Delhi Police Constable · Topic Collection

Quantitative Aptitude PYQs

Arithmetic, number systems, percentages, ratios, profit and loss, time and work, algebra, geometry, mensuration, and trigonometry.

1680 Total Questions112 Official PapersYears: 2017–2026Search in Quantitative Aptitude
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Delhi Police Constable (Executive) 2023 Official Paper (Held On: 24 Nov, 2023 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 781

Delhi Police Constable 2023• Numerical Ability• Numerical Ability

Which of the ratio is the smallest?

\(\frac{4}{5}\), \(\frac{12}{14}\), \(\frac{21}{23}\), \(\frac{16}{19}\), \(\frac{79}{85}\) = ?

  1. AOption (a)

    \(\frac{16}{19}\)

  2. BOption (b)

    \(\frac{12}{14}\)

  3. COption (c)

    \(\frac{79}{85}\)

  4. DOption (d)

    \(\frac{4}{5}\)

View answer & explanation

Correct answer

Answer: (d)D.

\(\frac{4}{5}\)

Why this answer is correct

Given:

Ratios to compare:

\(\frac{4}{5}\), \(\frac{12}{14}\), \(\frac{21}{23}\), \(\frac{16}{19}\), \(\frac{79}{85}\) 

Formula Used:

To compare ratios, we convert them to decimal form.

Calculations:

Convert each ratio to decimal form:

\(\frac{4}{5}\) = 0.8

\(\frac{12}{14}\) = 0.857

\(\frac{21}{23}\) = 0.913

\(\frac{16}{19}\) = 0.842

\(\frac{79}{85}\) = 0.929

Comparing these decimals, the smallest ratio is 0.8.

The smallest ratio is \(\frac{4}{5}\).

Delhi Police Constable (Executive) 2023 Official Paper (Held On: 24 Nov, 2023 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 782

Delhi Police Constable 2023• Numerical Ability• Numerical Ability

What is the result of the expression 4.5 × 2.8 + 3.6 × 2.5 - 1.7 × 12 ? (Use decimal upto 1 point)

  1. AOption (a)

    2.3

  2. BOption (b)

    1.9

  3. COption (c)

    3.4

  4. DOption (d)

    1.2

View answer & explanation

Correct answer

Answer: (d)D.

1.2

Why this answer is correct

Given:

Expression: 4.5 × 2.8 + 3.6 × 2.5 - 1.7 × 12

Formula Used:

Use the order of operations (BODMAS/BIDMAS):

  1. Brackets
  2. Orders (i.e. powers and square roots, etc.)
  3. Division and Multiplication (left to right)
  4. Addition and Subtraction (left to right)

Calculation:

4.5 × 2.8 + 3.6 × 2.5 - 1.7 × 12

⇒ 12.6 + 9.0 - 20.4

⇒ 21.6 - 20.4

⇒ 1.2

The result of the expression is 1.2.

Delhi Police Constable (Executive) 2023 Official Paper (Held On: 24 Nov, 2023 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 783

Delhi Police Constable 2023• Numerical Ability• Numerical Ability

The radius of the base and height of a solid right circular cylinder are in the ratio 7 ∶ 3 and its volume is 12474 cm3. What is the total surface area of the cylinder? (Use π = \(\frac{22}{7}\))

  1. AOption (a)

    1760 cm2

  2. BOption (b)

    2960 cm2

  3. COption (c)

    3960 cm2

  4. DOption (d)

    2160 cm2

View answer & explanation

Correct answer

Answer: (c)C.

3960 cm2

Why this answer is correct

Given:

Radius of the base and height of the cylinder are in the ratio 7 : 3.

Volume of the cylinder = 12474 cm3

Use π = 22/7

Formula Used:

Total surface area of the cylinder = 2πr(r + h)

Volume of the cylinder = πr2h

Calculation:

Let the radius of the base be 7x and the height be 3x.

Volume of the cylinder = πr2h

⇒ (22/7) × (7x)2 × (3x) = 12474

⇒ (22/7) × 49x2 × 3x = 12474

⇒ (22/7) × 147x3 = 12474

⇒ 22 × 21x3 = 12474

⇒ 462x3 = 12474

⇒ x3 = 27

⇒ x = 3

So, the radius of the base = 7x = 7 × 3 = 21 cm

Height of the cylinder = 3x = 3 × 3 = 9 cm

Total surface area of the cylinder = 2πr(r + h)

⇒ 2 × (22/7) × 21 × (21 + 9)

⇒ 2 × (22/7) × 21 × 30

⇒ 2 × 22 × 3 × 30

⇒ 2 × 22 × 90

⇒ 3960 cm2

The total surface area of the cylinder is 3960 cm2.

Delhi Police Constable (Executive) 2023 Official Paper (Held On: 24 Nov, 2023 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 784

Delhi Police Constable 2023• Numerical Ability• Numerical Ability

Ram received an annual salary of ₹48,580 in the year 2008. This was 25% more than his salary in 2007. What was his salary in 2007?

  1. AOption (a)

    ₹31,750

  2. BOption (b)

    ₹39,670

  3. COption (c)

    ₹33,864

  4. DOption (d)

    ₹38,864

View answer & explanation

Correct answer

Answer: (d)D.

₹38,864

Why this answer is correct

Given:

Annual salary in 2008 = ₹48,580

This was 25% more than his salary in 2007.

Formula Used:

If the salary in 2007 is X, then:

2008 Salary = 2007 Salary + 25% of 2007 Salary

₹48,580 = ₹X + 0.25 × ₹X

Calculations:

₹48,580 = ₹X + 0.25 × ₹X

₹48,580 = ₹X(1 + 0.25)

₹48,580 = ₹X × 1.25

→ ₹X = ₹48,580 / 1.25

→ ₹X = ₹38,864

∴ Ram's salary in 2007 was ₹38,864.

Delhi Police Constable (Executive) 2023 Official Paper (Held On: 24 Nov, 2023 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 785

Delhi Police Constable 2023• Numerical Ability• Numerical Ability

The price of an article is reduced by 25% and its daily sale is increased by 30%. The net effect on the daily sale receipts is:

  1. AOption (a)

    2\(\frac{1}{2}\)% decreased

  2. BOption (b)

    3% decreased

  3. COption (c)

    2\(\frac{1}{2}\)% increase

  4. DOption (d)

    3% increase

View answer & explanation

Correct answer

Answer: (a)A.

2\(\frac{1}{2}\)% decreased

Why this answer is correct

Given:

Price reduction = 25% = 0.25

Increase in sale = 30% = 0.30

Formula used:

Net effect (%) = (x + y + xy/100)%

Where x = -25% (reduction) and y = 30% (increase)

Calculation:

Net effect = (-25 + 30 + (-25 × 30)/100)%

⇒ Net effect = (5 - 7.5)%

⇒ Net effect = - 2.5%

∴ The net effect on the daily sale receipts is a decrease of 2\(\frac{1}{2}\)%.

Delhi Police Constable (Executive) 2023 Official Paper (Held On: 24 Nov, 2023 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 786

Delhi Police Constable 2023• Numerical Ability• Numerical Ability

If a person walked 14 km/h instead of 10 km/h, he would have walked 20 km more. The actual distance travelled by him is:

  1. AOption (a)

    100 km

  2. BOption (b)

    70 km

  3. COption (c)

    50 km

  4. DOption (d)

    150 km

View answer & explanation

Correct answer

Answer: (c)C.

50 km

Why this answer is correct

Given:

Speed 1 = 10 km/h

Speed 2 = 14 km/h

Extra distance covered at 14 km/h = 20 km

Formula used:

Time is constant, so:

Time = Distance/Speed

Calculation:

Let actual distance = D km

According to the question:

(D/10) = (D + 20)/14

Cross-multiplying:

14 × D = 10 × (D + 20)

14D = 10D + 200

14D - 10D = 200

4D = 200

D = 200/4

D = 50 km

∴ The actual distance travelled by him is 50 km.

Delhi Police Constable (Executive) 2023 Official Paper (Held On: 24 Nov, 2023 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 787

Delhi Police Constable 2023• Numerical Ability• Numerical Ability

Find the average of 72, 81, 90, 68, 61.

  1. AOption (a)

    78.6

  2. BOption (b)

    72.2

  3. COption (c)

    74.4

  4. DOption (d)

    76.8

View answer & explanation

Correct answer

Answer: (c)C.

74.4

Why this answer is correct

Given:

The numbers are 72, 81, 90, 68, 61.

Formula Used:

Average = (Sum of all numbers) / (Total count of numbers)

Calculation:

Sum of all numbers = 72 + 81 + 90 + 68 + 61

Sum = 372

Total count of numbers = 5

Average = Sum / Total count

Average = 372 / 5

∴ Average = 74.4

Delhi Police Constable (Executive) 2023 Official Paper (Held On: 24 Nov, 2023 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 788

Delhi Police Constable 2023• Numerical Ability• Numerical Ability

Four years ago, the population of a city was 10,000. The annual growth rate of the population during the first two years was 20%. In the third and fourth years, there was a decrease in the population at the rate of 10% and 5%, respectively. What is the current population of the city after four years?

  1. AOption (a)

    10500

  2. BOption (b)

    14288

  3. COption (c)

    16632

  4. DOption (d)

    12312

View answer & explanation

Correct answer

Answer: (d)D.

12312

Why this answer is correct

Given:

Population 4 years ago = 10,000

Annual growth rate for the first 2 years = 20%

Decrease rate in the third year = 10%

Decrease rate in the fourth year = 5%

Formula Used:

Population after n years = Initial Population × (1 + growth rate/100)number of years

Calculation:

Population after first year = 10,000 × (1 + 20/100)

⇒ Population after first year = 10,000 × 1.2

⇒ Population after first year = 12,000

Population after second year = 12,000 × (1 + 20/100)

⇒ Population after second year = 12,000 × 1.2

⇒ Population after second year = 14,400

Population after third year = 14,400 × (1 - 10/100)

⇒ Population after third year = 14,400 × 0.9

⇒ Population after third year = 12,960

Population after fourth year = 12,960 × (1 - 5/100)

⇒ Population after fourth year = 12,960 × 0.95

⇒ Population after fourth year = 12,312

The current population of the city after four years is 12,312.

Shortcut Trick Population after fourth year = 10,000 × (1 + 20/100) × (1 + 20/100) × (1 - 10/100) × (1 - 5/100)

⇒ 10,000 × 1.2 × 1.2 × 0.9 × 0.95

⇒ 12,312

Delhi Police Constable (Executive) 2023 Official Paper (Held On: 24 Nov, 2023 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 789

Delhi Police Constable 2023• Numerical Ability• Numerical Ability

8 men can complete a work in 6 hours. In how many hours can 12 men complete the same work?

  1. AOption (a)

    4

  2. BOption (b)

    6

  3. COption (c)

    5

  4. DOption (d)

    3

View answer & explanation

Correct answer

Answer: (a)A.

4

Why this answer is correct

Given:

8 men can complete a work in 6 hours.

Formula Used:

Work = Men × Time

Calculation:

Let the total work be W.

Work done by 8 men in 6 hours:

W = 8 × 6

Work done by 12 men in t hours:

W = 12 × t

Since the work is the same:

8 × 6 = 12 × t

⇒ t = (8 × 6) / 12

⇒ t = 48 / 12

⇒ t = 4

12 men can complete the same work in 4 hours.

Delhi Police Constable (Executive) 2023 Official Paper (Held On: 24 Nov, 2023 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 790

Delhi Police Constable 2023• Numerical Ability• Numerical Ability

Lalita bought 10 water bottles for ₹18 each and sold them for ₹20 each. What is her overall profit percentage?

  1. AOption (a)

    13\(\frac{2}{9}\)

  2. BOption (b)

    11%

  3. COption (c)

    11\(\frac{1}{9}\)%

  4. DOption (d)

    13%

View answer & explanation

Correct answer

Answer: (c)C.

11\(\frac{1}{9}\)%

Why this answer is correct

Given:

Cost Price (CP) of each water bottle = ₹18

Selling Price (SP) of each water bottle = ₹20

Number of water bottles = 10

Formula used:

Total CP = Number of bottles × CP per bottle

Total SP = Number of bottles × SP per bottle

Profit % = (Profit / Total CP) × 100

Calculation:

Total CP = 10 × 18 = ₹180

Total SP = 10 × 20 = ₹200

Profit = Total SP - Total CP

⇒ Profit = ₹200 - ₹180 = ₹20

Profit % = (20 / 180) × 100

⇒ Profit % = 11\(\frac{1}{9}\)%

∴ Lalita’s overall profit percentage is 11\(\frac{1}{9}\)%

Delhi Police Constable (Executive) 2023 Official Paper (Held On: 24 Nov, 2023 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 791

Delhi Police Constable 2023• Numerical Ability• Numerical Ability

The market price of a toy is 25% above the cost price. If the shopkeeper gives 12% discount, then find the gain in the deal.

  1. AOption (a)

    12%

  2. BOption (b)

    10%

  3. COption (c)

    15%

  4. DOption (d)

    13%

View answer & explanation

Correct answer

Answer: (b)B.

10%

Why this answer is correct

Given:

Market Price (MP) = 25% above Cost Price (CP)

Discount = 12%

Formula used:

Gain % = [(SP - CP) / CP] × 100

Calculation:

Let the Cost Price be ₹100.

Market Price = CP + 25% of CP = 1.25 × CP

Market Price = 1.25 × 100 = ₹125

Selling Price (SP) = MP - 12% of MP = MP × 0.88

Selling Price = 0.88 × 125 = ₹110

Gain = SP - CP = 110 - 100 = ₹10

Gain % = (10/100) × 100 = 10%

∴ The gain in the deal is 10%.

Delhi Police Constable (Executive) 2023 Official Paper (Held On: 24 Nov, 2023 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 792

Delhi Police Constable 2023• Numerical Ability• Numerical Ability

What is the difference between the total surface area and the curved surface area of a hemisphere (in cm2) when the radius is 21 cm? (Takе π = \(\frac{22}{7}\))

  1. AOption (a)

    1386

  2. BOption (b)

    1495

  3. COption (c)

    1586

  4. DOption (d)

    1376

View answer & explanation

Correct answer

Answer: (a)A.

1386

Why this answer is correct

Shortcut Trick

The difference between the Total Surface Area (3πr2) and the Curved Surface Area (2πr2) of a hemisphere is simply the area of its circular base (πr2).

Difference = Area of base = πr2

Difference = (22/7) × 21 × 21 = 22 × 3 × 21

Difference = 66 × 21 = 1386 cm2

∴ The correct answer is 1386 cm2.

Alternate Method

Given:

Radius of the hemisphere (r) = 21 cm

Value of π = 22/7

Formula Used:

Curved Surface Area (CSA) of hemisphere = 2πr2

Total Surface Area (TSA) of hemisphere = 3πr2

Calculations:

⇒ Curved Surface Area (CSA) = 2 × (22/7) × 21 × 21

⇒ CSA = 2 × 22 × 3 × 21 = 2772 cm2

⇒ Total Surface Area (TSA) = 3 × (22/7) × 21 × 21

⇒ TSA = 3 × 22 × 3 × 21 = 4158 cm2

⇒ Difference = TSA − CSA

⇒ Difference = 4158 − 2772 = 1386 cm2

∴ The correct answer is 1386 cm2.

Additional Information

Surface Area of a Sphere

A sphere has only one surface area, which is 4πr2. A hemisphere is half of a sphere but adds a flat circular base.

Volume of a Hemisphere

The volume of a hemisphere is exactly half the volume of a sphere: V = (2/3)πr3.

Base Area Relationship

The TSA of a hemisphere is always 1.5 times its CSA because 3πr2 = 1.5 × (2πr2).

Delhi Police Constable (Executive) 2023 Official Paper (Held On: 24 Nov, 2023 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 793

Delhi Police Constable 2023• Numerical Ability• Numerical Ability

An amount of ₹4,000 was divided into two parts in such a way that, when the first part was invested at 3% per annum simple interest and the second at 5% per annum simple interest, the total annual interest from both the investments was ₹144. How much was put at 3% per annum simple interest?

  1. AOption (a)

    ₹2,100

  2. BOption (b)

    ₹1,400

  3. COption (c)

    ₹2,800

  4. DOption (d)

    ₹700

View answer & explanation

Correct answer

Answer: (c)C.

₹2,800

Why this answer is correct

Given:

Total amount = ₹4000

Rate of interest for first part = 3% p.a.

Rate of interest for second part = 5% p.a.

Total annual interest = ₹144

Formula used:

Total interest = Interest on first part + Interest on second part

SI = (P × R × T) ÷ 100

Calculation:

Let the first part invested at 3% be ₹x.

Then, the second part invested at 5% will be ₹(4000 - x).

According to the question:

(x × 3 × 1)/100 + ((4000 - x) × 5 × 1)/100 = 144

⇒ 0.03x + 0.05(4000 - x) = 144

⇒ 0.03x + 200 - 0.05x = 144

⇒ -0.02x = 144 - 200

⇒ -0.02x = -56

⇒ x = 56 ÷ 0.02

⇒ x = 2800

∴ The amount invested at 3% per annum simple interest is ₹2800.

Delhi Police Constable (Executive) 2023 Official Paper (Held On: 24 Nov, 2023 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 794

Delhi Police Constable 2023• Numerical Ability• Numerical Ability

What is the difference between the smallest and the largest prime numbers between 1 to 100?

  1. AOption (a)

    95

  2. BOption (b)

    94

  3. COption (c)

    87

  4. DOption (d)

    86

View answer & explanation

Correct answer

Answer: (a)A.

95

Why this answer is correct

Given:

Smallest prime number between 1 and 100 = 2

Largest prime number between 1 and 100 = 97

Formula Used:

Difference = Largest prime number - Smallest prime number

Calculation:

Smallest prime number = 2

Largest prime number = 97

Difference = 97 - 2

∴ The difference between the smallest and the largest prime numbers between 1 to 100 is 95.

Delhi Police Constable (Executive) 2023 Official Paper (Held On: 24 Nov, 2023 Shift 2) (Previous Year Paper)·Numerical Ability
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Question 795

Delhi Police Constable 2023• Numerical Ability• Numerical Ability

The smallest four - digit number which is divisible by 15, 25, 40 and 75 is:

  1. AOption (a)

    1080

  2. BOption (b)

    1120

  3. COption (c)

    1100

  4. DOption (d)

    1200

View answer & explanation

Correct answer

Answer: (d)D.

1200

Why this answer is correct

Given:

We need to find the smallest four-digit number that is divisible by 15, 25, 40, and 75.

Formula Used:

The smallest number divisible by multiple numbers is the Least Common Multiple (LCM) of those numbers.

Calculation:

First, find the LCM of 15, 25, 40, and 75.

Prime factorization:

15 = 3 × 5

25 = 52

40 = 23 × 5

75 = 3 × 52

LCM is obtained by taking the highest powers of all prime factors.

LCM = 23 × 3 × 52

⇒ LCM = 8 × 3 × 25

⇒ LCM = 600

Now, find the smallest four-digit number divisible by 600.

Smallest four-digit number = 1000

Divide 1000 by 600 and round up to the next whole number.

⇒ 1000 / 600 ≈ 1.67

⇒ Next whole number = 2

Multiply LCM by 2:

⇒ 600 × 2 = 1200

The smallest four-digit number divisible by 15, 25, 40, and 75 is 1200.

Delhi Police Constable (Executive) 2023 Official Paper (Held On: 24 Nov, 2023 Shift 3) (Previous Year Paper)·Numerical Ability
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Question 796

Delhi Police Constable 2023• Numerical Ability• Numerical Ability

Find the sum of all those prime numbers which are less than 28. 

  1. AOption (a)

    97

  2. BOption (b)

    120

  3. COption (c)

    110

  4. DOption (d)

    100

View answer & explanation

Correct answer

Answer: (d)D.

100

Why this answer is correct

Shortcut Trick

List the prime numbers less than 28: 2, 3, 5, 7, 11, 13, 17, 19, 23.

Group the numbers to simplify the addition: (2 + 3 + 5) + (7 + 13) + (11 + 19) + (17 + 23).

Step 1: 10 + 20 + 30 + 40 = 100.

∴ The correct answer is 100.

Alternate Method

Given: We need to find the sum of all prime numbers smaller than 28.

Definition: A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself.

⇒ Identify prime numbers between 1 and 28: 2, 3, 5, 7, 11, 13, 17, 19, 23.

⇒ Sum = 2 + 3 + 5 + 7 + 11 + 13 + 17 + 19 + 23

⇒ Sum = (2 + 3 + 5) + (7 + 11 + 13) + (17 + 19 + 23)

⇒ Sum = 10 + 31 + 59

⇒ Sum = 100.

∴ The correct answer is 100.

Additional Information

Definition of Prime Numbers

Numbers that have exactly two factors, 1 and the number itself. Example: 2, 3, 5, 7, 11...

Even Prime Number

2 is the only even prime number and it is the smallest prime number.

Composite Numbers

Numbers having more than two factors are called composite numbers. 1 is neither prime nor composite.

Twin Primes

Pairs of prime numbers that have a difference of 2 are called twin primes (e.g., 3 and 5, 5 and 7).

Delhi Police Constable (Executive) 2023 Official Paper (Held On: 24 Nov, 2023 Shift 3) (Previous Year Paper)·Numerical Ability
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Question 797

Delhi Police Constable 2023• Numerical Ability• Numerical Ability

\(0.\overline{63}\) expressed in the form \(\frac{p}{q}\) equals:

  1. AOption (a)

    \(\frac{9}{11}\)

  2. BOption (b)

    \(\frac{3}{11}\)

  3. COption (c)

    \(\frac{7}{11}\)

  4. DOption (d)

    \(\frac{6}{11}\)

View answer & explanation

Correct answer

Answer: (c)C.

\(\frac{7}{11}\)

Why this answer is correct

Given:

Repeating decimal: \(0.\overline{63}\)

Calculation:

Let x = 0.636363...

Multiply by 100:

100x = 63.636363...

Subtract x from 100x:

100x - x = 63.636363... - 0.636363...

99x = 63

⇒ x = 63 / 99 = 7 / 11

0.63 expressed in the form p/q is 7/11.

Delhi Police Constable (Executive) 2023 Official Paper (Held On: 24 Nov, 2023 Shift 3) (Previous Year Paper)·Numerical Ability
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Question 798

Delhi Police Constable 2023• Numerical Ability• Numerical Ability

Select the correct statement.

  1. AOption (a)

    Loss% = \(\rm \frac{SP-CP}{CP}\times 100\)

  2. BOption (b)

    Profit% = \(\rm \frac{SP-CP}{CP}\times 100\)

  3. COption (c)

    Profit% = \(\rm \frac{CP-SP}{CP}\times 100\)

  4. DOption (d)

    Loss% = \(\rm \frac{SP+CP}{CP}\times 100\)

View answer & explanation

Correct answer

Answer: (b)B.

Profit% = \(\rm \frac{SP-CP}{CP}\times 100\)

Why this answer is correct

Given:

Formulas for Loss% and Profit%

Formula used:

Profit = Selling Price (SP) - Cost Price (CP)

Loss = Cost Price (CP) - Selling Price (SP)

Profit% = (Profit / CP) × 100

Loss% = (Loss / CP) × 100

Calculation:

  1. Analyze each

Statement:

1) Loss% = (SP - CP) / CP × 100

This formula is incorrect.

Loss% should be (CP - SP) / CP × 100.

2) Profit% = (SP - CP) / CP × 100

This formula is correct.

Profit% = (Profit / CP) × 100, and Profit = SP - CP.

3) Profit% = (CP - SP) / CP × 100

This formula is incorrect.

Profit% should be (SP - CP) / CP × 100.

4) Loss% = (SP + CP) / CP × 100

This formula is incorrect.

Loss% should be (CP - SP) / CP × 100.

∴ The correct statement is: Profit% = (SP - CP) / CP × 100

Delhi Police Constable (Executive) 2023 Official Paper (Held On: 24 Nov, 2023 Shift 3) (Previous Year Paper)·Numerical Ability
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Question 799

Delhi Police Constable 2023• Numerical Ability• Numerical Ability

Let x = \(\frac{6}{5}\), then arrange the numbers 6x, \(\frac{37}{6}\) , 6 - x and 5 + x in ascending order.

  1. AOption (a)

    6 - x, \(\frac{37}{6}\), 5 + x, 6x

  2. BOption (b)

    6 - x, 5 + x, 6x, \(\frac{37}{6}\)

  3. COption (c)

    6 - x, 5 + x, \(\frac{37}{6}\), 6x

  4. DOption (d)

    6 - x, \(\frac{37}{6}\), 6x, 5 + x

View answer & explanation

Correct answer

Answer: (a)A.

6 - x, \(\frac{37}{6}\), 5 + x, 6x

Why this answer is correct

Given:

x = 6/5

Numbers: 6x, 37/6, 6 - x, 5 + x

Calculation:

6x = 6 × (6/5) = 36/5 = 7.2

6 - x = 6 - (6/5) = (30/5) - (6/5) = 24/5 = 4.8

5 + x = 5 + (6/5) = (25/5) + (6/5) = 31/5 = 6.2

37/6 = 6.1666...

The numbers are in ascending order:

4.8 < 6.1666... < 6.2 < 7.2

24/5 < 37/6 < 31/5 < 36/5

6 - x < 37/6 < 5 + x < 6x

∴ The ascending order is: 6 - x, 37/6, 5 + x, 6x.

Delhi Police Constable (Executive) 2023 Official Paper (Held On: 24 Nov, 2023 Shift 3) (Previous Year Paper)·Numerical Ability
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Question 800

Delhi Police Constable 2023• Numerical Ability• Numerical Ability

The LCM of \(\frac{9}{10}, \frac{12}{15}, \frac{18}{35}, \frac{21}{40}\) is:

  1. AOption (a)

    \(\frac{100}{9}\)

  2. BOption (b)

    \(\frac{252}{5}\)

  3. COption (c)

    \(\frac{9}{100}\)

  4. DOption (d)

    \(\frac{151}{7}\)

View answer & explanation

Correct answer

Answer: (b)B.

\(\frac{252}{5}\)

Why this answer is correct

Given:

Fractions: 9/10, 12/15, 18/35, 21/40

Formula used:

LCM of fractions = (LCM of numerators) / (HCF of denominators)

Calculation:

LCM of the numerators (9, 12, 18, 21):

9 = 3 × 3

12 = 2 × 2 × 3

18 = 2 × 3 × 3

21 = 3 × 7

LCM(9, 12, 18, 21) = 2 × 2 × 3 × 3 × 7 = 252

HCF of the denominators (10, 15, 35, 40):

10 = 2 × 5

15 = 3 × 5

35 = 5 × 7

40 = 2 × 2 × 2 × 5

HCF(10, 15, 35, 40) = 5

LCM of the fractions is,

LCM = (LCM of numerators) / (HCF of denominators)

LCM = 252 / 5

∴ The LCM of 9/10, 12/15, 18/35, 21/40 is 252/5.

How should I prepare for Quantitative Aptitude in Delhi Police Constable?

Solving previous year questions by topic helps identify recurring concepts, question patterns, and frequently asked sub-topics. Attempt each question, review the step-by-step explanation, and note down key formulas or facts for quick revision before the exam.