Reasoning PYQs

**Given

Statements:

**  T > N < V = L ≤ W < K, V = H > I > F

On combining:   T > N < V = L ≤ W < K,  T > N < V = H > I > F

I. V > F → True ( As V = H > I > F so V > F is true )

II. T > H → False ( As T > N < V = H > I > F no direct relation is given between the two, so it is possibility but not definitely true Hence T > H is false)

Only I follow.

**Given

Statements:

** X < A ≤ H ≤ B; J = K; K ≤ B

On Combining: X < A ≤ H ≤ B ≥ K = J

Conclusions:

I. B ≥ J → True (As X < A ≤ H ≤ B ≥ K = J → B ≥ J. So, it is true)

II. X < K → False (As X < A ≤ H ≤ B ≥ K = J, there is no direct relation between X and K because of opposite signs between X and K. So, it is false)

Hence, Only I follow.

1- R sits fifth from the right extreme end of the row.

2- R sits second to the right of P.

3- T is immediate to the left of P.

4- Three persons sit between P and Q. 

5- Only three people sit between Q and S.

 

Case 2 is canceled because there is no space for S.

 

 

 

Case 2

 6- As many people sit between R and U as many between U and S.

7- Y sits second to the left of V, who is an immediate neighbor of Q. 

8- Not more than two people sit between V and S. 

9- Five persons sit between S and X. 

10- X sits on the extreme end of the row.

11- As many people sit between S and W as many between W and X.

 

 

 

 

Case-1

 

So final arrangement, 

 

Hence, 21 seats in a row.

1- R sits fifth from the right extreme end of the row.

2- R sits second to the right of P.

3- T is immediate to the left of P.

4- Three persons sit between P and Q. 

5- Only three people sit between Q and S.

 

Case 2 is canceled because there is no space for S.

 

 

 

Case 2

 6- As many people sit between R and U as many between U and S.

7- Y sits second to the left of V, who is an immediate neighbor of Q. 

8- Not more than two people sit between V and S. 

9- Five persons sit between S and X. 

10- X sits on the extreme end of the row.

11- As many people sit between S and W as many between W and X.

 

 

 

 

Case-1

 

So final arrangement, 

 

Hence, R sits sixth to the right of Q.

1- R sits fifth from the right extreme end of the row.

2- R sits second to the right of P.

3- T is immediate to the left of P.

4- Three persons sit between P and Q. 

5- Only three people sit between Q and S.

 

Case 2 is canceled because there is no space for S.

 

 

 

Case 2

 6- As many people sit between R and U as many between U and S.

7- Y sits second to the left of V, who is an immediate neighbor of Q. 

8- Not more than two people sit between V and S. 

9- Five persons sit between S and X. 

10- X sits on the extreme end of the row.

11- As many people sit between S and W as many between W and X.

 

 

 

 

Case-1

 

So final arrangement, 

 

Hence, six people are sit between S and T.

Given:-

Word: CONSISTENCY

3^rd letter = N ; 4^th letter = S ; 7^th letter = T; 8^th letter = E

Words formed using the above letters:

1. NEST - Home of Birds
2. SENT - Past simple and past particle of Send
3. STEN - To stride energetically / Narrow, little
4. TENS - used in mathematical operations.

Confusion Points NETS is not a meaningful word as we know NET is a meaningful word and NETS is its plural form so this cannot be considered a meaningful word. So by the given letters, only four meaningful words will be formed.

Given series:

Left Side  6 U # 7 Y 8 X @ Q 9 L S % $ V M 3 F 2 K 1 5 Z & 4 C * O ? D  Right Side

Letters, which are immediately preceded by a symbol and immediately followed by a number:

Symbol → Letter  → Number

6 U # 7 Y 8 X @ Q 9 L S % $ V M 3 F 2 K 1 5 Z & 4 C * O ? D

Hence, There is one letter, which is immediately preceded by a symbol and immediately followed by a number: @ Q 9.

Given series:

Left Side  - 6 U # 7 Y 8 X @ Q 9 L S % $ V M 3 F 2 K 1 5 Z & 4 C * O ? D  - Right Side

As, the numbers between X and Z are 9, 3, 2, 1 and 5.

Product of the numbers → 9 * 3 * 2 * 1 * 5 = 270

Hence, The product of these numbers would be 270.$

Given series:

Left Side  6 U # 7 Y 8 X @ Q 9 L S % $ V M 3 F 2 K 1 5 Z & 4 C * O ? D  Right Side

1. If all the odd numbers are dropped:

6 U # Y 8 X @ Q L S % $ V M F 2 K Z & 4 C * O ? D

2. 7^th element from the left end is @.

Hence, element that is 5^th to the right of 7^th from the left end is $.

Important Points

If we have to go from the left towards the left then we will subtract and vice versa.

If we have to move from the left towards the right then we will add and vice versa.

 

7^th from left: @

7 + 5 = 12^th

The 12^th element from the left end will be $.

Given series:

Left Side  6 U # 7 Y 8 X @ Q 9 L S % $ V M 3 F 2 K 1 5 Z & 4 C * O ? D  Right Side

1. Numbers that are immediately preceded by a symbol:

Symbol  → Number

6 U # 7 Y 8 X @ Q 9 L S % $ V M 3 F 2 K 1 5 Z & 4 C * O ? D

Hence, There are two numbers, which are immediately preceded by a symbol: #7 and &4.

In row-1 J, K, L, M, and N → facing South

In row-2 V, W, X, Y, and Z → facing North

1. Z sits third to the right of W.

2. V sits second to the left of Z.

3. The person facing V sits to the immediate right of K.

4. Only one person sits between K and M.

5. J is not an immediate neighbor of K. 

6. Only two people sit between J and L → Case 2 gets eliminated

(If we take 2 persons between J and L, then the place of L will not be determined as it is already occupied by K)

7. Neither K nor J faces Y → Case 1.1 gets eliminated

So, the final arrangement will be

Hence, V is facing N.

In row-1 J, K, L, M, and N → facing South

In row-2 V, W, X, Y, and Z → facing North

1. Z sits third to the right of W.

2. V sits second to the left of Z.

3. The person facing V sits to the immediate right of K.

4. Only one person sits between K and M.

5. J is not an immediate neighbor of K. 

6. Only two people sit between J and L → Case 2 gets eliminated

(If we take 2 persons between J and L, then the place of L will not be determined as it is already occupied by K)

7. Neither K nor J faces Y → Case 1.1 gets eliminated

So, the final arrangement will be

Hence, L sits to the immediate right of M is true**.**

In row-1 J, K, L, M, and N → facing South

In row-2 V, W, X, Y, and Z → facing North

1. Z sits third to the right of W.

2. V sits second to the left of Z.

3. The person facing V sits to the immediate right of K.

4. Only one person sits between K and M.

5. J is not an immediate neighbor of K. 

6. Only two people sit between J and L → Case 2 gets eliminated

(If we take 2 persons between J and L, then the place of L will not be determined as it is already occupied by K)

7. Neither K nor J faces Y → Case 1.1 gets eliminated

So, the final arrangement will be

Hence, K is facing X.

In row-1 J, K, L, M, and N → facing South

In row-2 V, W, X, Y, and Z → facing North

1. Z sits third to the right of W.

2. V sits second to the left of Z.

3. The person facing V sits to the immediate right of K.

4. Only one person sits between K and M.

5. J is not an immediate neighbor of K. 

6. Only two people sit between J and L → Case 2 gets eliminated

(If we take 2 persons between J and L, then the place of L will not be determined as it is already occupied by K)

7. Neither K nor J faces Y → Case 1.1 gets eliminated

So, the final arrangement will be

Hence, Z sits to the immediate left of Y**.**

In row-1 J, K, L, M, and N → facing South

In row-2 V, W, X, Y, and Z → facing North

1. Z sits third to the right of W.

2. V sits second to the left of Z.

3. The person facing V sits to the immediate right of K.

4. Only one person sits between K and M.

5. J is not an immediate neighbor of K. 

6. Only two people sit between J and L → Case 2 gets eliminated

(If we take 2 persons between J and L, then the place of L will not be determined as it is already occupied by K)

7. Neither K nor J faces Y → Case 1.1 gets eliminated

So, the final arrangement will be

Except N, all others are sitting at the end of the row.

Hence, N does not belong to the group.

Given:

1) B was 9m to the north of G.

2) G was 6 m west of Q.

3) D was 9m east of G.

4. M was 4m south of D.

5. F was 11m north of D and 2m east of O.

Now, O was in the Northwest direction with respect to D.

Using Pythagoras' theorem,

OD² = OP² + PD² = 2²+11²

OD² = 4+121 = 125

 OD = √125 

OD = 5√ 5 m

Hence, the correct answer is Northwest, 5√ 5 m.

Forward pair - 0

Backward pairs - GI, NR

Hence, two such pairs have as many letters in the word as they have between them in the English alphabetical series.

Table is drawn describing symbols and their meanings:

1) T is the daughter-in-law of Q who is the mother of P.

2) T is not married to P.

3) P is a male.

          

4) S has two children both of them are of same gender. 

5) A is the mother of O. A is not the wife of either S or T.

 

 

The above statement implies that A is a female and have a child O. There are three generations in the family. So, A can be either from I generation or II generation. She cannot be married to Q or T as the gender is same. So, she will be married to P. Also, S can be from II generation or I generation as he/she has two children.

6) R is the only son of B.

7)  Number of female and male in the family are same.

 

\

Now, as there could not be a single parent, so there should be a person married to Q. As R is the only son of B. B could not be married to S. Therefore, S is married to Q. 

Now, only B and R are to be paced. B will be married to T as there could not be single parent. There are equal number of male and female members, so, O will be a female member. 

 

Hence, O is the grand-daughter of S.

Table is drawn describing symbols and their meanings:

1) T is the daughter-in-law of Q who is the mother of P.

2) T is not married to P.

3) P is a male.

          

4) S has two children both of them are of same gender. 

5) A is the mother of O. A is not the wife of either S or T.

 

 

The above statement implies that A is a female and have a child O. There are three generations in the family. So, A can be either from I generation or II generation. She cannot be married to Q or T as the gender is same. So, she will be married to P. Also, S can be from II generation or I generation as he/she has two children.

6) R is the only son of B.

7)  Number of female and male in the family are same.

 

 

\

Now, as there could not be a single parent, so there should be a person married to Q. As R is the only son of B. B could not be married to S. Therefore, S is married to Q. 

Now, only B and R are to be paced. B will be married to T as there could not be single parent. There are equal number of male and female members, so, O will be a female member. 

 

Hence, B is the brother-in-law of A.

Table is drawn describing symbols and their meanings:

1) T is the daughter-in-law of Q who is the mother of P.

2) T is not married to P.

3) P is a male.

          

4) S has two children both of them are of same gender. 

5) A is the mother of O. A is not the wife of either S or T.

 

The above statement implies that A is a female and have a child O. There are three generations in the family. So, A can be either from I generation or II generation. She cannot be married to Q or T as the gender is same. So, she will be married to P. Also, S can be from II generation or I generation as he/she has two children.

6) R is the only son of B.

7)  Number of female and male in the family are same.

 

\

Now, as there could not be a single parent, so there should be a person married to Q. As R is the only son of B. B could not be married to S. Therefore, S is married to Q. 

Now, only B and R are to be paced. B will be married to T as there could not be single parent. There are equal number of male and female members, so, O will be a female member. 

 

Hence, R is nephew of P.