
Shortcut Trick
Let initial mixture = 100 units ⇒ Milk = 20 units, Water = 80 units.
Amount of water added = 80 units (equal to original water).
New water = 80 + 80 = 160 units, Total new mixture = 100 + 80 = 180 units.
Percentage of water = (160 ÷ 180) × 100 ≈ 89%.
∴ The correct answer is 89%.

Alternate Method
Given:
Percentage of milk in the initial mixture = 20%
Amount of water added = Initial amount of water in the mixture
Formula Used:
Percentage of component = (Amount of component ÷ Total mixture) × 100

Calculations:
Let the initial volume of the mixture be 100 units.
⇒ Initial Milk = 20% of 100 = 20 units
⇒ Initial Water = 100 − 20 = 80 units
⇒ Amount of water added = Initial water = 80 units
⇒ Total water in new mixture = 80 + 80 = 160 units
⇒ Total volume of new mixture = 100 + 80 = 180 units
⇒ Percentage of water in final mixture = (160 ÷ 180) × 100
⇒ (8 ÷ 9) × 100 = 88.88%
⇒ Approximating to nearest whole number = 89%
∴ The correct answer is 89%.

Additional Information
Rule of Alligation
Used to find the ratio in which two mixtures of known concentrations are mixed to get a desired concentration. Ratio = (d − m) : (m − c).
Percentage Change
When a new component is added, the total base of the mixture changes, affecting the percentage of all components. New % = (New Value ÷ New Total Base) × 100.
Replacement Formula
If 'y' units of a mixture of volume 'x' are replaced by an equal amount of water 'n' times, Final Amount of pure liquid = Initial Amount × (1 − y/x)n.