Given:
Ram and Ramesh can do work together =12 days
Ramesh and Somesh can do work together = 15 days
Somesh and Ram can do work together = 10 days
Formula used:
Work = Efficiency × Time
Calculation:
Let the Ram, Ramesh, and Somesh can complete the work together in X days
One day work of Ramesh and Ram = 121
One day work of Ramesh and Somesh = 151
One day work of Somesh and Ram = 101
One day work of all three = 121+151+101 = 605+4+6=6015=41
Working twice they can complete the work in = 4 days
They can complete the work = 8 days
∴ The required result will be 8 days.
Alternate MethodCalculation:
Ram and Ramesh = 12 days
Ramesh and Somesh = 15 days
Somesh and Ram = 10 days
LCM of (12,15, & 10) = 60 units
Efficiency of Ram and Ramesh = 60/12 = 5 units
Efficiency of Ramesh and Somesh = 60/15 = 4 units
Efficiency of Somesh and Ram = 60/10 = 6 units
Efficiency of 2(Ram, Ramesh & Somesh) = 15 units(5 + 4 + 6)
Total Efficiency of Ram, Ramesh & Somesh = (5 + 4 + 6)/2 = 7.5 units
Time taken by Ram, Ramesh, and Somesh together to complete the work:
Time = Total work / Total Efficiency
⇒ 60/7.5 = 8 days
∴ Ram, Ramesh, and Somesh together will complete the work in 8 days.