, D, E, F, G, H, I, J and K are participating in three different sports viz. Cricket, Football and Badminton. At-least two persons but not more than four persons are participating in the same sport.

Note: If it is given that ‘X’ is participating in the sport along with ‘Y’, then both are participating in the same sport.

1. B is participating in the sport along with H but doesn’t participate in Cricket. 
2. D is participating in neither Badminton nor participating in the sport along with H. 

So, there are three cases here case 1, case 2 and case 2a;

 

3. A is neither participating in the sport with D nor participating in Badminton. 
4. I is not participating in Football and Cricket. 
5. Both F and C are participating in the same sport.  6. C is participating in the sport with A.

Case 2 gets eliminated because there is no space left for C.

 

7. Neither C nor A are participating in the sport along with G. 
8. Both G and E are participating in different sports. 
9. E doesn’t participate in the sport along with B and C. 10. J and K participate in Football.

Case 1 gets eliminated because there is no place left for E. So, the final arrangement:

 

True combination: B-Badminton

Hence, the correct answer is ‘B-Badminton’.

Given: Eleven persons – A, B, C, D, E, F, G, H, I, J and K are participating in three different sports viz. Cricket, Football and Badminton. At-least two persons but not more than four persons are participating in the same sport.

Note: If it is given that ‘X’ is participating in the sport along with ‘Y’, then both are participating in the same sport.

1. B is participating in the sport along with H but doesn’t participate in Cricket. 
2. D is participating in neither Badminton nor participating in the sport along with H. 

So, there are three cases here case 1, case 2 and case 2a;

 

3. A is neither participating in the sport with D nor participating in Badminton. 
4. I is not participating in Football and Cricket. 
5. Both F and C are participating in the same sport.  6. C is participating in the sport with A.

Case 2 gets eliminated because there is no space left for C.

 

7. Neither C nor A are participating in the sport along with G. 
8. Both G and E are participating in different sports. 
9. E doesn’t participate in the sport along with B and C. 10. J and K participate in Football.

Case 1 gets eliminated because there is no place left for E. So, the final arrangement:

 

True statement: F and A are participating in Cricket

Hence, the correct answer is ‘F and A are participating in Cricket’.

Given:  Eleven persons – A, B, C, D, E, F, G, H, I, J and K are participating in three different sports viz. Cricket, Football and Badminton. At-least two persons but not more than four persons are participating in the same sport.

Note: If it is given that ‘X’ is participating in the sport along with ‘Y’, then both are participating in the same sport.

1. B is participating in the sport along with H but doesn’t participate in Cricket. 
2. D is participating in neither Badminton nor participating in the sport along with H. 

So, there are three cases here case 1, case 2 and case 2a;

 

3. A is neither participating in the sport with D nor participating in Badminton. 
4. I is not participating in Football and Cricket. 
5. Both F and C are participating in the same sport.  6. C is participating in the sport with A.

Case 2 gets eliminated because there is no space left for C.

 

7. Neither C nor A are participating in the sport along with G. 
8. Both G and E are participating in different sports. 
9. E doesn’t participate in the sport along with B and C. 10. J and K participate in Football.

Case 1 gets eliminated because there is no place left for E. So, the final arrangement:

 

G participates in Badminton.

Hence, the correct answer is ‘G’.

Given number: 2863471592

 

Therefore, there are two odd numbers in the final number, which are immediately followed by an even number. 

Hence, the correct answer is 2.

Given: Nine persons- A, B, C, D, E, F, G, H, and I are born in different months January, March, April, June, July, August, September, November, and December of the same year but not necessarily in the same order.

1. C is born in a month having an even number of days. 
2. D is born three persons after C. 
3. The number of persons born before C is the same as after G. 
4. Only one person is born between G and I. 

Here, there are three cases, i.e. Case 1, Case 2 and case 2a.

 

The number of persons born between C and I is the same as between A and B. B is born adjacent to G. A is born one of the months before B. 

Case 2a gets eliminated because there is no more space for A.

 

F is born in the just next month of E. H is not the eldest person. 

Case 2 gets eliminated because H is the eldest person. Hence, the final arrangement:

 

Three persons are born between E and G.

Hence, the correct answer is ‘Three’.

Given: Nine persons- A, B, C, D, E, F, G, H, and I are born in different months January, March, April, June, July, August, September, November, and December of the same year but not necessarily in the same order.

1. C is born in a month having an even number of days. 
2. D is born three persons after C. 
3. The number of persons born before C is the same as after G. 
4. Only one person is born between G and I. 

Here, there are three cases, i.e. Case 1, Case 2 and case 2a.

 

The number of persons born between C and I is the same as between A and B. B is born adjacent to G. A is born one of the months before B. 

Case 2a gets eliminated because there is no more space for A.

 

F is born in the just next month of E. H is not the eldest person. 

Case 2 gets eliminated because H is the eldest person. Hence, the final arrangement:

 

The one who is born immediately before E is born in January.

Hence, the correct answer is ‘The one who is born immediately before E’.

Given: Nine persons- A, B, C, D, E, F, G, H, and I are born in different months January, March, April, June, July, August, September, November, and December of the same year but not necessarily in the same order.

1. C is born in a month having an even number of days. 
2. D is born three persons after C. 
3. The number of persons born before C is the same as after G. 
4. Only one person is born between G and I. 

Here, there are three cases, i.e. Case 1, Case 2 and case 2a.

 

The number of persons born between C and I is the same as between A and B. B is born adjacent to G. A is born one of the months before B. 

Case 2a gets eliminated because there is no more space for A.

 

F is born in the just next month of E. H is not the eldest person. 

Case 2 gets eliminated because H is the eldest person. Hence, the final arrangement:

 

True statement: B is elder than D

Hence, the correct answer is ‘B is elder than D’.