What is the least number, which, when divided by 45 and 55 leaves a remainder of 3 in each case?
- AOption (a)
2475
- BOption (b)
498
- COption (c)
825
- DOption (d)
625
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Correct answer
498
Why this answer is correct
Given:
We need to find the least number, which, when divided by 45 and 55 leaves a remainder of 3 in each case.
Formula used:
Least Common Multiple (LCM) of 45 and 55
Required number = LCM(45, 55) + Remainder
Calculation:
Prime factorization:
45 = 32 × 5
55 = 5 × 11
LCM(45, 55) = 32 × 5 × 11 = 9 × 5 × 11
⇒ LCM(45, 55) = 495
Required number = 495 + 3
⇒ Required number = 498
∴ The correct answer is option (2).




