Reasoning PYQs

Using the following notations, we can draw the family tree,

1. M is the only son of X.

2. C is the wife of X.

3. None of the daughters of X is married.

4. S and Y are the daughters of C.

5. C is the daughter of W and R.

6. Q is the grandson of C.

7. D is the mother of X.

I) Y is Brother of M. ⇒ False (as Y is sister of M)

II) S is the granddaughter of D. ⇒ True

III) R is Father-in-Law of M.⇒ False (as per family diagram gender of R is not defined therefore R is either father-in-law or mother-in-law of M.)

Thus, only Statement II is definitely correct.

Using the following notations, we can draw the family tree,

1. M is the only son of X.

2. C is the wife of X.

3. None of the daughters of X is married.

4. S and Y are the daughters of C.

5. C is the daughter of W and R.

6. Q is the grandson of C.

7. D is the mother of X.

Hence, S is the aunt of Q.

Based on given information direction diagram can be traced as,

Hence, point F is South - East with respect to point B.

Based on given information direction diagram can be traced as,

Hence, A is 5 meter to the west of F.

Based on given information direction diagram can be traced as,

Hence, point Z is North - West with respect to point E.

Sushmita remembers that her birthday falls between April and October.

Therefore, Sushmita Birthday = May or June or July or August or September.

Zahida remembers that Sushmita’s birthday falls in between April and July.

Therefore, Sushmita Birthday = May or June

Box: S, T, U, V, W, X and Y.

1. There are 4 boxes between T and W.​

2. There are 2 boxes between W and Y.

 

3. Box U is kept above V.

4. Only one box is between U and V.

5. U is not immediately above Y.

6. U is not the topmost box.

 

7) As many boxes are between T and V is as between W and S.

Only, box X is left which will be placed between S and Y.

 

Above arrangement will be the final arrangement.

Hence, none will be kept below V, as V is the bottom-most box.

Box: S, T, U, V, W, X and Y.

1. There are 4 boxes between T and W.

2) There are 2 boxes between W and Y.

 

3. Box U is kept above V.

4. Only one box is between U and V.

5. U is not immediately above Y.

6. U is not the topmost box.

 

7) As many boxes are between T and V is as between W and S.

Only, box X is left which will be placed between S and Y.

 

Above arrangement will be the final arrangement.

As no box is kept between S and X, therefore none is the correct answer.

Box: S, T, U, V, W, X and Y.

1. There are 4 boxes between T and W.

2) There are 2 boxes between W and Y.

 

3. Box U is kept above V.

4. Only one box is between U and V.

5. U is not immediately above Y.

6. U is not the topmost box.

 

7) As many boxes are between T and V is as between W and S.

Only, box X is left which will be placed between S and Y.

 

Above arrangement will be the final arrangement.

Y is kept immediately above U.

Box: S, T, U, V, W, X and Y.

1. There are 4 boxes between T and W.

2) There are 2 boxes between W and Y.

 

3. Box U is kept above V.

4. Only one box is between U and V.

5. U is not immediately above Y.

6. U is not the topmost box.

 

7) As many boxes are between T and V is as between W and S.

Only, box X is left which will be placed between S and Y.

 

Above arrangement will be the final arrangement.

I) U is kept between T and Y. ⇒ True

II) W is the topmost box. ⇒ True

III) V is the bottommost box. ⇒ True

Hence, all I, II and III are true.

Box: S, T, U, V, W, X and Y.

1. There are 4 boxes between T and W.

2) There are 2 boxes between W and Y.

 

3. Box U is kept above V.

4. Only one box is between U and V.

5. U is not immediately above Y.

6. U is not the topmost box.

 

7) As many boxes are between T and V is as between W and S.

Only, box X is left which will be placed between S and Y.

 

Above arrangement will be the final arrangement.

Hence, Y is kept between X and U.

Friends: G, H, J, K, L, M, N and O

1. G lives on the floor numbered 5.

2. There are two floors between G and N.

 

3. L lives on an odd-numbered floor but immediately above O.

4. As many people live above N as below L.

Thus, Case 2 gets eliminated.

 

5. There are three people between L and K. 

 

6. J lives on one of the floors below M but not on the ground floor. 

 

Hence, the final arrangement will be : 

 

Hence, one person lives between M and O.

Friends: G, H, J, K, L, M, N and O

1. G lives on the floor numbered 5.

2. There are two floors between G and N.

 

3. L lives on an odd-numbered floor but immediately above O.

4. As many people live above N as below L.

Thus, Case 2 gets eliminated.

 

5. There are three people between L and K. 

 

6. J lives on one of the floors below M but not on the ground floor. 

 

Hence, the final arrangement will be : 

 

Hence, M and H occupy top and ground floor respectively.

Friends: G, H, J, K, L, M, N and O

1. G lives on the floor numbered 5.

2) There are two floors between G and N.

 

3. L lives on an odd-numbered floor but immediately above O.

4. As many people live above N as below L.

Thus, Case 2 gets eliminated.

 

5. There are three people between L and K. 

 

6. J lives on one of the floors below M but not on the ground floor. 

 

Hence, the final arrangement will be : 

 

1. M, O ⇒ Only one floor between M and O.

2. L, O ⇒ No floor between L and O.

3. O, J ⇒ Only one floor between O and J.

4. J, N ⇒ Only one floor between J and N.

5. K, H ⇒ Only one floor between K and H.

Friends: G, H, J, K, L, M, N and O

1. G lives on the floor numbered 5.

2) There are two floors between G and N.

 

3. L lives on an odd-numbered floor but immediately above O.

4. As many people live above N as below L.

Thus, Case 2 gets eliminated.

 

5. There are three people between L and K. 

 

6. J lives on one of the floors below M but not on the ground floor. 

 

Hence, the final arrangement will be : 

 

Hence, K lives on the third floor.

Friends: G, H, J, K, L, M, N and O

1. G lives on the floor numbered 5.

2) There are two floors between G and N.

 

3. L lives on an odd-numbered floor but immediately above O.

4. As many people live above N as below L.

Thus, Case 2 gets eliminated.

 

5. There are three people between L and K. 

 

6. J lives on one of the floors below M but not on the ground floor. 

 

Hence, the final arrangement will be : 

 

As H live on the ground floor, therefore no one lives below H.

**Given

Statement:

** R ≤ E = P ≤ D ˃ G and P ≥ J

I. G ˃ E → As (E = P ≤ D ˃ G) here the relationship between E and G cannot be established, hence false.

II. R ≤ J → As (R ≤ E = P ≥ J) here the relationship between R and J cannot be established, hence false.

So, neither conclusion I nor II follows.

Given

Statement:

M ≤ N ˂ P = R ≥ T ≥ V

I. M ˂ R → As (M ≤ N ˂ P = R) it is clear that R ˃ M, hence true.

II. P ≥ V → As (P = R ≥ T ≥ V) it is clear that P ≥ V, hence true.

So, both conclusions I and II follow.

Given

Statement:

Q = B = L ≤ M = O and B ˃ R ˂ H and G ≥ O

I. Q = G → As (G ≥ O = M ≥ L = B = Q) it is clear that (Q = G) can be a possibility.

II. G ˃ Q → As (G ≥ O = M ≥ L = B = Q) it is clear that (G ˃ Q), can be a possibility.

So, here either conclusion I or II can be a possibile thus, either of the conclusions follow.

Given

Statements:

S > O ≥ U ≥ P; O ≤ T < R; T ≥ E > A

On combining: S > O ≥ U ≥ P; O ≤ T ≥ E > A; T < R

I) P < O → False (as O ≥ U ≥ P)

II) R > E → True (as T < R; T ≥ E, R > E )

Hence, only conclusions II is true.