If the sum of the diagonals of a rhombus is L and the perimeter is 4P, find the area of the rhombus?
- AOption (a)
\(\frac{1}{4}\left(\mathrm{~L}^2-\mathrm{P}^2\right)\)
- BOption (b)
\(\frac{1}{4}\left(L^2-4 P^2\right)\)
- COption (c)
\(\frac{1}{2}\left(L^2-4 P^2\right)\)
- DOption (d)
\(\frac{1}{4}\left(\mathrm{~L}^2+3 \mathrm{P}^2\right)\)
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Correct answer
\(\frac{1}{4}\left(\mathrm{~L}^2-\mathrm{P}^2\right)\)

