SBI PO Mains Memory Based Paper (Held On: 5 December 2023) (Previous Year Paper)

1) Two persons sit between those who like Pineapple fruit and like Blue color when counted anticlockwise from the person who likes Pineapple T, who likes White sit second to the right of the person who likes Blue color. 

2) The one who likes Cherry and T are immediate neighbors. The immediate neighbor of the one who likes Cheery faces W. W sits immediately right of the one who likes Guava. 

 

3) One person sits between the one who likes Mango and W. Mango is two places away from V.

 

4)  R and W are immediate neighbors and neither of them like Pineapple. 

 

5. The one who likes Pineapple fruit and Blue color does not sit opposite to P. The one who likes the Green color sits second to the left of P. V. does not like the Green color.

6. S sits opposite to the one who sits second to the left of U. S does not like Cherry and Guava. Case 1(a) and Case 1(b) do not satisfy the given condition which is why Case 1(a) and Case 1(b) are eliminated.

The arrangement is:

7)  Q draws King of Spade. Q will shift his position just behind the person who sits second to the left of him at the inner table and will face inside. P draws King of Diamond. According to condition 5, P remains at the same position. R draws Queen of Diamond. R will shift his position just behind (i.e. outer circle) its previous position and will face outside.

8)  W draws King of Heart. W will shift to any corner of the table and will face inside. T draws 9 of Heart. According to condition 5, No change in the position of T.  S draws Jack of Club. S will shift his position just behind the person who sits immediately right of S and will face outside.

9)  U draws Queen of Club. According to Condition 5, No change in the position of U. Person V draws Jack of Club. V will shift his position just behind the person who sits immediately right of V and will face outside. V is sitting immediately left of U. 

The final arrangement is:

V is sitting immediately left of U.

1) Two persons sit between those who like Pineapple fruit and like Blue color when counted anticlockwise from the person who likes Pineapple T, who likes White sit second to the right of the person who likes Blue color. 

2) The one who likes Cherry and T are immediate neighbors. The immediate neighbor of the one who likes Cheery faces W. W sits immediately right of the one who likes Guava. 

 

3) One person sits between the one who likes Mango and W. Mango is two places away from V.

 

4)  R and W are immediate neighbors and neither of them like Pineapple. 

 

5. The one who likes Pineapple fruit and Blue color does not sit opposite to P. The one who likes the Green color sits second to the left of P. V. does not like the Green color.

6. S sits opposite to the one who sits second to the left of U. S does not like Cherry and Guava. Case 1(a) and Case 1(b) do not satisfy the given condition which is why Case 1(a) and Case 1(b) are eliminated.

The arrangement is:

7)  Q draws King of Spade. Q will shift his position just behind the person who sits second to the left of him at the inner table and will face inside. P draws King of Diamond. According to condition 5, P remains at the same position. R draws Queen of Diamond. R will shift his position just behind (i.e. outer circle) its previous position and will face outside.

8)  W draws King of Heart. W will shift to any corner of the table and will face inside. T draws 9 of Heart. According to condition 5, No change in the position of T.  S draws Jack of Club. S will shift his position just behind the person who sits immediately right of S and will face outside.

9)  U draws Queen of Club. According to Condition 5, No change in the position of U. Person V draws Jack of Club. V will shift his position just behind the person who sits immediately right of V and will face outside. T is sitting immediately right of V. 

The final arrangement is:

 Three persons are facing away from the center.

1) Two persons sit between those who like Pineapple fruit and like Blue color when counted anticlockwise from the person who likes Pineapple T, who likes White sit second to the right of the person who likes Blue color. 

2) The one who likes Cherry and T are immediate neighbors. The immediate neighbor of the one who likes Cheery faces W. W sits immediately right of the one who likes Guava. 

 

3) One person sits between the one who likes Mango and W. Mango is two places away from V.

 

4)  R and W are immediate neighbors and neither of them like Pineapple. 

 

5. The one who likes Pineapple fruit and Blue color does not sit opposite to P. The one who likes the Green color sits second to the left of P. V. does not like the Green color.

6. S sits opposite to the one who sits second to the left of U. S does not like Cherry and Guava. Case 1(a) and Case 1(b) do not satisfy the given condition which is why Case 1(a) and Case 1(b) are eliminated.

The arrangement is:

7)  Q draws King of Spade. Q will shift his position just behind the person who sits second to the left of him at the inner table and will face inside. P draws King of Diamond. According to condition 5, P remains at the same position. R draws Queen of Diamond. R will shift his position just behind (i.e. outer circle) its previous position and will face outside.

8)  W draws King of Heart. W will shift to any corner of the table and will face inside. T draws 9 of Heart. According to condition 5, No change in the position of T.  S draws Jack of Club. S will shift his position just behind the person who sits immediately right of S and will face outside.

9)  U draws Queen of Club. According to Condition 5, No change in the position of U. Person V draws Jack of Club. V will shift his position just behind the person who sits immediately right of V and will face outside. T is sitting immediately right of V. 

The final arrangement is:

The one who likes Green color is sitting at the corner of the square.

1) Two persons sit between those who like Pineapple fruit and like Blue color when counted anticlockwise from the person who likes Pineapple T, who likes White sit second to the right of the person who likes Blue color. 

2) The one who likes Cherry and T are immediate neighbors. The immediate neighbor of the one who likes Cheery faces W. W sits immediately right of the one who likes Guava. 

 

3) One person sits between the one who likes Mango and W. Mango is two places away from V.

 

4)  R and W are immediate neighbors and neither of them like Pineapple. 

 

5. The one who likes Pineapple fruit and Blue color does not sit opposite to P. The one who likes the Green color sits second to the left of P. V. does not like the Green color.

6. S sits opposite to the one who sits second to the left of U. S does not like Cherry and Guava. Case 1(a) and Case 1(b) do not satisfy the given condition which is why Case 1(a) and Case 1(b) are eliminated.

The arrangement is:

7)  Q draws King of Spade. Q will shift his position just behind the person who sits second to the left of him at the inner table and will face inside. P draws King of Diamond. According to condition 5, P remains at the same position. R draws Queen of Diamond. R will shift his position just behind (i.e. outer circle) its previous position and will face outside.

8)  W draws King of Heart. W will shift to any corner of the table and will face inside. T draws 9 of Heart. According to condition 5, No change in the position of T.  S draws Jack of Club. S will shift his position just behind the person who sits immediately right of S and will face outside.

9)  U draws Queen of Club. According to Condition 5, No change in the position of U. Person V draws Jack of Club. V will shift his position just behind the person who sits immediately right of V and will face outside. T is sitting immediately right of V. 

The final arrangement is:

Two person is sitting between S and the one who likes blue color when counted to the right of S(in the final arrangement)

1) Two persons sit between those who like Pineapple fruit and like Blue color when counted anticlockwise from the person who likes Pineapple T, who likes White sit second to the right of the person who likes Blue color. 

2) The one who likes Cherry and T are immediate neighbors. The immediate neighbor of the one who likes Cheery faces W. W sits immediately right of the one who likes Guava. 

 

 

3) One person sits between the one who likes Mango and W. Mango is two places away from V.

 

4)  R and W are immediate neighbors and neither of them like Pineapple. 

 

 

5. The one who likes Pineapple fruit and Blue color does not sit opposite to P. The one who likes the Green color sits second to the left of P. V. does not like the Green color.

6. S sits opposite to the one who sits second to the left of U. S does not like Cherry and Guava. Case 1(a) and Case 1(b) do not satisfy the given condition which is why Case 1(a) and Case 1(b) are eliminated.

The arrangement is:

7)  Q draws King of Spade. Q will shift his position just behind the person who sits second to the left of him at the inner table and will face inside. P draws King of Diamond. According to condition 5, P remains at the same position. R draws Queen of Diamond. R will shift his position just behind (i.e. outer circle) its previous position and will face outside.

8)  W draws King of Heart. W will shift to any corner of the table and will face inside. T draws 9 of Heart. According to condition 5, No change in the position of T.  S draws Jack of Club. S will shift his position just behind the person who sits immediately right of S and will face outside.

9)  U draws Queen of Club. According to Condition 5, No change in the position of U. Person V draws Jack of Club. V will shift his position just behind the person who sits immediately right of V and will face outside. T is sitting immediately right of V. 

The final arrangement is:

The one who likes blue sits just behind T in the outer circle.

Input:  82 Pleasure 17 Knowledge 23 Humanity 34 Countries 42 Earmarking

Step I:  Letter: Choose the word that comes first according to the reverse alphabetical order. Select the last four alphabets of that letter and try to form a possible meaningful word from the last four alphabets. Place that meaningful word on the left end in the next step. 

Number: Select the lowest number if the number is odd then multiply it by two and subtract the sum of the digits of the given number from that number multiple. If the number is even then divide it by two and add the sum of the digits of the given number. Place it at the extreme right end.

sure 82 Knowledge 23 Humanity 34 Countries 42 Earmarking 26

Step II: Letter: Choose the word that comes first according to the alphabetical order among the remaining words Select the last four alphabets of that letter and try to form a possible meaningful word. Place that meaningful word on the left end in the next step.

Number: Select the greatest number among the remaining numbers if the number is odd then multiply it by two and subtract the sum of the digits of the given number from that number multiple. If the number is even then divide it by two and add the sum of the digits of the given number. Place it at the extreme right end.

rise sure Knowledge 23 Humanity 34 42 Earmarking 26 51

Step III:  Letter: Choose the word that comes first according to the reverse alphabetical order among the remaining words Select the last four alphabets of that letter and try to form a possible meaningful word. Place that meaningful word on the left end in the next step.

Number: Select the lowest number among the remaining numbers if the number is odd then multiply it by two and subtract the sum of the digits of the given number from that number multiple. If the number is even then divide it by two and add the sum of the digits of the given number. Place it at the extreme right end.

edge rise sure Humanity 34 42 Earmarking 26 51 41

Step IV:  Letter: Choose the word that comes first according to the alphabetical order among the remaining words Select the last four alphabets of that letter and try to form a possible meaningful word. Place that meaningful word on the left end in the next step.

Number: Select the greatest number among the remaining numbers if the number is odd then multiply it by two and subtract the sum of the digits of the given number from that number multiple. If the number is even then divide it by two and add the sum of the digits of the given number. Place it at the extreme right end.

King edge rise sure Humanity 34 26 51 41 27

Step V:  Letter: Choose the remaining word. Select the last four alphabets of that letter and try to form a possible meaningful word. Place that meaningful word on the left end in the next step.

Number: Select the remaining number if the number is odd then multiply it by two and subtract the sum of the digits of the given number from that number multiple. If the number is even then divide it by two and add the sum of the digits of the given number. Place it at the extreme right end.

tiny king edge rise sure 26 51 41 27 24

Step VI: Letter: In every word, exchange every alphabet with its opposite alphabet. Then write the alphabet whose place value is two more than the opposite alphabet place value.

Number: Exchange the digits within the number.

itod rtov xyvx ktkx jhkx 62 15 14 72 42

"ktov" will come in place of (A), and "34" will come in place of (B).

Input:  82 Pleasure 17 Knowledge 23 Humanity 34 Countries 42 Earmarking

Step I:  Letter: Choose the word that comes first according to the reverse alphabetical order. Select the last four alphabets of that letter and try to form a possible meaningful word from the last four alphabets. Place that meaningful word on the left end in the next step. 

Number: Select the lowest number if the number is odd then multiply it by two and subtract the sum of the digits of the given number from that number multiple. If the number is even then divide it by two and add the sum of the digits of the given number. Place it at the extreme right end.

sure 82 Knowledge 23 Humanity 34 Countries 42 Earmarking 26

Step II: Letter: Choose the word that comes first according to the alphabetical order among the remaining words Select the last four alphabets of that letter and try to form a possible meaningful word. Place that meaningful word on the left end in the next step.

Number: Select the greatest number among the remaining numbers if the number is odd then multiply it by two and subtract the sum of the digits of the given number from that number multiple. If the number is even then divide it by two and add the sum of the digits of the given number. Place it at the extreme right end.

rise sure Knowledge 23 Humanity 34 42 Earmarking 26 51

Step III:  Letter: Choose the word that comes first according to the reverse alphabetical order among the remaining words Select the last four alphabets of that letter and try to form a possible meaningful word. Place that meaningful word on the left end in the next step.

Number: Select the lowest number among the remaining numbers if the number is odd then multiply it by two and subtract the sum of the digits of the given number from that number multiple. If the number is even then divide it by two and add the sum of the digits of the given number. Place it at the extreme right end.

edge rise sure Humanity 34 42 Earmarking 26 51 41

Step IV:  Letter: Choose the word that comes first according to the alphabetical order among the remaining words Select the last four alphabets of that letter and try to form a possible meaningful word. Place that meaningful word on the left end in the next step.

Number: Select the greatest number among the remaining numbers if the number is odd then multiply it by two and subtract the sum of the digits of the given number from that number multiple. If the number is even then divide it by two and add the sum of the digits of the given number. Place it at the extreme right end.

King edge rise sure Humanity 34 26 51 41 27

Step V:  Letter: Choose the remaining word. Select the last four alphabets of that letter and try to form a possible meaningful word. Place that meaningful word on the left end in the next step.

Number: Select the remaining number if the number is odd then multiply it by two and subtract the sum of the digits of the given number from that number multiple. If the number is even then divide it by two and add the sum of the digits of the given number. Place it at the extreme right end.

tiny king edge rise sure 26 51 41 27 24

Step VI: Letter: In every word, exchange every alphabet with its opposite alphabet. Then write the alphabet whose place value is two more than the opposite alphabet place value.

Number: Exchange the digits within the number.

itod rtov xyvx ktkx jhkx 62 15 14 72 42

Five elements (words or numbers) are there between "26" and "Knowledge" as they appear in Step II.

Input:  82 Pleasure 17 Knowledge 23 Humanity 34 Countries 42 Earmarking

Step I:  Letter: Choose the word that comes first according to the reverse alphabetical order. Select the last four alphabets of that letter and try to form a possible meaningful word from the last four alphabets. Place that meaningful word on the left end in the next step. 

Number: Select the lowest number if the number is odd then multiply it by two and subtract the sum of the digits of the given number from that number multiple. If the number is even then divide it by two and add the sum of the digits of the given number. Place it at the extreme right end.

sure 82 Knowledge 23 Humanity 34 Countries 42 Earmarking 26

Step II: Letter: Choose the word that comes first according to the alphabetical order among the remaining words Select the last four alphabets of that letter and try to form a possible meaningful word. Place that meaningful word on the left end in the next step.

Number: Select the greatest number among the remaining numbers if the number is odd then multiply it by two and subtract the sum of the digits of the given number from that number multiple. If the number is even then divide it by two and add the sum of the digits of the given number. Place it at the extreme right end.

rise sure Knowledge 23 Humanity 34 42 Earmarking 26 51

Step III:  Letter: Choose the word that comes first according to the reverse alphabetical order among the remaining words Select the last four alphabets of that letter and try to form a possible meaningful word. Place that meaningful word on the left end in the next step.

Number: Select the lowest number among the remaining numbers if the number is odd then multiply it by two and subtract the sum of the digits of the given number from that number multiple. If the number is even then divide it by two and add the sum of the digits of the given number. Place it at the extreme right end.

edge rise sure Humanity 34 42 Earmarking 26 51 41

Step IV:  Letter: Choose the word that comes first according to the alphabetical order among the remaining words Select the last four alphabets of that letter and try to form a possible meaningful word. Place that meaningful word on the left end in the next step.

Number: Select the greatest number among the remaining numbers if the number is odd then multiply it by two and subtract the sum of the digits of the given number from that number multiple. If the number is even then divide it by two and add the sum of the digits of the given number. Place it at the extreme right end.

King edge rise sure Humanity 34 26 51 41 27

Step V:  Letter: Choose the remaining word. Select the last four alphabets of that letter and try to form a possible meaningful word. Place that meaningful word on the left end in the next step.

Number: Select the remaining number if the number is odd then multiply it by two and subtract the sum of the digits of the given number from that number multiple. If the number is even then divide it by two and add the sum of the digits of the given number. Place it at the extreme right end.

tiny king edge rise sure 26 51 41 27 24

Step VI: Letter: In every word, exchange every alphabet with its opposite alphabet. Then write the alphabet whose place value is two more than the opposite alphabet place value.

Number: Exchange the digits within the number.

itod rtov xyvx ktkx jhkx 62 15 14 72 42

41 is second from the right end in Step IV.

Input:  82 Pleasure 17 Knowledge 23 Humanity 34 Countries 42 Earmarking

Step I:  Letter: Choose the word that comes first according to the reverse alphabetical order. Select the last four alphabets of that letter and try to form a possible meaningful word from the last four alphabets. Place that meaningful word on the left end in the next step. 

Number: Select the lowest number if the number is odd then multiply it by two and subtract the sum of the digits of the given number from that number multiple. If the number is even then divide it by two and add the sum of the digits of the given number. Place it at the extreme right end.

sure 82 Knowledge 23 Humanity 34 Countries 42 Earmarking 26

Step II: Letter: Choose the word that comes first according to the alphabetical order among the remaining words Select the last four alphabets of that letter and try to form a possible meaningful word. Place that meaningful word on the left end in the next step.

Number: Select the greatest number among the remaining numbers if the number is odd then multiply it by two and subtract the sum of the digits of the given number from that number multiple. If the number is even then divide it by two and add the sum of the digits of the given number. Place it at the extreme right end.

rise sure Knowledge 23 Humanity 34 42 Earmarking 26 51

Step III:  Letter: Choose the word that comes first according to the reverse alphabetical order among the remaining words Select the last four alphabets of that letter and try to form a possible meaningful word. Place that meaningful word on the left end in the next step.

Number: Select the lowest number among the remaining numbers if the number is odd then multiply it by two and subtract the sum of the digits of the given number from that number multiple. If the number is even then divide it by two and add the sum of the digits of the given number. Place it at the extreme right end.

edge rise sure Humanity 34 42 Earmarking 26 51 41

Step IV:  Letter: Choose the word that comes first according to the alphabetical order among the remaining words Select the last four alphabets of that letter and try to form a possible meaningful word. Place that meaningful word on the left end in the next step.

Number: Select the greatest number among the remaining numbers if the number is odd then multiply it by two and subtract the sum of the digits of the given number from that number multiple. If the number is even then divide it by two and add the sum of the digits of the given number. Place it at the extreme right end.

King edge rise sure Humanity 34 26 51 41 27

Step V:  Letter: Choose the remaining word. Select the last four alphabets of that letter and try to form a possible meaningful word. Place that meaningful word on the left end in the next step.

Number: Select the remaining number if the number is odd then multiply it by two and subtract the sum of the digits of the given number from that number multiple. If the number is even then divide it by two and add the sum of the digits of the given number. Place it at the extreme right end.

tiny king edge rise sure 26 51 41 27 24

Step VI: Letter: In every word, exchange every alphabet with its opposite alphabet. Then write the alphabet whose place value is two more than the opposite alphabet place value.

Number: Exchange the digits within the number.

itod rtov xyvx ktkx jhkx 62 15 14 72 42

 The third smallest number in Step II is 34 and the greatest number in Step III is 51. Hence, the difference between the third smallest number from Step II and the greatest number in Step III is 17.

Statement I: Students are restricted to admission to their desired courses by multiple rounds for selection. This could be the possible reason.

Statement II: Parents have knowledge of a few courses and they motivate or influence their children to take admission in the specific courses. Because of this, there is a great demand for a few courses and less for others. So, This could be the possible reason.

Statement III: There has been increased demand for some courses but there are limited seats in the reputed private and public colleges which leads to a demand and supply mismatch.

Statement IV: Public Institutions have lower fee structures than other institutions because they are funded by the government. So, most parents can afford these colleges. So, Statement IV could not be the reason.

Statement V: There is indeed a concentration of institutions in some specific areas which leads to demand and supply mismatch. So, this statement could be the possible reason.

All I, II, III, and V could be the possible reasons.

1) O is from Spain but not from Palma. Q belongs to the city of T who is not from Spain.

 

 

 

 

 

 

2) V and Q belong to the same country but not the city. P and S belong to the same city but not from country Italy. 

 

 

 

 

 

 

 

3. W neither belongs to Lecce nor Palma. The number of persons belonging to Q’s city is less than the number belonging to W’s city. 

4)  Z and U belong to the same country, but neither is from V’s country. Z and O belong to the different cities. U and Y belong to the same city.

 

 

 

 

 

 

 

 

4)  R and X belong to the same city where an odd number of persons belong. X does not belong to Venice. The number of persons belonging to City Palma and Lecce is the same. Z and Y do not belong to the same place. 

Case 1(a), Case 2(a)(i), Case 2(a)(ii), and Case 2(b) are eliminated because it does not satisfy the given conditions.

The final arrangement is:

 

 

 

 

 

 

 

P and Z belong to the same country. Y belongs to Lecce. Only I statement is correct.

1) O is from Spain but not from Palma. Q belongs to the city of T who is not from Spain.

 

 

 

 

 

 

2) V and Q belong to the same country but not the city. P and S belong to the same city but not from country Italy. 

 

 

 

 

 

 

 

3. W neither belongs to Lecce nor Palma. The number of persons belonging to Q’s city is less than the number belonging to W’s city. 

4)  Z and U belong to the same country, but neither is from V’s country. Z and O belong to the different cities. U and Y belong to the same city.

 

 

 

 

 

 

 

 

4)  R and X belong to the same city where an odd number of persons belong. X does not belong to Venice. The number of persons belonging to City Palma and Lecce is the same. Z and Y do not belong to the same place. 

Case 1(a), Case 2(a)(i), Case 2(a)(ii), and Case 2(b) are eliminated because it does not satisfy the given conditions.

The final arrangement is:

 

 

 

 

 

 

 

Z belongs to Palma.  Z-Palma is correctly matched.

1) O is from Spain but not from Palma. Q belongs to the city of T who is not from Spain.

 

 

 

 

 

 

2) V and Q belong to the same country but not the city. P and S belong to the same city but not from country Italy. 

 

 

 

 

 

 

 

3. W neither belongs to Lecce nor Palma. The number of persons belonging to Q’s city is less than the number belonging to W’s city. 

4)  Z and U belong to the same country, but neither is from V’s country. Z and O belong to the different cities. U and Y belong to the same city.

 

 

 

 

 

 

 

 

4)  R and X belong to the same city where an odd number of persons belong. X does not belong to Venice. The number of persons belonging to City Palma and Lecce is the same. Z and Y do not belong to the same place. 

Case 1(a), Case 2(a)(i), Case 2(a)(ii), and Case 2(b) are eliminated because it does not satisfy the given conditions.

The final arrangement is:

 

 

 

 

 

 

 

R belongs to Lecca.

1) O is from Spain but not from Palma. Q belongs to the city of T who is not from Spain.

 

 

 

 

 

 

2) V and Q belong to the same country but not the city. P and S belong to the same city but not from country Italy. 

 

 

 

 

 

 

 

3. W neither belongs to Lecce nor Palma. The number of persons belonging to Q’s city is less than the number belonging to W’s city. 

4)  Z and U belong to the same country, but neither is from V’s country. Z and O belong to the different cities. U and Y belong to the same city.

 

 

 

 

 

 

 

 

4)  R and X belong to the same city where an odd number of persons belong. X does not belong to Venice. The number of persons belonging to City Palma and Lecce is the same. Z and Y do not belong to the same place. 

Case 1(a), Case 2(a)(i), Case 2(a)(ii), and Case 2(b) are eliminated because it does not satisfy the given conditions.

The final arrangement is:

 

 

 

 

 

 

 

Two people are in Venice, and four people are in Madrid. Hence, The ratio of the persons from Venice and Madrid is 1:2.

1) E is kept at the fifth position. Only two boxes are kept between Box E and Box G. Box M is kept two boxes above Box G. 

 

2) Only three boxes are placed between F and M. Box O is kept immediately above Box L. L is kept at the odd number position. 

 

3) The number of boxes kept between E and N is the same as the number of boxes kept between N and J. Box N is above Box G. Case 1(a), and Case 1(b) are eliminated because it does not satisfy the given conditions.

 

4)  Box H is adjacent to Box K. Case 2(b) is eliminated as it does not satisfy the given conditions.

 

No option other than option 4 can provide the information about the box which is immediately below Box F. According to option 4, Box H is three boxes above Box M.

 

Box H is immediately below Box F.  Box H is three boxes above Box M is the statement from which we can answer the given question.

Given Word: University.

The meaningful word is:

 

Given Word: Accomplishment

The meaningful word is:

 

No meaningful word can be formed from the II, IV, and V given word.  Only I and III can form meaningful words.

1) Kia faces the one who likes Grapes and sits second to the right of the one who likes Iris. The one who likes Poppy sits immediately left to Kia. 

2)  Liv sits second to the right of the one who likes Grapes. One person sits between Liv and Ila, who sits opposite the one who likes Lily. 

3) The one who likes Apple faces Mae’s wife who sits just left of the one who likes Orchid. Case 2 is eliminated as it could not satisfy the given condition.

 

4. Two persons sit between Mae and the one who likes Kiwi. The number of people sitting to the right of Kiwi is the same as the number of people sitting to the left of Joy. The one who likes Kiwi is Eva’s husband. Joy’s wife sits at any end of the row.

There is mention of Joy's wife so Joy is Male. In Case 1(a) Mae could only sit opposite to his wife which contradicts the given conditions that Spouses cannot sit opposite to each other. So, Case 1(a) is eliminated. Case 2 cannot satisfy the given conditions. So, Case 2 is eliminated.

5) Eva does not like Iris. Kia and Eva are not immediate neighbors. Joy’s wife sits at any end of the row. The person opposite Joy’s wife is Kia’s Husband. Joy's wife does not like lily flowers.  Case 1(b) (ii)  and Case 1(b) (i) do not satisfy the given conditions which is why Case 1(b) (ii) and Case 1(b) (i) are eliminated. 

6) The one who likes Pear sits second to the right of Aya’s husband.  

7) Gia is female and not Mae’s wife. Gia does not sit opposite to the one who likes Kiwi. Zoe is male. 

The final arrangement is:

We follow the given symbols to illustrate the relations:

All except the one who is sitting immediately right of Joy are sitting at the extreme ends.The one who is sitting immediately right of Joy does not belong to the group.

1) Kia faces the one who likes Grapes and sits second to the right of the one who likes Iris. The one who likes Poppy sits immediately left to Kia. 

2)  Liv sits second to the right of the one who likes Grapes. One person sits between Liv and Ila, who sits opposite the one who likes Lily. 

3) The one who likes Apple faces Mae’s wife who sits just left of the one who likes Orchid. Case 2 is eliminated as it could not satisfy the given condition.

4. Two persons sit between Mae and the one who likes Kiwi. The number of people sitting to the right of Kiwi is the same as the number of people sitting to the left of Joy. The one who likes Kiwi is Eva’s husband. Joy’s wife sits at any end of the row.

There is mention of Joy's wife so Joy is Male. In Case 1(a) Mae could only sit opposite to his wife which contradicts the given conditions that Spouses cannot sit opposite to each other. So, Case 1(a) is eliminated. Case 2 cannot satisfy the given conditions. So, Case 2 is eliminated.

5) Eva does not like Iris. Kia and Eva are not immediate neighbors. Joy’s wife sits at any end of the row. The person opposite Joy’s wife is Kia’s Husband. Joy's wife does not like lily flowers.  Case 1(b) (ii)  and Case 1(b) (i) do not satisfy the given conditions which is why Case 1(b) (ii) and Case 1(b) (i) are eliminated. 

6) The one who likes Pear sits second to the right of Aya’s husband.  

7) Gia is female and not Mae’s wife. Gia does not sit opposite to the one who likes Kiwi. Zoe is male. 

The final arrangement is:

We follow the given symbols to illustrate the relations:

Only II and III are correct statements.

1) Kia faces the one who likes Grapes and sits second to the right of the one who likes Iris. The one who likes Poppy sits immediately left to Kia. 

2)  Liv sits second to the right of the one who likes Grapes. One person sits between Liv and Ila, who sits opposite the one who likes Lily. 

3) The one who likes Apple faces Mae’s wife who sits just left of the one who likes Orchid. Case 2 is eliminated as it could not satisfy the given condition.

4. Two persons sit between Mae and the one who likes Kiwi. The number of people sitting to the right of Kiwi is the same as the number of people sitting to the left of Joy. The one who likes Kiwi is Eva’s husband. Joy’s wife sits at any end of the row.

There is mention of Joy's wife so Joy is Male. In Case 1(a) Mae could only sit opposite to his wife which contradicts the given conditions that Spouses cannot sit opposite to each other. So, Case 1(a) is eliminated. Case 2 cannot satisfy the given conditions. So, Case 2 is eliminated.

5) Eva does not like Iris. Kia and Eva are not immediate neighbors. Joy’s wife sits at any end of the row. The person opposite Joy’s wife is Kia’s Husband. Joy's wife does not like lily flowers.  Case 1(b) (ii)  and Case 1(b) (i) do not satisfy the given conditions which is why Case 1(b) (ii) and Case 1(b) (i) are eliminated. 

6) The one who likes Pear sits second to the right of Aya’s husband.  

7) Gia is female and not Mae’s wife. Gia does not sit opposite to the one who likes Kiwi. Zoe is male. 

The final arrangement is:

We follow the given symbols to illustrate the relations:

 Wife of Zoe is sitting opposite to the one who likes Peach.

1) Kia faces the one who likes Grapes and sits second to the right of the one who likes Iris. The one who likes Poppy sits immediately left to Kia. 

2)  Liv sits second to the right of the one who likes Grapes. One person sits between Liv and Ila, who sits opposite the one who likes Lily. 

3) The one who likes Apple faces Mae’s wife who sits just left of the one who likes Orchid. Case 2 is eliminated as it could not satisfy the given condition.

4. Two persons sit between Mae and the one who likes Kiwi. The number of people sitting to the right of Kiwi is the same as the number of people sitting to the left of Joy. The one who likes Kiwi is Eva’s husband. Joy’s wife sits at any end of the row.

There is mention of Joy's wife so Joy is Male. In Case 1(a) Mae could only sit opposite to his wife which contradicts the given conditions that Spouses cannot sit opposite to each other. So, Case 1(a) is eliminated. Case 2 cannot satisfy the given conditions. So, Case 2 is eliminated.

5) Eva does not like Iris. Kia and Eva are not immediate neighbors. Joy’s wife sits at any end of the row. The person opposite Joy’s wife is Kia’s Husband. Joy's wife does not like lily flowers.  Case 1(b) (ii)  and Case 1(b) (i) do not satisfy the given conditions which is why Case 1(b) (ii) and Case 1(b) (i) are eliminated. 

6) The one who likes Pear sits second to the right of Aya’s husband.  

7) Gia is female and not Mae’s wife. Gia does not sit opposite to the one who likes Kiwi. Zoe is male. 

The final arrangement is:

We follow the given symbols to illustrate the relations:

Noa is the wife of Mae.

Statement I: This statement emphasizes the cost of the project rather than its benefits. So, Statement I does not strengthen the given passage

Statement II: This statement emphasizes the implication of the project which will help to reduce elephant injury and death. So, Statement II strengthens the given passage.

Statement III: This statement emphasizes the possible problem faced by the railway department in laying fiber. So, Statement III does not strengthen the given passage.

Statement IV: The two-year gap is very much as compared to the problem. So, this statement does not strengthen the given passage.

Statement V: This statement highlights that the device will not be able to differentiate between elephants and others which highlights the flaws in the system. So, this statement does not strengthen the given passage.

Only II is strong.

Assumption I: As cities are experiencing higher temperatures cities must have experienced prolonged heat waves also. So, Assumption I is Implicit.

Assumption II: Climate change and rapid urbanization could lead to micro-climate changes in cities. So, Assumption II is implicit.

Assumption III: From the passage, we cannot assume that cities are taking appropriate steps to protect the environment or increase emergency preparedness. So, Assumption III is not implicit.

Assumption IV: Crowed high-rise buildings of the cities could contribute to the increase in the temperature, not the decrease. Assumption IV is not implicit.

Only I and II assumptions are implicit.

Statement I: Organisations are focusing on skills within the educational stream this indicates the shift towards skills. Also, according to the passage companies are demanding different skills for different streams. So, companies are focusing on talent recruitment. This can be the conclusion for the given passage.

Statement ii: According to the passage companies are focusing on skills rather than rank and marks. So, this statement cannot be concluded from the given passage. This cannot be the conclusion for the given passage.

Statement III: As there is a change in the strategy of recruiters so there should be a change in the strategies of campus also. So, more and more companies visit campus for recruitment. This can be the conclusion for the given passage.

Statement IV: Companies are focusing on skills rather than college reputation. So, this cannot be the conclusion of the given passage.

Only Conclusion I and III follow.

1) B is two designations senior to P, who is neither the junior most nor the Manager. The number of designations junior to P is half the number of designations senior to K. 

 

2)  K is just senior to E. L and K are designated at the same designation. O is three designations junior to K. In Case 4, the given condition cannot be satisfied which is why Case 4 is eliminated.

 

3) Only one designation is between O and F. E and F are not designated at the same designation. In Case 3, the given conditions are not satisfied which is why Case 3 is eliminated.

 

4) No one is designated senior to G who has the same designation as N. N is two designations senior to A. A, and C are designated at the same designation. The just junior and just senior designations of A are vacant. 

 

5)  No one is designated between T and E. I is junior to E and have the same designation as T. O and I do not have the same designation. 

 

6)  R is just junior to S and just senior to W. D and W are at the same designation. No person is junior to W. 

 

7) R is not the assistant manager. This condition is not satisfied in Case 2. So, Case 2 is eliminated. Q is five designations senior to M and Q is just junior to L. No one is designated between C and H. H is not at the same designation as K.

The final arrangement is:

 

T is designated at CGM designation with one more person.

1) B is two designations senior to P, who is neither the junior most nor the Manager. The number of designations junior to P is half the number of designations senior to K. 

 

2)  K is just senior to E. L and K are designated at the same designation. O is three designations junior to K. In Case 4, the given condition cannot be satisfied which is why Case 4 is eliminated.

 

3) Only one designation is between O and F. E and F are not designated at the same designation. In Case 3, the given conditions are not satisfied which is why Case 3 is eliminated.

 

4) No one is designated senior to G who has the same designation as N. N is two designations senior to A. A, and C are designated at the same designation. The just junior and just senior designations of A are vacant. 

 

5)  No one is designated between T and E. I is junior to E and have the same designation as T. O and I do not have the same designation. 

 

6)  R is just junior to S and just senior to W. D and W are at the same designation. No person is junior to W. 

 

7) R is not the assistant manager. This condition is not satisfied in Case 2. So, Case 2 is eliminated. Q is five designations senior to M and Q is just junior to L. No one is designated between C and H. H is not at the same designation as K.

The final arrangement is:

 

Twenty persons are designated in the company.

1) B is two designations senior to P, who is neither the junior most nor the Manager. The number of designations junior to P is half the number of designations senior to K. 

 

2)  K is just senior to E. L and K are designated at the same designation. O is three designations junior to K. In Case 4, the given condition cannot be satisfied which is why Case 4 is eliminated.

 

3) Only one designation is between O and F. E and F are not designated at the same designation. In Case 3, the given conditions are not satisfied which is why Case 3 is eliminated.

 

4) No one is designated senior to G who has the same designation as N. N is two designations senior to A. A, and C are designated at the same designation. The just junior and just senior designations of A are vacant. 

 

5)  No one is designated between T and E. I is junior to E and have the same designation as T. O and I do not have the same designation. 

 

6)  R is just junior to S and just senior to W. D and W are at the same designation. No person is junior to W. 

 

7) R is not the assistant manager. This condition is not satisfied in Case 2. So, Case 2 is eliminated. Q is five designations senior to M and Q is just junior to L. No one is designated between C and H. H is not at the same designation as K.

The final arrangement is:

 

Only I and II are correct.

1) B is two designations senior to P, who is neither the junior most nor the Manager. The number of designations junior to P is half the number of designations senior to K. 

 

2)  K is just senior to E. L and K are designated at the same designation. O is three designations junior to K. In Case 4, the given condition cannot be satisfied which is why Case 4 is eliminated.

 

3) Only one designation is between O and F. E and F are not designated at the same designation. In Case 3, the given conditions are not satisfied which is why Case 3 is eliminated.

 

4) No one is designated senior to G who has the same designation as N. N is two designations senior to A. A, and C are designated at the same designation. The just junior and just senior designations of A are vacant. 

 

5)  No one is designated between T and E. I is junior to E and have the same designation as T. O and I do not have the same designation. 

 

6)  R is just junior to S and just senior to W. D and W are at the same designation. No person is junior to W. 

 

7) R is not the assistant manager. This condition is not satisfied in Case 2. So, Case 2 is eliminated. Q is five designations senior to M and Q is just junior to L. No one is designated between C and H. H is not at the same designation as K.

The final arrangement is:

 

Seven persons are designated lower to O.

1) Only one letter is arranged between F and E. Only two letters are arranged between F and W. 

2) One letter is between W and P. P is not adjacent to F. One letter is between F and L. L is not adjacent to W. 

3) O is adjacent to P. R and U are the remaining letters of the meaningful word. 

Case 1 is eliminated because no meaningful word could be formed in Case 1.

The meaningful word is:

The fourth letter is E, the fifth letter is R, the seventh letter is U, and the eighth letter is L from the left end of the word.

The meaningful words are:

1. RULE means an official statement that tells you what you must or must not do in a particular situation or when playing a game.

2. LURE means the attractive qualities of something.

More than one words are formed.  Y is the correct option.

1) Zoey has more weight than Kent but not heavier than Pearl. Blake is not shorter than Ian who has more height than Orla. Gav has 17 packets of Snacks. Julia is of a higher standard than Axel. 

 

2) Jack is 170 cm in height and is taller than Fna. Fna is not taller than Blake and is 165 cm in height. Only two persons are smaller than Fna. Blake is not the tallest among the students in the group. 

 

3) Pearl's weight is 55 kg which is 15 Kg more than Noel's. Noel's weight is more than Tim's but less than Zoey's. One person has less weight than Kent.  Kent's weight is lesser than the one whose weight is 40 Kg.

 

4) Clark has more snacks than Lynn. Gav has more Snacks than Clark. Gav does not have the maximum Snacks. At least two persons have fewer snacks than Clark. 

 

5)  Devon is in the 9^th standard. Devon is at a higher standard than Axel and a lower standard than Julia. One person is of a higher standard than Julia. 

 

6)  Eli is in 11^th standard. Ray is in the lowest standard among the group members. Information about the Height and Weight of Mia is not Known. Ava and Mia belong to the same group. Ava is upward in the group than Mia. Lynn does not have the least number of Snacks.

 

7) Mia belongs to car IV. Kent and Gav went in the car II. Jack went in the car VI with the person who had the maximum number of snacks. Ian went in car V with the person whose weight was the second highest. 

 

8) The one who is in 11^th standard went in car IV  with Orla. Blake went in Car I with Lynn. The person with the maximum weight went in the same car III with Axel.

 

9) Tim and the one who is in 9^th standard went in the same car. An odd number of people went in Car I.

Devon is in 9^th Standard. Car IV already has three students. So, Tim and Devon do not go in Car IV. Tim belongs to the weight group. Tim can only belong to Car I and VI because there is no member of the weight group in these two cars. If Tim and Devon belong to Car I then there will be an even number of persons in Car I which contradicts the given condition.

 

10) Fna does not go in the same car as Gav. Fna belongs to the Height Group. All cars except II and III have students from Height Group. Gav is in Car II. So, Fna will be in Car III.

 

11) Ray does not go in the same car in which Lynn and Ian went. Ray belongs to the Class Group. So, Ray could belong to Car I, II, and V. But according to the given condition, Ray can only belong to Car II. 

 

12. Noel belongs to Car I because Car II, Car III, Car V, and Car VI have students from the Weight Group. Noel cannot belong to Car IV because then there will be four students in more than one car which contradicts the given condition that only one car can have four students. 

 

13. Clark belongs to Car V because all the cars except Car III and Car V have a member from the Snacks group. In Car III, there are already three students so no more students can belong to Car III.

The final arrangement is:

 

 

Clark, Ian, Zoey went in Car V.

1) Zoey has more weight than Kent but not heavier than Pearl. Blake is not shorter than Ian who has more height than Orla. Gav has 17 packets of Snacks. Julia is of a higher standard than Axel. 

 

2) Jack is 170 cm in height and is taller than Fna. Fna is not taller than Blake and is 165 cm in height. Only two persons are smaller than Fna. Blake is not the tallest among the students in the group. 

 

3) Pearl's weight is 55 kg which is 15 Kg more than Noel's. Noel's weight is more than Tim's but less than Zoey's. One person has less weight than Kent.  Kent's weight is lesser than the one whose weight is 40 Kg.

 

4) Clark has more snacks than Lynn. Gav has more Snacks than Clark. Gav does not have the maximum Snacks. At least two persons have fewer snacks than Clark. 

 

5)  Devon is in the 9^th standard. Devon is at a higher standard than Axel and a lower standard than Julia. One person is of a higher standard than Julia. 

 

6)  Eli is in 11^th standard. Ray is in the lowest standard among the group members. Information about the Height and Weight of Mia is not Known. Ava and Mia belong to the same group. Ava is upward in the group than Mia. Lynn does not have the least number of Snacks.

 

7) Mia belongs to car IV. Kent and Gav went in the car II. Jack went in the car VI with the person who had the maximum number of snacks. Ian went in car V with the person whose weight was the second highest. 

 

8) The one who is in 11^th standard went in car IV  with Orla. Blake went in Car I with Lynn. The person with the maximum weight went in the same car III with Axel.

 

9) Tim and the one who is in 9^th standard went in the same car. An odd number of people went in Car I.

Devon is in 9^th Standard. Car IV already has three students. So, Tim and Devon do not go in Car IV. Tim belongs to the weight group. Tim can only belong to Car I and VI because there is no member of the weight group in these two cars. If Tim and Devon belong to Car I then there will be an even number of persons in Car I which contradicts the given condition.

 

10) Fna does not go in the same car as Gav. Fna belongs to the Height Group. All cars except II and III have students from Height Group. Gav is in Car II. So, Fna will be in Car III.

 

11) Ray does not go in the same car in which Lynn and Ian went. Ray belongs to the Class Group. So, Ray could belong to Car I, II, and V. But according to the given condition, Ray can only belong to Car II. 

 

12. Noel belongs to Car I because Car II, Car III, Car V, and Car VI have students from the Weight Group. Noel cannot belong to Car IV because then there will be four students in more than one car which contradicts the given condition that only one car can have four students. 

 

13. Clark belongs to Car V because all the cars except Car III and Car V have a member from the Snacks group. In Car III, there are already three students so no more students can belong to Car III.

The final arrangement is:

 

 

Car VI has maximum students.

1) Zoey has more weight than Kent but not heavier than Pearl. Blake is not shorter than Ian who has more height than Orla. Gav has 17 packets of Snacks. Julia is of a higher standard than Axel. 

 

2) Jack is 170 cm in height and is taller than Fna. Fna is not taller than Blake and is 165 cm in height. Only two persons are smaller than Fna. Blake is not the tallest among the students in the group. 

 

3) Pearl's weight is 55 kg which is 15 Kg more than Noel's. Noel's weight is more than Tim's but less than Zoey's. One person has less weight than Kent.  Kent's weight is lesser than the one whose weight is 40 Kg.

 

4) Clark has more snacks than Lynn. Gav has more Snacks than Clark. Gav does not have the maximum Snacks. At least two persons have fewer snacks than Clark. 

 

5)  Devon is in the 9^th standard. Devon is at a higher standard than Axel and a lower standard than Julia. One person is of a higher standard than Julia. 

 

6)  Eli is in 11^th standard. Ray is in the lowest standard among the group members. Information about the Height and Weight of Mia is not Known. Ava and Mia belong to the same group. Ava is upward in the group than Mia. Lynn does not have the least number of Snacks.

 

7) Mia belongs to car IV. Kent and Gav went in the car II. Jack went in the car VI with the person who had the maximum number of snacks. Ian went in car V with the person whose weight was the second highest. 

 

8) The one who is in 11^th standard went in car IV  with Orla. Blake went in Car I with Lynn. The person with the maximum weight went in the same car III with Axel.

 

9) Tim and the one who is in 9^th standard went in the same car. An odd number of people went in Car I.

Devon is in 9^th Standard. Car IV already has three students. So, Tim and Devon do not go in Car IV. Tim belongs to the weight group. Tim can only belong to Car I and VI because there is no member of the weight group in these two cars. If Tim and Devon belong to Car I then there will be an even number of persons in Car I which contradicts the given condition.

 

10) Fna does not go in the same car as Gav. Fna belongs to the Height Group. All cars except II and III have students from Height Group. Gav is in Car II. So, Fna will be in Car III.

 

11) Ray does not go in the same car in which Lynn and Ian went. Ray belongs to the Class Group. So, Ray could belong to Car I, II, and V. But according to the given condition, Ray can only belong to Car II. 

 

12. Noel belongs to Car I because Car II, Car III, Car V, and Car VI have students from the Weight Group. Noel cannot belong to Car IV because then there will be four students in more than one car which contradicts the given condition that only one car can have four students. 

 

13. Clark belongs to Car V because all the cars except Car III and Car V have a member from the Snacks group. In Car III, there are already three students so no more students can belong to Car III.

The final arrangement is:

 

 

Ray went in Car II. Car-II Ray is the correct pair.

1) Zoey has more weight than Kent but not heavier than Pearl. Blake is not shorter than Ian who has more height than Orla. Gav has 17 packets of Snacks. Julia is of a higher standard than Axel. 

 

2) Jack is 170 cm in height and is taller than Fna. Fna is not taller than Blake and is 165 cm in height. Only two persons are smaller than Fna. Blake is not the tallest among the students in the group. 

 

3) Pearl's weight is 55 kg which is 15 Kg more than Noel's. Noel's weight is more than Tim's but less than Zoey's. One person has less weight than Kent.  Kent's weight is lesser than the one whose weight is 40 Kg.

 

4) Clark has more snacks than Lynn. Gav has more Snacks than Clark. Gav does not have the maximum Snacks. At least two persons have fewer snacks than Clark. 

 

5)  Devon is in the 9^th standard. Devon is at a higher standard than Axel and a lower standard than Julia. One person is of a higher standard than Julia. 

 

6)  Eli is in 11^th standard. Ray is in the lowest standard among the group members. Information about the Height and Weight of Mia is not Known. Ava and Mia belong to the same group. Ava is upward in the group than Mia. Lynn does not have the least number of Snacks.

 

7) Mia belongs to car IV. Kent and Gav went in the car II. Jack went in the car VI with the person who had the maximum number of snacks. Ian went in car V with the person whose weight was the second highest. 

 

8) The one who is in 11^th standard went in car IV  with Orla. Blake went in Car I with Lynn. The person with the maximum weight went in the same car III with Axel.

 

9) Tim and the one who is in 9^th standard went in the same car. An odd number of people went in Car I.

Devon is in 9^th Standard. Car IV already has three students. So, Tim and Devon do not go in Car IV. Tim belongs to the weight group. Tim can only belong to Car I and VI because there is no member of the weight group in these two cars. If Tim and Devon belong to Car I then there will be an even number of persons in Car I which contradicts the given condition.

 

10) Fna does not go in the same car as Gav. Fna belongs to the Height Group. All cars except II and III have students from Height Group. Gav is in Car II. So, Fna will be in Car III.

 

11) Ray does not go in the same car in which Lynn and Ian went. Ray belongs to the Class Group. So, Ray could belong to Car I, II, and V. But according to the given condition, Ray can only belong to Car II. 

 

12. Noel belongs to Car I because Car II, Car III, Car V, and Car VI have students from the Weight Group. Noel cannot belong to Car IV because then there will be four students in more than one car which contradicts the given condition that only one car can have four students. 

 

13. Clark belongs to Car V because all the cars except Car III and Car V have a member from the Snacks group. In Car III, there are already three students so no more students can belong to Car III.

The final arrangement is:

 

 

Clark and Noel belong to different groups. Only the I and III statements are correct.

Statement I: It is mentioned in the passage that students are moving to foreign for studies, not to learn culture and foreign language. Statement I cannot be the reason. 

Statement II: Students get part-time jobs easily in foreign universities which help them to be financially independent at an early age. So, Statement II can be the reason.

Statement III: Students do not independently decide that they will pursue studies in foreign it needs the parent's support also. Only based on a liberal lifestyle parents will not send their children to foreign on their hard-earned money. 

Statement IV: As it is mentioned a lot of students are moving abroad for studies but not so many people are rich. So, this statement cannot be the reason for the given situation.

Statement V: It is a well-known fact that students face a lot of problems in getting jobs after the completion of their graduation in India but this is not the case in foreign. Higher education aims to get a job that is easily achievable in foreign. So, this statement could be the possible reason.

II, and V could be the possible reasons.

Statement I: Innovation in health care could help patients to have equitable health care access. So, Statement I could be the course of action.

Statement II: Providing subsidies for medical research would help the healthcare facility to use their funds to enhance the services and patient care. Also, pilot projects will help to understand the field problems well and observe the impact of rate caps. So, Statement II could be the course of action.

Statement III: Public-private partnership will help to share advanced technologies resulting in better patient care. Statement III could be the course of action.

Statement IV: Government hospitals are funded by the government but private hospitals bear all expenses through medical bills if there is standardization of medical procedures then it will impact the service delivery and patient care in private hospitals. So, Statement IV cannot be the course of action.

Only I, II, and III follow.

Because of the growing instances of digital payment fraud in India. RBI has proposed a Digital Payment Intelligence Platform and a committee to examine various aspects to widen the adoption of small-value payment devices.

Statement III is the cause, and Statements I and II are the effect.

Statement I: In zoos, animals are under human care. So, Zoo animals are dependent on humans to deal will stressful situations such as extreme weather.

Statement II: Yes, animals are affected by heatstroke that is why a set of doctors are studying its effect on animals.

Statement III: Yes, Zoo has started a summer management diet for this purpose.

Statement IV: It is not mentioned anywhere in the passage that heatwaves have started early this summer. So, this statement can not be inferred from the given passage.

Statement V: Wild animals are also affected by the sudden change in climate which is why Zoos have made changes in the diet of Animals according to the season. So, the given statement cannot be inferred from the given passage.

Both IV and V cannot be inferred from the given information.