Question 141
In a pentagon ABCDE, ∠A = (2x + 9°), ∠B = (2x + 1°), ∠C = (2x - 1°), ∠D = (2x + 5°) and ∠E = (2x - 4°). Then, value of (2x + 10°) is:
- AOption (a)
114°
- BOption (b)
116°
- COption (c)
118°
- DOption (d)
124°
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Correct answer
116°
Why this answer is correct
Given:
Pentagon ABCDE with angles:
- \(\angle A = (2x + 9^\circ)\)
- \(\angle B = (2x + 1^\circ)\)
- \(\angle C = (2x - 1^\circ)\)
- \(\angle D = (2x + 5^\circ)\)
- \(\angle E = (2x - 4^\circ)\)
Concept:
The sum of interior angles of a pentagon is \(540^\circ\).
Step 1: Sum all angles and set equal to 540°
(2x + 9° ) + (2x + 1° ) + (2x - 1° ) + (2x + 5° ) + (2x - 4° ) = 540°Â
Step 2: Simplify the equation
\(10x + 10^\circ = 540^\circ\)
Step 3: Solve for x
\(10x = 530^\circ\)
x = 53°Â
Step 4: Calculate (2x+10∘)(2x+10∘)(2x+10∘)(2x+10∘)
2x + 10° = 2(53° ) + 10° = 106° + 10° = 116°